According to Union by size, each node x which has the size of the su.pdf
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According to Union by size, each node x which has the size of the subtree rooted at x is stored. In UNION, the tree of the smaller set is made the subtree of the other tree and the size field of the root of the resulting tree is updated. According to path compression heuristics, the parent pointer is reset from x such that it points to the root for the find operation. Let the number of nodes be n and the number of finds be m. The union operations are executed before the find operations, so a tree is constructed before any operation. There are at most O(n) union operations and each union operation takes O (1) time. Thus, the total cost of union is O(n). The cost of a find operation is the increment of the number of new children to the root by 1. Each find operation will take O(m) time. So, the total cost of m find operation is O (m + n). Here, n = 1 + max (number of children of the root) Solution According to Union by size, each node x which has the size of the subtree rooted at x is stored. In UNION, the tree of the smaller set is made the subtree of the other tree and the size field of the root of the resulting tree is updated. According to path compression heuristics, the parent pointer is reset from x such that it points to the root for the find operation. Let the number of nodes be n and the number of finds be m. The union operations are executed before the find operations, so a tree is constructed before any operation. There are at most O(n) union operations and each union operation takes O (1) time. Thus, the total cost of union is O(n). The cost of a find operation is the increment of the number of new children to the root by 1. Each find operation will take O(m) time. So, the total cost of m find operation is O (m + n). Here, n = 1 + max (number of children of the root).
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Above 70 °C, sodium bicarbonate gradually decomposes into sodium car.pdf
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2
Solution
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2.
You need to put your electrons in the first one .pdf
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+.
Solution
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+..
PbSO4 is not generally soluble in water. It will .pdf
PbSO4 is not generally soluble in water. It will form aprecipicate Pb(OH)2 is
generally not soluble in water, athough morethan PbSO4. I hope this helps, Steve
Solution
PbSO4 is not generally soluble in water. It will form aprecipicate Pb(OH)2 is
generally not soluble in water, athough morethan PbSO4. I hope this helps, Steve.
pH is proportional to the cell potential and it i.pdf
pH is proportional to the cell potential and it is indicated by the Nernst equation
According to Nernst equation -if the reaction occurs in preence of acidic media - Ecell = E0(cell)
- 0.0592/n log 1/[H+] [because all other species are at standard conditions] Therefore - Ecell =
0.42 V - (0.0592/n) log 1/[H+] Let n = 1, then - 0 V = 0.42 V - 0.592 pH 0.0592 pH = 0.42
Therefore - pH = 0.42/0.0592 = 6.75
Solution
pH is proportional to the cell potential and it is indicated by the Nernst equation
According to Nernst equation -if the reaction occurs in preence of acidic media - Ecell = E0(cell)
- 0.0592/n log 1/[H+] [because all other species are at standard conditions] Therefore - Ecell =
0.42 V - (0.0592/n) log 1/[H+] Let n = 1, then - 0 V = 0.42 V - 0.592 pH 0.0592 pH = 0.42
Therefore - pH = 0.42/0.0592 = 6.75.
Nitration occurs through electrophilic addition o.pdf
Nitration occurs through electrophilic addition of aromatic rings by breaking one of
its aromatic bonds in order to attack the nitogen. The ring with more electron density will be
more likely to add NO2 groups in its meta position (the only position if another group is already
attached). When electrophillic addition occurs, the benzene ring would have to unfavorably
break its stable aromaticity to attack. However, the phenyl oxygen can donate its electrons to the
benzene ring, thus enriching it with electron density and stabilizing the positive charge. The
carbonyl group does nothing to stabilize the other benzene ring during its electrophilic addition.
In fact, the carbonyl group may as well have the opposite effect: the resonance structure of a
single bonded carbon to its oxygen pulls electrons away from the benzene ring through inductive
effect.
Solution
Nitration occurs through electrophilic addition of aromatic rings by breaking one of
its aromatic bonds in order to attack the nitogen. The ring with more electron density will be
more likely to add NO2 groups in its meta position (the only position if another group is already
attached). When electrophillic addition occurs, the benzene ring would have to unfavorably
break its stable aromaticity to attack. However, the phenyl oxygen can donate its electrons to the
benzene ring, thus enriching it with electron density and stabilizing the positive charge. The
carbonyl group does nothing to stabilize the other benzene ring during its electrophilic addition.
In fact, the carbonyl group may as well have the opposite effect: the resonance structure of a
single bonded carbon to its oxygen pulls electrons away from the benzene ring through inductive
effect..
I Hope some more information required to solve th.pdf
I Hope some more information required to solve the problem once verify the
question
Solution
I Hope some more information required to solve the problem once verify the
question.
Recommended
Above 70 °C, sodium bicarbonate gradually decomposes into sodium car.pdf
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2
Solution
Above 70 °C, sodium bicarbonate gradually decomposes into sodium carbonate, water and
carbon dioxide. The conversion is fast at 200 °C 2 NaHCO3 ? Na2CO3 + H2O + CO2.
You need to put your electrons in the first one .pdf
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+.
Solution
You need to put your electrons in the first one: ClO2 + e- => ClO2- In the second
one, you have done nothing with the hydrogen. H2O2 => O2 + 2H+ + 2e- Now you must
multiply the first one by 2 to get the same number of electrons on both sides: 2ClO2 + 2e- =>
2ClO2- Now add the equations and eliminate the electrons: H2O2 + 2ClO2 => 2ClO2- + O2 +
2H+ This is now balanced. The charges are the same on both sides and the number of atoms of
each element is the same on both sides. The oxidizing agent is the one which gains electrons and
is itself reduced. So, yes, it is the ClO2. The reducing agent is the H2O2. This is itself oxidized
because it loses electrons to form H+..
