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H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold
energy)+H(sublimation)
= 878KJ/mol
Solution
H = H(lattice) + H(first ionisation) +H(second ionization) +2*H(electron affinity)+H(bold
energy)+H(sublimation)
= 878KJ/mol

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