This mathematical function defines f(x) as the sine of x plus a constant value c. The function f(x)=sin(x) + c is presented as the solution to the given problem statement. No other context or explanation is provided.
the one thing that comes to mind for me is about .pdfasif1401
ย
the one thing that comes to mind for me is about the diatomic elements
H,N,F,O,I,Cl,B they\'re all really the ones that could form a molecule since they are composed of
more than one element (all of them are subscript 2, as in H2). most other elements exists as 1.
dont confuse this with MOLECULES which are composed of different atoms together.
Solution
the one thing that comes to mind for me is about the diatomic elements
H,N,F,O,I,Cl,B they\'re all really the ones that could form a molecule since they are composed of
more than one element (all of them are subscript 2, as in H2). most other elements exists as 1.
dont confuse this with MOLECULES which are composed of different atoms together..
#include
#include
using namespace std;
class twoStacks
{
int *arr;
int size;
int top1, top2;
public:
twoStacks(int n) // constructor
{
size = n;
arr = new int[n];
top1 = -1;
top2 = size;
}
// Method to push an element x to stack1
void push1(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top1++;
arr[top1] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to push an element x to stack2
void push2(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top2--;
arr[top2] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to pop an element from first stack
int pop1()
{
if (top1 >= 0 )
{
int x = arr[top1];
top1--;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
// Method to pop an element from second stack
int pop2()
{
if (top2 < size)
{
int x = arr[top2];
top2++;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
};
/* Driver program to test twStacks class */
int main()
{
twoStacks ts(5);
ts.push1(5);
ts.push2(10);
ts.push2(15);
ts.push1(11);
ts.push2(7);
cout << \"Popped element from stack1 is \" << ts.pop1();
ts.push2(40);
cout << \"\ Popped element from stack2 is \" << ts.pop2();
return 0;
}
#include
#include
using namespace std;
class twoStacks
{
int *arr;
int size;
int top1, top2;
public:
twoStacks(int n) // constructor
{
size = n;
arr = new int[n];
top1 = -1;
top2 = size;
}
// Method to push an element x to stack1
void push1(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top1++;
arr[top1] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to push an element x to stack2
void push2(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top2--;
arr[top2] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to pop an element from first stack
int pop1()
{
if (top1 >= 0 )
{
int x = arr[top1];
top1--;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
// Method to pop an element from second stack
int pop2()
{
if (top2 < size)
{
int x = arr[top2];
top2++;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
};
/* Driver program to test twStacks class */
int main()
{
twoStacks ts(5);
ts.push1(5);
ts.push2(10);
ts.push2(15);
ts.push1(11);
ts.push2(7);
cout << \"Popped element from stack1 is \" << ts.pop1();
ts.push2(40);
cout << \"\ Popped element from stack2 is \" << ts.pop2();
return 0;
}
Solution
#include
#include
using namespace std;
class twoStacks
{
int *arr;
int size;
int top1, top2;
public:
twoStacks(int n) // constructor
{
size = n;
arr = new int[n];
top1 = -1;
top2 = size;
}
// Method to push an element x to stack1
void push1(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top1++;
arr[top1] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to push an element x to stack2
void push2(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{.
(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen.pdfasif1401
ย
(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen, and other chemicals in
the atmosphere to form various acidic compounds. Sunlight increases the rate of most of these
reactions. The result is a mild solution of sulfuric acid and nitric acid.
Acid rain causes acidification of lakes and streams and contributes to damage of trees at high
elevations and many sensitive forest soils.
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution
= ( 5.47 x 10 -3 / 46 ) / 1.0
= 1.189 x 10 -4 M
According to the balanced equation,
2 mole of NO2 produces 2 moles of HNO3
So the concentration of HNO3 is = 1.189 x 10 -4 M
HNO3 ---> H+ + NO3-
1 mole of HNO3 produces 1 mole of H+
So [H+] = 1.189 x 10 -4 M
pH = - log [H+]
= -log ( 1.189 x 10 -4 )
= 4 - log 1.189
= 3.92
(3) HNO3 + H2O ----> HNO3 (aq)
H2SO4 + H2O ---> H2SO4 (aq)
HCl + H2O ---> HCl (aq)
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution
= ( 5.47 x 10 -3 / 46 ) / 1.0
= 1.189 x 10 -4 M
According to the balanced equation,
2 mole of NO2 produces 2 moles of HNO3
So the concentration of HNO3 is = 1.189 x 10 -4 M
HNO3 ---> H+ + NO3-
1 mole of HNO3 produces 1 mole of H+
So [H+] = 1.189 x 10 -4 M
pH = - log [H+]
= -log ( 1.189 x 10 -4 )
= 4 - log 1.189
= 3.92
(3) HNO3 + H2O ----> HNO3 (aq)
H2SO4 + H2O ---> H2SO4 (aq)
HCl + H2O ---> HCl (aq)
Solution
(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen, and other chemicals in
the atmosphere to form various acidic compounds. Sunlight increases the rate of most of these
reactions. The result is a mild solution of sulfuric acid and nitric acid.
Acid rain causes acidification of lakes and streams and contributes to damage of trees at high
elevations and many sensitive forest soils.
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution
= ( 5.47 x 10 -3 / 46 ) / 1.0
= 1.189 x 10 -4 M
According to the balanced equation,
2 mole of NO2 produces 2 moles of HNO3
So the concentration of HNO3 is = 1.189 x 10 -4 M
HNO3 ---> H+ + NO3-
1 mole of HNO3 produces 1 mole of H+
So [H+] = 1.189 x 10 -4 M
pH = - log [H+]
= -log ( 1.189 x 10 -4 )
= 4 - log 1.189
= 3.92
(3) HNO3 + H2O ----> HNO3 (aq)
H2SO4 + H2O ---> H2SO4 (aq)
HCl + H2O ---> HCl (aq)
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Vol.
Iodine will replace both Cl and Br It will be SN2.pdfasif1401
ย
Iodine will replace both Cl and Br It will be SN2 reaction and hence there will be
Walden Inversion.
Solution
Iodine will replace both Cl and Br It will be SN2 reaction and hence there will be
Walden Inversion..
The number of outcomes in the event A is 4 Yes event A is a s.pdfasif1401
ย
The number of outcomes in the event A is 4
Yes event A is a sample event
Solution
The number of outcomes in the event A is 4
Yes event A is a sample event.
There were very few planetary leftovers in this r.pdfasif1401
ย
There were very few planetary leftovers in this region, because most of the solid
material was accreted by the terrestrial planets as the planets formed.
Solution
There were very few planetary leftovers in this region, because most of the solid
material was accreted by the terrestrial planets as the planets formed..
i have no idea. im just seeing if i get karma p.pdfasif1401
ย
i have no idea. i\'m just seeing if i get karma points for a half ass answer.
Solution
i have no idea. i\'m just seeing if i get karma points for a half ass answer..
the one thing that comes to mind for me is about .pdfasif1401
ย
the one thing that comes to mind for me is about the diatomic elements
H,N,F,O,I,Cl,B they\'re all really the ones that could form a molecule since they are composed of
more than one element (all of them are subscript 2, as in H2). most other elements exists as 1.
dont confuse this with MOLECULES which are composed of different atoms together.
