assume that the distribution of all the tempeture readings is standard normal distribution with the mean reading of 0 dregree celsious and the standard deviation of 1.00 degree celsious. A thermometer is randomly selected and tested what is the temperature reading corresponding to the 40th percentile Solution 40th percentile ==> P(x>0.4) ==>P(z>0.23) (z = xbar - mu /sd) ==> p = 0.641.