A researcher was interested in studying Americans email habits. She .pdf
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A researcher was interested in studying Americans email habits. She suspected that Americans spend less than 7 hours a week answering their email.The General Social Survey in 2004 included a question that asked about the number of hours that the respondent spend on email per week. The General Social Survey in 2002 asked 1,264 respondents this question. The sample mean number of hours was 6.02 and the sample standard deviation was 7.80. Find the test statistic.A. 4.47 Solution Test Statistic Population Mean(U)=7 Sample X(Mean)=6.02 Standard Deviation(S.D)=7.8 Number (n)=1264 we use Test Statistic (t) = x-U/(s.d/Sqrt(n)) to =6.02-7/(7.8/Sqrt(1263)) to =-4.47 ANS:B.-4.47.
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Briefly explain four functions of stems. SolutionFunction of S.pdf
Briefly explain four functions of stems.
Solution
Function of Stems:
1. It helps store water , as in cacti, and the products of photosynthesis, as in the trunk of sago
palm (Metroxylon sagu) and sweet palm (Argenga pinnata) which store large stock of starch
2. Young green stem also performs a minor role in the production of food through the process of
photosynthesis, but in some species (e.g. cactus) the stem is the chief photosynthesizing organ
3. It supports the leaves, flowers and fruits and connect them with roots. In trees and shrubs the
main stem or trunk provides a strong columnar structure from which branches are attached
raising the leaves upward to be expressed more fully to the sun
4. The plant stem serves as a means of asexual reproduction in many species..
AVR was one of the first microcontroller families to use A. on-chip .pdf
AVR was one of the first microcontroller families to use A. on-chip flash memory for program
storage B. one-time programmable ROM, EPROM, or EEPROM C. both A and B
EMBEDDED SYSTEMS is a computer system with a dedicated function within a larger A.
digital and logical system B. mechanical or electrical system C. both A and B An integrated
circuit that contains all the functions of a central processing unit of a computer is A.
Microprocessor B. Microcontroller C. Both A and b A main system bus, ram, rom/flash, and
typically a set of other devices such as a programmable interrupt controller, analog/digital
converters, any number of general purpose 10 devices A. Microcontroller B. Microprocessor
C. None of the above ASSEMBLY LANGUAGE is an assembly (or assembler) language, often
abbreviated asm, is a A. low-level programming language for a computer B. high-level
programming language for a computer A. C. both A and B
Solution
AVR was one of the first micro controller families to use on chipflash memory for program
storage
Embedded syatems are mechanical or electrical syatems
An integrated circuit that has all functions of a cpu is micro processor
Assembler language is low level programming language for a computer
A main system........... Micro processor.
Complete the implementation of the binary search tree started in cla.pdf
Complete the implementation of the binary search tree started in class. You know you are done
when the main function runs correctly with all commented lines uncommented, and printing
shows the expected behavior of a BST.
CODE:
# TODO: implement inorder
# TODO: implement find
# TODO: implement maximum, minimum
# TODO: implement successor, predecessor
# TODO: implement delete
def main():
bst = Node(3, None)
for k in [5, 7, 4, 5, 6]:
bst.insert(k)
# print(bst.inorder())
# for k in [4, 3, 6, 2, 1, 7]:
# print(\"find {}: {}\".format(k, bst.find(k) != None))
# for k in [4,3, 2]:
# n = bst.find(k)
# if n != None:
# s = n.successor()
# print(\"successor of {}: {}\".format(k, s.key if s != None else None))
# s = n.predecessor()
# print(\"predecessor of {}: {}\".format(k, s.key if s != None else None))
# s = n.delete()
# print(\"deleted {}\".format(s.key))
# print(bst.inorder())
class Node:
def __init__(self, key, parent):
self.key = key # self is Python for \"this\"
self.parent = parent
self.left = None
self.right = None
def inorder(self):
\'\'\'returns list of the keys in an inorder traversal of the tree rooted at self\'\'\'
