D intermolecular forces are important when the so.pdf
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D intermolecular forces are important when the solvent or solute is a liquid or a solid. Solution D intermolecular forces are important when the solvent or solute is a liquid or a solid..
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You can use Network Monitor or type netstat -a in your command promp.pdf
You can use Network Monitor or type netstat -a in your command prompt window.
this will list all your conections.
Solution
You can use Network Monitor or type netstat -a in your command prompt window.
this will list all your conections..
There are no statements given.SolutionThere are no statements .pdf
There are no statements given.
Solution
There are no statements given..
The answer is B- Lagging strand.Lagging strand of DNA is synthesi.pdf
The answer is: B- Lagging strand.
Lagging strand of DNA is synthesized toward the middle of the replication bubble.
Solution
The answer is: B- Lagging strand.
Lagging strand of DNA is synthesized toward the middle of the replication bubble..
solution in c++program Program to implement a queue using two .pdf
solution in c++
program
/* Program to implement a queue using two stacks */
#include
#include
using namespace std;
/* structure of a stack node */
struct sNode
{
int data;
struct sNode *next;
};
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data);
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref);
/* structure of queue having two stacks */
struct queue
{
struct sNode *stack1;
struct sNode *stack2;
};
/* Function to enqueue an item to queue */
void enQueue(struct queue *q, int x)
{
push(&q->stack1, x);
}
/* Function to dequeue an item from queue */
int deQueue(struct queue *q)
{
int x;
/* If both stacks are empty then error */
if(q->stack1 == NULL && q->stack2 == NULL)
{
printf(\"Q is empty\");
getchar();
exit(0);
}
/* Move elements from satck1 to stack 2 only if
stack2 is empty */
if(q->stack2 == NULL)
{
while(q->stack1 != NULL)
{
x = pop(&q->stack1);
push(&q->stack2, x);
}
}
x = pop(&q->stack2);
return x;
}
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data)
{
/* allocate node */
struct sNode* new_node =
(struct sNode*) malloc(sizeof(struct sNode));
if(new_node == NULL)
{
printf(\"Stack is empty \ \");
getchar();
exit(0);
}
else{
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*top_ref);
/* move the head to point to the new node */
(*top_ref) = new_node;
}
}
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref)
{
int res;
struct sNode *top;
/*If stack is empty then error */
if(*top_ref == NULL)
{
printf(\"Stack overflow \ \");
getchar();
exit(0);
}
else
{
top = *top_ref;
res = top->data;
*top_ref = top->next;
free(top);
return res;
}
}
/* Driver function to test anove functions */
int main()
{
/* Create a queue with items 1 2 3*/
struct queue *q = (struct queue*)malloc(sizeof(struct queue));
q->stack1 = NULL;
q->stack2 = NULL;
for(int i=0;i<15;i++)
{
enQueue(q, i);
}
//enQueue(q, 2);
//enQueue(q, 3);
//enQueue(q,4);
/* Dequeue items */
printf(\"the dequeue items\");
for(int i=0;i<16;i++)
{
printf(\"%d \", deQueue(q));
//printf(\"%d \", deQueue(q));
}
getchar();
}
output
the dequeue items
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
q is empty
Solution
solution in c++
program
/* Program to implement a queue using two stacks */
#include
#include
using namespace std;
/* structure of a stack node */
struct sNode
{
int data;
struct sNode *next;
};
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data);
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref);
/* structure of queue having two stacks */
struct queue
{
struct sNode *stack1;
struct sNode *stack2;
};
/* Function to enqueue an item to queue */
void enQueue(struct queue *q, int x)
{
push(&q->stack1, x);
}
/* Function to dequeue an item from queue */
int deQueue(struct queue *q)
{
int x;
/* If both stacks are empty then error */
if(q->stack1 == NULL && q->stack2 == NULL)
{
printf(\"Q .
Organs of the digestive tract1.Mouth-2.Tongue-3.Epiglottis-.pdf
Organs of the digestive tract:
1.Mouth-
2.Tongue-
3.Epiglottis-
4.Pharynx-
5.Oesophagus-
6.Diaphragm-
7.Stomach-
Pancreas-
8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large
intestine.
The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus.
(a)Small intestine-
9.Cecum-
(b) Large intestine-
Specialized structures or cells in the digestive tract:
These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes
and microfold cells.
Solution
Organs of the digestive tract:
1.Mouth-
2.Tongue-
3.Epiglottis-
4.Pharynx-
5.Oesophagus-
6.Diaphragm-
7.Stomach-
Pancreas-
8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large
intestine.
The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus.
(a)Small intestine-
9.Cecum-
(b) Large intestine-
Specialized structures or cells in the digestive tract:
These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes
and microfold cells..
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b..pdf
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and
no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a
single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has
three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N
atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The
second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N.
The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H).
Solution
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and
no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a
single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has
three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N
atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The
second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N.
The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H)..
u can feed air by possible putting zinc chloride.pdf
u can feed air by possible putting zinc chloride aroud it and the first part of
question is incorrect
Solution
u can feed air by possible putting zinc chloride aroud it and the first part of
question is incorrect.
