a=2i + j - 2k Find the length of the vector. Find a unit vec.pdf
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a=2i + j - 2k Find the length of the vector. Find a unit vector having the same direction as a. Please show detailed work so that I can understand how you figured this out. Thank You! Solution l=(4+1+4)=3 unit vector= 1/3(2i + j - 2k).
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A.Determine what is the sampleB State what constitutes the populat.pdf
A.Determine what is the sample
B State what constitutes the population.
C.Identify at least one variable.
D.Determine if the variable is quantitative or categorical
E.Determine if the scale is nominal, ordinal, interval or ratio.
F.Find one piece of datum.
G.Find a statistic in the scenario.
H.Find a parameter in the scenario.
Solution
a. the sample is 345
b. no of people in a city using detergents
c. variable will be the number of people knowing the name of detergent or not
d. the data is quantative
e. the scale is nominal
f. the piece of datum is the squares on the map
g. the statistic is 1.32
h. the parameter is 9.
A.C. Markkula, Jr., a co-founder of Apple, takes the position that a.pdf
A.C. Markkula, Jr., a co-founder of Apple, takes the position that access to the internet is a
privilege and not a right. To curb some of the abuses and harmful effects Markkula suggests
(perhaps tongue in cheek or perhaps seriously?) a drivers
Solution
In my opinion Markkula.
According to a certain book men have a 14.216 chance of dying at age.pdf
According to a certain book men have a 14.216 chance of dying at age 90. A group of 90-year-
old men meet monthly to discuss philosophy and politics. They are discussing the possibliliy of
some of thier group dying this year.
If 4 men are chosen at random from the group, what is the probability that all of the 4 men will
die this year?
Solution
p(4) =(0.14216)4
=4.084x10-4.
According to a 2007 CBC article, Canadians face about a 10 chance o.pdf
According to a 2007 CBC article, Canadians face about a 10% chance of acquiring an infection
when hospitalized. If records of 15 randomly selected hospitalized patients are examined find for
the number of Canadians who are infected when hospitalized.
d. the probability that two or more of the 15 aquire an infection while hospitalized
Solution
Given X~Binomial(n=15, p=0.1) P(X=x)=xC15*(0.1^x)*(0.9^(15-x)) So the
probability is P(X>=2)=1-P(X=0)-P(X=1)= 0.450957.
According to 2003 report of the US Health Resources, co-infection of.pdf
According to 2003 report of the US Health Resources, co-infection of HIV and hepatitis C
(HCV) is on the rise. Only about 2% of Americans have HCV, but 25% Americans with HIV
have HCV. And about 10% of Americans with HCV also have HIV. (2) What is the probability
that a randomly chosen American has both HIV and HCV? ?
Solution
P(HCV) = 0.02; P(HCV | HIV) = 0.25; P(HIV | HCV) = 0.10. P(HIV & HCV) =
P(HCV).P(HIV | HCV) = 0.02*0.1 = 0.002.
a.Overly complicated or difficult to use products b.Low selection .pdf
a.Overly complicated or difficult to use products
b.Low selection or poor availability of product
c.Business place dirty, messy, or cluttered
d.Employees who lack knowledge or who are not helpful4. Which of these can be a people
turnoff for customers?)
Solution
Option \'d\' is correct.
People turnoffs: these are the things most often associate with poor service and include lack of
courtesy or attention, inapproprite or unprofessional behavior, or an indifferent attitude-in short
any behavior that conveys a lack of care or consideration for the costumer..
a.There are 10 PAPER MATE pens in a box and 3 are defective. Two pen.pdf
a.There are 10 PAPER MATE pens in a box and 3 are defective. Two pens are to be selected one
after the other. What is the probability that both pens will be defective? b.A statistics
professor receives an average of 5 e-mail messages a day from her students. Assume the number
of messages follow a Poisson distribution. What is the probability that on a randomly selected
day she will have no messages
Solution
a. 2/15 b. e^(-1/5).
Above-average warmth extended over the east and southeast on January.pdf
Above-average warmth extended over the east and southeast on January 13, 2005. The day\'s
forecasted high temperatures in four cities in the affected area were as follows.
a. What is the random variable involved in this study?
b. Is the random variable discrete or continuous? Explain.
Solution
random variable involve is temperature
ans temperature.
Recommended
A.Determine what is the sampleB State what constitutes the populat.pdf
A.Determine what is the sample
B State what constitutes the population.
