ANSimport java.io.; import java.util.; public class Pseu_.pdf
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ANS: import java.io.*; import java.util.*; public class Pseu_code { cus[] listOfcuss = new cus[1000000]; //size of the array int fre_lo=0; public void add_go(cus tem_jo) //adds to the array { listOfcuss[fre_lo] = tem_jo; //adds to the array fre_lo++; //gives to add the new cus } public void write_tho() { try { FileWriter fw = new FileWriter(\"cuss.txt\"); //the file to write to BufferedWriter bw = new BufferedWriter(fw); for(int i=0;i Solution ANS: import java.io.*; import java.util.*; public class Pseu_code { cus[] listOfcuss = new cus[1000000]; //size of the array int fre_lo=0; public void add_go(cus tem_jo) //adds to the array { listOfcuss[fre_lo] = tem_jo; //adds to the array fre_lo++; //gives to add the new cus } public void write_tho() { try { FileWriter fw = new FileWriter(\"cuss.txt\"); //the file to write to BufferedWriter bw = new BufferedWriter(fw); for(int i=0;i.
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![ANS:
import java.io.*;
import java.util.*;
public class Pseu_code
{
cus[] listOfcuss = new cus[1000000]; //size of the array
int fre_lo=0;
public void add_go(cus tem_jo) //adds to the array
{
listOfcuss[fre_lo] = tem_jo; //adds to the array
fre_lo++; //gives to add the new cus
}
public void write_tho()
{
try
{
FileWriter fw = new FileWriter("cuss.txt"); //the file to write to
BufferedWriter bw = new BufferedWriter(fw);
for(int i=0;i
Solution
ANS:
import java.io.*;
import java.util.*;
public class Pseu_code
{
cus[] listOfcuss = new cus[1000000]; //size of the array
int fre_lo=0;
public void add_go(cus tem_jo) //adds to the array](https://image.slidesharecdn.com/ansimportjava-230413054409-d48cca86/85/ANSimport-java-io-import-java-util-public-class-Pseu_-pdf-1-320.jpg)
![{
listOfcuss[fre_lo] = tem_jo; //adds to the array
fre_lo++; //gives to add the new cus
}
public void write_tho()
{
try
{
FileWriter fw = new FileWriter("cuss.txt"); //the file to write to
BufferedWriter bw = new BufferedWriter(fw);
for(int i=0;i](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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5.2 Потоки байт
5.3 Потоки символов
5.4 Продвинутые возможности
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5.2 Потоки байт
5.3 Потоки символов
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alcohols also do not give tollens test.... only a.pdf
alcohols also do not give tollens test.... only aldehydes give tollens test
Solution
alcohols also do not give tollens test.... only aldehydes give tollens test.
Acid Buffer - Weak acid + plus its salt Basic B.pdf
Acid Buffer - Weak acid + plus it\'s salt Basic Buffer - Weak base + plus its salt
hence, A. Acidic Buffer B. Not a Buffer C. Not a Buffer D. Not a Buffer
Solution
Acid Buffer - Weak acid + plus it\'s salt Basic Buffer - Weak base + plus its salt
hence, A. Acidic Buffer B. Not a Buffer C. Not a Buffer D. Not a Buffer.
Total vapor pressure of mixture = P(benzene) + P(.pdf
Total vapor pressure of mixture = P(benzene) + P(toluene) Ptotal =
X(benzene)(Pbenzene pure) + X(toluene)(Ptoluene pure) X = mole fraction Ptotal = (7.97 /(7.97
+ 5.90))380 + (5.90/(7.97 + 5.90)) 130 Ptotal = 0.575(380) + 0.425(130) = 274 torr
Solution
Total vapor pressure of mixture = P(benzene) + P(toluene) Ptotal =
X(benzene)(Pbenzene pure) + X(toluene)(Ptoluene pure) X = mole fraction Ptotal = (7.97 /(7.97
+ 5.90))380 + (5.90/(7.97 + 5.90)) 130 Ptotal = 0.575(380) + 0.425(130) = 274 torr.
