calendar above answer the following questions Which day th.pdf

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calendar above, answer the following questions: Which day this month would you be able to see the Moon at its highest point in the sky as the Sun is setting? Which day this month would you be able to see the Moon at its highest point in the sky as the Sun is rising? Which is the only day this month when the Moon will be visible ONLY at night?.

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Cada ao en los Estados Unidos, cientos de iglesias cristianas celebran el cumpleaos de Charles Darwin. Hacen esto para enfatizar el hecho de que la seleccin natural es compatible con su fe. Y ha sido la posicin de la Iglesia Catlica desde 1950 que la evolucin es real, y que la teora de la seleccin natural parece ser vlida. Entonces, dado que la seleccin natural no dice que no hay dios, y no dice que dios no cre a los humanos, por qu los conceptos de evolucin y seleccin natural siguen siendo problemticos para algunos?.

Can you please add comments so I can understand it Thank yo.pdf

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Can you please add comments so I can understand it. Thank you so much V. Use either a Venn Diagram or a Leibniz Diagram to confirm (or deny) the validity of the following arguments. Be sure to use statement variables for clarity, if needed. a) No things derived from sensory impressions are items of knowledge of substance itself. All items of knowledge are things derived from sensory impressions Therefore, no items of knowledge are items of knowledge of substance itself. b) All bankrupt companies are companies unable to pay interest on their debts. Barcelona Traction is a company unable to pay interest on its debts. Therefore, Barcelona Traction is a bankrupt company. c) No gold is base metal. Some base metals are things that glitter. Therefore, some things that glitter are not gold..

can you help me write this code in Net Maui App please than.pdf

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can you help me write this code in .Net Maui App please thank you Make Reservation When a travel agent selects a flight from the list, the text fields are populated with the selected flight code, airline, day, time and cost. The travel agent enters the travellers full name and citizenship. The flight code, airline, day, time and cost cannot be edited. An error message is displayed if: A reservation is to be made but no flight is selected The name field is empty The citizenship field is empty The makeReservation method receives as its input arguments: a Flight object, the travelers name and citizenship. An exception is thrown if the flight is completely booked, or the flight is null, or the name is empty/null, or the citizenship is empty/null. If there are no exceptions thrown a Reservation object is created, saved to the binary file and returned by the method. Find Reservations A travel agent can search for an existing reservation that contains the specified reservation code, and/or airline and/or travellers full name. The list is populated with any reservations that are found. Each row in the list displays the code of the corresponding reservation record. The findReservation method receives as its input arguments: reservation code, airline and/or travelers full name. The method returns a list of matching Reservation objects. If no matches are found, the list control is empty. If the user doesnt enter any input, then all the reservations are displayed in the list. Update Reservation When a reservation in the list generated by the findReservation method is selected, the corresponding fields are populated, displaying the following information: Reservation code Flight code Airline name Cost Name Citizenship Status (active or inactive) The only fields that can be edited are the name, citizenship and status. None of the other fields can be modified in any way by the user. After the travel agent has made changes to the reservation, they click the Update button. The mutator methods in the Reservation object are called and an error is displayed if an exception occurs. The persist method in the ReservationManager class saves all Reservation objects to a binary file on the hard drive. Notes The ReservationManager class generates the reservation code. Each reservation is for one seat only. The name and citizenship do not need to follow any specific format; however, they cannot be empty. Each problem domain class overrides the toString() method. Flight codes use the following format: (L meaning letter, D meaning digit) LL-DDDD (e.g.: GA-1234) Reservation codes use the following format: (L meaning Letter, D meaning Digit) LDDDD (e.g., I1234) Times are in 24-hour format: HH:MM Reservations Loesing Reseresion coofir Reserve fager fryal coule Aurire Auriene Day Cont. tires Nunes Crumense Nare Stin n Aative.

Can you help me with these two questions I will give you a .pdf

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Can you help me design this interface in HTML Flight Find.pdf

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Can You build the web based project Homepage for me Home .pdf