Solution
the one thing that comes to mind for me is about the diatomic elements
H,N,F,O,I,Cl,B they\'re all really the ones that could form a molecule since they are composed of
more than one element (all of them are subscript 2, as in H2). most other elements exists as 1.
dont confuse this with MOLECULES which are composed of different atoms together..
#include
#include
using namespace std;
class twoStacks
{
int *arr;
int size;
int top1, top2;
public:
twoStacks(int n) // constructor
{
size = n;
arr = new int[n];
top1 = -1;
top2 = size;
}
// Method to push an element x to stack1
void push1(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top1++;
arr[top1] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to push an element x to stack2
void push2(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top2--;
arr[top2] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to pop an element from first stack
int pop1()
{
if (top1 >= 0 )
{
int x = arr[top1];
top1--;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
// Method to pop an element from second stack
int pop2()
{
if (top2 < size)
{
int x = arr[top2];
top2++;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
};
/* Driver program to test twStacks class */
int main()
{
twoStacks ts(5);
ts.push1(5);
ts.push2(10);
ts.push2(15);
ts.push1(11);
ts.push2(7);
cout << \"Popped element from stack1 is \" << ts.pop1();
ts.push2(40);
cout << \"\ Popped element from stack2 is \" << ts.pop2();
return 0;
}
#include
#include
using namespace std;
class twoStacks
{
int *arr;
int size;
int top1, top2;
public:
twoStacks(int n) // constructor
{
size = n;
arr = new int[n];
top1 = -1;
top2 = size;
}
// Method to push an element x to stack1
void push1(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top1++;
arr[top1] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to push an element x to stack2
void push2(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top2--;
arr[top2] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to pop an element from first stack
int pop1()
{
if (top1 >= 0 )
{
int x = arr[top1];
top1--;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
// Method to pop an element from second stack
int pop2()
{
if (top2 < size)
{
int x = arr[top2];
top2++;
return x;
}
else
{
cout << \"Stack UnderFlow\";
exit(1);
}
}
};
/* Driver program to test twStacks class */
int main()
{
twoStacks ts(5);
ts.push1(5);
ts.push2(10);
ts.push2(15);
ts.push1(11);
ts.push2(7);
cout << \"Popped element from stack1 is \" << ts.pop1();
ts.push2(40);
cout << \"\ Popped element from stack2 is \" << ts.pop2();
return 0;
}
Solution
#include
#include
using namespace std;
class twoStacks
{
int *arr;
int size;
int top1, top2;
public:
twoStacks(int n) // constructor
{
size = n;
arr = new int[n];
top1 = -1;
top2 = size;
}
// Method to push an element x to stack1
void push1(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{
top1++;
arr[top1] = x;
}
else
{
cout << \"Stack Overflow\";
exit(1);
}
}
// Method to push an element x to stack2
void push2(int x)
{
// There is at least one empty space for new element
if (top1 < top2 - 1)
{.
(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen.pdfasif1401
ย
(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen, and other chemicals in
the atmosphere to form various acidic compounds. Sunlight increases the rate of most of these
reactions. The result is a mild solution of sulfuric acid and nitric acid.
Acid rain causes acidification of lakes and streams and contributes to damage of trees at high
elevations and many sensitive forest soils.
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution
= ( 5.47 x 10 -3 / 46 ) / 1.0
= 1.189 x 10 -4 M
According to the balanced equation,
2 mole of NO2 produces 2 moles of HNO3
So the concentration of HNO3 is = 1.189 x 10 -4 M
HNO3 ---> H+ + NO3-
1 mole of HNO3 produces 1 mole of H+
So [H+] = 1.189 x 10 -4 M
pH = - log [H+]
= -log ( 1.189 x 10 -4 )
= 4 - log 1.189
= 3.92
(3) HNO3 + H2O ----> HNO3 (aq)
H2SO4 + H2O ---> H2SO4 (aq)
HCl + H2O ---> HCl (aq)
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution
= ( 5.47 x 10 -3 / 46 ) / 1.0
= 1.189 x 10 -4 M
According to the balanced equation,
2 mole of NO2 produces 2 moles of HNO3
So the concentration of HNO3 is = 1.189 x 10 -4 M
HNO3 ---> H+ + NO3-
1 mole of HNO3 produces 1 mole of H+
So [H+] = 1.189 x 10 -4 M
pH = - log [H+]
= -log ( 1.189 x 10 -4 )
= 4 - log 1.189
= 3.92
(3) HNO3 + H2O ----> HNO3 (aq)
H2SO4 + H2O ---> H2SO4 (aq)
HCl + H2O ---> HCl (aq)
Solution
(1) Acid rain occurs when the gases SO2 ,NOx react with water,oxygen, and other chemicals in
the atmosphere to form various acidic compounds. Sunlight increases the rate of most of these
reactions. The result is a mild solution of sulfuric acid and nitric acid.
Acid rain causes acidification of lakes and streams and contributes to damage of trees at high
elevations and many sensitive forest soils.
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Volume of the solution
= ( 5.47 x 10 -3 / 46 ) / 1.0
= 1.189 x 10 -4 M
According to the balanced equation,
2 mole of NO2 produces 2 moles of HNO3
So the concentration of HNO3 is = 1.189 x 10 -4 M
HNO3 ---> H+ + NO3-
1 mole of HNO3 produces 1 mole of H+
So [H+] = 1.189 x 10 -4 M
pH = - log [H+]
= -log ( 1.189 x 10 -4 )
= 4 - log 1.189
= 3.92
(3) HNO3 + H2O ----> HNO3 (aq)
H2SO4 + H2O ---> H2SO4 (aq)
HCl + H2O ---> HCl (aq)
(2) 2NO2 + H2O ---> 2HNO3
Given mass of NO2 is , m = 5.47 mg
= 5.47 x 10 -3 g Since 1 mg = 10 -3 g
Volume of the solution , V = 1.0 L
Molar mass of NO2 is = 14 + (2x16) = 46 g/mol
So Molarity of NO2 , M = ( mass/Molar mass) / Vol.
Iodine will replace both Cl and Br It will be SN2.pdfasif1401
ย
Iodine will replace both Cl and Br It will be SN2 reaction and hence there will be
Walden Inversion.
Solution
Iodine will replace both Cl and Br It will be SN2 reaction and hence there will be
Walden Inversion..
The number of outcomes in the event A is 4 Yes event A is a s.pdfasif1401
ย
The number of outcomes in the event A is 4
Yes event A is a sample event
Solution
The number of outcomes in the event A is 4
Yes event A is a sample event.
There were very few planetary leftovers in this r.pdfasif1401
ย
There were very few planetary leftovers in this region, because most of the solid
material was accreted by the terrestrial planets as the planets formed.
Solution
There were very few planetary leftovers in this region, because most of the solid
material was accreted by the terrestrial planets as the planets formed..
i have no idea. im just seeing if i get karma p.pdfasif1401
ย
i have no idea. i\'m just seeing if i get karma points for a half ass answer.
Solution
i have no idea. i\'m just seeing if i get karma points for a half ass answer..