Not necessarily. It could very well mean that you.pdf
Not necessarily. It could very well mean that you have not used aneluent that is
sufficiently polar to displace any cpds. I would trya more polar eluent to see if separation occurs.
Hope this helps, Steve
Solution
Not necessarily. It could very well mean that you have not used aneluent that is
sufficiently polar to displace any cpds. I would trya more polar eluent to see if separation occurs.
Hope this helps, Steve.
For Li, B, and F they only formed single bond bet.pdf
For Li, B, and F they only formed single bond between each other. For oxygen, O,
it formed double bond. For N, it formed triple bond between the molecule. So, N2 got the largest
bond dissociation energy, becauseof having most bond between molecule. Bond order of 2: O2
Solution
For Li, B, and F they only formed single bond between each other. For oxygen, O,
it formed double bond. For N, it formed triple bond between the molecule. So, N2 got the largest
bond dissociation energy, becauseof having most bond between molecule. Bond order of 2: O2.
Enzyme Induction- the synthesis of enzymes in res.pdf
Enzyme Induction- the synthesis of enzymes in response to changing metabolic
needs...
Solution
Enzyme Induction- the synthesis of enzymes in response to changing metabolic
needs....
Buffer Capacity is the ranges of volume of acid o.pdf
Buffer Capacity is the ranges of volume of acid or base which when added to the
buffer can resit the change in pH. The three factor are (1)pKa or Pkb of the buffering
component (2) concentration of the component and (3)the self-ionization of water which is
independent of the presence or absence of buffering agents.
Solution
Buffer Capacity is the ranges of volume of acid or base which when added to the
buffer can resit the change in pH. The three factor are (1)pKa or Pkb of the buffering
component (2) concentration of the component and (3)the self-ionization of water which is
independent of the presence or absence of buffering agents..
a. CH4 has no free valence electrons so it can no.pdf
a. CH4 has no free valence electrons so it can not act as a ligand d. comlex ions are
formed MAINLY from transition metals Had this exact question.
Solution
a. CH4 has no free valence electrons so it can not act as a ligand d. comlex ions are
formed MAINLY from transition metals Had this exact question..
We are living in a world where cyber security is a top priority for .pdf
We are living in a world where cyber security is a top priority for all governments and
businesses. In fact, last week the United States announced cyber security as its biggest. James
Clapper, the Director of National Intelligence, says that “the world is applying digital
technologies faster than our ability to understand the security implications and mitigate potential
risks.” Hackers are able to get ahead of governments because they are applying technology faster
than many can understand it.
(http://ca.reuters.com/article/technologyNews/idCABRE92B0LS20130312)
These attackers are persistent, and it is important to be aware of the methods used by hackers as
it is an important step towards defending sensitive company data.
When a hacker strikes, the cost to a company could potentially be millions of dollars. Not only
will it affect the bottom line, but hard-earned reputations can be compromised or destroyed.
It is important to recognize the differences between the different kinds of cyber threats: external
and internal. An external, or outsider threat is much trickier to pinpoint. It can be “from someone
that does not have authorized access to the data and has no formal relationship to the company.”
They could be from someone who is actively targeting the company, or accidentally from
someone who found a lost mobile device.
Internal threats are likely to come from an authorized individual that has easy access to sensitive
corporate data as part of their day-to-day duties. This could be anyone working within the
company or acting as a third party representative. The Global Knowledge Blog states that
insiders have a much greater advantage because they have means, motive, and opportunity,
whereas outsiders most often only have a motive.
(http://globalknowledgeblog.com/technology/security/hacking-cybercrime/insider-vs-outsider-
threats/)
When focusing on internal threats, we have made a digital security check list:
Implement an Intrusion Detection System (IDS). These systems act like security cameras
watching a network. They react to suspicious activity by logging off suspect users, or in some
cases, they might reprogram firewalls to snag a possible intrusion.
Implement a log management platform that will centralize all the logs and correlate to find
threats and alert on them.
Stay proactive with Identity Management systems that will monitor high risk or suspicious user
activity by detecting and correcting situations that are out of compliance or present a security
risk.
