2𝑥2 + 7𝑥 + 3
𝑎 = 2 𝑏 = 7 𝑐 = 3
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−(7) ± (7)2−4(2)(3)
2(2)
𝑥 =
−7 ± 49 − 24
4
𝑥 =
−7 ± 5
4
𝑥1 =
−7 + 5
4
𝑥2 =
−7 − 5
4
𝑥1 =
−2
4
𝑥2 =
−12
4
𝑥1 = −
1
2
𝑥2 = −3
5𝑥2 − 7𝑥 − 6
𝑎 = 5 𝑏 = −7 𝑐 = −6
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−(−7) ± (−7)2−4(5)(−6)
2(5)
𝑥 =
7 ± 49 + 120
10
𝑥 =
7 ± 13
10
𝑥1 =
7 + 13
10
𝑥2 =
7 − 13
10
𝑥1 =
20
10
𝑥2 =
−6
10
𝑥1 = 2
𝑥2 = −
3
5
2𝑥2 + 7𝑥 + 3
𝑎 = 𝑏 = 𝑐 =
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−() ± ()2−4()()
2()
𝑥 =
− ± −
𝑥 =
− ±
4
𝑥1 =
− +
4
𝑥2 =
− −
4
𝑥1 =
−
𝑥2 =
−
𝑥1 = −
𝑥2 = −
5𝑥2 − 7𝑥 − 6
𝑎 = 𝑏 = 𝑐 =
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−() ± ()2−4(5)()
2()
𝑥 =
± +
10
𝑥 =
±
10
𝑥1 =
+
10
𝑥2 =
−
10
𝑥1 =
10
𝑥2 =
−
10
𝑥1 =
𝑥2 = −
2𝑥2 + 5𝑥 − 12
𝑎 = 𝑏 = 𝑐 =
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−() ± ()2−4()()
2()
𝑥 =
− ± −
𝑥 =
− ±
𝑥1 =
+
𝑥2 =
+
𝑥1 =
𝑥2 =
𝑥1 =
𝑥2 =
𝑥2 − 𝑥 − 6
𝑎 = 𝑏 = 𝑐 =
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−() ± ()2−4()()
2()
𝑥 =
− ± −
𝑥 =
− ±
𝑥1 =
+
𝑥2 =
+
𝑥1 =
𝑥2 =
𝑥1 =
𝑥2 =
𝑥2 + 5𝑥 − 15
𝑎 = 𝑏 = 𝑐 =
𝑥 =
−𝑏 ± 𝑏2 − 4𝑎𝑐
2𝑎
𝑥 =
−() ± ()2−4()()
2()
𝑥 =
− ± −
𝑥 =
− ±
𝑥1 =
+
𝑥2 =
+
𝑥1 =
𝑥2 =
𝑥1 =
𝑥2 =

aplicacion de la formula general matematica.pptx

  • 1.
    2𝑥2 + 7𝑥+ 3 𝑎 = 2 𝑏 = 7 𝑐 = 3 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −(7) ± (7)2−4(2)(3) 2(2) 𝑥 = −7 ± 49 − 24 4 𝑥 = −7 ± 5 4 𝑥1 = −7 + 5 4 𝑥2 = −7 − 5 4 𝑥1 = −2 4 𝑥2 = −12 4 𝑥1 = − 1 2 𝑥2 = −3
  • 2.
    5𝑥2 − 7𝑥− 6 𝑎 = 5 𝑏 = −7 𝑐 = −6 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −(−7) ± (−7)2−4(5)(−6) 2(5) 𝑥 = 7 ± 49 + 120 10 𝑥 = 7 ± 13 10 𝑥1 = 7 + 13 10 𝑥2 = 7 − 13 10 𝑥1 = 20 10 𝑥2 = −6 10 𝑥1 = 2 𝑥2 = − 3 5
  • 3.
    2𝑥2 + 7𝑥+ 3 𝑎 = 𝑏 = 𝑐 = 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −() ± ()2−4()() 2() 𝑥 = − ± − 𝑥 = − ± 4 𝑥1 = − + 4 𝑥2 = − − 4 𝑥1 = − 𝑥2 = − 𝑥1 = − 𝑥2 = −
  • 4.
    5𝑥2 − 7𝑥− 6 𝑎 = 𝑏 = 𝑐 = 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −() ± ()2−4(5)() 2() 𝑥 = ± + 10 𝑥 = ± 10 𝑥1 = + 10 𝑥2 = − 10 𝑥1 = 10 𝑥2 = − 10 𝑥1 = 𝑥2 = −
  • 5.
    2𝑥2 + 5𝑥− 12 𝑎 = 𝑏 = 𝑐 = 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −() ± ()2−4()() 2() 𝑥 = − ± − 𝑥 = − ± 𝑥1 = + 𝑥2 = + 𝑥1 = 𝑥2 = 𝑥1 = 𝑥2 =
  • 6.
    𝑥2 − 𝑥− 6 𝑎 = 𝑏 = 𝑐 = 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −() ± ()2−4()() 2() 𝑥 = − ± − 𝑥 = − ± 𝑥1 = + 𝑥2 = + 𝑥1 = 𝑥2 = 𝑥1 = 𝑥2 =
  • 7.
    𝑥2 + 5𝑥− 15 𝑎 = 𝑏 = 𝑐 = 𝑥 = −𝑏 ± 𝑏2 − 4𝑎𝑐 2𝑎 𝑥 = −() ± ()2−4()() 2() 𝑥 = − ± − 𝑥 = − ± 𝑥1 = + 𝑥2 = + 𝑥1 = 𝑥2 = 𝑥1 = 𝑥2 =