# TODO: replace \"pass\" keyword with actual code
# Hint: li.append(value) appends a value to list li
# Hint: li = list1 + list2 returns the concatnenation of list1 and list2
# Hint: use dot notation to call method: inorder(node) ---> node.inorder()
# To test: uncomment line 10 and click \"Run\"
li = [] # empty list
if self.left is not None:
pass
pass
if self.right is not None:
pass
return li
def insert(self, key):
\'\'\'inserts a new node with given key into subtree rooted at self node\'\'\'
if key < self.key:
if self.left is None: # None is Python for null, \"is\" = \"==\", \"is not\" = \"!=\"
self.left = Node(key, self)
else:
self.left.insert(key)
else:
if self.right is None:
self.right = Node(key, self)
else:
self.right.insert(key)
def find(self, key):
\'\'\'returns a node in the subtree rooted at self with this key or
None if no such key exists\'\'\'
# Hint: similar to insert()
# Test: uncomment lines 11 and 12, click \"Run\"
pass
def minimum(self):
\'\'\'returns the node with minimum key in the subtree rooted at self\'\'\'
pass
def maximum(self):
\'\'\'returns the node with maximum key in the is subtree rooted at self\'\'\'
pass
def successor(self):
\'\'\'returns successor of the self node or None if it does not have one\'\'\'
# TODO: fill the if statement
if self.right is not None:
pass
c, p = self, self.parent
while p is not None and c is p.right:
c, p = p, p.parent
return p
def predecessor(self):
\'\'\'returns the predecessor of the self node or None if it does not have one\'\'\'
pass
def delete(self):
\'\'\'deletes the self node from the tree and returns that node\'\'\'
parent, left, right = self.parent, self.left, self.right
# case 0: no children
if left is None and right is None:
if parent is not None:
if self is parent.left:
parent.left = None
else:
parent.right = None
return self
# case 1: one or two children, no pa.
A 50 mL stock sample of cells is diluted 110 six times. If 0.1 mL o.pdf
A 50 mL stock sample of cells is diluted 1/10 six times. If 0.1 mL of the most dilute sample
generates 75 colonies on an agar plate, calculate the original concentration of bacteria present in
the original sample?
Solution
Answer:
Given:
Dilution factor= 1/10^6
Number of colonies= 75
Volume of sample = 0.1 mL to the plate
CFU/ml = ?
cfu/ml = (no. of colonies)/ dilution factor x volume of culture plate
cfu/ml = (75)/ (1/10^6 x 0.1)
cfu/ml = 75 x 10^7.
Why are clocks (or timers) discussed in the context of IO systems.pdf
Why are clocks (or timers) discussed in the context of I/O systems?
Solution
1) Time operations are not standard across all systems.
2) A timer can be used to trigger operations and to measure elapsed time. It can be set to trigger
an interrupt at a specific future time, or to trigger interrupts periodically on a regular basis to take
place.
3) Provide current time, elapsed time, etc..
why the SSB receiver re-injects the missing carrier Why add the c.pdf
why the SSB receiver re-injects the missing carrier? Why add the carrier back in after
downshifting the incoming modulated signal instead of before
why the SSB receiver re-injects the missing carrier? Why add the carrier back in after
downshifting the incoming modulated signal instead of before
Solution
Re-injection of carrier is done by BFO,this re-injection of carrier allows easy de-modulation of
RF and even IF signal also.if injected carrier is at the wrong frequencyrelative to the station then
the audiio will become disorted..
80 µl of 10^-5 dilution of E. coli culture was plated on LB agar and.pdf
80 µl of 10^-5 dilution of E. coli culture was plated on LB agar and incubated at 37 degree
Celsius overnight. Next day, you observed 212 colonies on this plate. Based on this information,
calculate the viable count (cfu/mL) of the original E. coli culture.
Solution
Colony forming units (CFU)/mL (from plate C) = (no. of colonies x dilution factor) / volume of
culture plate
Number of colonies observed is = 212
Dilution factor is = 10^5
Volume of culture plate =80 µl
Colony forming units (CFU)/mL (from plate C) = 212*10^5/ 0.08 ml
= 26.50* 10^7 CFU/ml.
Which of the following statements about pyruvate is most accurate P.pdf
Which of the following statements about pyruvate is most accurate? Pyruvate can be produced
only from carbohydrates; Pyruvate dehydrogenase complex does not belong to the Krebs cycle.