Fe+3 solution is more acidic because it produces .pdfasif1401
ย
Fe+3 solution is more acidic because it produces H+ ion in the aqueous solution,
but Fe+2 is not. The following reaction represents this- [Fe(H2O)6]3+H2O ---------->
[Fe(H2O)5OH]+2+ + H3O+(aq) Therefore - a) Fe+3 b) ii
Solution
Fe+3 solution is more acidic because it produces H+ ion in the aqueous solution,
but Fe+2 is not. The following reaction represents this- [Fe(H2O)6]3+H2O ---------->
[Fe(H2O)5OH]+2+ + H3O+(aq) Therefore - a) Fe+3 b) ii.
Copper chloride. Copper ions will form precipitat.pdfasif1401
ย
Copper chloride. Copper ions will form precipitated with sulfide, Coppersulfide.
For other cations, there are solubile when there form with eithersulfide ions or acetate ions. So,
the only way to separate is using copper ions.
Solution
Copper chloride. Copper ions will form precipitated with sulfide, Coppersulfide.
For other cations, there are solubile when there form with eithersulfide ions or acetate ions. So,
the only way to separate is using copper ions..
ย ย ย CCl4 molecule can give IR and Raman spectroscopy.ย ย Selection r.pdfasif1401
ย
CCl4 molecule can give IR and Raman spectroscopy.
Selection rule of IR spectra: During the vibration dipolemoment change.
Selection rule of Raman spectra: During the vibration polarizibility change.
CCl4 molecule centrosymmetric molecule, so it can exibit Raman spectroscopy
According to mutual exclusion principle, IR inactive modes are raman active
Raman inactive modes are IR active modes.
Therefore, CCl4 molecule can give multiple peaks.
Solution
CCl4 molecule can give IR and Raman spectroscopy.
Selection rule of IR spectra: During the vibration dipolemoment change.
Selection rule of Raman spectra: During the vibration polarizibility change.
CCl4 molecule centrosymmetric molecule, so it can exibit Raman spectroscopy
According to mutual exclusion principle, IR inactive modes are raman active
Raman inactive modes are IR active modes.
Therefore, CCl4 molecule can give multiple peaks..
the inner electronsSolutionthe inner electrons.pdfasif1401
ย
This very short document does not provide enough context or information to generate a meaningful 3 sentence summary. The document consists of only two words repeated, without any surrounding context.
SolutionThe investees net income should be recorded as an increa.pdfasif1401
ย
Solution
The investee\'s net income should be recorded as an increase to the investment account.
False
Explanation
Not all the net income of investee is recorded as an increase to investment account. Only the part
of net income proportionate to investor share is recorded as increase in investment account. For
example if investor have 30% share in investee company and the net income of investee is
100000 then only 30000 will be recorded as an increase in investment account.
QuestionAnswer1TrueThe corpus callosum , otherwise called th.pdfasif1401
ย
Question
Answer
1
True
The corpus callosum , otherwise called the callosal commissure, is a wide, level heap of neural
filaments around 10 cm long underneath the cortex in the eutherian cerebrum at the longitudinal
gap. It associates the left and right cerebral sides of the equator and encourages interhemispheric
correspondence. It is the biggest white matter structure in the mind, comprising of 200โ250
million contralateral axonal projections.
The (back) bit of the corpus callosum is known as the splenium; the foremost (front) is known as
the genu (or \"knee\"); between the two is the truncus, or \"body\", of the corpus callosum. The
part between the body and the splenium is frequently extraordinarily contracted and along these
lines alluded to as the \"isthmus\". The platform is the part of the corpus callosum that ventures
posteriorly and poorly from the anteriormost genu, as can be seen on the sagittal picture of the
cerebrum showed on the privilege. The platform is so named for its likeness to a winged
creature\'s mouth.
Corpus callosum
On either side of the corpus callosum, the filaments transmit in the white matter and go to the
different parts of the cerebral cortex; those bending forward from the genu into the frontal flap
constitute the forceps foremost, and those bending in reverse into the occipital projection, the
forceps back. Between these two sections is the fundamental body of the filaments which
constitute the tapetum and expand along the side on either side into the transient projection, and
cover in the focal part of the horizontal ventricle.
2
False
Ramus communicans (plural rami communicantes) is the Latin expression utilized for a nerve
which associates two different nerves, and can be deciphered as \"conveying branch\".When
utilized without further definition, it quite often alludes to an imparting branch between a spinal
nerve and the thoughtful trunk. All the more particularly, it generally alludes to one of the
accompanying :
Dark ramus communicans
White ramus communicans
The dark and white rami communicantes are in charge of passing on autonomic signs,
particularly for the thoughtful sensory system. Their distinction in tinge is brought about by
contrasts in myelination of the nerve filaments contained inside, i.e. there are more myelinated
than unmyelinated filaments in the white rami communicantes while the opposite is valid for the
dim rami communicantes.
3
False
tentorium cerebelli isolates the occipital flaps of the cerebral sides of the equator from the
cerebellum. Its inward, sunken, free fringe adds to the tentorial indent. (See underneath.) The
outer, arched fringe encases the transverse sinus where it appends to the dura over within the
occiput. Past the \"petrous edge,\" the tentorium is tied down to the foremost and back clinoid
forms
4
False
myelin sheath(deep) and Neurilemma (superficial)
5
False
Cranial nerves are the nerves that develop straightforwardly from the cerebrum (counting the
brainstem), a.
No. of Moles = Given MassMolecular Mass=3.0 x 101398= 3.06101.pdfasif1401
ย
No. of Moles = Given Mass/Molecular Mass
=3.0 x 1013/98
= 3.06*1011 Moles
Solution
No. of Moles = Given Mass/Molecular Mass
=3.0 x 1013/98
= 3.06*1011 Moles.
Let the sample size be n ,Mean of the sample = 27 (same as pop.pdfasif1401
ย
Let the sample size be n ,
Mean of the sample = 27 (same as population mean)
Standard deviation of sample = population standard deviation / sqrt(n)
= 2.5/sqrt(n)
Solution
Let the sample size be n ,
Mean of the sample = 27 (same as population mean)
Standard deviation of sample = population standard deviation / sqrt(n)
= 2.5/sqrt(n).
This very short document appears to be a communication between two individuals, Jeff and Solution. It contains the name "Jeff" repeated twice without any other words or context, making it difficult to determine the intent or meaning based on the limited information provided.
import java.util.Scanner;public class Assignment4 { ย ย public st.pdfasif1401
ย
import java.util.Scanner;
public class Assignment4 {
public static void main(String args[]) {
final int LEN = 5;
int[] hand = new int[LEN];
Scanner input = new Scanner(System.in);
//input the hand
System.out.println(\"Enter five numeric cards, no face cards. Use 2-9.\");
for (int i = 0; i < hand.length; i++) {
hand[i] = input.nextInt();
}
//sort the collection
bubbleSortCards(hand);
//determine players hand type
//flow of evaluation -> checking complex hands first
if (containsFullHouse(hand)) {
System.out.println(\"Full House!\");
} else if (containsStraight(hand)) {
System.out.println(\"Straight!\");
} else if (containsFourOfaKind(hand)) {
System.out.println(\"Four of a Kind!\");
} else if (containsThreeOfaKind(hand)) {
System.out.println(\"Three of a Kind!\");
} else if (containsTwoPair(hand)) {
System.out.println(\"Two Pair!\");
} else if (containsPair(hand)) {
System.out.println(\"Pair!\");
} else
System.out.println(\"High Card!\");
}
//cardInSets is called with hand[] and pair to check if a pair is found.
public static boolean containsPair(int hand[]) {
int pair = 2;
return cardInSets(hand, pair) != NOT_FOUND;
}
//cardInSets is called with hand[] and pair to check if a pair is found.