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Can You build the web based project Homepage for me? Home Page: After login, all the summary will be shown in this page. Update Account Details: In this feature, all the users except visitors and lawyers can access and update or delete their account information. Access Control System: Admin can control the access of all the users. He can add or remove access of any of the user. Update System Information: Only administrator will have access to this feature to update any sort of system. Cell Block Management: In here, cell block information will be stored the number of cells added or blocked. It will be managed by the guards. View Cell Block Details Add New Cell Block Edit/Update Cell Block Details Delete Cell Block Crime Management: All of crimes will be listed in this section. It will have a complete record. View Crime Details Add New Crime List All Crimes Edit/Update Crime Details View Crime Details Delete Crime Prisoner Management: Prisoners details will be stored here for which crime they are imprisoned and penalty details. Itll be managed by the officers. View Prisoner Details Add New Prisoner List All Prisoner Edit Prisoner Details Update Prisoner Visitor Privilege Print Prisoner Details Add Penalty Record List All Penalty Records Delete Penalty Record Weekly/Monthly Prisoner Report Guard Management: The number of guards and how many cell blocks are under each guard will be recorded here. View Guard Details Add New Guard List All Guard Details Edit Guard Details Delete Guard Details Staff : There will be few staffs to manage the other things Meal Management Health Management Prisoners Request Visitor Management: Number of people visiting the prison each will be recorded here. It will have all the details about the visitors how many times they have been here in a week, their relationship with the prisoner etc. Officers will update the record every day. View Visitor Details Add New Visitor List All Visitor Details Edit Visitor Details Delete Visitor Details Weekly/Monthly Visitor Records Visitors will have access to some features View Prisoner Details Request portal Lawyer Management: Lawyers defending each prisoner will be listed here. Officers can update their information. View Lawyer Details Add New Lawyer List All Lawyer Details Edit Lawyer Delete Lawyer Lawyers will have access to some features View Prisoner Details Request portal View Prisoner Reports Meal Management: Meal and food services for all prisoners, guards and stuffs will be sorted here. Staffs will have access to the segment. Add Meal Records View Meal Details Update Meal Details List Meal Details Weekly/Monthly Meal Records Duty Management: In the Duty Management, the timings, schedules and miscellaneous of all the guards, and stuffs will be updated consecutively by the officers. Add Duty Schedule Edit Duty Schedule Delete Duty Schedule View Duty Details List All Duty Details Prisoners Request Management: Prisoners requests will be listed here by the staffs and then it wi.

Can You build the web based project for me Home Page Aft.pdf

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Can You build the web based project for me? Home Page: After login, all the summary will be shown in this page. Update Account Details: In this feature, all the users except visitors and lawyers can access and update or delete their account information. Access Control System: Admin can control the access of all the users. He can add or remove access of any of the user. Update System Information: Only administrator will have access to this feature to update any sort of system. Cell Block Management: In here, cell block information will be stored the number of cells added or blocked. It will be managed by the guards. View Cell Block Details Add New Cell Block Edit/Update Cell Block Details Delete Cell Block Crime Management: All of crimes will be listed in this section. It will have a complete record. View Crime Details Add New Crime List All Crimes Edit/Update Crime Details View Crime Details Delete Crime Prisoner Management: Prisoners details will be stored here for which crime they are imprisoned and penalty details. Itll be managed by the officers. View Prisoner Details Add New Prisoner List All Prisoner Edit Prisoner Details Update Prisoner Visitor Privilege Print Prisoner Details Add Penalty Record List All Penalty Records Delete Penalty Record Weekly/Monthly Prisoner Report Guard Management: The number of guards and how many cell blocks are under each guard will be recorded here. View Guard Details Add New Guard List All Guard Details Edit Guard Details Delete Guard Details Staff : There will be few staffs to manage the other things Meal Management Health Management Prisoners Request Visitor Management: Number of people visiting the prison each will be recorded here. It will have all the details about the visitors how many times they have been here in a week, their relationship with the prisoner etc. Officers will update the record every day. View Visitor Details Add New Visitor List All Visitor Details Edit Visitor Details Delete Visitor Details Weekly/Monthly Visitor Records Visitors will have access to some features View Prisoner Details Request portal Lawyer Management: Lawyers defending each prisoner will be listed here. Officers can update their information. View Lawyer Details Add New Lawyer List All Lawyer Details Edit Lawyer Delete Lawyer Lawyers will have access to some features View Prisoner Details Request portal View Prisoner Reports Meal Management: Meal and food services for all prisoners, guards and stuffs will be sorted here. Staffs will have access to the segment. Add Meal Records View Meal Details Update Meal Details List Meal Details Weekly/Monthly Meal Records Duty Management: In the Duty Management, the timings, schedules and miscellaneous of all the guards, and stuffs will be updated consecutively by the officers. Add Duty Schedule Edit Duty Schedule Delete Duty Schedule View Duty Details List All Duty Details Prisoners Request Management: Prisoners requests will be listed here by the staffs and then it will be rev.