PbSO4 is not generally soluble in water. It will .pdf
PbSO4 is not generally soluble in water. It will form aprecipicate Pb(OH)2 is
generally not soluble in water, athough morethan PbSO4. I hope this helps, Steve
Solution
PbSO4 is not generally soluble in water. It will form aprecipicate Pb(OH)2 is
generally not soluble in water, athough morethan PbSO4. I hope this helps, Steve.
pH is proportional to the cell potential and it i.pdf
pH is proportional to the cell potential and it is indicated by the Nernst equation
According to Nernst equation -if the reaction occurs in preence of acidic media - Ecell = E0(cell)
- 0.0592/n log 1/[H+] [because all other species are at standard conditions] Therefore - Ecell =
0.42 V - (0.0592/n) log 1/[H+] Let n = 1, then - 0 V = 0.42 V - 0.592 pH 0.0592 pH = 0.42
Therefore - pH = 0.42/0.0592 = 6.75
Solution
pH is proportional to the cell potential and it is indicated by the Nernst equation
According to Nernst equation -if the reaction occurs in preence of acidic media - Ecell = E0(cell)
- 0.0592/n log 1/[H+] [because all other species are at standard conditions] Therefore - Ecell =
0.42 V - (0.0592/n) log 1/[H+] Let n = 1, then - 0 V = 0.42 V - 0.592 pH 0.0592 pH = 0.42
Therefore - pH = 0.42/0.0592 = 6.75.
Nitration occurs through electrophilic addition o.pdf
Nitration occurs through electrophilic addition of aromatic rings by breaking one of
its aromatic bonds in order to attack the nitogen. The ring with more electron density will be
more likely to add NO2 groups in its meta position (the only position if another group is already
attached). When electrophillic addition occurs, the benzene ring would have to unfavorably
break its stable aromaticity to attack. However, the phenyl oxygen can donate its electrons to the
benzene ring, thus enriching it with electron density and stabilizing the positive charge. The
carbonyl group does nothing to stabilize the other benzene ring during its electrophilic addition.
In fact, the carbonyl group may as well have the opposite effect: the resonance structure of a
single bonded carbon to its oxygen pulls electrons away from the benzene ring through inductive
effect.
Solution
Nitration occurs through electrophilic addition of aromatic rings by breaking one of
its aromatic bonds in order to attack the nitogen. The ring with more electron density will be
more likely to add NO2 groups in its meta position (the only position if another group is already
attached). When electrophillic addition occurs, the benzene ring would have to unfavorably
break its stable aromaticity to attack. However, the phenyl oxygen can donate its electrons to the
benzene ring, thus enriching it with electron density and stabilizing the positive charge. The
carbonyl group does nothing to stabilize the other benzene ring during its electrophilic addition.
In fact, the carbonyl group may as well have the opposite effect: the resonance structure of a
single bonded carbon to its oxygen pulls electrons away from the benzene ring through inductive
effect..
I Hope some more information required to solve th.pdf
I Hope some more information required to solve the problem once verify the
question
Solution
I Hope some more information required to solve the problem once verify the
question.
Water qualities1. Physical qualitiesOdour and taste unobject.pdf
Water qualities:
1. Physical qualities:
Odour and taste : unobjectionable to most users
Colour : 15 TCU
pH : 6.5 TO 8
Hardness : 500 as caco3
Dissolved solids : 1000 ppm
Turbidity : 5 NTU
Conductivity : 1500µs/cm
2.Chemical water qualities:
Calcium (Ca) :200 mg/litre
Chloride (Cl) :250 mg/litre
Chlorine residue 0.2-0.5 mg/litre
Copper (Cu) 1.0 mg/litre
Iron (Fe) 0.3 mg/litre
Magnesium (Mg) 150 mg/litre
Sulfate 400 mg/litre
Zinc 3 mg/litre
Phenolic compounds (as phenol) 0.002 mg/litre
Detergents (alkyl benzene sulphonates ) 1.0 mg/litre
Sodium 200 mg/litre
Types of elevated tanks:
1.Water spheroid elevated tank
2. Hydropilar elevated tanks
3. Composite elevated water tank
Standard Water spheroid Tank Dimensions:
Standard Hydropillar Tank Dimensions
Standard Composite Elevated Tank Dimensions:Capacity
(US Gallons)Head Range
(Feet) Tank Diameter
(Feet)500,00040\'55\'10\"750,00040\'64\'8\"1,000,00040\'74\'8\"
Solution
Water qualities:
1. Physical qualities:
Odour and taste : unobjectionable to most users
Colour : 15 TCU
pH : 6.5 TO 8
Hardness : 500 as caco3
Dissolved solids : 1000 ppm
Turbidity : 5 NTU
Conductivity : 1500µs/cm
2.Chemical water qualities:
Calcium (Ca) :200 mg/litre
Chloride (Cl) :250 mg/litre
Chlorine residue 0.2-0.5 mg/litre
Copper (Cu) 1.0 mg/litre
Iron (Fe) 0.3 mg/litre
Magnesium (Mg) 150 mg/litre
Sulfate 400 mg/litre
Zinc 3 mg/litre
Phenolic compounds (as phenol) 0.002 mg/litre
Detergents (alkyl benzene sulphonates ) 1.0 mg/litre
Sodium 200 mg/litre
Types of elevated tanks:
1.Water spheroid elevated tank
2. Hydropilar elevated tanks
3. Composite elevated water tank
Standard Water spheroid Tank Dimensions:
Standard Hydropillar Tank Dimensions
Standard Composite Elevated Tank Dimensions:Capacity
(US Gallons)Head Range
(Feet) Tank Diameter
(Feet)500,00040\'55\'10\"750,00040\'64\'8\"1,000,00040\'74\'8\".