//Then calls back again with fcard result to check for another pair.
public static boolean containsTwoPair(int hand[]) {
int pair = 2;
int fcard = cardInSets(hand, pair);
int scard = cardInSets(hand, pair, fcard);
return fcard!=NOT_FOUND && scard!=NOT_FOUND;
}
//cardInSets is called with hand[] and threeaKind to check if three of a kind has been found.
public static boolean containsThreeOfaKind(int hand[]) {
int threeaKind = 3;
return cardInSets(hand, threeaKind) != NOT_FOUND;
}
//hasStraight will resolve to true, unless the previous value++ is not equivalent.
//The loop ends as soon as hasStaight is false or the end of the hand is reached.
public static boolean containsStraight(int hand[]) {
boolean hasStraight = true;
int i=1;
do {
hasStraight = (hand[i] == (hand[i-1] + 1));
} while(hasStraight && ++i < hand.length);
return hasStraight;
}
//cardInSets is called with hand[] and threeKinds to check if three of a kind is found.
//Then calls back again with pair and tcard result to check for a pair of another card type.
public static boolean containsFullHouse(int hand[]) {
int threeKinds = 3;
int pair = 2;
int tcard = cardInSets(hand, threeKinds);
int pcard = cardInSets(hand, pair, tcard);
return tcard!=NOT_FOUND && pcard!=NOT_FOUND;
}
//cardInSets is called with hand[] and fouraKind to check if four of a kind is found.
public static boolean containsFourOfaKind(int hand[]) {
int fouraKind = 4;
return cardInSets(hand, fouraKind) != NOT_FOUND;
}
//When ignoreCard isn\'t needed, it overloads with a sentinel 0.
public static int cardInSets(int hand[], int numKinds) {
return cardInSets(hand, numKinds, 0);
}
//The method cardInSets is a generic evaluation that returns if the parameter specified
numKinds(like 2 for pair) has been found in the hand.
//The ignoreCard d.
In computer graphics are geometric functions which used to design va.pdfasif1401
ย
In computer graphics are geometric functions which used to design various graphics acoording to
the user requirements
output primitives:
some of the important output primitive are
1)text
2)line
3)tone
4)interpolation
the above primitive consists of two components they index and types of line and tone consists of
pattern index
line:
i)line indexes:
the width or thickness of line and color together to be considered with nnm is called as lineindex
ii)line type:
it indicates type of line (dashed,dotted,solid) these will be allocated by numbers
tone:
the component inside it is tone pattern index. it consists of color and pattern information
1)horizontal hatch
2)vertical hatch
3)cross hatch
4)right up hacth
5)leftup hatch
here the first three didgits is for pattern and last three digits is for color
interpolation :
i)line interpolation:it uses coordinates system of user
ii)great circle interpolation:it uses map projection coordinates
text:
it deals with textual data .it conatain following components
i)size
ii)width
iii)type
iv)font
v)height
input primtives:
input primitives are nothing but input devices ,generally the input devices are consists of both
physical and logical
1)mouse
2)tablet
3)electronic pens
all the above device contains the similar input primitive it is coordinate position
4)Keyboard: the keyboard is example of string device its input primitive is characters
5)sensing devices ; these devices comes under vector devices its input primitive values is
between 0 and 1
Solution
In computer graphics are geometric functions which used to design various graphics acoording to
the user requirements
output primitives:
some of the important output primitive are
1)text
2)line
3)tone
4)interpolation
the above primitive consists of two components they index and types of line and tone consists of
pattern index
line:
i)line indexes:
the width or thickness of line and color together to be considered with nnm is called as lineindex
ii)line type:
it indicates type of line (dashed,dotted,solid) these will be allocated by numbers
tone:
the component inside it is tone pattern index. it consists of color and pattern information
1)horizontal hatch
2)vertical hatch
3)cross hatch
4)right up hacth
5)leftup hatch
here the first three didgits is for pattern and last three digits is for color
interpolation :
i)line interpolation:it uses coordinates system of user
ii)great circle interpolation:it uses map projection coordinates
text:
it deals with textual data .it conatain following components
i)size
ii)width
iii)type
iv)font
v)height
input primtives:
input primitives are nothing but input devices ,generally the input devices are consists of both
physical and logical
1)mouse
2)tablet
3)electronic pens
all the above device contains the similar input primitive it is coordinate position
4)Keyboard: the keyboard is example of string device its input primitive is characters
5)sensing devices ; these devices comes under vector devices its input primitive values is
betwe.
Dipteran insects and their positive role in environment.The word D.pdfasif1401
ย
Dipteran insects and their positive role in environment.
The word Diptera is derived from Greek di meaning two and ptera meaning wings.Though these
insects are known to have two wing they efficiently use only there for flight and the hind wings
being reduced to balanced organs called \"Halterers\".
The order diptera includes a large number of species most of them are known for their ability to
cause diseases in human beings but they are of considerable ecological and human
importance.They are known to cause dreadful diseases like malaria,dengue, yellow fever by
acting as vectors but their beneficial role in ecosystem cannot be ignored.
Some of the positive aspects of the order can be listed as follows:
1. We know that pollination is an essential mechanism for fruit production and we are aware that
bees are important pollinators .Dipterans are the second largest pollinators after the
hymenopterans.In fact they are said to be the earliest pollinating agents. Many crop plants are
dependent on these insect for pollination without which the fruit bearing process is not
completed.
The chocolate which we enjoy would have not been there had there been no flies. It is a known
fact that the chocolate plant Theobroma cocoa produces very small flowers and are self
incompatable for various reasons very small midges of the families Ceratopogonidae and
Cecidomyiidae pollinate the small white flowers emerging from the stems. so next time we curse
a fly remember that we will go without chocolate if we eradicate them.
2. The study of genetics has made many things impossible possible now , we should not forget
the contribution of our fruit fly here . Most of the genetic studies are based upon the experiments
conducted on fruit flies,because of there smaller genome and easy to rear they serve as excellent
genetic model organisms.
3. They play an important role at various trophic level both as consumers and as prey. In many
aquatic ecosystems they form the main food source for birds and fishes.As herbivores in
wetlands, flies can be very beneficial in controlling potential eutrophication.Many of the aquatic
flies are known to reduce algal proliferation, despite very high algal productivity.
4. They form a dominant taxa in temperate ecosystems.
5.Maggots are reared and are used as fishing baits.
6. Some of the maggots which selectvely feed on the necrotic tissue are used in medicine in
debraidment to clear wounds.
7.Some members belonging to the families Muscidae or the Sphaeroceridae are detritivores,
meaning they feed on decaying material. . These are beneficial in that they speed up nutrient
cycling and thus lead to a richer soil (indirectly).Larve of some of the diptran insects are known
to act as excellent scavengers , decomposers.
8 .Some flies play an important role in bilogical control of weeds and pests.
9. They are used in forensic labs also . some of the maggots that feed on corpses provide the
evidence for the time of death in that they are known to fe.