The ammonia molecule (NH3) has three pairs of ele.pdf
The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but
there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom;
however, it influences the overall shape through repulsions. As in methane above, there are four
regions of electron density. Therefore, the overall orientation of the regions of electron density is
tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E
type molecule because the lone pair is represented by an E. The observed shape of the molecule
is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to
determine molecular geometry. The shape of a molecule is found from the relationship of the
atoms even though it can be influenced by lone pairs of electron
Solution
The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but
there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom;
however, it influences the overall shape through repulsions. As in methane above, there are four
regions of electron density. Therefore, the overall orientation of the regions of electron density is
tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E
type molecule because the lone pair is represented by an E. The observed shape of the molecule
is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to
determine molecular geometry. The shape of a molecule is found from the relationship of the
atoms even though it can be influenced by lone pairs of electron.
Recommended
You can use Network Monitor or type netstat -a in your command promp.pdf
You can use Network Monitor or type netstat -a in your command prompt window.
this will list all your conections.
Solution
You can use Network Monitor or type netstat -a in your command prompt window.
this will list all your conections..
There are no statements given.SolutionThere are no statements .pdf
There are no statements given.
Solution
There are no statements given..
The answer is B- Lagging strand.Lagging strand of DNA is synthesi.pdf
The answer is: B- Lagging strand.
Lagging strand of DNA is synthesized toward the middle of the replication bubble.
Solution
The answer is: B- Lagging strand.
Lagging strand of DNA is synthesized toward the middle of the replication bubble..
solution in c++program Program to implement a queue using two .pdf
solution in c++
program
/* Program to implement a queue using two stacks */
#include
#include
using namespace std;
/* structure of a stack node */
struct sNode
{
int data;
struct sNode *next;
};
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data);
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref);
/* structure of queue having two stacks */
struct queue
{
struct sNode *stack1;
struct sNode *stack2;
};
/* Function to enqueue an item to queue */
void enQueue(struct queue *q, int x)
{
push(&q->stack1, x);
}
/* Function to dequeue an item from queue */
int deQueue(struct queue *q)
{
int x;
/* If both stacks are empty then error */
if(q->stack1 == NULL && q->stack2 == NULL)
{
printf(\"Q is empty\");
getchar();
exit(0);
}
/* Move elements from satck1 to stack 2 only if
stack2 is empty */
if(q->stack2 == NULL)
{
while(q->stack1 != NULL)
{
x = pop(&q->stack1);
push(&q->stack2, x);
}
}
x = pop(&q->stack2);
return x;
}
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data)
{
/* allocate node */
struct sNode* new_node =
(struct sNode*) malloc(sizeof(struct sNode));
if(new_node == NULL)
{
printf(\"Stack is empty \ \");
getchar();
exit(0);
}
else{
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*top_ref);
/* move the head to point to the new node */
(*top_ref) = new_node;
}
}
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref)
{
int res;
struct sNode *top;
/*If stack is empty then error */
if(*top_ref == NULL)
{
printf(\"Stack overflow \ \");
getchar();
exit(0);
}
else
{
top = *top_ref;
res = top->data;
*top_ref = top->next;
free(top);
return res;
}
}
/* Driver function to test anove functions */
int main()
{
/* Create a queue with items 1 2 3*/
struct queue *q = (struct queue*)malloc(sizeof(struct queue));
q->stack1 = NULL;
q->stack2 = NULL;
for(int i=0;i<15;i++)
{
enQueue(q, i);
}
//enQueue(q, 2);
//enQueue(q, 3);
//enQueue(q,4);
/* Dequeue items */
printf(\"the dequeue items\");
for(int i=0;i<16;i++)
{
printf(\"%d \", deQueue(q));
//printf(\"%d \", deQueue(q));
}
getchar();
}
output
the dequeue items
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14
q is empty
Solution
solution in c++
program
/* Program to implement a queue using two stacks */
#include
#include
using namespace std;
/* structure of a stack node */
struct sNode
{
int data;
struct sNode *next;
};
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data);
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref);
/* structure of queue having two stacks */
struct queue
{
struct sNode *stack1;
struct sNode *stack2;
};
/* Function to enqueue an item to queue */
void enQueue(struct queue *q, int x)
{
push(&q->stack1, x);
}
/* Function to dequeue an item from queue */
int deQueue(struct queue *q)
{
int x;
/* If both stacks are empty then error */
if(q->stack1 == NULL && q->stack2 == NULL)
{
printf(\"Q .
Organs of the digestive tract1.Mouth-2.Tongue-3.Epiglottis-.pdf
Organs of the digestive tract:
1.Mouth-
2.Tongue-
3.Epiglottis-
4.Pharynx-
5.Oesophagus-
6.Diaphragm-
7.Stomach-
Pancreas-
8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large
intestine.
The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus.
(a)Small intestine-
9.Cecum-
(b) Large intestine-
Specialized structures or cells in the digestive tract:
These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes
and microfold cells.
