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exp5phenytoin1-210626113119.pdf111111111
1. Title: Synthesis of Phenytoin from Benzyl
Presented by…
Prof. Sonali R. Pawar
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2. Procedure: [Ref: B. S. Furniss, A. J. Hannaford, P. W. G. Smith, Vogel’s textbook of practical
organic chemistry, 5th edition, Copublished in the United States with John Wiley & Sons, Inc., New
York Page No. 1153
Sachin Kumar Ghosh, Advanced General Organic Chemistry A Modern Approach, Published by
New Central Book Agency (P) Ltd., Kolkata, 2nd edition, Page No. 604-605]
Place 5.3 g (0.0125 mol) of benzil (Expt 6.143), 1.5 g (0.05 mol) of urea, 7.5 ml of 30 per cent
aqueous sodium hydroxide solution and 35 ml of ethanol in a 100- ml round-bottomed flask. Attach
a reflux condenser and boil under reflux using an electric heating mantle for at least 2 hours. Cool
to room temperature, pour the reaction product into 62.5 ml of water and mix thoroughly. Allow to
stand for 15 minutes and then filter under suction to remove an insoluble by-product. Render the
filtrate strongly acidic with concentrated hydrochloric acid, cool in ice-water and immediately filter
off the precipitated product under suction.
Recrystallise at least once from industrial spirit to obtain about 2.8 g (44%) of pure 5,5-
diphenylhydantoin, m.p. 297-298 °C.
4. Principle:
Synthesis of 5,5-diphenylimidazolidine-2,4-dione (1) involves Pinacol-pinacolone
rearrangement reaction. The base catalysed reaction proceeds via an intermediate
heterocyclic pinacol (1,2 diol), which on acidification yields phenytoin.
Step Ι] Condensation of urea and benzil to form glycol (1,2-diol)
Benzil Urea Glycol (1, 2-diol)
5. Step ΙΙ] Protonation of glycol to form oxonium ion
Glycol (1,2-diol) Oxonium ion
Step ΙΙΙ] Dehydration to form corbonium ion.
Carbonium ion
6. Step ΙV] 1,2 shift of phenyl ring to form phenonium ion
Phenonium ion
Step V] Rearrangement of carbonium ion
Rearranged carbonium ion
Step VΙ] Loss of proton to give 5,5-diphenylimidazolidine-2,4-dione (1) (pinacolone)
7. CALCULATIONS :-
Molecular weight of benzil = 210.23gm/M
Molecular weight of phenytoin= 252.26gm/M
Weight taken of benzil =2.65gm/M
Practical yield = 2.9gm
X(theoretical yield )=molecular weight phenytoin x weight of benzil taken
molecular weight of benzil
=252.26g/M x 2.65g/210.23g/M = 3.17gm
Percentage yield = practical yield /theoretical yieldx100%
Percentage yield =2.9/3.17x100%
Percentage yield = 91.4%