can you break this down in python codes please ? Task 1: Create a login system with a username and password. Required technologies: Python, Tkinter, SQL (for storing and retrieving user account information). Task 2: Allow the user to add initial cash to invest and generate a client ID. Required technologies: Python, Tkinter, SQL (for storing and retrieving user account information). Task 3: Implement the "Invest Now" option to allow the user to view investment types and prices, choose one to invest in, and confirm the transaction. Required technologies: Python, Tkinter, web scraping (to retrieve investment prices from external websites), SQL (for storing and retrieving user portfolio information). Task 4: Implement the "Portfolio Viewing" option to allow the user to view a list of all transactions. Required technologies: Python, Tkinter, SQL (for storing and retrieving user portfolio information). Task 5: Implement the "Money In/Out" option to allow the user to add or withdraw money to their account. Required technologies: Python, Tkinter, SQL (for storing and retrieving user account information). Step 2/2 Task 6: Set up a server to store all the data. Required technologies: Python, SQL. Task 7: Build a client/server desktop application in Python to interact with the user on the client side and add or update data on the server side. Required technologies: Python, Tkinter, SQL. Task 8: Create a UML diagram to design the Investment Trading Platform. Required technologies: UML design software (such as Lucidchart or Draw.io). Task 9: Write a report detailing your credentials, UML diagram, implementation plan, and running instructions. Required technologies: Word processing software (such as Microsoft Word or Google Docs). Task 10: Create a GUI with an intuitive user interface for all user-related interactions. Required technologies: Python, Tkinter.

Can someone explain this to me step by step Consider a give.pdf

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Can you answer these True or False questions for me please .pdf

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Can you answer these True or False questions for me please. (This was already answered but seems some answers are wrong so i want to make sure) 1- Chilean economic policies from the 1970s were focused on helping the cooper and mining industry and other sectors to secure the best technology globally to be competitive ? True or False 2- It will take years for the global economy to recover from corona COVID 19 ? True or False 3- Wise policymakers today recognize that it is entrepreneur training and technology that will help modern economies survive the tsunami of globalization ? True or False 4- Using the U6 unemployment data measure, in May 2020, US unemployment hit 25.2% ? True or False 5- A generation of low-skilled US manufacturing workers were left behind during the 2000s and they voted en masse in 2016 for protectionist President Trump who committed to bring their jobs back to the USA ? True or False 6- U6 also covers workers who have given up looking for work and part timers who are seeking full-time employment ? True or False 7- The role of State Trade programs is to focus on finding small businesses in their state that have export potential in targeted industries where they have competitive advantage, assist them in researching and finding new markets to find competent local partners, and get out of the way ? True or False.

Can someone please help with this Now that you have compl.pdf

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Can someone please help with this :) Now that you have completed the Punnete squaies you can ule this information to pecdict the Probability of specific outcomes in the F2, 2. Each of the four boxes represents a one in four (or 25% ) chance or probabilicy of a genorype. What is the genotypic ratio for this cross? 3. For each of the above genotypes, give the phenorype that would be expressod in the F2 generation. 4. What is the phenotypic ratio for this cross? SECTION 5: DIHYBRID CROSSES UP to this point, you have considered genetic crosses that involved a single trait controlled by 2 single gene (monohybrid cross). Mendel also made crosses that involved two genes, each located on a different pair of homologous chromosomes. This type of cross is called a dihybrid cross and illustrates Mendel's Law of Independent Assortment. Mendel demonstrated that when two traits are determined by genes located on two different chromosomes, each pair of alleles segregates independently of one another during gamete formation. The different possible allele combinations that result from meiosis are illustrated in Figure 8-3. Two equallv probable arranaements of chromosomes at metaphase l:Step 9: Phenotypic ratio of F2 Tongue roller, Taster Tongue roller, Non-taster Non-roller, Taster Non-roller, Non-taster.