Uses of HRIS SystemsThe principle motivation behind keeping up HR.pdf
Uses of HRIS Systems:
The principle motivation behind keeping up HRIS framework is to assemble, arrange, process,
record and disperses the data required for productive and successful administration of HR in the
association.The various uses of HRIS in an organisation can be listed as follows:
1. Work force Administration:
It envelops individual data of a worker. These may incorporate name, address, date of birth,
conjugal status, and the date of joining the association. It additionally contains the name and
address of next kinfolk of the worker concern. These data depict the representative.
2. Compensation Administration:
One of the elements of HRIS is to give a report containing data like present compensation,
advantages, last boost in salary and proposed increment in future.
3. Leave/Absence Increase:
HRIS is likewise used to control leave/nonattendance of representatives. This is finished by
keeping up a leave history of every worker. Each worker can be issued a character card
composing each representative\'s token number coded on it. Worker\'s entrance and exit from the
association ought to be recorded on the personality card. This diminishes chances for
misbehavior or oversight in computing compensation for every worker.
4. Aptitude Inventory:
Recording representative aptitudes and checking an expertise information base is yet another
utilization of the HRIS. Such an aptitude record recognizes representatives with the fundamental
expertise for specific positions or occupations in an association.
5. Labor Planning:
HRIS is utilized for labor arranging too. It keeps data of hierarchical necessities as far as
positions. HRIS associates workers to the required positions in the association. It is additionally
used to recognize opening and build up workers consequently. HRIS can likewise distinguish a
legitimate movement way and the progressions to be taken for worker progress/headway.
6. Enlistment:
Enlistment shapes the most crucial capacity of HRM. HRIS helps in the enlistment procedure
bigly by recording the points of interest of exercises required in worker enrollment. These may
incorporate expense and strategy for enlistment and time taken to fill the positions level astute,
for instance.
7. Profession Planning:
By giving important data, for example, which representatives have been reserved for which
positions, HRIS encourages positional headway of workers. At the end of the day, HRIS helps in
making arrangements for progression.
8. Aggregate Bargaining:
HRIS through a work station can give a la mode pertinent and required data, statistical data
points and, in this manner, can encourage aggregate bartering. It would he be able to p aggregate
bartering as \"consider the possibility that investigation\" rather as sentiments and fictions. In the
same way, HRIS can likewise keep up better human relations in the association.
Solution
Uses of HRIS Systems:
The principle motivation behind keeping up HRIS framework is to assemble, arrange, proces.
The moving force behind IT decisions are variable as to what context.pdf
The moving force behind IT decisions are variable as to what context can it profit an
organisation or a business. Some of it are as follows-
1) Displacement of labour and capital(ex-ATM)
2)Data repositories, ERP, business intelligence and high-end analytics help decision-makers
discover operational flaws and successes which augments future strategic initiatives.
3)Maintaining the customer relationshio management(CRM) [by providing goods and services
that customers value].
4) Maintaining the supply chain management(SCM).[ex- increase productivity through the most
efficient manufacturing processes available. In the computer industry, Dell Computer has
consistently been a market leader as they have achieved efficiencies through implementing both
CRM and SCM with success.]
General Recommendations
• Develop a three-tiered set of business case methodologies that are scaled to
the size and complexity of an initiative. These methodologies should be
Web-supported. Specific tools should include:
Tier 1 (least complex/cost): Total Cost of Ownership;
Tier 2 (middle/cost): Total Cost of Ownership, Payback Period,
Benefit/Cost Ratio, Internal Rate of Return, and Return on Investment;
Tier 3 (most complex/cost): Applied Information Economics.
• The tier requirements are phased to the initiative’s life cycle, requiring that
business case metrics be completed during the planning phase and refined
as the initiative moves through the various stages of its remaining life
cycle.
• Convene a task group to develop accounting reports/tools to more easily track the
financial metrics identified by the business case methodologies.
• Develop an in-depth training program and technical assistance program for
agency program, business, IT, and legislative staff on the adopted business
case methodologies.
• Develop a training/orientation program for senior department and line/staff
managers that include essential legal, financial/budgetary, IT architectural,
and IT project management issues. This orientation should be offered (possibly required) for all
agencies contemplating an initiative involving an information technology
investment.
Solution
The moving force behind IT decisions are variable as to what context can it profit an
organisation or a business. Some of it are as follows-
1) Displacement of labour and capital(ex-ATM)
2)Data repositories, ERP, business intelligence and high-end analytics help decision-makers
discover operational flaws and successes which augments future strategic initiatives.
3)Maintaining the customer relationshio management(CRM) [by providing goods and services
that customers value].
4) Maintaining the supply chain management(SCM).[ex- increase productivity through the most
efficient manufacturing processes available. In the computer industry, Dell Computer has
consistently been a market leader as they have achieved efficiencies through implementing both
CRM and SCM with success.]
General Recommendations
• Develop a three-tiered set of business .
The Canadian city with a pre- 1800 historic heart is QuebecSolut.pdf
The Canadian city with a pre- 1800 historic heart is Quebec
Solution
The Canadian city with a pre- 1800 historic heart is Quebec.
Solution Millennials referred to as narcissistic referred to as n.pdf
Solution
:
Millennials referred to as narcissistic referred to as narcissistic because people born between
19th and 20th century are consider as more self centred than any other generation.But this
statement is not valid due to the fact that when we compare many generation then it is found that
some previous generation are more narcissistic than Millennials.Self esteem is common factor
for all the generation but there is difference in degree it exist.So,it is not right to blame one
generation as narcissistic..