Therefore, pyruvate dehydrogenase is not a step-controlling enzyme for the Krebs cycle;
Pyruvate can be reversibly converted to phosphoenolpyruvate by pyruvate kinase; Pyruvate is a
main precursor of oxaloacetate in the Krebs cycle; Pyruvate dehydrogenase converts pyruvate to
acetyl CoA and generates one NADH that is equivalent to 2ATP if the NADH is transferred to
mitochondria via glycerol 3-phosphate shuttle system.
Solution
Correct answer is B
Pyruvate dehydrogenase complex does not belong to Krebs Cycle.Therefore pyruvate
dehydrogenase is not a step controlling enzyme for krebs cycle.
PDH complex catalyses the conversion of Pyruvate into Acetyl CoA. Acetyl CoA then enters
Krebs cycle and forms oxaloacetate. Therefore action of PDH comples does not determine the
control of krebs cycle,..
Recommended
Briefly explain four functions of stems. SolutionFunction of S.pdf
Briefly explain four functions of stems.
Solution
Function of Stems:
1. It helps store water , as in cacti, and the products of photosynthesis, as in the trunk of sago
palm (Metroxylon sagu) and sweet palm (Argenga pinnata) which store large stock of starch
2. Young green stem also performs a minor role in the production of food through the process of
photosynthesis, but in some species (e.g. cactus) the stem is the chief photosynthesizing organ
3. It supports the leaves, flowers and fruits and connect them with roots. In trees and shrubs the
main stem or trunk provides a strong columnar structure from which branches are attached
raising the leaves upward to be expressed more fully to the sun
4. The plant stem serves as a means of asexual reproduction in many species..
AVR was one of the first microcontroller families to use A. on-chip .pdf
AVR was one of the first microcontroller families to use A. on-chip flash memory for program
storage B. one-time programmable ROM, EPROM, or EEPROM C. both A and B
EMBEDDED SYSTEMS is a computer system with a dedicated function within a larger A.
digital and logical system B. mechanical or electrical system C. both A and B An integrated
circuit that contains all the functions of a central processing unit of a computer is A.
Microprocessor B. Microcontroller C. Both A and b A main system bus, ram, rom/flash, and
typically a set of other devices such as a programmable interrupt controller, analog/digital
converters, any number of general purpose 10 devices A. Microcontroller B. Microprocessor
C. None of the above ASSEMBLY LANGUAGE is an assembly (or assembler) language, often
abbreviated asm, is a A. low-level programming language for a computer B. high-level
programming language for a computer A. C. both A and B
Solution
AVR was one of the first micro controller families to use on chipflash memory for program
storage
Embedded syatems are mechanical or electrical syatems
An integrated circuit that has all functions of a cpu is micro processor
Assembler language is low level programming language for a computer
A main system........... Micro processor.
Complete the implementation of the binary search tree started in cla.pdf
Complete the implementation of the binary search tree started in class. You know you are done
when the main function runs correctly with all commented lines uncommented, and printing
shows the expected behavior of a BST.
CODE:
# TODO: implement inorder
# TODO: implement find
# TODO: implement maximum, minimum
# TODO: implement successor, predecessor
# TODO: implement delete
def main():
bst = Node(3, None)
for k in [5, 7, 4, 5, 6]:
bst.insert(k)
# print(bst.inorder())
# for k in [4, 3, 6, 2, 1, 7]:
# print(\"find {}: {}\".format(k, bst.find(k) != None))
# for k in [4,3, 2]:
# n = bst.find(k)
# if n != None:
# s = n.successor()
# print(\"successor of {}: {}\".format(k, s.key if s != None else None))
# s = n.predecessor()
# print(\"predecessor of {}: {}\".format(k, s.key if s != None else None))
# s = n.delete()
# print(\"deleted {}\".format(s.key))
# print(bst.inorder())
class Node:
def __init__(self, key, parent):
self.key = key # self is Python for \"this\"
self.parent = parent
self.left = None
self.right = None
def inorder(self):
\'\'\'returns list of the keys in an inorder traversal of the tree rooted at self\'\'\'
# TODO: replace \"pass\" keyword with actual code
# Hint: li.append(value) appends a value to list li
# Hint: li = list1 + list2 returns the concatnenation of list1 and list2
# Hint: use dot notation to call method: inorder(node) ---> node.inorder()
# To test: uncomment line 10 and click \"Run\"
li = [] # empty list