Can someone solve the TODO parts of the following problem i.pdf

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Can someone solve the TODO parts of the following problem #include <iostream> #include <fstream> #include <sstream> #include<string> #include "Queuecpp.h" #include "Songcpp.h" #include "RequestCpp.h" //GIVEN int main() { LinkedList<Song> list; Queue<Request> q; populateSongDataBase(list); // fill the Songs Data Base into Linked List std::cout<<"*************************************n"; list.printList(); // std::cout<<"*************************************n"; populateRequests(q); // fill the request q std::cout<<"n"; std::cout<<"---------------PRINTING QUEUE-------------------n"; q.printList(); std::cout<<"------------------------------------n"; processQueue(list,q); // process the requests std::cout<<"*************************************n"; list.printList(); std::cout<<"*************************************n"; } //GIVEN void populateRequests(Queue<Request> &q){ } //GIVEN std::string playSong(LinkedList<Song>&list, Song s){ } //GIVEN void printTopTenSongs(LinkedList<Song>& list){ } //TODO void addThisSong(LinkedList<Song> &list, Song s){ //TODO /* Use this code if (found>=0) {std::cout<<"ADDED THIS SONG "<<found+1<<" " ;list.printSong(found+1);} else std::cout<<"SORRY CANNOT FIND SONG n"; */ } //TODO void removeThisSong(LinkedList<Song> &list, Song s){ /* Use this code if (found>=0) {std::cout<<"SORRY CANNOT REMOVE THIS SONG - STILL FOUND AT "<<found;} else{ std::cout<<"REMOVED THIS SONG n"; std::cout<<"THE SONG AT CHARTPOSITION "<<chartPos<<" IS NOW "; list.printSong(chartPos); std::cout<<"n"; */ } } //TODO void moveThisSong(LinkedList<Song> &list, Song s, int pos){ int chartPos=list.get(s); std::cout<<"MOVING SONG "<<s.toString()<<"n"; list.move(s,pos); std::cout<<"ITS NEW CHART POSITION n"; list.printSong(pos); std::cout<<"THE SONG AT PREVIOUS POSITION "<<chartPos+1<< " IS NOW ";list.printSong(chartPos+1); } //GIVEN void processRequest(LinkedList<Song> &list,std::string action, std::string title,std::string singer,int chartPos){ Song s(title,singer,chartPos); char ch =action[0]; switch(ch){ case 'P' : std::cout<<playSong(list,s)<<"n";break; case 'A' : addThisSong(list,s);break;; case 'R' : removeThisSong(list,s);break; case 'M' : moveThisSong(list,s,chartPos);break; case 'T' : printTopTenSongs(list);break; } } //TODO void processQueue(LinkedList<Song> &list ,Queue<Request>& q){ int requestNumber=1; //Create an iterator for the Queue to iteratate through requests std::cout<<"-------------------------------------------------------------------------n"; // call processRequest std::cout<<"-------------------------------------------------------------------------n" std::cout<<"-------------------------------------------------------------------------n"; } //GIVEN void populateSongDataBase(LinkedList<Song> &list){ std::string line=""; std::string token=""; std::string title=""; std::string singer=""; int chartPos=-1; try { std::ifstream input("SongsData.txt"); if (input.fail()) throw new std::string("FILE OPEN ERROR EXCEPTION n"); else{ while (getli.

Calculate the amount of money Dylan had to deposit in an inv.pdf

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Can someone please help me implement the addSong function .pdf

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Can someone please help me implement the "addSong" function in the code below? Thank you! // You are given a partially completed program that creates a list of songs, like a music repository. // Each song has this information: song's id, song's name, singer's name, genre of the song, and its published year. // The struct 'musicRepository' holds information of one song. Genre is enum type. // An array of structs called 'list' is made to hold the list of songs. // You should not modify any of the given code, the return types, or the parameters, you will risk of getting compilation error. // You are not allowed to modify main (). // You can use string library functions. #include <stdio.h> #include <stdlib.h> #include <string.h> #pragma warning(disable : 4996) // for Visual Studio Only #define MAX_SONGS 20 #define MAX_SONG_NAME_LENGTH 40 #define MAX_SINGER_NAME_LENGTH 40 typedef enum { unclassified = 0, Pop, Rock, Reggae, Country, Blues, Balad, } genreType; // enum type struct musicRepository { // struct for song details unsigned int ID; char songName[MAX_SONG_NAME_LENGTH]; char singerName[MAX_SINGER_NAME_LENGTH]; genreType genre; unsigned int year; }; struct musicRepository list[MAX_SONGS]; // declare the list of songs int numSongs = 0; // the number of songs currently stored in the list (initialized to 0) // Given functions void initializeRepository(struct musicRepository repo[], int size); void printRepository(struct musicRepository repo[], int numSongs); void flushSngIn(); // functions that need to be implemented by you int addSong(struct musicRepository repo[], char* songName, char* singerName, char* genre, unsigned int year, int numSongs); struct musicRepository* searchSong(struct musicRepository repo[], char* songName, int numSongs); void printSong(struct musicRepository repo[], int ID); int editSong(struct musicRepository* repo, int numSongs, char* songName); int deleteSongByName(struct musicRepository* repo, char* songName, int numSongs); // This function takes in an array of musicRepository structures and the size of the array as parameters. It then loops through each index of the array and sets the values of id, year, genre, name, and singer to their respective initial values. // NOTE that strcpy is used to copy an empty string to name and singer, rather than setting them equal to "". This is because arrays in C are not assignable, so the strcpy function must be used to copy the empty string into the array. void initializeRepository(struct musicRepository repo[], int size) { for (int i = 0; i < size; i++) { repo[i].ID = 0; repo[i].year = 0; repo[i].genre = 0; strcpy(repo[i].songName, ""); strcpy(repo[i].singerName, ""); } } // This function takes in the musicRepository array and iterates through each element. If the ID of the song is not 0, it prints the details of the song. void printRepository(struct musicRepository repo[], int numSongs) { printf("n--- Song Repository ---n"); for (int i = 0; i < numSongs; i++) { if (repo[i].ID != 0) .