Be aware of who has keys and access codes to vulnerable information. Monitor the activity
when these spaces are accessed, authorized, or not.
Create safety policies for when employees with these security privileges leave the company or
are terminated. This will reduce the risk of theft due to careless behaviour, or break-ins from
disgruntled employees.
Get employees involved with the security procedures of the company. As a team, you can work
to strengthen your digital security pr.
highest bond energy molecule is CO because its bond order is = 3.pdf
highest bond energy molecule is CO
because its bond order is = 3
so it needs more energy to break
Solution
highest bond energy molecule is CO
because its bond order is = 3
so it needs more energy to break.
Urine is concentrated byc) facilitated diffusion in the collecting d.pdf
Urine is concentrated byc) facilitated diffusion in the collecting ducts.
The collecting duct concentrates it by water reabsorption through facilitated diffusion when
ADH is present.The permeability of the collecting ducts for water leads to a concentration of the
urine up to the fivefold osmolarity of the plasma.The permeability of the collecting ducts is
regulated with ADH.
Solution
Urine is concentrated byc) facilitated diffusion in the collecting ducts.
The collecting duct concentrates it by water reabsorption through facilitated diffusion when
ADH is present.The permeability of the collecting ducts for water leads to a concentration of the
urine up to the fivefold osmolarity of the plasma.The permeability of the collecting ducts is
regulated with ADH..
The two fund theorem is the establishment of two efficient Funds.pdf
The \"two fund theorem\" is the establishment of two efficient Funds or Portfolios with the
purpose that any efficient fund or portfolio can copied or duplicated (in terms of mean and any
variance overall combined) to the other fund or portfolio so that the profit or benefits could be
doubled for the investors.
The importance of creating such \"Theorem\" is that the investors invest in the portfolio in
combination in both the portfolios or funds to have gain. The both the funds in combination
provides the complete portfolio services to the investors.
Solution
The \"two fund theorem\" is the establishment of two efficient Funds or Portfolios with the
purpose that any efficient fund or portfolio can copied or duplicated (in terms of mean and any
variance overall combined) to the other fund or portfolio so that the profit or benefits could be
doubled for the investors.
The importance of creating such \"Theorem\" is that the investors invest in the portfolio in
combination in both the portfolios or funds to have gain. The both the funds in combination
provides the complete portfolio services to the investors..
the nuclide is147N which is nitrogenSolutionthe nuclide .pdf
the nuclide is
147N which is nitrogen
Solution
the nuclide is
147N which is nitrogen.
The Programmer has created multiple entry point which can be used to.pdf
The Programmer has created multiple entry point which can be used to gain unauthorized access
Which makes it a security flaw. So he has created Back door in the program.
Solution
The Programmer has created multiple entry point which can be used to gain unauthorized access
Which makes it a security flaw. So he has created Back door in the program..
The halide is iodine as it gives pale yellow precipitate with AgNO3 .pdf
The halide is iodine as it gives pale yellow precipitate with AgNO3 ..The precipitate is AgI.This
makes complex WITH CONC NH3 i.e. [Ag(NH3)2]+ WHICH GIVES precipitate
Another test to confirm identity of iodide is addition of conc H2S04..which gives fumes of HI
and purple iodine vapours..
Solution
The halide is iodine as it gives pale yellow precipitate with AgNO3 ..The precipitate is AgI.This
makes complex WITH CONC NH3 i.e. [Ag(NH3)2]+ WHICH GIVES precipitate
Another test to confirm identity of iodide is addition of conc H2S04..which gives fumes of HI
and purple iodine vapours...
The answer isd. The pi electrons are distributed over the entire .pdf
The answer is:
d. The pi electrons are distributed over the entire molecule.
In benzene, the pi electrons are delocalized and distributed over the entire molecule due to
resonance effects.
Solution
The answer is:
d. The pi electrons are distributed over the entire molecule.
In benzene, the pi electrons are delocalized and distributed over the entire molecule due to
resonance effects..