Accepts number and base and returns result in integerimport jav.pdfasif1401
ย
// Accepts number and base and returns result in integer
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Base {
public static void main(String[] args) throws IOException {
System.out.println(\"Enter number: \");
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String st=br.readLine();
System.out.println(\"Enter base\");
String st1=br.readLine();
int n=Integer.parseInt(st);
int b=Integer.parseInt(st1);
int sum=0;
int i=0;
while(n!=0)
{
sum=(int) (sum+(n%10)*Math.pow(b,i++));
n=n/10;
}
System.out.println(sum);
}
}
Solution
// Accepts number and base and returns result in integer
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Base {
public static void main(String[] args) throws IOException {
System.out.println(\"Enter number: \");
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String st=br.readLine();
System.out.println(\"Enter base\");
String st1=br.readLine();
int n=Integer.parseInt(st);
int b=Integer.parseInt(st1);
int sum=0;
int i=0;
while(n!=0)
{
sum=(int) (sum+(n%10)*Math.pow(b,i++));
n=n/10;
}
System.out.println(sum);
}
}.
a. steering committeeAn advisory committee usually made up of high.pdfasif1401
ย
a. steering committee
An advisory committee usually made up of high level stakeholders and/or experts who provide
guidance on key issues such as company policy and objectives, budgetary control, marketing
strategy, resource allocation, and decisions involving large expenditures.
b. Role of steerig commitee
Control over the IT process of Define the IT processes, organisation and relationships that
satisfies the business requirement for IT of being agile in responding to the business strategy
whilst complying with governance requirements and providing defined and competent points of
contact by focusing on establishing transparent, flexible and responsive IT organisational
structures and defining and implementing IT processes with owners, roles and responsibilities
integrated into business and decision processes is achieved by:
and is measured by
c)
Role of CEO
Decisionmaking may be simply defined as choosing a course of action from among alternatives.
If there are no alternatives, then no decision is required. A basis assumption is that the best
decision is the one that involves the most revenue or the least amount of cost. The task of
management with the help of the management accountant is to find the best alternative.
The process of making decisions is generally considered to involve the following
steps:
1
Identify the various alternatives for a given type of decision.
2.
Obtain the necessary data necessary to evaluate the various alternatives.
3.
Analyze and determine the consequences of each alternative.
4.
Select the alternative that appears to best achieve the desired goals or objectives.
5.
Implement the chosen alternative.
6.
At an appropriate time, evaluate the results of the decisions against standards or other desired
result
Role of Accounting manager -
Planning and control techniques which management may use include business budgeting,
costvolumeprofit
analysis, incremental analysis, flexible budgeting, segmental contribution reporting, inventory
models, and capital budgeting models.
Nature of Accounting Information -
Information for acounting manager -In order for the accounting department to make meaningful
analysis of data, it is necessary to distinguish between fixed and variable costs and other types of
costs that are not important in the recording of business transactions.
CEO - Some but not all of the information needed by management can be provided from
financial statements and historical accounting records. In addition to historical data, management
will expect the management accountant to provide other types of data, such as estimates,
forecasts, future data, and standards. Management Accounting and Decision-Making managerial
technique requires an identifiable type of information. The accounting department will be
expected to provide the information required by a specific tool. In order for the accounting
department to make many types of analysis, a separation of costs into fixed and variable will be
required. The managem.
Answer. Treponema ,Borrelia and leptospiraFamily Leptospiraceae-G.pdfasif1401
ย
Answer. Treponema ,Borrelia and leptospira
Family :Leptospiraceae-Genus:Leptospira
Family -Spirochaetaceae-Genus:Treponema,Borrelia
Spirochetes are gram neative bacteria that are long,thin,helcal and motile
Axial filaments (a form of flagella ) is found between the peptidoglcan layer and outer
membrane and running parallel to them are the locomotory organelles
C) cause the disease relapsing fever
Clinical significance :its a vector borne disease.
Relapsing fever (Borrelia recurrentis)-lice,ticks
Clinical aspect :sudden fever,chills,headache,nausea for 2-9 days,symptoms reappear after 3-10
days ;evolution continueswith similar cycles
Laboratory diagnosis:
Detection of spirochetes in blood smear
ELISA test
Genus Leptospira have the general charateristics of axial filamemts which provide high motility
Solution
Answer. Treponema ,Borrelia and leptospira
Family :Leptospiraceae-Genus:Leptospira
Family -Spirochaetaceae-Genus:Treponema,Borrelia
Spirochetes are gram neative bacteria that are long,thin,helcal and motile
Axial filaments (a form of flagella ) is found between the peptidoglcan layer and outer
membrane and running parallel to them are the locomotory organelles
C) cause the disease relapsing fever
Clinical significance :its a vector borne disease.
Relapsing fever (Borrelia recurrentis)-lice,ticks
Clinical aspect :sudden fever,chills,headache,nausea for 2-9 days,symptoms reappear after 3-10
days ;evolution continueswith similar cycles
Laboratory diagnosis:
Detection of spirochetes in blood smear
ELISA test
Genus Leptospira have the general charateristics of axial filamemts which provide high motility.
Fe+3 solution is more acidic because it produces .pdfasif1401
ย
Fe+3 solution is more acidic because it produces H+ ion in the aqueous solution,
but Fe+2 is not. The following reaction represents this- [Fe(H2O)6]3+H2O ---------->
[Fe(H2O)5OH]+2+ + H3O+(aq) Therefore - a) Fe+3 b) ii
Solution
Fe+3 solution is more acidic because it produces H+ ion in the aqueous solution,
but Fe+2 is not. The following reaction represents this- [Fe(H2O)6]3+H2O ---------->
[Fe(H2O)5OH]+2+ + H3O+(aq) Therefore - a) Fe+3 b) ii.
Copper chloride. Copper ions will form precipitat.pdfasif1401
ย
Copper chloride. Copper ions will form precipitated with sulfide, Coppersulfide.
For other cations, there are solubile when there form with eithersulfide ions or acetate ions. So,
the only way to separate is using copper ions.
Solution
Copper chloride. Copper ions will form precipitated with sulfide, Coppersulfide.
For other cations, there are solubile when there form with eithersulfide ions or acetate ions. So,
the only way to separate is using copper ions..
ย ย ย CCl4 molecule can give IR and Raman spectroscopy.ย ย Selection r.pdfasif1401
ย
CCl4 molecule can give IR and Raman spectroscopy.
Selection rule of IR spectra: During the vibration dipolemoment change.
Selection rule of Raman spectra: During the vibration polarizibility change.
CCl4 molecule centrosymmetric molecule, so it can exibit Raman spectroscopy
According to mutual exclusion principle, IR inactive modes are raman active
Raman inactive modes are IR active modes.
Therefore, CCl4 molecule can give multiple peaks.
Solution
CCl4 molecule can give IR and Raman spectroscopy.
Selection rule of IR spectra: During the vibration dipolemoment change.
Selection rule of Raman spectra: During the vibration polarizibility change.
CCl4 molecule centrosymmetric molecule, so it can exibit Raman spectroscopy
According to mutual exclusion principle, IR inactive modes are raman active
Raman inactive modes are IR active modes.
Therefore, CCl4 molecule can give multiple peaks..
the inner electronsSolutionthe inner electrons.pdfasif1401
ย
This very short document does not provide enough context or information to generate a meaningful 3 sentence summary. The document consists of only two words repeated, without any surrounding context.
SolutionThe investees net income should be recorded as an increa.pdfasif1401
ย
Solution
The investee\'s net income should be recorded as an increase to the investment account.