Can someone please help me complete the add_song function .pdf

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Can someone please help me complete the "add_song" function below. Thank you! // Each song has this information: song's id, song's name, singer's name, genre of the song, and its published year. // The struct 'musicRepository' holds information of one song. Genre is enum type. // An array of structs called 'list' is made to hold the list of songs. // You should not modify any of the given code, the return types, or the parameters, you will risk of getting compilation error. // You are not allowed to modify main (). // You can use string library functions. #include <stdio.h> #include <stdlib.h> #include <string.h> #pragma warning(disable : 4996) // for Visual Studio Only #define MAX_SONGS 20 #define MAX_SONG_NAME_LENGTH 40 #define MAX_SINGER_NAME_LENGTH 40 typedef enum { unclassified = 0, Pop, Rock, Reggae, Country, Blues, Balad, } genreType; // enum type struct musicRepository { // struct for song details unsigned int ID; char songName[MAX_SONG_NAME_LENGTH]; char singerName[MAX_SINGER_NAME_LENGTH]; genreType genre; unsigned int year; }; struct musicRepository list[MAX_SONGS]; // declare the list of songs int numSongs = 0; // the number of songs currently stored in the list (initialized to 0) // This function takes in an array of musicRepository structures and the size of the array as parameters. It then loops through each index of the array and sets the values of id, year, genre, name, and singer to their respective initial values. // NOTE that strcpy is used to copy an empty string to name and singer, rather than setting them equal to "". This is because arrays in C are not assignable, so the strcpy function must be used to copy the empty string into the array. void initializeRepository(struct musicRepository repo[], int size) { for (int i = 0; i < size; i++) { repo[i].ID = 0; repo[i].year = 0; repo[i].genre = 0; strcpy(repo[i].songName, ""); strcpy(repo[i].singerName, ""); } } // This function takes in the musicRepository array and iterates through each element. If the ID of the song is not 0, it prints the details of the song. void printRepository(struct musicRepository repo[], int numSongs) { printf("n--- Song Repository ---n"); for (int i = 0; i < numSongs; i++) { if (repo[i].ID != 0) { printf("ID: %dn", repo[i].ID); printf("Name: %sn", repo[i].songName); printf("Singer: %sn", repo[i].singerName); if (repo[i].genre == 0) printf("Genre: unclassifiedn"); else if (repo[i].genre == 1) printf("Genre: Popn"); else if (repo[i].genre == 2) printf("Genre: Rockn"); else if (repo[i].genre == 3) printf("Genre: Reggaen"); else if (repo[i].genre == 4) printf("Genre: Countryn"); else if (repo[i].genre == 5) printf("Genre: Bluesn"); else if (repo[i].genre == 6) printf("Genre: Baladn"); printf("Year: %dn", repo[i].year); printf("n"); } } } // Problem 2 // struct to hold information about a song struct Song { int id; char name[MAX_SONG_NAME_LENGTH]; char singer[MAX_SINGER_NAME_LENGTH]; genreType genre; int year; struct Song* next; }; // Function declarati.