C.Identify at least one variable.
D.Determine if the variable is quantitative or categorical
E.Determine if the scale is nominal, ordinal, interval or ratio.
F.Find one piece of datum.
G.Find a statistic in the scenario.
H.Find a parameter in the scenario.
Solution
a. the sample is 345
b. no of people in a city using detergents
c. variable will be the number of people knowing the name of detergent or not
d. the data is quantative
e. the scale is nominal
f. the piece of datum is the squares on the map
g. the statistic is 1.32
h. the parameter is 9.
A.C. Markkula, Jr., a co-founder of Apple, takes the position that a.pdf
A.C. Markkula, Jr., a co-founder of Apple, takes the position that access to the internet is a
privilege and not a right. To curb some of the abuses and harmful effects Markkula suggests
(perhaps tongue in cheek or perhaps seriously?) a drivers
Solution
In my opinion Markkula.
According to a certain book men have a 14.216 chance of dying at age.pdf
According to a certain book men have a 14.216 chance of dying at age 90. A group of 90-year-
old men meet monthly to discuss philosophy and politics. They are discussing the possibliliy of
some of thier group dying this year.
If 4 men are chosen at random from the group, what is the probability that all of the 4 men will
die this year?
Solution
p(4) =(0.14216)4
=4.084x10-4.
According to a 2007 CBC article, Canadians face about a 10 chance o.pdf
According to a 2007 CBC article, Canadians face about a 10% chance of acquiring an infection
when hospitalized. If records of 15 randomly selected hospitalized patients are examined find for
the number of Canadians who are infected when hospitalized.
d. the probability that two or more of the 15 aquire an infection while hospitalized
Solution
Given X~Binomial(n=15, p=0.1) P(X=x)=xC15*(0.1^x)*(0.9^(15-x)) So the
probability is P(X>=2)=1-P(X=0)-P(X=1)= 0.450957.
According to 2003 report of the US Health Resources, co-infection of.pdf
According to 2003 report of the US Health Resources, co-infection of HIV and hepatitis C
(HCV) is on the rise. Only about 2% of Americans have HCV, but 25% Americans with HIV
have HCV. And about 10% of Americans with HCV also have HIV. (2) What is the probability
that a randomly chosen American has both HIV and HCV? ?
Solution
P(HCV) = 0.02; P(HCV | HIV) = 0.25; P(HIV | HCV) = 0.10. P(HIV & HCV) =
P(HCV).P(HIV | HCV) = 0.02*0.1 = 0.002.
a.Overly complicated or difficult to use products b.Low selection .pdf
a.Overly complicated or difficult to use products
b.Low selection or poor availability of product
c.Business place dirty, messy, or cluttered
d.Employees who lack knowledge or who are not helpful4. Which of these can be a people
turnoff for customers?)
Solution
Option \'d\' is correct.
People turnoffs: these are the things most often associate with poor service and include lack of
courtesy or attention, inapproprite or unprofessional behavior, or an indifferent attitude-in short
any behavior that conveys a lack of care or consideration for the costumer..
a.There are 10 PAPER MATE pens in a box and 3 are defective. Two pen.pdf
a.There are 10 PAPER MATE pens in a box and 3 are defective. Two pens are to be selected one
after the other. What is the probability that both pens will be defective? b.A statistics
professor receives an average of 5 e-mail messages a day from her students. Assume the number
of messages follow a Poisson distribution. What is the probability that on a randomly selected
day she will have no messages
Solution
a. 2/15 b. e^(-1/5).
Above-average warmth extended over the east and southeast on January.pdf
Above-average warmth extended over the east and southeast on January 13, 2005. The day\'s
forecasted high temperatures in four cities in the affected area were as follows.
a. What is the random variable involved in this study?
b. Is the random variable discrete or continuous? Explain.
Solution
random variable involve is temperature
ans temperature.
about 20 of babies born with a certian ailment recover fully, A hos.pdf
about 20% of babies born with a certian ailment recover fully, A hospital is caring for five babies
bornh with this ailment. the random varialble represents the number of babais that recover fully.
decide weather the experiment is a binomial experiment, if it is identify the a succsess, specify
the values of n, q, p, and list the possible variable of x
Solution
n=5, p=0.2 q=1-p=1-0.2=0.8 the possible variable of x: 0,1,2,3,4,5.