False
Explanation
Not all the net income of investee is recorded as an increase to investment account. Only the part
of net income proportionate to investor share is recorded as increase in investment account. For
example if investor have 30% share in investee company and the net income of investee is
100000 then only 30000 will be recorded as an increase in investment account.
QuestionAnswer1TrueThe corpus callosum , otherwise called th.pdfasif1401
ย
Question
Answer
1
True
The corpus callosum , otherwise called the callosal commissure, is a wide, level heap of neural
filaments around 10 cm long underneath the cortex in the eutherian cerebrum at the longitudinal
gap. It associates the left and right cerebral sides of the equator and encourages interhemispheric
correspondence. It is the biggest white matter structure in the mind, comprising of 200โ250
million contralateral axonal projections.
The (back) bit of the corpus callosum is known as the splenium; the foremost (front) is known as
the genu (or \"knee\"); between the two is the truncus, or \"body\", of the corpus callosum. The
part between the body and the splenium is frequently extraordinarily contracted and along these
lines alluded to as the \"isthmus\". The platform is the part of the corpus callosum that ventures
posteriorly and poorly from the anteriormost genu, as can be seen on the sagittal picture of the
cerebrum showed on the privilege. The platform is so named for its likeness to a winged
creature\'s mouth.
Corpus callosum
On either side of the corpus callosum, the filaments transmit in the white matter and go to the
different parts of the cerebral cortex; those bending forward from the genu into the frontal flap
constitute the forceps foremost, and those bending in reverse into the occipital projection, the
forceps back. Between these two sections is the fundamental body of the filaments which
constitute the tapetum and expand along the side on either side into the transient projection, and
cover in the focal part of the horizontal ventricle.
2
False
Ramus communicans (plural rami communicantes) is the Latin expression utilized for a nerve
which associates two different nerves, and can be deciphered as \"conveying branch\".When
utilized without further definition, it quite often alludes to an imparting branch between a spinal
nerve and the thoughtful trunk. All the more particularly, it generally alludes to one of the
accompanying :
Dark ramus communicans
White ramus communicans
The dark and white rami communicantes are in charge of passing on autonomic signs,
particularly for the thoughtful sensory system. Their distinction in tinge is brought about by
contrasts in myelination of the nerve filaments contained inside, i.e. there are more myelinated
than unmyelinated filaments in the white rami communicantes while the opposite is valid for the
dim rami communicantes.
3
False
tentorium cerebelli isolates the occipital flaps of the cerebral sides of the equator from the
cerebellum. Its inward, sunken, free fringe adds to the tentorial indent. (See underneath.) The
outer, arched fringe encases the transverse sinus where it appends to the dura over within the
occiput. Past the \"petrous edge,\" the tentorium is tied down to the foremost and back clinoid
forms
4
False
myelin sheath(deep) and Neurilemma (superficial)
5
False
Cranial nerves are the nerves that develop straightforwardly from the cerebrum (counting the
brainstem), a.
No. of Moles = Given MassMolecular Mass=3.0 x 101398= 3.06101.pdfasif1401
ย
No. of Moles = Given Mass/Molecular Mass
=3.0 x 1013/98
= 3.06*1011 Moles
Solution
No. of Moles = Given Mass/Molecular Mass
=3.0 x 1013/98
= 3.06*1011 Moles.
Let the sample size be n ,Mean of the sample = 27 (same as pop.pdfasif1401
ย
Let the sample size be n ,
Mean of the sample = 27 (same as population mean)
Standard deviation of sample = population standard deviation / sqrt(n)
= 2.5/sqrt(n)
Solution
Let the sample size be n ,
Mean of the sample = 27 (same as population mean)
Standard deviation of sample = population standard deviation / sqrt(n)
= 2.5/sqrt(n).
This very short document appears to be a communication between two individuals, Jeff and Solution. It contains the name "Jeff" repeated twice without any other words or context, making it difficult to determine the intent or meaning based on the limited information provided.
import java.util.Scanner;public class Assignment4 { ย ย public st.pdfasif1401
ย
import java.util.Scanner;
public class Assignment4 {
public static void main(String args[]) {
final int LEN = 5;
int[] hand = new int[LEN];
Scanner input = new Scanner(System.in);
//input the hand
System.out.println(\"Enter five numeric cards, no face cards. Use 2-9.\");
for (int i = 0; i < hand.length; i++) {
hand[i] = input.nextInt();
}
//sort the collection
bubbleSortCards(hand);
//determine players hand type
//flow of evaluation -> checking complex hands first
if (containsFullHouse(hand)) {
System.out.println(\"Full House!\");
} else if (containsStraight(hand)) {
System.out.println(\"Straight!\");
} else if (containsFourOfaKind(hand)) {
System.out.println(\"Four of a Kind!\");
} else if (containsThreeOfaKind(hand)) {
System.out.println(\"Three of a Kind!\");
} else if (containsTwoPair(hand)) {
System.out.println(\"Two Pair!\");
} else if (containsPair(hand)) {
System.out.println(\"Pair!\");
} else
System.out.println(\"High Card!\");
}
//cardInSets is called with hand[] and pair to check if a pair is found.
public static boolean containsPair(int hand[]) {
int pair = 2;
return cardInSets(hand, pair) != NOT_FOUND;
}
//cardInSets is called with hand[] and pair to check if a pair is found.
//Then calls back again with fcard result to check for another pair.
public static boolean containsTwoPair(int hand[]) {
int pair = 2;
int fcard = cardInSets(hand, pair);
int scard = cardInSets(hand, pair, fcard);
return fcard!=NOT_FOUND && scard!=NOT_FOUND;
}
//cardInSets is called with hand[] and threeaKind to check if three of a kind has been found.
public static boolean containsThreeOfaKind(int hand[]) {
int threeaKind = 3;
return cardInSets(hand, threeaKind) != NOT_FOUND;
}
//hasStraight will resolve to true, unless the previous value++ is not equivalent.
//The loop ends as soon as hasStaight is false or the end of the hand is reached.
public static boolean containsStraight(int hand[]) {
boolean hasStraight = true;
int i=1;
do {
hasStraight = (hand[i] == (hand[i-1] + 1));
} while(hasStraight && ++i < hand.length);
return hasStraight;
}
//cardInSets is called with hand[] and threeKinds to check if three of a kind is found.
//Then calls back again with pair and tcard result to check for a pair of another card type.
public static boolean containsFullHouse(int hand[]) {
int threeKinds = 3;
int pair = 2;
int tcard = cardInSets(hand, threeKinds);
int pcard = cardInSets(hand, pair, tcard);
return tcard!=NOT_FOUND && pcard!=NOT_FOUND;
}
//cardInSets is called with hand[] and fouraKind to check if four of a kind is found.
public static boolean containsFourOfaKind(int hand[]) {
int fouraKind = 4;
return cardInSets(hand, fouraKind) != NOT_FOUND;
}
//When ignoreCard isn\'t needed, it overloads with a sentinel 0.
public static int cardInSets(int hand[], int numKinds) {
return cardInSets(hand, numKinds, 0);
}
//The method cardInSets is a generic evaluation that returns if the parameter specified
numKinds(like 2 for pair) has been found in the hand.
//The ignoreCard d.