SolutionThe SELECT DISTINCT stamen will returns distinct values. .pdf
Solution
:
The SELECT DISTINCT stamen will returns distinct values. SELECT DISTINCT statement
will eliminates the duplicates from the result. DISTINCT can be used for single column, it does
not support the multiple columns. Using this we can get the unique record from the table instead
of duplicate records..
Starting from the topmost column,1. Cerebellum2. Spinocerebellar.pdf
Starting from the topmost column,
1. Cerebellum
2. Spinocerebellar pathway
3. Posterior spinocerebellar tract
4. Anterior spinocerebellar tract
Solution
Starting from the topmost column,
1. Cerebellum
2. Spinocerebellar pathway
3. Posterior spinocerebellar tract
4. Anterior spinocerebellar tract.
Rheumatic fever shows various symptoms and signs, out of which sore .pdf
Rheumatic fever shows various symptoms and signs, out of which sore throat is one of the
symptoms.
Only 35-60% of patients show the symptom of upper respiratory sore throat several weeks
preceeding rheumatic fever. Many symptomatic individuals do not seek medical attention, go
undiagnosed, or do not take the prescribed antibiotic for acute rheumatic fever prevention.
Treatment with penicillin will reduce 80% of rheumatic fever risk.
Solution
Rheumatic fever shows various symptoms and signs, out of which sore throat is one of the
symptoms.
Only 35-60% of patients show the symptom of upper respiratory sore throat several weeks
preceeding rheumatic fever. Many symptomatic individuals do not seek medical attention, go
undiagnosed, or do not take the prescribed antibiotic for acute rheumatic fever prevention.
Treatment with penicillin will reduce 80% of rheumatic fever risk..
Physiological responce are those in which the functions of the body .pdf
Physiological responce are those in which the functions of the body parts changes or affected. so
examples include
1) excessive heat causes the blood vessel to dilate
2) a mammal shivers to generate heat when it is cold
Anatomical response are those in which internal body tissue or organs affects.So examples
include
1) A rabbit grows thicker fur during winter
2) A plant grows deeper root in draught.
Behavioral response are those in which behavior of an organism affects So example includes
1) During cold weather honey bee huddle together to keep warm
2) Monarch butterfly migrate to warmer region during winter
3) A reptile migrate to shaded area to lower its body temperature.
Solution
Physiological responce are those in which the functions of the body parts changes or affected. so
examples include
1) excessive heat causes the blood vessel to dilate
2) a mammal shivers to generate heat when it is cold
Anatomical response are those in which internal body tissue or organs affects.So examples
include
1) A rabbit grows thicker fur during winter
2) A plant grows deeper root in draught.
Behavioral response are those in which behavior of an organism affects So example includes
1) During cold weather honey bee huddle together to keep warm
2) Monarch butterfly migrate to warmer region during winter
3) A reptile migrate to shaded area to lower its body temperature..
co2 because of the sqrt of their molar mases.. .pdf
co2 because of the sqrt of their molar mases..
Solution
co2 because of the sqrt of their molar mases...
L{e^{-t}} = int _0 to infinty [e^{st}e^{-t} dt = int _0 to infinty .pdf
L{e^{-t}} = int _0 to infinty [e^{st}*e^{-t} dt = int _0 to infinty [e^{(s-1)t} dt
L{e^{-t}} = 1/(s+1)
Solution
L{e^{-t}} = int _0 to infinty [e^{st}*e^{-t} dt = int _0 to infinty [e^{(s-1)t} dt
L{e^{-t}} = 1/(s+1).
carbon forms 4 hydrogen forms 1 nitrogen forms 3 .pdf
carbon forms 4 hydrogen forms 1 nitrogen forms 3 and oxygen can form 2
Solution
carbon forms 4 hydrogen forms 1 nitrogen forms 3 and oxygen can form 2.
H = H(lattice) + H(first ionisation) +H(second ionization) +2H(elec.pdf
H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold
energy)+H(sublimation)
= 878KJ/mol
Solution
H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold
energy)+H(sublimation)
= 878KJ/mol.
Heptatomic molecules contain 7 atomsNo. of H atoms = 2No. of S .pdf
Heptatomic molecules contain 7 atoms:
No. of H atoms = 2
No. of S atoms = 1
No. of O atoms = 7 - 2 - 1 = 4
The formula is thus H2SO4 (sulfuric acid)
Solution
Heptatomic molecules contain 7 atoms:
No. of H atoms = 2
No. of S atoms = 1
No. of O atoms = 7 - 2 - 1 = 4
The formula is thus H2SO4 (sulfuric acid).
ExperimentRegionTissue expressedConclusion1ABCLIVER.pdf
Experiment
Region
Tissue expressed
Conclusion
1
A
B
C
LIVER
KIDNEY
-
X, Y and Z protiens are interacting with regions A, B and C, respectively. Expression is observed
only in liver and kidney, indicating that interaction of any one of these proteins is blocking the
expression of this gene in heart.
2
-
-
-
-
-
HEART
None of the promoter region is present for binding site and still expression is observed in heart.
This confirms that any one of these regions are blocking the expression of this gene in heart.
3
A
-
-
-
KIDNEY
HEART
Region B and C are mutated. Expression is observed in kidney and heart, indicating that A is not
blocking gene expression in heart, but gives specific expression in kidney. Interaction of A-X is
essential for kidney-specific expression.
4
-
B
-
LIVER
-
HEART
Region A and C are mutated. Expression is observed in liver and heart, indicating that B is not
blocking gene expression in heart, but gives specific expression in liver. Interaction of B-Y is
essential for liver-specific expression.
5
-
-
C
-
-
-
Region A and B are mutated. Expression is not observed in any tissue, indicating that C is
blocking gene expression in heart. Interaction of C-Z is essential for blocking the gene
expression in heart.