About 40 of the general population ddonate their time and energy to.pdf
About 40% of the general population ddonate their time and energy to community projects.
suppose 15 people have been randomly selected fron a community and each asked if they
donated their time and energy to community projects. Let x be the number of them that do donate
their time and energy to community projects. Find the probability that more than seven of the15
do donate their time and energy to community projects.
Solution
Given X~Binomial(n=15, p=0.4) P(X=x)=xC15*(0.4^x)*(0.6^(15-x)) SO the
probability is P(X>7)=P(X=8)+P(X=9)+...+P(X=15)=0.2131032.
about 13 of the population is nervous around strangers. If 2 peopl.pdf
about 13% of the population is nervous around strangers. If 2 people are randomally seclected,
what is the probability that both are nervous around strangers?
Solution
P(nervous around stranger)=0.07
(a)P(Both will be nervous around stranger)=P(nervous around stranger)*P(nervous around
stranger)
=0.07*0.07=0.0049
(B) P(atleast one will be nervous)=1-P(none will be nercvous)
=1-0.93*0.93=0.1351.
ABC’s return on equity is above the industry average. At the same ti.pdf
ABC’s return on equity is above the industry average. At the same time, both its profit margin
and its debt ratio are below the industry average. Which of the following statements is
CORRECT?
Its total assets turnover must be above the industry average.
Its return on assets must equal the industry average.
Its TIE ratio must be below the industry average.
Its total assets turnover must be below the industry average.
Its total assets turnover must equal the industry average.
Its total assets turnover must be above the industry average.
Its return on assets must equal the industry average.
Its TIE ratio must be below the industry average.
Its total assets turnover must be below the industry average.
Its total assets turnover must equal the industry average.
Solution
According to Dupont Analysis
Return on Equity, ROE = Profit Margin (Profit/Sales) * Total Asset Turnover (Sales/Assets) *
Equity Multiplier (Assets/Equity)
Equity Multiplier, EM = (Debt(D) + Equity(E))/ Equity(E)
(as Asset(A) = D+E)
EM =1 + D/E => D/E = EM - 1
Debt Ratio(DR) = D/A => 1/DR = A/D = (D+E)/D = 1 + E/D = 1 + 1/(D/E) = 1 + 1/(EM-1)
1/DR = (EM -1 + 1)/(EM-1) = EM/(EM-1) => DR = (EM-1)/EM
So EM = 1/(1-DR)
So ROE = Profit Margin(PM) * Total Asset Turnover * 1/(1-DR)
So Total Asset Turnover = ROE/(PM * 1/(1-DR)) = ROE*(1-DR)/PM
So Total Asset Turnover will increase if ROE is high; DR is low & PM is low which is the case
in this question
So Option 1 is correct..
Abigail, Bart, Carol, Dan, Ehud, Fred, Golda, Hiro, and Juan are to .pdf
Abigail, Bart, Carol, Dan, Ehud, Fred, Golda, Hiro, and Juan are to be seated at a circular table.
As usual, two seating arrangements are considered different exactly when someone has a
different person to his or her right. If Fred can not be seated next to Ehud or Golda, how many
different seating arrangments are possible?
Thanks in advance
Solution
It doesn\'t matter where the first person sits; that person is a frame of reference.
Let\'s have Abigail be the frame of reference. Bart then has 8 possible choices for where he can
sit. Carol has 7. Dan has 6. Ehud has 5. Fred (we\'ll get back to him later). Golda has 4, Hiro 3,
and Juan 2. Fred then is left with one spot left. 2/9 of this time (on average), he will be next to
Ehud, Golda, or both of them. So, if we take 8! then multiply that by 7/9, we\'ll get how many
arrangements there are at the table total. 8! * 7 / 9 = 31360..
ABC Corp. has a fixed rate asset for which the firm receives an inte.pdf
ABC Corp. has a fixed rate asset for which the firm receives an interest rate of 5%. The firm
enters into an interest rate swap on the same notional principal as the fixed rate debt. In the swap,
the firm pays 4% and receives LIBOR. What is the effective cash inflow that the firm receives
with the interest rate swap?
a. 4%
b. 5%
c. 6%
d. LIBOR+1%
e. LIBOR-1%
Solution
Interest received = 5%
pays = 4%
effective cash inflow = 5%-4% = 1%
= LIBOR + 1%.