In computer graphics are geometric functions which used to design va.pdfasif1401
ย
In computer graphics are geometric functions which used to design various graphics acoording to
the user requirements
output primitives:
some of the important output primitive are
1)text
2)line
3)tone
4)interpolation
the above primitive consists of two components they index and types of line and tone consists of
pattern index
line:
i)line indexes:
the width or thickness of line and color together to be considered with nnm is called as lineindex
ii)line type:
it indicates type of line (dashed,dotted,solid) these will be allocated by numbers
tone:
the component inside it is tone pattern index. it consists of color and pattern information
1)horizontal hatch
2)vertical hatch
3)cross hatch
4)right up hacth
5)leftup hatch
here the first three didgits is for pattern and last three digits is for color
interpolation :
i)line interpolation:it uses coordinates system of user
ii)great circle interpolation:it uses map projection coordinates
text:
it deals with textual data .it conatain following components
i)size
ii)width
iii)type
iv)font
v)height
input primtives:
input primitives are nothing but input devices ,generally the input devices are consists of both
physical and logical
1)mouse
2)tablet
3)electronic pens
all the above device contains the similar input primitive it is coordinate position
4)Keyboard: the keyboard is example of string device its input primitive is characters
5)sensing devices ; these devices comes under vector devices its input primitive values is
between 0 and 1
Solution
In computer graphics are geometric functions which used to design various graphics acoording to
the user requirements
output primitives:
some of the important output primitive are
1)text
2)line
3)tone
4)interpolation
the above primitive consists of two components they index and types of line and tone consists of
pattern index
line:
i)line indexes:
the width or thickness of line and color together to be considered with nnm is called as lineindex
ii)line type:
it indicates type of line (dashed,dotted,solid) these will be allocated by numbers
tone:
the component inside it is tone pattern index. it consists of color and pattern information
1)horizontal hatch
2)vertical hatch
3)cross hatch
4)right up hacth
5)leftup hatch
here the first three didgits is for pattern and last three digits is for color
interpolation :
i)line interpolation:it uses coordinates system of user
ii)great circle interpolation:it uses map projection coordinates
text:
it deals with textual data .it conatain following components
i)size
ii)width
iii)type
iv)font
v)height
input primtives:
input primitives are nothing but input devices ,generally the input devices are consists of both
physical and logical
1)mouse
2)tablet
3)electronic pens
all the above device contains the similar input primitive it is coordinate position
4)Keyboard: the keyboard is example of string device its input primitive is characters
5)sensing devices ; these devices comes under vector devices its input primitive values is
betwe.
Dipteran insects and their positive role in environment.The word D.pdfasif1401
ย
Dipteran insects and their positive role in environment.
The word Diptera is derived from Greek di meaning two and ptera meaning wings.Though these
insects are known to have two wing they efficiently use only there for flight and the hind wings
being reduced to balanced organs called \"Halterers\".
The order diptera includes a large number of species most of them are known for their ability to
cause diseases in human beings but they are of considerable ecological and human
importance.They are known to cause dreadful diseases like malaria,dengue, yellow fever by
acting as vectors but their beneficial role in ecosystem cannot be ignored.
Some of the positive aspects of the order can be listed as follows:
1. We know that pollination is an essential mechanism for fruit production and we are aware that
bees are important pollinators .Dipterans are the second largest pollinators after the
hymenopterans.In fact they are said to be the earliest pollinating agents. Many crop plants are
dependent on these insect for pollination without which the fruit bearing process is not
completed.
The chocolate which we enjoy would have not been there had there been no flies. It is a known
fact that the chocolate plant Theobroma cocoa produces very small flowers and are self
incompatable for various reasons very small midges of the families Ceratopogonidae and
Cecidomyiidae pollinate the small white flowers emerging from the stems. so next time we curse
a fly remember that we will go without chocolate if we eradicate them.
2. The study of genetics has made many things impossible possible now , we should not forget
the contribution of our fruit fly here . Most of the genetic studies are based upon the experiments
conducted on fruit flies,because of there smaller genome and easy to rear they serve as excellent
genetic model organisms.
3. They play an important role at various trophic level both as consumers and as prey. In many
aquatic ecosystems they form the main food source for birds and fishes.As herbivores in
wetlands, flies can be very beneficial in controlling potential eutrophication.Many of the aquatic
flies are known to reduce algal proliferation, despite very high algal productivity.
4. They form a dominant taxa in temperate ecosystems.
5.Maggots are reared and are used as fishing baits.
6. Some of the maggots which selectvely feed on the necrotic tissue are used in medicine in
debraidment to clear wounds.
7.Some members belonging to the families Muscidae or the Sphaeroceridae are detritivores,
meaning they feed on decaying material. . These are beneficial in that they speed up nutrient
cycling and thus lead to a richer soil (indirectly).Larve of some of the diptran insects are known
to act as excellent scavengers , decomposers.
8 .Some flies play an important role in bilogical control of weeds and pests.
9. They are used in forensic labs also . some of the maggots that feed on corpses provide the
evidence for the time of death in that they are known to fe.
Accepts number and base and returns result in integerimport jav.pdfasif1401
ย
// Accepts number and base and returns result in integer
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Base {
public static void main(String[] args) throws IOException {
System.out.println(\"Enter number: \");
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String st=br.readLine();
System.out.println(\"Enter base\");
String st1=br.readLine();
int n=Integer.parseInt(st);
int b=Integer.parseInt(st1);
int sum=0;
int i=0;
while(n!=0)
{
sum=(int) (sum+(n%10)*Math.pow(b,i++));
n=n/10;
}
System.out.println(sum);
}
}
Solution
// Accepts number and base and returns result in integer
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Base {
public static void main(String[] args) throws IOException {
System.out.println(\"Enter number: \");
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
String st=br.readLine();
System.out.println(\"Enter base\");
String st1=br.readLine();
int n=Integer.parseInt(st);
int b=Integer.parseInt(st1);
int sum=0;
int i=0;
while(n!=0)
{
sum=(int) (sum+(n%10)*Math.pow(b,i++));
n=n/10;
}
System.out.println(sum);
}
}.
a. steering committeeAn advisory committee usually made up of high.pdfasif1401
ย
a. steering committee
An advisory committee usually made up of high level stakeholders and/or experts who provide
guidance on key issues such as company policy and objectives, budgetary control, marketing
strategy, resource allocation, and decisions involving large expenditures.
b. Role of steerig commitee
Control over the IT process of Define the IT processes, organisation and relationships that
satisfies the business requirement for IT of being agile in responding to the business strategy
whilst complying with governance requirements and providing defined and competent points of
contact by focusing on establishing transparent, flexible and responsive IT organisational
structures and defining and implementing IT processes with owners, roles and responsibilities
integrated into business and decision processes is achieved by:
and is measured by
c)
Role of CEO
Decisionmaking may be simply defined as choosing a course of action from among alternatives.
If there are no alternatives, then no decision is required. A basis assumption is that the best
decision is the one that involves the most revenue or the least amount of cost. The task of
management with the help of the management accountant is to find the best alternative.
The process of making decisions is generally considered to involve the following
steps:
1
Identify the various alternatives for a given type of decision.
2.
Obtain the necessary data necessary to evaluate the various alternatives.
3.
Analyze and determine the consequences of each alternative.
4.