if self.left is not None:
pass
pass
if self.right is not None:
pass
return li
def insert(self, key):
\'\'\'inserts a new node with given key into subtree rooted at self node\'\'\'
if key < self.key:
if self.left is None: # None is Python for null, \"is\" = \"==\", \"is not\" = \"!=\"
self.left = Node(key, self)
else:
self.left.insert(key)
else:
if self.right is None:
self.right = Node(key, self)
else:
self.right.insert(key)
def find(self, key):
\'\'\'returns a node in the subtree rooted at self with this key or
None if no such key exists\'\'\'
# Hint: similar to insert()
# Test: uncomment lines 11 and 12, click \"Run\"
pass
def minimum(self):
\'\'\'returns the node with minimum key in the subtree rooted at self\'\'\'
pass
def maximum(self):
\'\'\'returns the node with maximum key in the is subtree rooted at self\'\'\'
pass
def successor(self):
\'\'\'returns successor of the self node or None if it does not have one\'\'\'
# TODO: fill the if statement
if self.right is not None:
pass
c, p = self, self.parent
while p is not None and c is p.right:
c, p = p, p.parent
return p
def predecessor(self):
\'\'\'returns the predecessor of the self node or None if it does not have one\'\'\'
pass
def delete(self):
\'\'\'deletes the self node from the tree and returns that node\'\'\'
parent, left, right = self.parent, self.left, self.right
# case 0: no children
if left is None and right is None:
if parent is not None:
if self is parent.left:
parent.left = None
else:
parent.right = None
return self
# case 1: one or two children, no pa.
A 50 mL stock sample of cells is diluted 110 six times. If 0.1 mL o.pdf
A 50 mL stock sample of cells is diluted 1/10 six times. If 0.1 mL of the most dilute sample
generates 75 colonies on an agar plate, calculate the original concentration of bacteria present in
the original sample?
Solution
Answer:
Given:
Dilution factor= 1/10^6
Number of colonies= 75
Volume of sample = 0.1 mL to the plate
CFU/ml = ?
cfu/ml = (no. of colonies)/ dilution factor x volume of culture plate
cfu/ml = (75)/ (1/10^6 x 0.1)
cfu/ml = 75 x 10^7.
Why are clocks (or timers) discussed in the context of IO systems.pdf
Why are clocks (or timers) discussed in the context of I/O systems?
Solution
1) Time operations are not standard across all systems.
2) A timer can be used to trigger operations and to measure elapsed time. It can be set to trigger
an interrupt at a specific future time, or to trigger interrupts periodically on a regular basis to take
place.
3) Provide current time, elapsed time, etc..
why the SSB receiver re-injects the missing carrier Why add the c.pdf
why the SSB receiver re-injects the missing carrier? Why add the carrier back in after
downshifting the incoming modulated signal instead of before
why the SSB receiver re-injects the missing carrier? Why add the carrier back in after
downshifting the incoming modulated signal instead of before
Solution
Re-injection of carrier is done by BFO,this re-injection of carrier allows easy de-modulation of
RF and even IF signal also.if injected carrier is at the wrong frequencyrelative to the station then
the audiio will become disorted..
80 µl of 10^-5 dilution of E. coli culture was plated on LB agar and.pdf
80 µl of 10^-5 dilution of E. coli culture was plated on LB agar and incubated at 37 degree
Celsius overnight. Next day, you observed 212 colonies on this plate. Based on this information,
calculate the viable count (cfu/mL) of the original E. coli culture.
Solution
Colony forming units (CFU)/mL (from plate C) = (no. of colonies x dilution factor) / volume of
culture plate
Number of colonies observed is = 212
Dilution factor is = 10^5
Volume of culture plate =80 µl
Colony forming units (CFU)/mL (from plate C) = 212*10^5/ 0.08 ml
= 26.50* 10^7 CFU/ml.
Which of the following statements about pyruvate is most accurate P.pdf
Which of the following statements about pyruvate is most accurate? Pyruvate can be produced
only from carbohydrates; Pyruvate dehydrogenase complex does not belong to the Krebs cycle.
Therefore, pyruvate dehydrogenase is not a step-controlling enzyme for the Krebs cycle;
Pyruvate can be reversibly converted to phosphoenolpyruvate by pyruvate kinase; Pyruvate is a
main precursor of oxaloacetate in the Krebs cycle; Pyruvate dehydrogenase converts pyruvate to
acetyl CoA and generates one NADH that is equivalent to 2ATP if the NADH is transferred to
mitochondria via glycerol 3-phosphate shuttle system.