ABC Airlines operates 50 seat planes between Albany and Boston. For .pdf
ABC Airlines operates 50 seat planes between Albany and Boston. For tomorrow
Solution
PLEASE RATE ME AND AWARD ME KARMA POINTS IF IT IS HELPFUL
FOR YOU Albany after the capital of New York; both were located at the navigable heads of
rivers. Alexander Shotwell laid out the town in 1836. It was incorporated as a city by an act of
the General Assembly of Georgia on December 27, 1838.[7] Tift for decades was its leading
entrepreneur. An ardent booster, he promoted education, business, and railroad construction.
During the Civil War he provided naval supplies and helped build two ships. He opposed Radical
Reconstruction inside the state and in Congress and was scornful of the Yankee.
A.What is the sensitivity of self-reported smoking statusSolut.pdf
A.What is the sensitivity of self-reported smoking status?
Solution
Assessment of validity of self-reported smoking status by Suzy L. Wong, Margot
Shields, Scott Leatherdale, Eric Malaison and David Hammond The health risks associated with
cigarette smoking are well-documented and widely recognized—cancer, respiratory illness, heart
disease, and stroke.1-3 In Canada, smoking contributes to more than 37,000 deaths a year.4
Tobacco-related health care expenditures amount to billions of dollars annually, with additional
indirect costs such as lost productivity, longer-term disability and premature death.4 Self-
reported data are typically used to monitor trends in cigarette smoking.5-7 However, estimates
based on self-report, particularly of socially undesirable behaviours, are subject to reporting
biases.8 The widespread implementation of legislation prohibiting smoking in workplaces and
public areas9 and prominent health warnings on cigarette packages may reinforce the perception
of smoking as socially undesirable, and thereby increased the tendency to underreport over time.
To validate self-reported smoking status, the urinary concentration of cotinine, a widely accepted
objective measure of exposure to tobacco smoke,10 has been used. Cotinine is the major
metabolite of nicotine, with a half-life of about 16 to 20 hours.11 Because of its high sensitivity
and specificity, cotinine is considered to be an accurate quantitative measure of recent exposure
to tobacco smoke.12 Compared with estimates based on cotinine concentration, smoking
prevalence based on self-report, is generally lower,13 although the extent of the difference varies
by country.14 The validity of self-reported cigarette smoking data have yet to be determined for
Canada. Thus, this study compares estimates of the prevalence of cigarette smoking based on
self-report with estimates based on urinary cotinine concentrations. The data are from the 2007
to 2009 Canadian Health Measures Survey, which included self-reported smoking status and the
first nationally representative measures of urinary cotinine. Methods Data source The Canadian
Health Measures Survey (CHMS) is a nationally representative survey of the household
population. Data for cycle 1 were collected from March 2007 through February 2009 at 15 sites
across the country for respondents aged 6 to 79. Full-time members of the Canadian Forces and
residents of Crown lands, Indian reserves, institutions and certain remote regions were excluded.
The sample represented approximately 96% of the population.15 The CHMS consisted of a
household interview during which information about socio- demographic characteristics, health
and lifestyle was gathered. This was followed by a visit to a mobile examination centre where
direct measurements, including the collection of urine samples, were taken. Of the households
selected for the survey, 69.6% agreed to participate. One or two members of each responding
household were invited to take p.
a. Made a Type I errorb. Made a Type II errorc. Made a correc.pdf
a. Made a Type I error
b. Made a Type II error
c. Made a correct decision
d. Increased the power of the test
Solution
we rejected a true null A type I error, also known as a false positive, occurs when a
statistical test rejects a true null hypothesis so a..
A.Their presence indicates that the standard error of the model is u.pdf
A.Their presence indicates that the standard error of the model is understated and the model is
unreliable.
B. They indicate that the model may be subject to Type I error.
C. They indicate that the residuals are not normally distributed.
D. 1 and 2 above.
E. None of the above.Why are heteroscedasticity, multicollinearity and serial correlation a
problem in regression model reliability?
Solution
ANSWER IS D.
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https://meetups.mulesoft.com/events/details/mulesoft-mysore-presents-exploring-gemini-ai-and-integration-with-mulesoft/
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● Which MuleSoft products are in scope?