Modified Code Game.javaimport java.util.;public class Game.pdf
Modified Code: Game.java:
import java.util.*;
public class Game
{
private Parser parser;
private Room currentRoom;
private Stack route;
/**
* Create the game and initialize its internal map.
*/
public Game()
{
createRooms();
parser = new Parser();
route=new Stack();
}
/**
* Create all the rooms and link their exits together.
*/
private void createRooms()
{
Room outside, theatre, pub, lab, office, basement;
// create the rooms
outside = new Room(\"outside the main entrance of the university\");
theatre = new Room(\"in a lecture theatre\");
pub = new Room(\"in the campus pub\");
lab = new Room(\"in a computing lab\");
office = new Room(\"in the computing admin office\");
basement = new Room(\"in the basement\");
// initialise room exits
outside.setExit(\"east\", theatre);
outside.setExit(\"south\", lab);
outside.setExit(\"west\", pub);
theatre.setExit(\"west\", outside);
pub.setExit(\"east\", outside);
lab.setExit(\"north\", outside);
lab.setExit(\"east\", office);
lab.setExit(\"down\", basement);
basement.setExit(\"up\", lab);
office.setExit(\"west\", lab);
currentRoom = outside; // start game outside
}
/**
* Main play routine. Loops until end of play.
*/
public void play()
{
printWelcome();
// Enter the main command loop. Here we repeatedly read commands and
// execute them until the game is over.
boolean finished = false;
while (! finished)
{
Command command = parser.getCommand();
finished = processCommand(command);
}
System.out.println(\"Thank you for playing. Good bye.\");
}
/**
* Print out the opening message for the player.
*/
private void printWelcome()
{
System.out.println();
System.out.println(\"Welcome to the World of Zuul!\");
System.out.println(\"World of Zuul is a new, incredibly boring adventure game.\");
System.out.println(\"Type \'help\' if you need help.\");
System.out.println();
System.out.println(currentRoom.getLongDescription());
}
/**
* Given a command, process (that is: execute) the command.
* If this command ends the game, true is returned, otherwise false is
* returned.
*/
private boolean processCommand(Command command)
{
boolean wantToQuit = false;
if(command.isUnknown())
{
System.out.println(\"I don\'t know what you mean...\");
return false;
}
String commandWord = command.getCommandWord();
if (commandWord.equals(\"help\")){
printHelp();
}
else if (commandWord.equals(\"go\")) {
goRoom(command);
}
else if (commandWord.equals(\"back\")) {
goBack();
}
else if (commandWord.equals(\"quit\")) {
wantToQuit = quit(command);
}
return wantToQuit;
}
// implementations of user commands:
/**
* Print out some help information.
* Here we print some stupid, cryptic message and a list of the
* command words.
*/
private void printHelp()
{
System.out.println(\"You are lost. You are alone. You wander\");
System.out.println(\"around at the university.\");
System.out.println();
System.out.println(\"Your command words are:\");
parser.showCommands();
}
/**
* Try to go to one direction. If there is an exit, enter the new
* room, otherwise prin.
678020731-Sumas-y-Restas-Para-Colorear.pdf
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alcohols also do not give tollens test.... only a.pdf
alcohols also do not give tollens test.... only aldehydes give tollens test
Solution
alcohols also do not give tollens test.... only aldehydes give tollens test.
Acid Buffer - Weak acid + plus its salt Basic B.pdf
Acid Buffer - Weak acid + plus it\'s salt Basic Buffer - Weak base + plus its salt
hence, A. Acidic Buffer B. Not a Buffer C. Not a Buffer D. Not a Buffer
Solution
Acid Buffer - Weak acid + plus it\'s salt Basic Buffer - Weak base + plus its salt
hence, A. Acidic Buffer B. Not a Buffer C. Not a Buffer D. Not a Buffer.