Select the alternative that appears to best achieve the desired goals or objectives.
5.
Implement the chosen alternative.
6.
At an appropriate time, evaluate the results of the decisions against standards or other desired
result
Role of Accounting manager -
Planning and control techniques which management may use include business budgeting,
costvolumeprofit
analysis, incremental analysis, flexible budgeting, segmental contribution reporting, inventory
models, and capital budgeting models.
Nature of Accounting Information -
Information for acounting manager -In order for the accounting department to make meaningful
analysis of data, it is necessary to distinguish between fixed and variable costs and other types of
costs that are not important in the recording of business transactions.
CEO - Some but not all of the information needed by management can be provided from
financial statements and historical accounting records. In addition to historical data, management
will expect the management accountant to provide other types of data, such as estimates,
forecasts, future data, and standards. Management Accounting and Decision-Making managerial
technique requires an identifiable type of information. The accounting department will be
expected to provide the information required by a specific tool. In order for the accounting
department to make many types of analysis, a separation of costs into fixed and variable will be
required. The managem.
Answer. Treponema ,Borrelia and leptospiraFamily Leptospiraceae-G.pdfasif1401
ย
Answer. Treponema ,Borrelia and leptospira
Family :Leptospiraceae-Genus:Leptospira
Family -Spirochaetaceae-Genus:Treponema,Borrelia
Spirochetes are gram neative bacteria that are long,thin,helcal and motile
Axial filaments (a form of flagella ) is found between the peptidoglcan layer and outer
membrane and running parallel to them are the locomotory organelles
C) cause the disease relapsing fever
Clinical significance :its a vector borne disease.
Relapsing fever (Borrelia recurrentis)-lice,ticks
Clinical aspect :sudden fever,chills,headache,nausea for 2-9 days,symptoms reappear after 3-10
days ;evolution continueswith similar cycles
Laboratory diagnosis:
Detection of spirochetes in blood smear
ELISA test
Genus Leptospira have the general charateristics of axial filamemts which provide high motility
Solution
Answer. Treponema ,Borrelia and leptospira
Family :Leptospiraceae-Genus:Leptospira
Family -Spirochaetaceae-Genus:Treponema,Borrelia
Spirochetes are gram neative bacteria that are long,thin,helcal and motile
Axial filaments (a form of flagella ) is found between the peptidoglcan layer and outer
membrane and running parallel to them are the locomotory organelles
C) cause the disease relapsing fever
Clinical significance :its a vector borne disease.
Relapsing fever (Borrelia recurrentis)-lice,ticks
Clinical aspect :sudden fever,chills,headache,nausea for 2-9 days,symptoms reappear after 3-10
days ;evolution continueswith similar cycles
Laboratory diagnosis:
Detection of spirochetes in blood smear
ELISA test
Genus Leptospira have the general charateristics of axial filamemts which provide high motility.
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...PECB
ย
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
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Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
Webinars: https://pecb.com/webinars
Article: https://pecb.com/article
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Slideshare: http://www.slideshare.net/PECBCERTIFICATION
Philippine Edukasyong Pantahanan at Pangkabuhayan (EPP) CurriculumMJDuyan
ย
(๐๐๐ ๐๐๐) (๐๐๐ฌ๐ฌ๐จ๐ง ๐)-๐๐ซ๐๐ฅ๐ข๐ฆ๐ฌ
๐๐ข๐ฌ๐๐ฎ๐ฌ๐ฌ ๐ญ๐ก๐ ๐๐๐ ๐๐ฎ๐ซ๐ซ๐ข๐๐ฎ๐ฅ๐ฎ๐ฆ ๐ข๐ง ๐ญ๐ก๐ ๐๐ก๐ข๐ฅ๐ข๐ฉ๐ฉ๐ข๐ง๐๐ฌ:
- Understand the goals and objectives of the Edukasyong Pantahanan at Pangkabuhayan (EPP) curriculum, recognizing its importance in fostering practical life skills and values among students. Students will also be able to identify the key components and subjects covered, such as agriculture, home economics, industrial arts, and information and communication technology.
๐๐ฑ๐ฉ๐ฅ๐๐ข๐ง ๐ญ๐ก๐ ๐๐๐ญ๐ฎ๐ซ๐ ๐๐ง๐ ๐๐๐จ๐ฉ๐ ๐จ๐ ๐๐ง ๐๐ง๐ญ๐ซ๐๐ฉ๐ซ๐๐ง๐๐ฎ๐ซ:
-Define entrepreneurship, distinguishing it from general business activities by emphasizing its focus on innovation, risk-taking, and value creation. Students will describe the characteristics and traits of successful entrepreneurs, including their roles and responsibilities, and discuss the broader economic and social impacts of entrepreneurial activities on both local and global scales.
Temple of Asclepius in Thrace. Excavation resultsKrassimira Luka
ย
The temple and the sanctuary around were dedicated to Asklepios Zmidrenus. This name has been known since 1875 when an inscription dedicated to him was discovered in Rome. The inscription is dated in 227 AD and was left by soldiers originating from the city of Philippopolis (modern Plovdiv).
Walmart Business+ and Spark Good for Nonprofits.pdfTechSoup
ย
"Learn about all the ways Walmart supports nonprofit organizations.
You will hear from Liz Willett, the Head of Nonprofits, and hear about what Walmart is doing to help nonprofits, including Walmart Business and Spark Good. Walmart Business+ is a new offer for nonprofits that offers discounts and also streamlines nonprofits order and expense tracking, saving time and money.
The webinar may also give some examples on how nonprofits can best leverage Walmart Business+.
The event will cover the following::
Walmart Business + (https://business.walmart.com/plus) is a new shopping experience for nonprofits, schools, and local business customers that connects an exclusive online shopping experience to stores. Benefits include free delivery and shipping, a 'Spend Analyticsโ feature, special discounts, deals and tax-exempt shopping.
Special TechSoup offer for a free 180 days membership, and up to $150 in discounts on eligible orders.
Spark Good (walmart.com/sparkgood) is a charitable platform that enables nonprofits to receive donations directly from customers and associates.
Answers about how you can do more with Walmart!"
This document provides an overview of wound healing, its functions, stages, mechanisms, factors affecting it, and complications.
A wound is a break in the integrity of the skin or tissues, which may be associated with disruption of the structure and function.
Healing is the bodyโs response to injury in an attempt to restore normal structure and functions.
Healing can occur in two ways: Regeneration and Repair
There are 4 phases of wound healing: hemostasis, inflammation, proliferation, and remodeling. This document also describes the mechanism of wound healing. Factors that affect healing include infection, uncontrolled diabetes, poor nutrition, age, anemia, the presence of foreign bodies, etc.
Complications of wound healing like infection, hyperpigmentation of scar, contractures, and keloid formation.
Beyond Degrees - Empowering the Workforce in the Context of Skills-First.pptxEduSkills OECD
ย
Ivรกn Bornacelly, Policy Analyst at the OECD Centre for Skills, OECD, presents at the webinar 'Tackling job market gaps with a skills-first approach' on 12 June 2024
How to Make a Field Mandatory in Odoo 17Celine George
ย
In Odoo, making a field required can be done through both Python code and XML views. When you set the required attribute to True in Python code, it makes the field required across all views where it's used. Conversely, when you set the required attribute in XML views, it makes the field required only in the context of that particular view.