The document presents a question regarding an assembly language instruction. It explains that after executing the instruction involving the register $t0, which has the value 12, the register $s0 will equal the value stored at memory address 16. The computation is detailed as $s0 = value in address (4 + $t0) = value in address 16.

1. Assembly Language Question: Consider the following instruction: 1w $s0, 4 (St0) Suppose the
register $t0 contains the value 12 before the above instruction is executed. After the above
instruction has been executed, the value of the register $s0 will be equal to the value stored in
which memory address (in decimal)?
Solution
The value of the register $s0 will be equal to the value stored in memory address 16 .
Explanation :
$t0 contains 12 value.
lw $s0,4($t0) => $s0 = value in address (4+ $t0) => $s0 = value in address (4+12) =>$s0 =
value in memory address 16