Total vapor pressure of mixture = P(benzene) + P(.pdf
Total vapor pressure of mixture = P(benzene) + P(toluene) Ptotal =
X(benzene)(Pbenzene pure) + X(toluene)(Ptoluene pure) X = mole fraction Ptotal = (7.97 /(7.97
+ 5.90))380 + (5.90/(7.97 + 5.90)) 130 Ptotal = 0.575(380) + 0.425(130) = 274 torr
Solution
Total vapor pressure of mixture = P(benzene) + P(toluene) Ptotal =
X(benzene)(Pbenzene pure) + X(toluene)(Ptoluene pure) X = mole fraction Ptotal = (7.97 /(7.97
+ 5.90))380 + (5.90/(7.97 + 5.90)) 130 Ptotal = 0.575(380) + 0.425(130) = 274 torr.
Not necessarily. It could very well mean that you.pdf
Not necessarily. It could very well mean that you have not used aneluent that is
sufficiently polar to displace any cpds. I would trya more polar eluent to see if separation occurs.
Hope this helps, Steve
Solution
Not necessarily. It could very well mean that you have not used aneluent that is
sufficiently polar to displace any cpds. I would trya more polar eluent to see if separation occurs.
Hope this helps, Steve.
For Li, B, and F they only formed single bond bet.pdf
For Li, B, and F they only formed single bond between each other. For oxygen, O,
it formed double bond. For N, it formed triple bond between the molecule. So, N2 got the largest
bond dissociation energy, becauseof having most bond between molecule. Bond order of 2: O2
Solution
For Li, B, and F they only formed single bond between each other. For oxygen, O,
it formed double bond. For N, it formed triple bond between the molecule. So, N2 got the largest
bond dissociation energy, becauseof having most bond between molecule. Bond order of 2: O2.
Enzyme Induction- the synthesis of enzymes in res.pdf
Enzyme Induction- the synthesis of enzymes in response to changing metabolic
needs...
Solution
Enzyme Induction- the synthesis of enzymes in response to changing metabolic
needs....
Buffer Capacity is the ranges of volume of acid o.pdf
Buffer Capacity is the ranges of volume of acid or base which when added to the
buffer can resit the change in pH. The three factor are (1)pKa or Pkb of the buffering
component (2) concentration of the component and (3)the self-ionization of water which is
independent of the presence or absence of buffering agents.
Solution
Buffer Capacity is the ranges of volume of acid or base which when added to the
buffer can resit the change in pH. The three factor are (1)pKa or Pkb of the buffering
component (2) concentration of the component and (3)the self-ionization of water which is
independent of the presence or absence of buffering agents..
a. CH4 has no free valence electrons so it can no.pdf
a. CH4 has no free valence electrons so it can not act as a ligand d. comlex ions are
formed MAINLY from transition metals Had this exact question.
Solution
a. CH4 has no free valence electrons so it can not act as a ligand d. comlex ions are
formed MAINLY from transition metals Had this exact question..
We are living in a world where cyber security is a top priority for .pdf
We are living in a world where cyber security is a top priority for all governments and
businesses. In fact, last week the United States announced cyber security as its biggest. James
Clapper, the Director of National Intelligence, says that “the world is applying digital
technologies faster than our ability to understand the security implications and mitigate potential
risks.” Hackers are able to get ahead of governments because they are applying technology faster
than many can understand it.
(http://ca.reuters.com/article/technologyNews/idCABRE92B0LS20130312)
These attackers are persistent, and it is important to be aware of the methods used by hackers as
it is an important step towards defending sensitive company data.
When a hacker strikes, the cost to a company could potentially be millions of dollars. Not only
will it affect the bottom line, but hard-earned reputations can be compromised or destroyed.
It is important to recognize the differences between the different kinds of cyber threats: external
and internal. An external, or outsider threat is much trickier to pinpoint. It can be “from someone
that does not have authorized access to the data and has no formal relationship to the company.”
They could be from someone who is actively targeting the company, or accidentally from
someone who found a lost mobile device.
Internal threats are likely to come from an authorized individual that has easy access to sensitive
corporate data as part of their day-to-day duties. This could be anyone working within the
company or acting as a third party representative. The Global Knowledge Blog states that
insiders have a much greater advantage because they have means, motive, and opportunity,
whereas outsiders most often only have a motive.