Solution
Organs of the digestive tract:
1.Mouth-
2.Tongue-
3.Epiglottis-
4.Pharynx-
5.Oesophagus-
6.Diaphragm-
7.Stomach-
Pancreas-
8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large
intestine.
The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus.
(a)Small intestine-
9.Cecum-
(b) Large intestine-
Specialized structures or cells in the digestive tract:
These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes
and microfold cells..
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b..pdf
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and
no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a
single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has
three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N
atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The
second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N.
The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H).
Solution
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and
no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a
single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has
three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N
atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The
second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N.
The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H)..
u can feed air by possible putting zinc chloride.pdf
u can feed air by possible putting zinc chloride aroud it and the first part of
question is incorrect
Solution
u can feed air by possible putting zinc chloride aroud it and the first part of
question is incorrect.
The ammonia molecule (NH3) has three pairs of ele.pdf
The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but
there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom;
however, it influences the overall shape through repulsions. As in methane above, there are four
regions of electron density. Therefore, the overall orientation of the regions of electron density is
tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E
type molecule because the lone pair is represented by an E. The observed shape of the molecule
is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to
determine molecular geometry. The shape of a molecule is found from the relationship of the
atoms even though it can be influenced by lone pairs of electron
Solution
The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but
there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom;
however, it influences the overall shape through repulsions. As in methane above, there are four
regions of electron density. Therefore, the overall orientation of the regions of electron density is
tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E
type molecule because the lone pair is represented by an E. The observed shape of the molecule
is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to
determine molecular geometry. The shape of a molecule is found from the relationship of the
atoms even though it can be influenced by lone pairs of electron.
E)Mg2- note more electron filled in the valence.pdf
E)Mg2- note: more electron filled in the valence shell, bigger the size is.
Solution
E)Mg2- note: more electron filled in the valence shell, bigger the size is..
CH4 (methane) molecules only have london dispersi.pdf
CH4 (methane) molecules only have london dispersion forces. They are nonpolar,
so no other IMF\'s will exist in them
Solution
CH4 (methane) molecules only have london dispersion forces. They are nonpolar,
so no other IMF\'s will exist in them.
PbCl4 - lead tetra chloride PbSo4 - lead sulfate.pdf
PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite
Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate -
KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2
lithium hydrogen sulfite - LiHSO3
Solution
PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite
Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate -
KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2
lithium hydrogen sulfite - LiHSO3.
NiCl2 for sure. None of the rest are soluble in w.pdf
NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit,
but CCl4 has a melting point below zero.
Solution
NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit,
but CCl4 has a melting point below zero..
It is polar. That is part of the reason it mixes .pdf
It is polar. That is part of the reason it mixes with water. It is also soluble with
nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a
charge
Solution
It is polar. That is part of the reason it mixes with water. It is also soluble with
nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a
charge.
Do you have an image of the IR If so it would be.pdf
Do you have an image of the IR? If so it would be much easier to help you out.
Solution
Do you have an image of the IR? If so it would be much easier to help you out..
Cooperativity Two different theories of the coo.pdf
Cooperativity : Two different theories of the cooperative mechanism were
postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or
“concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and
FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the
subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule
as it was transformed from one conformation (T) to a second conformation (R) under the
influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound,
so that changes in one subunit led to distortions in the shape and/or interactions of other subunits
of the protein. The KNF model, however, also predicted that in some cases the first ligand to
bind could make it more difficult for subsequent ligands to bind. This was called “negative
cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative”
because binding of one ligand made the binding of subsequent ligands more difficult.The MWC
theory allowed no such alternative. Because only the KNF theory fit negatively cooperative
enzymes, it is easy to select that model for such enzymes, but because both theories fit positively
cooperative enzymes more sophisticated tools must be applied to such cases.
Solution
Cooperativity : Two different theories of the cooperative mechanism were
postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or
“concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and
FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the
subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule
as it was transformed from one conformation (T) to a second conformation (R) under the
influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound,
so that changes in one subunit led to distortions in the shape and/or interactions of other subunits
of the protein. The KNF model, however, also predicted that in some cases the first ligand to
bind could make it more difficult for subsequent ligands to bind. This was called “negative
cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative”
because binding of one ligand made the binding of subsequent ligands more difficult.The MWC
theory allowed no such alternative. Because only the KNF theory fit negatively cooperative
enzymes, it is easy to select that model for such enzymes, but because both theories fit positively
cooperative enzymes more sophisticated tools must be applied to such cases..
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II).pdf
i) Lithium oxide
ii) Sodium hypochlorite
iii) Strontium (II) cyanide
iv) Chromium (III) hydroxide
v) Iron (III) sulfite
vi) Cobalt (II) nitrate
vii) Ammonium sulfite
viii) Sodium dihyrogen phosphate
ix) Potassium permanganate
x) Sodium dichromate
Hope this helps! :-)
Solution
i) Lithium oxide
ii) Sodium hypochlorite
iii) Strontium (II) cyanide
iv) Chromium (III) hydroxide
v) Iron (III) sulfite
vi) Cobalt (II) nitrate
vii) Ammonium sulfite
viii) Sodium dihyrogen phosphate
ix) Potassium permanganate
x) Sodium dichromate
Hope this helps! :-).