Solution
Correct answer is B
Pyruvate dehydrogenase complex does not belong to Krebs Cycle.Therefore pyruvate
dehydrogenase is not a step controlling enzyme for krebs cycle.
PDH complex catalyses the conversion of Pyruvate into Acetyl CoA. Acetyl CoA then enters
Krebs cycle and forms oxaloacetate. Therefore action of PDH comples does not determine the
control of krebs cycle,..
Which CLI modes let you use the show running-config commandA. Use.pdf
Which CLI modes let you use the show running-config command?
A. User
B. Privileged
C. Global Configuration
D. Setup
E. All of the above
Solution
B is correct. You can run the show running-config command in Privileged (Enable) modes.
A, C, D, and E are incorrect. A, C, and D are incorrect because the show running-
configcommand is not available in these modes. E is incorrect because choices A, C, and D are
incorrect..
What is meant by star activity with respect to a restriction enz.pdf
What is meant by \"star activity\" with respect to a restriction enzyme.
I just need a 1-2 sentence explanation
Solution
1. Star activity is a general property of Restriction endonuclease.
2. During some non-standard reaction conitions, specific restriction enzymes are can cleave the
sequences which are similar , but not identical ,to their efined recognition seqences.
3.Such kind of soecificity has been calle \" Star activity\"..
Type III hypersensitivities are also referred to as immune complex me.pdf
Type III hypersensitivities are also referred to as immune complex mediated hypersensitivities.
Which cell is responsible for clearing the antibody-antigen complexes that are formed? In type I
hypersensitivity, prior sensitization to the antigen/allergen is not required because it\'s an
immediate type of reaction. True False Which cell types participate in antibody mediated
attacks of either cells or red blood cells in type II hypersensitivities?
Solution
Hypersensitive is the group of unfavourable reactions produced by the normal Immune system. It
includes allergies and Autoimmunity. Type-III immunity is immune complex mediated diseases
that include Serum sickness, Rheumatoid arthritis etc. The mediators are IgG, complement and
Neutrophills.
7. Answer is Macrophages.
8. False: Prior sensitization with allergin, leads to IgE production, then they bind to mast cells.
Again encounter wits same allergin, bind to these mast cell bound IgE. Finally leads to
degranulation and Type-1 hypersensitivity.
9. All three types of cells: Macrophages, NK cells and Neutrophils.
True, False, Uncertain with Explanation(a) Including an interacti.pdf
True, False, Uncertain with Explanation:
(a) Including an interaction term between two independent variables, X1 and X2, allows for the
measurement of the effect of a unit increase in X1 and X2, above and beyond the sum of the
individual effects of a unit increase in the two variables alone.
Solution
When an interaction is present, the lines in a graph of the means will not be parallel. Another
way of describing the interaction is to say that the effects of one factor are not the same at all
levels of the other factor.Also we woll say that “the simple effects are different,” because a
simple effect looks at the effects of one factor at each level of the other factor.
An interaction effect is a change in the simple main effect of one variable over levels of the
second. An A X B or A BY B interaction is a change in the simple main effect of B over levels
of A or the change in the simple main effect of A over levels of B.In either case the cell means
cannot be modeled simply by knowing the size of the main effects. An additional set of
parameters must be used to explain the differences between the cell means. These parameters are
collectively called an interaction.
If interaction is significant, determine whether interactions are important. If not, can examine
main effects
If interaction present & important, determine whether interaction is simple or complex.
. For simple interactions, can still talk about the main effects of A at each level of B
For complex interaction, must simply consider all pairs of levels as separate treatments.
If interaction effects are very small compared to main effects or only apparent in a small number
of treatments, then they are probably unimportant.
We can proceed by keeping interaction in the model, but using marginal means for each
significant main effect individually
The interaction effect is so large and/or pervasive that main effects cannot be interpreted on their
own.
This is TRUE statement..
Traits that are detrimental to the long-term survival of an individu.pdf
Traits that are detrimental to the long-term survival of an individual can occur in a population
(select all that apply):
a. if they arise due to a mutation.
b. Never
c. when the trait increases an individual\'s chance of reproducing.
d. because there has to be variation in the population.
e. if they enter the population through gene flow from another habitat where the traits are
favorable.