(http://globalknowledgeblog.com/technology/security/hacking-cybercrime/insider-vs-outsider-
threats/)
When focusing on internal threats, we have made a digital security check list:
Implement an Intrusion Detection System (IDS). These systems act like security cameras
watching a network. They react to suspicious activity by logging off suspect users, or in some
cases, they might reprogram firewalls to snag a possible intrusion.
Implement a log management platform that will centralize all the logs and correlate to find
threats and alert on them.
Stay proactive with Identity Management systems that will monitor high risk or suspicious user
activity by detecting and correcting situations that are out of compliance or present a security
risk.
Be aware of who has keys and access codes to vulnerable information. Monitor the activity
when these spaces are accessed, authorized, or not.
Create safety policies for when employees with these security privileges leave the company or
are terminated. This will reduce the risk of theft due to careless behaviour, or break-ins from
disgruntled employees.
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highest bond energy molecule is CO because its bond order is = 3.pdf
highest bond energy molecule is CO
because its bond order is = 3
so it needs more energy to break
Solution
highest bond energy molecule is CO
because its bond order is = 3
so it needs more energy to break.
Urine is concentrated byc) facilitated diffusion in the collecting d.pdf
Urine is concentrated byc) facilitated diffusion in the collecting ducts.
The collecting duct concentrates it by water reabsorption through facilitated diffusion when
ADH is present.The permeability of the collecting ducts for water leads to a concentration of the
urine up to the fivefold osmolarity of the plasma.The permeability of the collecting ducts is
regulated with ADH.
Solution
Urine is concentrated byc) facilitated diffusion in the collecting ducts.
The collecting duct concentrates it by water reabsorption through facilitated diffusion when
ADH is present.The permeability of the collecting ducts for water leads to a concentration of the
urine up to the fivefold osmolarity of the plasma.The permeability of the collecting ducts is
regulated with ADH..
The two fund theorem is the establishment of two efficient Funds.pdf
The \"two fund theorem\" is the establishment of two efficient Funds or Portfolios with the
purpose that any efficient fund or portfolio can copied or duplicated (in terms of mean and any
variance overall combined) to the other fund or portfolio so that the profit or benefits could be
doubled for the investors.
The importance of creating such \"Theorem\" is that the investors invest in the portfolio in
combination in both the portfolios or funds to have gain. The both the funds in combination
provides the complete portfolio services to the investors.
Solution
The \"two fund theorem\" is the establishment of two efficient Funds or Portfolios with the
purpose that any efficient fund or portfolio can copied or duplicated (in terms of mean and any
variance overall combined) to the other fund or portfolio so that the profit or benefits could be
doubled for the investors.
The importance of creating such \"Theorem\" is that the investors invest in the portfolio in
combination in both the portfolios or funds to have gain. The both the funds in combination
provides the complete portfolio services to the investors..
the nuclide is147N which is nitrogenSolutionthe nuclide .pdf
the nuclide is
147N which is nitrogen
Solution
the nuclide is
147N which is nitrogen.
The Programmer has created multiple entry point which can be used to.pdf
The Programmer has created multiple entry point which can be used to gain unauthorized access
Which makes it a security flaw. So he has created Back door in the program.
Solution
The Programmer has created multiple entry point which can be used to gain unauthorized access
Which makes it a security flaw. So he has created Back door in the program..
The halide is iodine as it gives pale yellow precipitate with AgNO3 .pdf
The halide is iodine as it gives pale yellow precipitate with AgNO3 ..The precipitate is AgI.This
makes complex WITH CONC NH3 i.e. [Ag(NH3)2]+ WHICH GIVES precipitate
Another test to confirm identity of iodide is addition of conc H2S04..which gives fumes of HI
and purple iodine vapours..
Solution
The halide is iodine as it gives pale yellow precipitate with AgNO3 ..The precipitate is AgI.This
makes complex WITH CONC NH3 i.e. [Ag(NH3)2]+ WHICH GIVES precipitate
Another test to confirm identity of iodide is addition of conc H2S04..which gives fumes of HI
and purple iodine vapours...
The answer isd. The pi electrons are distributed over the entire .pdf
The answer is:
d. The pi electrons are distributed over the entire molecule.