6
A
B
-
LIVER
KIDNEY
HEART
Region C is mutated. Expression is observed in all tissues, confirming that A and B are not
blocking gene expression in heart.
7
A
-
C
-
KIDNEY
-
Region B is mutated. Expression is observed in only kidney, confirming that C is blocking gene
expression in heart.
8
-
B
C
LIVER
-
-
Region A is mutated. Expression is observed in only liver, confirming that C is blocking gene
expression in heart.
From the data given, it is clear that the region C is important for heart-specific expression of this
gene. Therefore protein Z is present in heart.
Experiment
Region
Tissue expressed
Conclusion
1
A
B
C
LIVER
KIDNEY
-
X, Y and Z protiens are interacting with regions A, B and C, respectively. Expression is
observed only in liver and kidney, indicating that interaction of any one of these proteins is
blocking the expression of this gene in heart.
2
-
-
-
-
-
HEART
None of the promoter region is present for binding site and still expression is observed in heart.
This confirms that any one of these regions are blocking the expression of this gene in heart.
3
A
-
-
-
KIDNEY
HEART
Region B and C are mutated. Expression is observed in kidney and heart, indicating that A is not
blocking gene expression in heart, but gives specific expression in kidney. Interaction of A-X is
essential for kidney-specific expression.
4
-
B
-
LIVER
-
HEART
Region A and C are mutated. Expression is observed in liver and heart, indicating that B is not
blocking gene expression in heart, but gives specific expression in liver. Interaction of B-Y is
essential for liver-specific expression.
5
-
-
C
-
-
-
Region A and B are mutated. Expression is not observed in any tissue, indicating that C is
blocking gene expression in heart. Interaction of.
D . All of the above could be reported within the fund financial sta.pdf
D . All of the above could be reported within the fund financial statements.
i.e Statement of net assets , Statement of cash flows and Balance Sheet
Solution
D . All of the above could be reported within the fund financial statements.
i.e Statement of net assets , Statement of cash flows and Balance Sheet.
Codeclass Main { public static void main(String[] args) { dou.pdf
Code:
class Main {
public static void main(String[] args) {
double[] p = new double[12];
p[1] = 100;
int r = 5;
for(int i=2; i < 12; i++){
p[i] = p[i-1]*(1+(r/100.0));
}
System.out.println(\"Initial Population is : \"+p[1]);
System.out.println(\"Hour --> Population\");
for(int i=2; i < 12; i++){
System.out.println(i-1+\" --> \"+p[i]);
}
}
}
Output:
Solution
Code:
class Main {
public static void main(String[] args) {
double[] p = new double[12];
p[1] = 100;
int r = 5;
for(int i=2; i < 12; i++){
p[i] = p[i-1]*(1+(r/100.0));
}
System.out.println(\"Initial Population is : \"+p[1]);
System.out.println(\"Hour --> Population\");
for(int i=2; i < 12; i++){
System.out.println(i-1+\" --> \"+p[i]);
}
}
}
Output:.
Thesis Statement for students diagnonsed withADHD.ppt
Presentation required for the master in Education.
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Mule 4.6 & Java 17 Upgrade | MuleSoft Mysore Meetup #46
Event Link:-
https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
Agenda
● Java 17 Upgrade Overview
● Why and by when do customers need to upgrade to Java 17?
● Is there any immediate impact to upgrading to Mule Runtime 4.6 and beyond?
● Which MuleSoft products are in scope?
For Upcoming Meetups Join Mysore Meetup Group - https://meetups.mulesoft.com/mysore/
YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Organizers:-
Shubham Chaurasia - https://www.linkedin.com/in/shubhamchaurasia1/
Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
Shyam Raj Prasad-
https://www.linkedin.com/in/shyam-raj-prasad/
More Related Content
More from sanjeevtandonsre
Water qualities1. Physical qualitiesOdour and taste unobject.pdf
Water qualities:
1. Physical qualities:
Odour and taste : unobjectionable to most users
Colour : 15 TCU
pH : 6.5 TO 8
Hardness : 500 as caco3
Dissolved solids : 1000 ppm
Turbidity : 5 NTU
Conductivity : 1500µs/cm
2.Chemical water qualities:
Calcium (Ca) :200 mg/litre
Chloride (Cl) :250 mg/litre
Chlorine residue 0.2-0.5 mg/litre
Copper (Cu) 1.0 mg/litre
Iron (Fe) 0.3 mg/litre
Magnesium (Mg) 150 mg/litre
Sulfate 400 mg/litre
Zinc 3 mg/litre
Phenolic compounds (as phenol) 0.002 mg/litre
Detergents (alkyl benzene sulphonates ) 1.0 mg/litre
Sodium 200 mg/litre
Types of elevated tanks:
1.Water spheroid elevated tank
2. Hydropilar elevated tanks
3. Composite elevated water tank
Standard Water spheroid Tank Dimensions:
Standard Hydropillar Tank Dimensions
Standard Composite Elevated Tank Dimensions:Capacity
(US Gallons)Head Range
(Feet) Tank Diameter
(Feet)500,00040\'55\'10\"750,00040\'64\'8\"1,000,00040\'74\'8\"
Solution
Water qualities:
1. Physical qualities:
Odour and taste : unobjectionable to most users
Colour : 15 TCU
pH : 6.5 TO 8
Hardness : 500 as caco3
Dissolved solids : 1000 ppm
Turbidity : 5 NTU
Conductivity : 1500µs/cm
2.Chemical water qualities:
Calcium (Ca) :200 mg/litre
Chloride (Cl) :250 mg/litre
Chlorine residue 0.2-0.5 mg/litre
Copper (Cu) 1.0 mg/litre
Iron (Fe) 0.3 mg/litre
Magnesium (Mg) 150 mg/litre
Sulfate 400 mg/litre
Zinc 3 mg/litre
Phenolic compounds (as phenol) 0.002 mg/litre
Detergents (alkyl benzene sulphonates ) 1.0 mg/litre
Sodium 200 mg/litre
Types of elevated tanks:
1.Water spheroid elevated tank
2. Hydropilar elevated tanks
3. Composite elevated water tank
Standard Water spheroid Tank Dimensions:
Standard Hydropillar Tank Dimensions
Standard Composite Elevated Tank Dimensions:Capacity
(US Gallons)Head Range
(Feet) Tank Diameter
(Feet)500,00040\'55\'10\"750,00040\'64\'8\"1,000,00040\'74\'8\".