can someone please assist me with analysis of this case atud.pdf

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can someone please assist me with analysis of this case atudy VAKRANGEE: ANATOMY OF STOCK VALUATION 1 Poga Gupti and Zahid Jamar wrote this case solby to provide matorial for chas discussion. The authors do not intond to iflustrate either oflective or innflloctive handing of a managonial sihution. The authors may have disguised certain names and other idantifying information to protect confidentilith. This publication may not be transmitted, pholocopied, digitinod, or othorwise reproduced in any form or by any moans without the pormissian of the copynight holder. Reproduction of this material is not covered under autherization by any reproduction rights organization. To arder copies or nequest pemission to reproduce materials, contact Ney Pubbishing. Avey Business School, Westem Cogyright 92020, Ney Business School Foundation Vorsion: 20200703 On April 20, 2018, Priyankar Khandelwal was furious as he watched the stock value from his fund seemingly evaporate right in front of his eyes. Khandelwal, the fund manager at Principal First, had been managing the mid-sized information technology (IT) fund for the previous five years. Khandelwal asked his assistant to put in a sell order to cover his long position 2 in Vakrangee Limited (Vakrangee) at a substantial loss. He had bought the stock in the beginning of October 2017. The stock hit a high in Jamuary 2018 but had subsequently been sliding (see Exhibit 1). In his fund, Khandelwal had allocated a substantial amount to Vakrangee in the initial investment. Based on the current market price of the stock, there was a net loss of 169 million 3 and a loss of 592 million unrealized from the top for the fund. 4 This loss caused the net asset value of the fund to fall by 35 per cent year to date, because Khandelwal had not hedged his position. Khandelwal's clients were irate, and more than 25 per cent of his firm's investors had withdrawn their money from the fund. Principal First had also reprimanded him and put him on notice. Khandelwal wondered where he went wrong in his analysis of Vakrangee. He had done the valuation exercise himself, checked and cross-checked his assumptions, looked at industry and credit reports, and had found it to be a good stock with good future prospects. What had he missed? What could he have done better? PRINCIPAL FIRST Principal First was a Mumbai-based boutique investment management and investment advisory firm. The investment objective of the firm was to deliver notable risk-adjusted retums consistently while ensuring capital preservation. The firm was founded in 2005 and had been an carly investor in the Indian alternative 'This case was awarded an honourable mention in the the ISB-lvey Global Case Compettion 2018. The prize was sponsored by ISB. 2 A long position was the buying of a stock, commodity, or currency with the expectation that it (would] rise in value; "Long Position (Long)," Investopedia, March 20, 2020, accessed April 6, 2010, www. investopedia.com/terms/Vi.

can someone help me with this class ENVS 200040 Pollution.pdf

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can someone help me with this class ENVS 200-040 Pollution is the introduction of contaminants into the natural environment that can cause adverse effect to the environment and human health. Pollution can take the form of chemical, biological, physical or radiological. Pollutants, the components of pollution, can be either manmade (Anthropological) or naturally occurring contaminants (In nature). Pollution is often classed as point source (know where it is coming from) or nonpoint source (can't identify the exact location) pollution. What are some of the causes/sources of pollution? Examine some of the effects of pollution to humans. How do the other 2Ps (Population and Poverty) contribute to or influence pollution? What would you consider as some solutions to the pollution problem?.

Can someone help me with these questions 1 Main structures.pdf

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Can someone help with these functions doAddTweet doEditTwe.pdf

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Can someone help with these functions : doAddTweet doEditTweet Expected Output: // Program to implement a very simplified list of tweets // from a single simulated Twitter account // Tweets can be added, deleted, and liked #include <iostream> using namespace std; const int MSGSIZE = 100; // Maximum size for a tweet message const int CAPACITY = 10; // Maximum number of tweets // Structure used to define a tweet entry struct Tweet { int id; char msg[MSGSIZE]; int likes; }; void displayTimeline(const Tweet timeline[], int usedSize, int selected); void doEditTweet(Tweet timeline[], int usedSize, int selected); void doLikeTweet(Tweet timeline[], int usedSize, int selected); void doDeleteTweet(Tweet timeline[], int& usedSize, int& selected); /* * If there is room in the timeline for new tweets, then this gets * a new tweet from the user and adds it to the timeline. * timeline = timeline in which the tweet is to be added * usedSize = number of tweets in the timeline * If tweet was able to be added, returns the position number in the * timeline of where the item was added, and usedSize will be * updated to reflect the number of tweets now in the timeline. * If tweet was not able to be added, returns -1, and usedSize * remains unchanged. */ int doAddTweet(Tweet timeline[], int& usedSize); int addTweet(Tweet timeline[], int& usedSize, const char message[]); int getNextId(Tweet timeline[], int usedSize); int selectTweet(const Tweet timeline[], int usedSize); int main() { Tweet timeline[CAPACITY]; // Twitter timeline int choice; // User's menu choice int usedSize = 0; // Num of tweets in the timeline int selected = -1; // Currently selected tweet int tmp; // Temporary variable // Add some starter entries for testing purposes selected = addTweet(timeline, usedSize, "Where do they get the seeds to plant seedless watermelons?"); selected = addTweet(timeline, usedSize, "Waffles are just pancakes with convenient boxes to hold your syrup."); selected = addTweet(timeline, usedSize, "Last night I even struck up a conversation with a spider. Turns out he's a web designer."); do { cout << "1. Display Timelinen"; cout << "2. Select Tweetn"; cout << "3. Add New Tweetn"; cout << "4. Edit Selected Tweetn"; cout << "5. Like Selected Tweetn"; cout << "6. Delete Tweetn"; cout << "7. Exitn"; cout << endl; cout << "Select: "; // Get the numeric entry from the menu cin >> choice; while (cin.fail()) { cin.clear(); cin.ignore(numeric_limits<streamsize>::max(), 'n'); cout << "Select: "; cin >> choice; } cin.ignore(); switch (choice) { case 1: displayTimeline(timeline, usedSize, selected); break; case 2: tmp = selectTweet(timeline, usedSize); if (tmp > -1) selected = tmp; break; case 3: tmp = doAddTweet(timeline, usedSize); if (tmp > -1) selected = tmp; break; case 4: doEditTweet(timeline, usedSize, selected); break; case 5: doLikeTweet(timeline, usedSize, selected); break; case 6: doDeleteTweet(timeline, usedSize, selected); break; } } while (choice != 7); return 0; } int doAd.