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YouTube:- youtube.com/@mulesoftmysore
Mysore WhatsApp group:- https://chat.whatsapp.com/EhqtHtCC75vCAX7gaO842N
Speaker:-
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Priya Shaw - https://www.linkedin.com/in/priya-shaw
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Giridhar Meka - https://www.linkedin.com/in/giridharmeka
Priya Shaw - https://www.linkedin.com/in/priya-shaw
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about 20 of babies born with a certian ailment recover fully, A hos.pdf
about 20% of babies born with a certian ailment recover fully, A hospital is caring for five babies
bornh with this ailment. the random varialble represents the number of babais that recover fully.
decide weather the experiment is a binomial experiment, if it is identify the a succsess, specify
the values of n, q, p, and list the possible variable of x
Solution
n=5, p=0.2 q=1-p=1-0.2=0.8 the possible variable of x: 0,1,2,3,4,5.
About 40 of the general population ddonate their time and energy to.pdf
About 40% of the general population ddonate their time and energy to community projects.
suppose 15 people have been randomly selected fron a community and each asked if they
donated their time and energy to community projects. Let x be the number of them that do donate
their time and energy to community projects. Find the probability that more than seven of the15
do donate their time and energy to community projects.
Solution
Given X~Binomial(n=15, p=0.4) P(X=x)=xC15*(0.4^x)*(0.6^(15-x)) SO the
probability is P(X>7)=P(X=8)+P(X=9)+...+P(X=15)=0.2131032.
about 13 of the population is nervous around strangers. If 2 peopl.pdf
about 13% of the population is nervous around strangers. If 2 people are randomally seclected,
what is the probability that both are nervous around strangers?
Solution
P(nervous around stranger)=0.07
(a)P(Both will be nervous around stranger)=P(nervous around stranger)*P(nervous around
stranger)
=0.07*0.07=0.0049
(B) P(atleast one will be nervous)=1-P(none will be nercvous)
=1-0.93*0.93=0.1351.
ABC’s return on equity is above the industry average. At the same ti.pdf
ABC’s return on equity is above the industry average. At the same time, both its profit margin
and its debt ratio are below the industry average. Which of the following statements is
CORRECT?
Its total assets turnover must be above the industry average.
Its return on assets must equal the industry average.
Its TIE ratio must be below the industry average.
Its total assets turnover must be below the industry average.
Its total assets turnover must equal the industry average.
Its total assets turnover must be above the industry average.
Its return on assets must equal the industry average.
Its TIE ratio must be below the industry average.
Its total assets turnover must be below the industry average.
Its total assets turnover must equal the industry average.
Solution
According to Dupont Analysis
Return on Equity, ROE = Profit Margin (Profit/Sales) * Total Asset Turnover (Sales/Assets) *
Equity Multiplier (Assets/Equity)
Equity Multiplier, EM = (Debt(D) + Equity(E))/ Equity(E)
(as Asset(A) = D+E)
EM =1 + D/E => D/E = EM - 1
Debt Ratio(DR) = D/A => 1/DR = A/D = (D+E)/D = 1 + E/D = 1 + 1/(D/E) = 1 + 1/(EM-1)
1/DR = (EM -1 + 1)/(EM-1) = EM/(EM-1) => DR = (EM-1)/EM
So EM = 1/(1-DR)
So ROE = Profit Margin(PM) * Total Asset Turnover * 1/(1-DR)
So Total Asset Turnover = ROE/(PM * 1/(1-DR)) = ROE*(1-DR)/PM
So Total Asset Turnover will increase if ROE is high; DR is low & PM is low which is the case
in this question
So Option 1 is correct..
Abigail, Bart, Carol, Dan, Ehud, Fred, Golda, Hiro, and Juan are to .pdf
Abigail, Bart, Carol, Dan, Ehud, Fred, Golda, Hiro, and Juan are to be seated at a circular table.
As usual, two seating arrangements are considered different exactly when someone has a
different person to his or her right. If Fred can not be seated next to Ehud or Golda, how many
different seating arrangments are possible?
Thanks in advance
Solution
It doesn\'t matter where the first person sits; that person is a frame of reference.
Let\'s have Abigail be the frame of reference. Bart then has 8 possible choices for where he can
sit. Carol has 7. Dan has 6. Ehud has 5. Fred (we\'ll get back to him later). Golda has 4, Hiro 3,
and Juan 2. Fred then is left with one spot left. 2/9 of this time (on average), he will be next to
Ehud, Golda, or both of them. So, if we take 8! then multiply that by 7/9, we\'ll get how many
arrangements there are at the table total. 8! * 7 / 9 = 31360..