Hominin is the subtribe of tribe Hominini. These belong to modern hu.pdf
Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients.
They are evolved from the split with chimpanzees. So all Homo termed species are Hominin.
From the given picture, there are five hominin species coexisted 1.7 million years ago. Their
names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo
habilis.
Solution
Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients.
They are evolved from the split with chimpanzees. So all Homo termed species are Hominin.
From the given picture, there are five hominin species coexisted 1.7 million years ago. Their
names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo
habilis..
Heat evolved = mass of water x specific heat capacity x temperature .pdf
Heat evolved = mass of water x specific heat capacity x temperature change
= 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ
Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol
Solution
Heat evolved = mass of water x specific heat capacity x temperature change
= 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ
Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol.
D. Primary lymphatic structure are sites where white blood cells are.pdf
D. Primary lymphatic structure are sites where white blood cells are produced and/or mature.
secondary lymphatic structure are where immune response are initiated.
Solution
D. Primary lymphatic structure are sites where white blood cells are produced and/or mature.
secondary lymphatic structure are where immune response are initiated..
domain (-inf,inf) range [-4,inf) x intercept (1,0) and (5,0.pdf
domain: (-inf,inf)
range: [-4,inf)
x intercept: (1,0) and (5,0)
y intercept: (0,5)
increasing interval: (3,INF)
decreasing interval: (0,3)
constant interval: (-INF,0)
at x=3 we have a minima
f(-2)=5
at x=2 and at x=4, f(x)=-3
function is neither even nor odd
Solution
domain: (-inf,inf)
range: [-4,inf)
x intercept: (1,0) and (5,0)
y intercept: (0,5)
increasing interval: (3,INF)
decreasing interval: (0,3)
constant interval: (-INF,0)
at x=3 we have a minima
f(-2)=5
at x=2 and at x=4, f(x)=-3
function is neither even nor odd.
Earlier a place value notation number system had evolved over a leng.pdf
Earlier a place value notation number system had evolved over a lengthy period with a number
base of 60. It allowed arbitrarily large numbers and fractions to be represented and so proved to
be the foundation of more high powered mathematical development.
Number problems such as that of the Pythagorean triples (a,b,c) with a2+b2 = c2 were studied
from at least 1700 BC. Systems of linear equations were studied in the context of solving number
problems. Quadratic equations were also studied and these examples led to a type of numerical
algebra.
Geometric problems relating to similar figures, area and volume were also studied and values
obtained for π.
The Babylonian basis of mathematics was inherited by the Greeks and independent development
by the Greeks began from around 450 BC. Zeno of Elea\'s paradoxes led to the atomic theory of
Democritus. A more precise formulation of concepts led to the realisation that the rational
numbers did not suffice to measure all lengths. A geometric formulation of irrational numbers
arose. Studies of area led to a form of integration.
The theory of conic sections shows a high point in pure mathematical study by Apollonius.
Further mathematical discoveries were driven by the astronomy, for example the study of
trigonometry.
The major Greek progress in mathematics was from 300 BC to 200 AD. After this time progress
continued in Islamic countries. Mathematics flourished in particular in Iran, Syria and India. This
work did not match the progress made by the Greeks but in addition to the Islamic progress, it
did preserve Greek mathematics. From about the 11th Century Adelard of Bath, then later
Fibonacci, brought this Islamic mathematics and its knowledge of Greek mathematics back into
Europe.
Major progress in mathematics in Europe began again at the beginning of the 16th Century with
Pacioli, then Cardan, Tartaglia and Ferrari with the algebraic solution of cubic and quartic
equations. Copernicus and Galileo revolutionised the applications of mathematics to the study of
the universe.
The progress in algebra had a major psychological effect and enthusiasm for mathematical
research, in particular research in algebra, spread from Italy to Stevin in Belgium and Viète in
France.
The 17th Century saw Napier, Briggs and others greatly extend the power of mathematics as a
calculatory science with his discovery of logarithms. Cavalieri made progress towards the
calculus with his infinitesimal methods and Descartes added the power of algebraic methods to
geometry.
Progress towards the calculus continued with Fermat, who, together with Pascal, began the
mathematical study of probability. However the calculus was to be the topic of most significance
to evolve in the 17th Century.
Newton, building on the work of many earlier mathematicians such as his teacher Barrow,
developed the calculus into a tool to push forward the study of nature. His work contained a
wealth of new discoveries showing the interaction between mathemat.
Cyclohexanone is slightly soluble in water.NaCl is added to make t.pdf
Cyclohexanone is slightly soluble in water.
NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in
the aqueous layer is decreased.
This will increase the partition coefficient and more cyclohexanone will be extracted into the
organic layer.
Thus the extraction of cyclohexanone will be more efficient.
Solution
Cyclohexanone is slightly soluble in water.
NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in
the aqueous layer is decreased.
This will increase the partition coefficient and more cyclohexanone will be extracted into the
organic layer.