Can someone derive the Rossby wave dispersion relation with .pdf

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Calculate EPS of Solid Ltd and Sound Ltd assuming a 2x1 .pdf

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can do this in java please thanks in advance The code that y.pdf

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can do this in java please thanks in advance The code that you will write i would like it to be similar to snippets shown below for me to better understand the codes i have been given to fix: 1) public abstract class BasePerson { protected String name; private boolean publish; private int age; private int id; public BasePerson(String name,int age, boolean pub) { this.name =name; this.age=age; publish = pub; } public int getAge() { return age; } public abstract String getName(); protected void setId(int id) { this.id = id; } public int getId() { return id; } public boolean getPublish() { return publish; } } 2) public class Person extends BasePerson implements Comparable<Person> { private static int nextId=0; public Person(String name, int age, boolean willPublish) { super(name, age, willPublish); super.setId(nextId); nextId++; } public String getName() { return name; } public static String getPHeader() { String returnval = "IDtNametAgetWillPublish"; returnval+="n---------------------------------"; return returnval; } public String toString() { return(getId()+"t"+getName()+"t"+getAge()+"t"+getPublish()); } public static void resetId() { nextId=0; } public int compareTo(Person other) { return other.getId() - this.getId(); } 3) import java.util.ArrayList; import java.util.Scanner; import java.io.File; import java.io.IOException; public class VaccineBatch { private int size; private int balance=0; private String name; private int preference; private ArrayList<String> contras; public VaccineBatch( String name,int size, int preference, String contraIndicators) { this.size = size; this.balance = size; this.preference = preference; this.name = name; Scanner stringScan = new Scanner(contraIndicators); contras = new ArrayList<String>(); stringScan.useDelimiter(","); while (stringScan.hasNext()) contras.add(stringScan.next()); } public int getSize() { return size; } public int getBalance() { return balance; } public int getPreference() { return preference; } public String getName() { return name; } public String getContras() { String returnval=""; for (int i=0; i<contras.size();i++) { returnval+=contras.get(i); if (i<contras.size()-1) returnval+=","; } return returnval; } public static String getVBHeader() { String returnval = "NametSizetBalancetPreferencetContraIndicators"; returnval+="n---------------------------------"; return returnval; } public boolean contraImpact(ArrayList<String> comorbs) { boolean found = false; int i =0; while((!found)&&(i<contras.size())) { int j=0; while ((!found)&&(j<comorbs.size())) { if (contras.get(i).equals(comorbs.get(j))) found=true; else j++; } i++; } return found; } //public int compareTo(VaccineBatch other) //{ // return other.preference-this.preference ; //} public void reduceBalance() { balance--; } } 4) import java.util.ArrayList; public class ApprovedPerson extends BasePerson { ArrayList<String> comorbidities; public ApprovedPerson(int age, String name, boolean publish, int id) { super( name, age,publish); super.