Uses of HRIS SystemsThe principle motivation behind keeping up HR.pdf
Uses of HRIS Systems:
The principle motivation behind keeping up HRIS framework is to assemble, arrange, process,
record and disperses the data required for productive and successful administration of HR in the
association.The various uses of HRIS in an organisation can be listed as follows:
1. Work force Administration:
It envelops individual data of a worker. These may incorporate name, address, date of birth,
conjugal status, and the date of joining the association. It additionally contains the name and
address of next kinfolk of the worker concern. These data depict the representative.
2. Compensation Administration:
One of the elements of HRIS is to give a report containing data like present compensation,
advantages, last boost in salary and proposed increment in future.
3. Leave/Absence Increase:
HRIS is likewise used to control leave/nonattendance of representatives. This is finished by
keeping up a leave history of every worker. Each worker can be issued a character card
composing each representative\'s token number coded on it. Worker\'s entrance and exit from the
association ought to be recorded on the personality card. This diminishes chances for
misbehavior or oversight in computing compensation for every worker.
4. Aptitude Inventory:
Recording representative aptitudes and checking an expertise information base is yet another
utilization of the HRIS. Such an aptitude record recognizes representatives with the fundamental
expertise for specific positions or occupations in an association.
5. Labor Planning:
HRIS is utilized for labor arranging too. It keeps data of hierarchical necessities as far as
positions. HRIS associates workers to the required positions in the association. It is additionally
used to recognize opening and build up workers consequently. HRIS can likewise distinguish a
legitimate movement way and the progressions to be taken for worker progress/headway.
6. Enlistment:
Enlistment shapes the most crucial capacity of HRM. HRIS helps in the enlistment procedure
bigly by recording the points of interest of exercises required in worker enrollment. These may
incorporate expense and strategy for enlistment and time taken to fill the positions level astute,
for instance.
7. Profession Planning:
By giving important data, for example, which representatives have been reserved for which
positions, HRIS encourages positional headway of workers. At the end of the day, HRIS helps in
making arrangements for progression.
8. Aggregate Bargaining:
HRIS through a work station can give a la mode pertinent and required data, statistical data
points and, in this manner, can encourage aggregate bartering. It would he be able to p aggregate
bartering as \"consider the possibility that investigation\" rather as sentiments and fictions. In the
same way, HRIS can likewise keep up better human relations in the association.
Solution
Uses of HRIS Systems:
The principle motivation behind keeping up HRIS framework is to assemble, arrange, proces.
The moving force behind IT decisions are variable as to what context.pdf
The moving force behind IT decisions are variable as to what context can it profit an
organisation or a business. Some of it are as follows-
1) Displacement of labour and capital(ex-ATM)
2)Data repositories, ERP, business intelligence and high-end analytics help decision-makers
discover operational flaws and successes which augments future strategic initiatives.
3)Maintaining the customer relationshio management(CRM) [by providing goods and services
that customers value].
4) Maintaining the supply chain management(SCM).[ex- increase productivity through the most
efficient manufacturing processes available. In the computer industry, Dell Computer has
consistently been a market leader as they have achieved efficiencies through implementing both
CRM and SCM with success.]
General Recommendations
• Develop a three-tiered set of business case methodologies that are scaled to
the size and complexity of an initiative. These methodologies should be
Web-supported. Specific tools should include:
Tier 1 (least complex/cost): Total Cost of Ownership;
Tier 2 (middle/cost): Total Cost of Ownership, Payback Period,
Benefit/Cost Ratio, Internal Rate of Return, and Return on Investment;
Tier 3 (most complex/cost): Applied Information Economics.
• The tier requirements are phased to the initiative’s life cycle, requiring that
business case metrics be completed during the planning phase and refined
as the initiative moves through the various stages of its remaining life
cycle.
• Convene a task group to develop accounting reports/tools to more easily track the
financial metrics identified by the business case methodologies.
• Develop an in-depth training program and technical assistance program for
agency program, business, IT, and legislative staff on the adopted business
case methodologies.
• Develop a training/orientation program for senior department and line/staff
managers that include essential legal, financial/budgetary, IT architectural,
and IT project management issues. This orientation should be offered (possibly required) for all
agencies contemplating an initiative involving an information technology
investment.
Solution
The moving force behind IT decisions are variable as to what context can it profit an
organisation or a business. Some of it are as follows-
1) Displacement of labour and capital(ex-ATM)
2)Data repositories, ERP, business intelligence and high-end analytics help decision-makers
discover operational flaws and successes which augments future strategic initiatives.
3)Maintaining the customer relationshio management(CRM) [by providing goods and services
that customers value].
4) Maintaining the supply chain management(SCM).[ex- increase productivity through the most
efficient manufacturing processes available. In the computer industry, Dell Computer has
consistently been a market leader as they have achieved efficiencies through implementing both
CRM and SCM with success.]
General Recommendations
• Develop a three-tiered set of business .