Thus the extraction of cyclohexanone will be more efficient..
amniotic eggs evolved primarily as an adaptation toa. protect the .pdf
amniotic eggs evolved primarily as an adaptation to
a. protect the developing embryo while the parents sits on it
b. protect the developing embryo from predators
c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER
d. allow the embryo to remain protected while the parent is out gathering food
e. to provide a nice compact case that is easy to boil and subsequently eat
=============================================================
Amniotes
:They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm
blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are
recognized from the anamniotes (fishes and creatures of land and water), which commonly lay
their eggs in water. Amniotes are tetrapods (relatives of four-limbed and backboned creatures)
that are portrayed by having an egg outfitted with an amnion, an adjustment to lay eggs ashore as
opposed to in water as the anamniotes (counting frogs) regularly do. Amniotes incorporate
synapsids (warm blooded creatures alongside their wiped out family) and sauropsids (reptiles
and winged creatures), and additionally their predecessors. Amniote developing lives, whether
laid as eggs or conveyed by the female, are ensured and supported by a few broad layers. In
eutherian warm blooded creatures, (for example, people), these films incorporate the amniotic
sac that encompasses the embryo. These embryonic films and the absence of a larval stage
recognize amniotes from tetrapod creatures of land and water shedding is controlled by
trademark hormones called ecdysteroids
the fingernail skin has 3 layers epicuticle, exocuticle, and endocuticle
epicuticle is trilaminate alpha-chitin in internal layer
Some taxa have lost the genuine coelom and have gotten to be blastocoelic (pseudocoelomic).
Arthropods are eucoelomic, however in develop creatures the coelom is incredibly diminished.
The open circulatory framework utilizes an optionally delivered pit, the hemocoel. Valentine
(2004) recommends that another synapomorphic character is immediate advancement or
improvement in which hatchlings are comparative when all is said in done frame to the develop
grown-up, a character that has changed altogether in numerous arthropod bunches.
Solution
amniotic eggs evolved primarily as an adaptation to
a. protect the developing embryo while the parents sits on it
b. protect the developing embryo from predators
c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER
d. allow the embryo to remain protected while the parent is out gathering food
e. to provide a nice compact case that is easy to boil and subsequently eat
=============================================================
Amniotes
:They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm
blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are
recognized from the anamniotes (.
Code#include stdio.h #includemalloc.h struct node { .pdf
Code:
#include
#include
struct node
{
int data;
struct node* next;
};
typedef struct node * immense_int_t;
void insert_front(immense_int_t head, char c);
void print(immense_int_t head);
immense_int_t add(immense_int_t head1, immense_int_t head2);
immense_int_t sub(immense_int_t head1, immense_int_t head2);
int main()
{
char s[1000],c;
int i;
immense_int_t head1 = malloc(sizeof(struct node));//dummy node for ease of coding
immense_int_t head2 = malloc(sizeof(struct node));// dummy node for ease of coding
head1->next = head2->next = NULL;
immense_int_t result ;
scanf(\"%s\",s);
for(i=0;s[i]!=\'\\0\';i++)
insert_front(head1,s[i]);// put input into linked list
scanf(\"%s\",s);
for(i=0;s[i]!=\'\\0\';i++)
insert_front(head2,s[i]);// put input into linked list
scanf(\"%s\",s);
switch(s[0])
{
case \'+\':
result = add(head1->next,head2->next);
break;
case \'\"\':
result = sub(head1->next,head2->next);
break;
}
print(result->next);// print from dummy next node
printf(\"\ \");
return 0;
}
void insert_front(immense_int_t head, char c)
{
immense_int_t node = malloc(sizeof(struct node));
node->data = c-\'0\';
node->next = head->next;
head->next = node;
}
void print(immense_int_t head)
{
if(head==NULL)
return;
print(head->next);
printf(\"%d\",head->data);
}
immense_int_t add(immense_int_t head1, immense_int_t head2)
{
immense_int_t result = malloc(sizeof(struct node));
immense_int_t temp, temp1;
temp = malloc(sizeof(struct node));
result->next = temp;
temp1 = temp;
int carry =0;
while(head1 && head2)
{
temp->data = (head1->data + head2->data + carry)%10;
carry = (head1->data + head2->data + carry)/10 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head1 = head1->next;
head2 = head2->next;
}
while(head1) // if number of digits of first are more than second
{
temp->data = (head1->data + carry)%10;
carry = (head1->data + carry)/10 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head1 = head1->next;
}
while(head2)// if number of digits of second are more than first
{
temp->data = (head2->data + carry)%10;
carry = (head2->data + carry)/10 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head2 = head2->next;
}
if(carry)// if the number of digits in result is more than number of digits in both the numbers
{
temp->data = carry;
temp1->next = temp;
temp1 = temp;
}
temp1->next = NULL;
return result;
}
immense_int_t sub(immense_int_t head1, immense_int_t head2)
{
immense_int_t result = malloc(sizeof(struct node));
immense_int_t temp, temp1;
temp = malloc(sizeof(struct node));
result->next = temp;
temp1 = temp;
int borrow =0;
while(head1 && head2)
{
temp->data = (head1->data - head2->data - borrow + 10)%10;
borrow = (head1->data - head2->data - borrow) < 0? 1:0 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head1 = head1->next;
head2 = head2->next;
}
while(head1)// if number of digits of first are more than second
{
temp->data = (head1->data - borrow)%10;
borrow = (head1->da.
a) Anomeric carbon The carbonyl carbon found in the open chain . Eg.pdf
a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose
b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose
and D-Galactose - C4 epimers
c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose
d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose
e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose
Solution
a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose
b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose
and D-Galactose - C4 epimers
c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose
d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose
e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose.