can anyone help with these questions Plagues and People by .pdf

akshpatil4

can anyone help with these questions? Plagues and People by William McNeill: Chapters 3 & 4 Chapter III Confluence of the Civilized Disease-Pools of Eurasia: 500 B.C. to A.D 1200 What main events in civilization history are described in this chapter? How do those correlate with pathogens/infectious diseases? Chapter IV The Impact of the Mongol Empire on Shifting Disease Balances (1200-1500) Why did the author start reducing the time frame intervals in this chapter? What cultural events shape the outcome of disease in this chapter?.

can assume that any sufficient statistic found is also a com.pdf

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Can anyone help me with 2.1 , 2.3 ,2.5, 2.7 In C programming 2.1 Elephant *new_elephant(const char name[], enum type which_type, unsigned int id, unsigned short weight, float trunk_length) Project #5 discussed some approaches for writing structure functions in C. Another option not mentioned then is for a function to return a pointer to a structure that the function has itself dynamically allocated. Using this approach a function can return a pointer to an initialized structure without requiring the caller to declare a structure or to allocate memory for : structure. It is common for functions to dynamically allocate a structure and return a pointer to it after suitably initializing its fields. This function will use this approach. The function should just return NULL without doing anything else if its array parameter is NULL. Otherwise it should return a pointer to a dynamically-allocated Elephant structure that has the parameters' values stored in its fields. The name field of the newly created Elephant structure has no fixed or maximum length, so this function now must allocatea string of exactly the right size to store the name parameter (however long it may be), copy the value of the name parameter to the allocated string, and make the name field of the allocated structure point to it. To emphasize: the new elephant's name field must point to new memory that this function allocates, not just point to the parameter name that was passed in. In other words, this function should not just be doing pointer aliasing. Use string library functions for all manipulations of the elephant's name, not loops (or recursion), or you will lose considerable credit. 2.2 unsigned short get_type(const Elephant * const el_ptr, enum type *const type_ptr) This function should "return" to the caller the type of its parameter elephant, but it should also return 0 if either parameter is NULL. However, since the first constant in an enum has the numeric value 0 , if the function only returned a value, the caller would not be able to distinguish between it returning 0 to indicate that either parameter was NULL, or it returning the enum value AFRICAN. What the function should do instead is to return 0 or 1 depending upon its parameters' validity, and, if the parameters are valid, to store the elephant's type into the variable that type ptr points to. So if either parameter is NULL the function should return 0 without changing anything else, while otherwise it should return 1 after storing its parameter elephant's type into the variable that its second parameter points to. 2.3 const char *get_name(const Elephant *const el_ptr) This function should return NULL if it parameter is NULL, or if its parameter is not NULL but its parameter's name field is NULL. Otherwise it should return its parameter elephant's name, but it should not just return a pointer to the name field of the Elephant structure itself. Instead, it should allocate enough memory to store the name, copy th.

Camp toenteble by inserting an up Parrow or a down arrow in.pdf

akshpatil4

Campus Solution is an education management consulting compan.pdf

akshpatil4

Campus Solution is an education management consulting company located in Austin Texas. Dr. Judy Marconi (retired President of a local college) and her friend Mr. Thomas Irwin formed the company in 1990. The company specializes in providing housing campus management solutions for small, medium, and large colleges and universities. The system can be added to any existing student management system and configured according to the processes and policies of the college and/or university. Vision of the company: Provide a customizable intuitive campus housing management software solution for delightful customer experiences. Mission of the company: To build a robust platform-independent secure end-to-end software product for managers and students to save them time and provide the best living experiences while in college. Most of the colleges and universities provides safe living spaces for their students in dormitories/dorms in an around campus. Managing students and providing a variety of services require proper processes and record keeping of all the students. There are large number of students (freshman to senior) living in, leaving, or changing dormitory every year which requires proper management. It creates a lot of confusion and inconvenience for the dormitory management personnel to deal with. The workload is large, and the processing time is long and requires a lot of human and material resources. There should be a proper process of reviewing applications, processing them and approving student requests. There is a process of proper matching of students, sometimes according to the student choices, but it is not always possible. Students pay their dorm fees in various ways. Some students pay them monthly, but some pay them annually. In addition, there are request for dormitory equipment repairs and other student accommodation requests. Your team is tasked with creating a proper dormitory management system to handle all the tasks. Due to the limiting time and resources availability, your job would be identifying the possible components, and built some part of the software platform. Follow the SDLC life cycle process and complete the process. Your submission would be in two different phases. I have chose Move in/ Move out for my component and on a web-based platform. Deliverables phase 1: Group members Scope (identify the problem and focus on one chosen component) Project Schedule Workflow diagrams /Activity diagrams Event table Couple of fully developed description of events from event table.

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