ABC Corp. has a fixed rate asset for which the firm receives an inte.pdf
ABC Corp. has a fixed rate asset for which the firm receives an interest rate of 5%. The firm
enters into an interest rate swap on the same notional principal as the fixed rate debt. In the swap,
the firm pays 4% and receives LIBOR. What is the effective cash inflow that the firm receives
with the interest rate swap?
a. 4%
b. 5%
c. 6%
d. LIBOR+1%
e. LIBOR-1%
Solution
Interest received = 5%
pays = 4%
effective cash inflow = 5%-4% = 1%
= LIBOR + 1%.
ABC Airlines operates 50 seat planes between Albany and Boston. For .pdf
ABC Airlines operates 50 seat planes between Albany and Boston. For tomorrow
Solution
PLEASE RATE ME AND AWARD ME KARMA POINTS IF IT IS HELPFUL
FOR YOU Albany after the capital of New York; both were located at the navigable heads of
rivers. Alexander Shotwell laid out the town in 1836. It was incorporated as a city by an act of
the General Assembly of Georgia on December 27, 1838.[7] Tift for decades was its leading
entrepreneur. An ardent booster, he promoted education, business, and railroad construction.
During the Civil War he provided naval supplies and helped build two ships. He opposed Radical
Reconstruction inside the state and in Congress and was scornful of the Yankee.
A.What is the sensitivity of self-reported smoking statusSolut.pdf
A.What is the sensitivity of self-reported smoking status?
Solution
Assessment of validity of self-reported smoking status by Suzy L. Wong, Margot
Shields, Scott Leatherdale, Eric Malaison and David Hammond The health risks associated with
cigarette smoking are well-documented and widely recognized—cancer, respiratory illness, heart
disease, and stroke.1-3 In Canada, smoking contributes to more than 37,000 deaths a year.4
Tobacco-related health care expenditures amount to billions of dollars annually, with additional
indirect costs such as lost productivity, longer-term disability and premature death.4 Self-
reported data are typically used to monitor trends in cigarette smoking.5-7 However, estimates
based on self-report, particularly of socially undesirable behaviours, are subject to reporting
biases.8 The widespread implementation of legislation prohibiting smoking in workplaces and
public areas9 and prominent health warnings on cigarette packages may reinforce the perception
of smoking as socially undesirable, and thereby increased the tendency to underreport over time.
To validate self-reported smoking status, the urinary concentration of cotinine, a widely accepted
objective measure of exposure to tobacco smoke,10 has been used. Cotinine is the major
metabolite of nicotine, with a half-life of about 16 to 20 hours.11 Because of its high sensitivity
and specificity, cotinine is considered to be an accurate quantitative measure of recent exposure
to tobacco smoke.12 Compared with estimates based on cotinine concentration, smoking
prevalence based on self-report, is generally lower,13 although the extent of the difference varies
by country.14 The validity of self-reported cigarette smoking data have yet to be determined for
Canada. Thus, this study compares estimates of the prevalence of cigarette smoking based on
self-report with estimates based on urinary cotinine concentrations. The data are from the 2007
to 2009 Canadian Health Measures Survey, which included self-reported smoking status and the
first nationally representative measures of urinary cotinine. Methods Data source The Canadian
Health Measures Survey (CHMS) is a nationally representative survey of the household
population. Data for cycle 1 were collected from March 2007 through February 2009 at 15 sites
across the country for respondents aged 6 to 79. Full-time members of the Canadian Forces and
residents of Crown lands, Indian reserves, institutions and certain remote regions were excluded.
The sample represented approximately 96% of the population.15 The CHMS consisted of a
household interview during which information about socio- demographic characteristics, health
and lifestyle was gathered. This was followed by a visit to a mobile examination centre where
direct measurements, including the collection of urine samples, were taken. Of the households
selected for the survey, 69.6% agreed to participate. One or two members of each responding
household were invited to take p.
a. Made a Type I errorb. Made a Type II errorc. Made a correc.pdf
a. Made a Type I error
b. Made a Type II error
c. Made a correct decision
d. Increased the power of the test
Solution
we rejected a true null A type I error, also known as a false positive, occurs when a
statistical test rejects a true null hypothesis so a..
A.Their presence indicates that the standard error of the model is u.pdf
A.Their presence indicates that the standard error of the model is understated and the model is
unreliable.
B. They indicate that the model may be subject to Type I error.
C. They indicate that the residuals are not normally distributed.
D. 1 and 2 above.
E. None of the above.Why are heteroscedasticity, multicollinearity and serial correlation a
problem in regression model reliability?
Solution
ANSWER IS D.
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