How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.More Related Content
More from brijmote
E)Mg2- note more electron filled in the valence.pdf
E)Mg2- note: more electron filled in the valence shell, bigger the size is.
Solution
E)Mg2- note: more electron filled in the valence shell, bigger the size is..
CH4 (methane) molecules only have london dispersi.pdf
CH4 (methane) molecules only have london dispersion forces. They are nonpolar,
so no other IMF\'s will exist in them
Solution
CH4 (methane) molecules only have london dispersion forces. They are nonpolar,
so no other IMF\'s will exist in them.
PbCl4 - lead tetra chloride PbSo4 - lead sulfate.pdf
PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite
Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate -
KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2
lithium hydrogen sulfite - LiHSO3
Solution
PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite
Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate -
KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2
lithium hydrogen sulfite - LiHSO3.
NiCl2 for sure. None of the rest are soluble in w.pdf
NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit,
but CCl4 has a melting point below zero.
Solution
NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit,
but CCl4 has a melting point below zero..
It is polar. That is part of the reason it mixes .pdf
It is polar. That is part of the reason it mixes with water. It is also soluble with
nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a
charge
Solution
It is polar. That is part of the reason it mixes with water. It is also soluble with
nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a
charge.
Do you have an image of the IR If so it would be.pdf
Do you have an image of the IR? If so it would be much easier to help you out.
Solution
Do you have an image of the IR? If so it would be much easier to help you out..
Cooperativity Two different theories of the coo.pdf
Cooperativity : Two different theories of the cooperative mechanism were
postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or
“concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and
FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the
subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule
as it was transformed from one conformation (T) to a second conformation (R) under the
influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound,
so that changes in one subunit led to distortions in the shape and/or interactions of other subunits
of the protein. The KNF model, however, also predicted that in some cases the first ligand to
bind could make it more difficult for subsequent ligands to bind. This was called “negative
cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative”
because binding of one ligand made the binding of subsequent ligands more difficult.The MWC
theory allowed no such alternative. Because only the KNF theory fit negatively cooperative
enzymes, it is easy to select that model for such enzymes, but because both theories fit positively
cooperative enzymes more sophisticated tools must be applied to such cases.
Solution
Cooperativity : Two different theories of the cooperative mechanism were
postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or
“concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and
FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the
subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule
as it was transformed from one conformation (T) to a second conformation (R) under the
influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound,
so that changes in one subunit led to distortions in the shape and/or interactions of other subunits
of the protein. The KNF model, however, also predicted that in some cases the first ligand to
bind could make it more difficult for subsequent ligands to bind. This was called “negative
cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative”
because binding of one ligand made the binding of subsequent ligands more difficult.The MWC
theory allowed no such alternative. Because only the KNF theory fit negatively cooperative
enzymes, it is easy to select that model for such enzymes, but because both theories fit positively
cooperative enzymes more sophisticated tools must be applied to such cases..
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II).pdf
i) Lithium oxide
ii) Sodium hypochlorite
iii) Strontium (II) cyanide
iv) Chromium (III) hydroxide
v) Iron (III) sulfite
vi) Cobalt (II) nitrate
vii) Ammonium sulfite
viii) Sodium dihyrogen phosphate
ix) Potassium permanganate
x) Sodium dichromate
Hope this helps! :-)
Solution
i) Lithium oxide
ii) Sodium hypochlorite
iii) Strontium (II) cyanide
iv) Chromium (III) hydroxide
v) Iron (III) sulfite
vi) Cobalt (II) nitrate
vii) Ammonium sulfite
viii) Sodium dihyrogen phosphate
ix) Potassium permanganate
x) Sodium dichromate
Hope this helps! :-).
Hominin is the subtribe of tribe Hominini. These belong to modern hu.pdf
Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients.
They are evolved from the split with chimpanzees. So all Homo termed species are Hominin.
From the given picture, there are five hominin species coexisted 1.7 million years ago. Their
names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo
habilis.
Solution
Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients.
They are evolved from the split with chimpanzees. So all Homo termed species are Hominin.
From the given picture, there are five hominin species coexisted 1.7 million years ago. Their
names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo
habilis..
Heat evolved = mass of water x specific heat capacity x temperature .pdf
Heat evolved = mass of water x specific heat capacity x temperature change
= 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ
Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol
Solution
Heat evolved = mass of water x specific heat capacity x temperature change
= 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ
Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol.