The Canadian city with a pre- 1800 historic heart is QuebecSolut.pdf
The Canadian city with a pre- 1800 historic heart is Quebec
Solution
The Canadian city with a pre- 1800 historic heart is Quebec.
Solution Millennials referred to as narcissistic referred to as n.pdf
Solution
:
Millennials referred to as narcissistic referred to as narcissistic because people born between
19th and 20th century are consider as more self centred than any other generation.But this
statement is not valid due to the fact that when we compare many generation then it is found that
some previous generation are more narcissistic than Millennials.Self esteem is common factor
for all the generation but there is difference in degree it exist.So,it is not right to blame one
generation as narcissistic..
SolutionThe SELECT DISTINCT stamen will returns distinct values. .pdf
Solution
:
The SELECT DISTINCT stamen will returns distinct values. SELECT DISTINCT statement
will eliminates the duplicates from the result. DISTINCT can be used for single column, it does
not support the multiple columns. Using this we can get the unique record from the table instead
of duplicate records..
Starting from the topmost column,1. Cerebellum2. Spinocerebellar.pdf
Starting from the topmost column,
1. Cerebellum
2. Spinocerebellar pathway
3. Posterior spinocerebellar tract
4. Anterior spinocerebellar tract
Solution
Starting from the topmost column,
1. Cerebellum
2. Spinocerebellar pathway
3. Posterior spinocerebellar tract
4. Anterior spinocerebellar tract.
Rheumatic fever shows various symptoms and signs, out of which sore .pdf
Rheumatic fever shows various symptoms and signs, out of which sore throat is one of the
symptoms.
Only 35-60% of patients show the symptom of upper respiratory sore throat several weeks
preceeding rheumatic fever. Many symptomatic individuals do not seek medical attention, go
undiagnosed, or do not take the prescribed antibiotic for acute rheumatic fever prevention.
Treatment with penicillin will reduce 80% of rheumatic fever risk.
Solution
Rheumatic fever shows various symptoms and signs, out of which sore throat is one of the
symptoms.
Only 35-60% of patients show the symptom of upper respiratory sore throat several weeks
preceeding rheumatic fever. Many symptomatic individuals do not seek medical attention, go
undiagnosed, or do not take the prescribed antibiotic for acute rheumatic fever prevention.
Treatment with penicillin will reduce 80% of rheumatic fever risk..
Physiological responce are those in which the functions of the body .pdf
Physiological responce are those in which the functions of the body parts changes or affected. so
examples include
1) excessive heat causes the blood vessel to dilate
2) a mammal shivers to generate heat when it is cold
Anatomical response are those in which internal body tissue or organs affects.So examples
include
1) A rabbit grows thicker fur during winter
2) A plant grows deeper root in draught.
Behavioral response are those in which behavior of an organism affects So example includes
1) During cold weather honey bee huddle together to keep warm
2) Monarch butterfly migrate to warmer region during winter
3) A reptile migrate to shaded area to lower its body temperature.
Solution
Physiological responce are those in which the functions of the body parts changes or affected. so
examples include
1) excessive heat causes the blood vessel to dilate
2) a mammal shivers to generate heat when it is cold
Anatomical response are those in which internal body tissue or organs affects.So examples
include
1) A rabbit grows thicker fur during winter
2) A plant grows deeper root in draught.
Behavioral response are those in which behavior of an organism affects So example includes
1) During cold weather honey bee huddle together to keep warm
2) Monarch butterfly migrate to warmer region during winter
3) A reptile migrate to shaded area to lower its body temperature..
co2 because of the sqrt of their molar mases.. .pdf
co2 because of the sqrt of their molar mases..
Solution
co2 because of the sqrt of their molar mases...
L{e^{-t}} = int _0 to infinty [e^{st}e^{-t} dt = int _0 to infinty .pdf
L{e^{-t}} = int _0 to infinty [e^{st}*e^{-t} dt = int _0 to infinty [e^{(s-1)t} dt
L{e^{-t}} = 1/(s+1)
Solution
L{e^{-t}} = int _0 to infinty [e^{st}*e^{-t} dt = int _0 to infinty [e^{(s-1)t} dt
L{e^{-t}} = 1/(s+1).
carbon forms 4 hydrogen forms 1 nitrogen forms 3 .pdf
carbon forms 4 hydrogen forms 1 nitrogen forms 3 and oxygen can form 2
Solution
carbon forms 4 hydrogen forms 1 nitrogen forms 3 and oxygen can form 2.
H = H(lattice) + H(first ionisation) +H(second ionization) +2H(elec.pdf
H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold
energy)+H(sublimation)
= 878KJ/mol
Solution
H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold
energy)+H(sublimation)
= 878KJ/mol.
Heptatomic molecules contain 7 atomsNo. of H atoms = 2No. of S .pdf
Heptatomic molecules contain 7 atoms:
No. of H atoms = 2
No. of S atoms = 1
No. of O atoms = 7 - 2 - 1 = 4
The formula is thus H2SO4 (sulfuric acid)
Solution
Heptatomic molecules contain 7 atoms:
No. of H atoms = 2
No. of S atoms = 1
No. of O atoms = 7 - 2 - 1 = 4
The formula is thus H2SO4 (sulfuric acid).
ExperimentRegionTissue expressedConclusion1ABCLIVER.pdf
Experiment
Region
Tissue expressed
Conclusion
1
A
B
C
LIVER
KIDNEY
-
X, Y and Z protiens are interacting with regions A, B and C, respectively. Expression is observed
only in liver and kidney, indicating that interaction of any one of these proteins is blocking the
expression of this gene in heart.
2
-
-
-
-
-
HEART
None of the promoter region is present for binding site and still expression is observed in heart.