In benzene, the pi electrons are delocalized and distributed over the entire molecule due to
resonance effects.
Solution
The answer is:
d. The pi electrons are distributed over the entire molecule.
In benzene, the pi electrons are delocalized and distributed over the entire molecule due to
resonance effects..
Modified Code Game.javaimport java.util.;public class Game.pdf
Modified Code: Game.java:
import java.util.*;
public class Game
{
private Parser parser;
private Room currentRoom;
private Stack route;
/**
* Create the game and initialize its internal map.
*/
public Game()
{
createRooms();
parser = new Parser();
route=new Stack();
}
/**
* Create all the rooms and link their exits together.
*/
private void createRooms()
{
Room outside, theatre, pub, lab, office, basement;
// create the rooms
outside = new Room(\"outside the main entrance of the university\");
theatre = new Room(\"in a lecture theatre\");
pub = new Room(\"in the campus pub\");
lab = new Room(\"in a computing lab\");
office = new Room(\"in the computing admin office\");
basement = new Room(\"in the basement\");
// initialise room exits
outside.setExit(\"east\", theatre);
outside.setExit(\"south\", lab);
outside.setExit(\"west\", pub);
theatre.setExit(\"west\", outside);
pub.setExit(\"east\", outside);
lab.setExit(\"north\", outside);
lab.setExit(\"east\", office);
lab.setExit(\"down\", basement);
basement.setExit(\"up\", lab);
office.setExit(\"west\", lab);
currentRoom = outside; // start game outside
}
/**
* Main play routine. Loops until end of play.
*/
public void play()
{
printWelcome();
// Enter the main command loop. Here we repeatedly read commands and
// execute them until the game is over.
boolean finished = false;
while (! finished)
{
Command command = parser.getCommand();
finished = processCommand(command);
}
System.out.println(\"Thank you for playing. Good bye.\");
}
/**
* Print out the opening message for the player.
*/
private void printWelcome()
{
System.out.println();
System.out.println(\"Welcome to the World of Zuul!\");
System.out.println(\"World of Zuul is a new, incredibly boring adventure game.\");
System.out.println(\"Type \'help\' if you need help.\");
System.out.println();
System.out.println(currentRoom.getLongDescription());
}
/**
* Given a command, process (that is: execute) the command.
* If this command ends the game, true is returned, otherwise false is
* returned.
*/
private boolean processCommand(Command command)
{
boolean wantToQuit = false;
if(command.isUnknown())
{
System.out.println(\"I don\'t know what you mean...\");
return false;
}
String commandWord = command.getCommandWord();
if (commandWord.equals(\"help\")){
printHelp();
}
else if (commandWord.equals(\"go\")) {
goRoom(command);
}
else if (commandWord.equals(\"back\")) {
goBack();
}
else if (commandWord.equals(\"quit\")) {
wantToQuit = quit(command);
}
return wantToQuit;
}
// implementations of user commands:
/**
* Print out some help information.
* Here we print some stupid, cryptic message and a list of the
* command words.
*/
private void printHelp()
{
System.out.println(\"You are lost. You are alone. You wander\");
System.out.println(\"around at the university.\");
System.out.println();
System.out.println(\"Your command words are:\");
parser.showCommands();
}
/**
* Try to go to one direction. If there is an exit, enter the new
* room, otherwise prin.
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- 1. ANS: import java.io.*; import java.util.*; public class Pseu_code { cus[] listOfcuss = new cus[1000000]; //size of the array int fre_lo=0; public void add_go(cus tem_jo) //adds to the array { listOfcuss[fre_lo] = tem_jo; //adds to the array fre_lo++; //gives to add the new cus } public void write_tho() { try { FileWriter fw = new FileWriter("cuss.txt"); //the file to write to BufferedWriter bw = new BufferedWriter(fw); for(int i=0;i Solution ANS: import java.io.*; import java.util.*; public class Pseu_code { cus[] listOfcuss = new cus[1000000]; //size of the array int fre_lo=0; public void add_go(cus tem_jo) //adds to the array
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