D. Primary lymphatic structure are sites where white blood cells are.pdf
D. Primary lymphatic structure are sites where white blood cells are produced and/or mature.
secondary lymphatic structure are where immune response are initiated.
Solution
D. Primary lymphatic structure are sites where white blood cells are produced and/or mature.
secondary lymphatic structure are where immune response are initiated..
domain (-inf,inf) range [-4,inf) x intercept (1,0) and (5,0.pdf
domain: (-inf,inf)
range: [-4,inf)
x intercept: (1,0) and (5,0)
y intercept: (0,5)
increasing interval: (3,INF)
decreasing interval: (0,3)
constant interval: (-INF,0)
at x=3 we have a minima
f(-2)=5
at x=2 and at x=4, f(x)=-3
function is neither even nor odd
Solution
domain: (-inf,inf)
range: [-4,inf)
x intercept: (1,0) and (5,0)
y intercept: (0,5)
increasing interval: (3,INF)
decreasing interval: (0,3)
constant interval: (-INF,0)
at x=3 we have a minima
f(-2)=5
at x=2 and at x=4, f(x)=-3
function is neither even nor odd.
Earlier a place value notation number system had evolved over a leng.pdf
Earlier a place value notation number system had evolved over a lengthy period with a number
base of 60. It allowed arbitrarily large numbers and fractions to be represented and so proved to
be the foundation of more high powered mathematical development.
Number problems such as that of the Pythagorean triples (a,b,c) with a2+b2 = c2 were studied
from at least 1700 BC. Systems of linear equations were studied in the context of solving number
problems. Quadratic equations were also studied and these examples led to a type of numerical
algebra.
Geometric problems relating to similar figures, area and volume were also studied and values
obtained for π.
The Babylonian basis of mathematics was inherited by the Greeks and independent development
by the Greeks began from around 450 BC. Zeno of Elea\'s paradoxes led to the atomic theory of
Democritus. A more precise formulation of concepts led to the realisation that the rational
numbers did not suffice to measure all lengths. A geometric formulation of irrational numbers
arose. Studies of area led to a form of integration.
The theory of conic sections shows a high point in pure mathematical study by Apollonius.
Further mathematical discoveries were driven by the astronomy, for example the study of
trigonometry.
The major Greek progress in mathematics was from 300 BC to 200 AD. After this time progress
continued in Islamic countries. Mathematics flourished in particular in Iran, Syria and India. This
work did not match the progress made by the Greeks but in addition to the Islamic progress, it
did preserve Greek mathematics. From about the 11th Century Adelard of Bath, then later
Fibonacci, brought this Islamic mathematics and its knowledge of Greek mathematics back into
Europe.
Major progress in mathematics in Europe began again at the beginning of the 16th Century with
Pacioli, then Cardan, Tartaglia and Ferrari with the algebraic solution of cubic and quartic
equations. Copernicus and Galileo revolutionised the applications of mathematics to the study of
the universe.
The progress in algebra had a major psychological effect and enthusiasm for mathematical
research, in particular research in algebra, spread from Italy to Stevin in Belgium and Viète in
France.
The 17th Century saw Napier, Briggs and others greatly extend the power of mathematics as a
calculatory science with his discovery of logarithms. Cavalieri made progress towards the
calculus with his infinitesimal methods and Descartes added the power of algebraic methods to
geometry.
Progress towards the calculus continued with Fermat, who, together with Pascal, began the
mathematical study of probability. However the calculus was to be the topic of most significance
to evolve in the 17th Century.
Newton, building on the work of many earlier mathematicians such as his teacher Barrow,
developed the calculus into a tool to push forward the study of nature. His work contained a
wealth of new discoveries showing the interaction between mathemat.
Cyclohexanone is slightly soluble in water.NaCl is added to make t.pdf
Cyclohexanone is slightly soluble in water.
NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in
the aqueous layer is decreased.
This will increase the partition coefficient and more cyclohexanone will be extracted into the
organic layer.
Thus the extraction of cyclohexanone will be more efficient.
Solution
Cyclohexanone is slightly soluble in water.
NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in
the aqueous layer is decreased.
This will increase the partition coefficient and more cyclohexanone will be extracted into the
organic layer.
Thus the extraction of cyclohexanone will be more efficient..