This confirms that any one of these regions are blocking the expression of this gene in heart.
3
A
-
-
-
KIDNEY
HEART
Region B and C are mutated. Expression is observed in kidney and heart, indicating that A is not
blocking gene expression in heart, but gives specific expression in kidney. Interaction of A-X is
essential for kidney-specific expression.
4
-
B
-
LIVER
-
HEART
Region A and C are mutated. Expression is observed in liver and heart, indicating that B is not
blocking gene expression in heart, but gives specific expression in liver. Interaction of B-Y is
essential for liver-specific expression.
5
-
-
C
-
-
-
Region A and B are mutated. Expression is not observed in any tissue, indicating that C is
blocking gene expression in heart. Interaction of C-Z is essential for blocking the gene
expression in heart.
6
A
B
-
LIVER
KIDNEY
HEART
Region C is mutated. Expression is observed in all tissues, confirming that A and B are not
blocking gene expression in heart.
7
A
-
C
-
KIDNEY
-
Region B is mutated. Expression is observed in only kidney, confirming that C is blocking gene
expression in heart.
8
-
B
C
LIVER
-
-
Region A is mutated. Expression is observed in only liver, confirming that C is blocking gene
expression in heart.
From the data given, it is clear that the region C is important for heart-specific expression of this
gene. Therefore protein Z is present in heart.
Experiment
Region
Tissue expressed
Conclusion
1
A
B
C
LIVER
KIDNEY
-
X, Y and Z protiens are interacting with regions A, B and C, respectively. Expression is
observed only in liver and kidney, indicating that interaction of any one of these proteins is
blocking the expression of this gene in heart.
2
-
-
-
-
-
HEART
None of the promoter region is present for binding site and still expression is observed in heart.
This confirms that any one of these regions are blocking the expression of this gene in heart.
3
A
-
-
-
KIDNEY
HEART
Region B and C are mutated. Expression is observed in kidney and heart, indicating that A is not
blocking gene expression in heart, but gives specific expression in kidney. Interaction of A-X is
essential for kidney-specific expression.
4
-
B
-
LIVER
-
HEART
Region A and C are mutated. Expression is observed in liver and heart, indicating that B is not
blocking gene expression in heart, but gives specific expression in liver. Interaction of B-Y is
essential for liver-specific expression.
5
-
-
C
-
-
-
Region A and B are mutated. Expression is not observed in any tissue, indicating that C is
blocking gene expression in heart. Interaction of.
D . All of the above could be reported within the fund financial sta.pdf
D . All of the above could be reported within the fund financial statements.
i.e Statement of net assets , Statement of cash flows and Balance Sheet
Solution
D . All of the above could be reported within the fund financial statements.
i.e Statement of net assets , Statement of cash flows and Balance Sheet.
Codeclass Main { public static void main(String[] args) { dou.pdf
Code:
class Main {
public static void main(String[] args) {
double[] p = new double[12];
p[1] = 100;
int r = 5;
for(int i=2; i < 12; i++){
p[i] = p[i-1]*(1+(r/100.0));
}
System.out.println(\"Initial Population is : \"+p[1]);
System.out.println(\"Hour --> Population\");
for(int i=2; i < 12; i++){
System.out.println(i-1+\" --> \"+p[i]);
}
}
}
Output:
Solution
Code:
class Main {
public static void main(String[] args) {
double[] p = new double[12];
p[1] = 100;
int r = 5;
for(int i=2; i < 12; i++){
p[i] = p[i-1]*(1+(r/100.0));
}
System.out.println(\"Initial Population is : \"+p[1]);
System.out.println(\"Hour --> Population\");
for(int i=2; i < 12; i++){
System.out.println(i-1+\" --> \"+p[i]);
}
}
}
Output:.
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carbon forms 4 hydrogen forms 1 nitrogen forms 3 .pdf
carbon forms 4 hydrogen forms 1 nitrogen forms 3 .pdf
H = H(lattice) + H(first ionisation) +H(second ionization) +2H(elec.pdf
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Heptatomic molecules contain 7 atomsNo. of H atoms = 2No. of S .pdf
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D . All of the above could be reported within the fund financial sta.pdf
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Digital Artifact 2 - Investigating Pavilion Designs
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
Welcome to TechSoup New Member Orientation and Q&A (May 2024).pdf
According to Union by size, each node x which has the size of the su.pdf
- 1. According to Union by size, each node x which has the size of the subtree rooted at x is stored. In UNION, the tree of the smaller set is made the subtree of the other tree and the size field of the root of the resulting tree is updated. According to path compression heuristics, the parent pointer is reset from x such that it points to the root for the find operation. Let the number of nodes be n and the number of finds be m. The union operations are executed before the find operations, so a tree is constructed before any operation. There are at most O(n) union operations and each union operation takes O (1) time. Thus, the total cost of union is O(n). The cost of a find operation is the increment of the number of new children to the root by 1. Each find operation will take O(m) time. So, the total cost of m find operation is O (m + n). Here, n = 1 + max (number of children of the root) Solution According to Union by size, each node x which has the size of the subtree rooted at x is stored. In UNION, the tree of the smaller set is made the subtree of the other tree and the size field of the root of the resulting tree is updated. According to path compression heuristics, the parent pointer is reset from x such that it points to the root for the find operation. Let the number of nodes be n and the number of finds be m. The union operations are executed before the find operations, so a tree is constructed before any operation. There are at most O(n) union operations and each union operation takes O (1) time. Thus, the total cost of union is O(n). The cost of a find operation is the increment of the number of new children to the root by 1. Each find operation will take O(m) time. So, the total cost of m find operation is O (m + n). Here, n = 1 + max (number of children of the root)