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H = H(lattice) + H(first ionisation) +H(second ionization) +2H(elec.pdf

The document discusses a calculation involving various enthalpy changes, including lattice energy, ionization energies, electron affinity, bold energy, and sublimation. The total enthalpy change is calculated to be 878 kJ/mol. This calculation is presented in a repeated format for clarity.

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H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold energy)+H(sublimation) = 878KJ/mol Solution H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold energy)+H(sublimation) = 878KJ/mol

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H = H(lattice) + H(first ionisation) +H(second ionization) +2H(elec.pdf

  • 1.
    H = H(lattice)+ H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold energy)+H(sublimation) = 878KJ/mol Solution H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold energy)+H(sublimation) = 878KJ/mol