amniotic eggs evolved primarily as an adaptation toa. protect the .pdf
amniotic eggs evolved primarily as an adaptation to
a. protect the developing embryo while the parents sits on it
b. protect the developing embryo from predators
c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER
d. allow the embryo to remain protected while the parent is out gathering food
e. to provide a nice compact case that is easy to boil and subsequently eat
=============================================================
Amniotes
:They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm
blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are
recognized from the anamniotes (fishes and creatures of land and water), which commonly lay
their eggs in water. Amniotes are tetrapods (relatives of four-limbed and backboned creatures)
that are portrayed by having an egg outfitted with an amnion, an adjustment to lay eggs ashore as
opposed to in water as the anamniotes (counting frogs) regularly do. Amniotes incorporate
synapsids (warm blooded creatures alongside their wiped out family) and sauropsids (reptiles
and winged creatures), and additionally their predecessors. Amniote developing lives, whether
laid as eggs or conveyed by the female, are ensured and supported by a few broad layers. In
eutherian warm blooded creatures, (for example, people), these films incorporate the amniotic
sac that encompasses the embryo. These embryonic films and the absence of a larval stage
recognize amniotes from tetrapod creatures of land and water shedding is controlled by
trademark hormones called ecdysteroids
the fingernail skin has 3 layers epicuticle, exocuticle, and endocuticle
epicuticle is trilaminate alpha-chitin in internal layer
Some taxa have lost the genuine coelom and have gotten to be blastocoelic (pseudocoelomic).
Arthropods are eucoelomic, however in develop creatures the coelom is incredibly diminished.
The open circulatory framework utilizes an optionally delivered pit, the hemocoel. Valentine
(2004) recommends that another synapomorphic character is immediate advancement or
improvement in which hatchlings are comparative when all is said in done frame to the develop
grown-up, a character that has changed altogether in numerous arthropod bunches.
Solution
amniotic eggs evolved primarily as an adaptation to
a. protect the developing embryo while the parents sits on it
b. protect the developing embryo from predators
c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER
d. allow the embryo to remain protected while the parent is out gathering food
e. to provide a nice compact case that is easy to boil and subsequently eat
=============================================================
Amniotes
:They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm
blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are
recognized from the anamniotes (.
Code#include stdio.h #includemalloc.h struct node { .pdf
Code:
#include
#include
struct node
{
int data;
struct node* next;
};
typedef struct node * immense_int_t;
void insert_front(immense_int_t head, char c);
void print(immense_int_t head);
immense_int_t add(immense_int_t head1, immense_int_t head2);
immense_int_t sub(immense_int_t head1, immense_int_t head2);
int main()
{
char s[1000],c;
int i;
immense_int_t head1 = malloc(sizeof(struct node));//dummy node for ease of coding
immense_int_t head2 = malloc(sizeof(struct node));// dummy node for ease of coding
head1->next = head2->next = NULL;
immense_int_t result ;
scanf(\"%s\",s);
for(i=0;s[i]!=\'\\0\';i++)
insert_front(head1,s[i]);// put input into linked list
scanf(\"%s\",s);
for(i=0;s[i]!=\'\\0\';i++)
insert_front(head2,s[i]);// put input into linked list
scanf(\"%s\",s);
switch(s[0])
{
case \'+\':
result = add(head1->next,head2->next);
break;
case \'\"\':
result = sub(head1->next,head2->next);
break;
}
print(result->next);// print from dummy next node
printf(\"\ \");
return 0;
}
void insert_front(immense_int_t head, char c)
{
immense_int_t node = malloc(sizeof(struct node));
node->data = c-\'0\';
node->next = head->next;
head->next = node;
}
void print(immense_int_t head)
{
if(head==NULL)
return;
print(head->next);
printf(\"%d\",head->data);
}
immense_int_t add(immense_int_t head1, immense_int_t head2)
{
immense_int_t result = malloc(sizeof(struct node));
immense_int_t temp, temp1;
temp = malloc(sizeof(struct node));
result->next = temp;
temp1 = temp;
int carry =0;
while(head1 && head2)
{
temp->data = (head1->data + head2->data + carry)%10;
carry = (head1->data + head2->data + carry)/10 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head1 = head1->next;
head2 = head2->next;
}
while(head1) // if number of digits of first are more than second
{
temp->data = (head1->data + carry)%10;
carry = (head1->data + carry)/10 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head1 = head1->next;
}
while(head2)// if number of digits of second are more than first
{
temp->data = (head2->data + carry)%10;
carry = (head2->data + carry)/10 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head2 = head2->next;
}
if(carry)// if the number of digits in result is more than number of digits in both the numbers
{
temp->data = carry;
temp1->next = temp;
temp1 = temp;
}
temp1->next = NULL;
return result;
}
immense_int_t sub(immense_int_t head1, immense_int_t head2)
{
immense_int_t result = malloc(sizeof(struct node));
immense_int_t temp, temp1;
temp = malloc(sizeof(struct node));
result->next = temp;
temp1 = temp;
int borrow =0;
while(head1 && head2)
{
temp->data = (head1->data - head2->data - borrow + 10)%10;
borrow = (head1->data - head2->data - borrow) < 0? 1:0 ;
temp1->next = temp;
temp1 = temp;
temp = malloc(sizeof(struct node));
head1 = head1->next;
head2 = head2->next;
}
while(head1)// if number of digits of first are more than second
{
temp->data = (head1->data - borrow)%10;
borrow = (head1->da.
a) Anomeric carbon The carbonyl carbon found in the open chain . Eg.pdf
a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose
b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose
and D-Galactose - C4 epimers
c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose
d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose
e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose
Solution
a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose
b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose
and D-Galactose - C4 epimers
c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose
d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose
e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose.
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