Solution
a. if they arise due to a mutation.
d. because there has to be variation in the population..
The sampling distribution of the sample mean is the probability dist.pdf
The sampling distribution of the sample mean is the probability distribution of all
a. the sample statistics and their probability of occurrence..
b. the normal population parameters and their probability of occurrence..
c. the possible sample means and their probability of occurrence.
d. sample means.
Solution
sample means..
The lantana has which inflorescence morphology type campanulte tub.pdf
The lantana has which inflorescence morphology type? campanulte tubular cruciform rotate
ligulate The rose has which inflorescence morphology type? campanulte tubular cruciform
rotate ligulate The fig is which type of fruit? Simple - Legume Simple - Drupe Simple - Berry
Multiple Aggregate
Solution
19- lantana has campanulate inflorescence
20-Rotate
21-Multiple fruit or false fruit.
The intensity of the sound of traffic at a busy intersection was mea.pdf
The intensity of the sound of traffic at a busy intersection was measured at 2.0 × 101 W/m2. Find
the decibel level. (Round your answer to the nearest whole number.)
Solution
Sound intensity of traffic at a busy intersection is given by I = 2×10^1 W/m².
Now,
Reference sound intensity Io = 10^12 W/m² (Threshold of hearing)
Reference sound intensity level LIo = 0 dB (Threshold of hearing level)
we need to find sound intensity level LI in dB when entering sound intensity I = 2×10^1 W/m².
Sound intensity level LI = 10×log (I / Io) dB = 10×log (2×10^1 / 10^12)=10*11.30 dB
= 113.01 dB
=113dB on round off.
The garden pea is described as self-fertilizing. What does this .pdf
The garden pea is described as \"self-fertilizing.\" What does this mean and why was this
significant to the success of Mendel\'s inheritance experiments?
Solution
The pea plant which Mendel chose for conducting experiments, is most ideal for controlled
breeding, since it can easily be subjected to cross pollination as well as self pollination. This
gives the success to Mendel\'s inheritance experiments.
The main other resons for mendal success are.
The equation for the time of one swing of a pendulum is given by T = .pdf
The equation for the time of one swing of a pendulum is given by T = 2 pi Squareroot L/32
where T is the time in seconds, pi almostequalto 3.14, & L is the length in feet. What is the
length of the pendulum if it makes one (1) swing in 4 seconds, according to the formula?
Solution
T=2*pi*(L/32)^.5
Squaring on both sides
(T/(2*pi))^2=L/32
Given time =4 sec
L/32= (4/(2pi))^2
L/32= 4/10
L=128/10
L=12.8
Length of pendulum =12.8 units
L/32=.
The assumption that arrivals follow a Poisson probability distributi.pdf
The assumption that arrivals follow a Poisson probability distribution is equivalent to the
assumption that the time between arrivals has
a normal probability distribution
an exponential probability distribution
a uniform probability distribution
a Poisson probability distributiona.
a normal probability distributionb.
an exponential probability distributionc.
a uniform probability distributiond.
a Poisson probability distribution
Solution
The assumption that arrivals follow a Poisson probability distribution is equivalent to the
assumption that the time between arrivals has b. an exponential probability distribution.
Some yeasts process xylitol and some cannot. The ability to process .pdf
Some yeasts process xylitol and some cannot. The ability to process xylitol is dominant… so
what would you cross a xylitol processing yeast with in other to determine if it is heterozygous
or homozygous dominant?
Solution
A xylitol processing yeast will be crossed with another xylitol processing yeast. If they are
homozygous dominant all offspring will be xylitol processing but if they are heterozygous
dominant then 25% of the offspring will not process xylitol..
Prove the identify on the left is equal to the right (sin x - cos x).pdf
Prove the identify on the left is equal to the right (sin x - cos x) (sin x + cos x^) = - cos x
Solution
(sinx-cosx)(sinx+cosx) = -cosx
the identity you have proved is wrong
you can verify it by substituting x = pi/4
sin(pi/4) = 1/sqrt(2)
cos(pi/4) = 1/sqrt(2)
sinx - cosx = 0
which makes lhs = 0
rhs = -cosx = -1/sqrt(2)
so the identity is wrong..
Please show all required work to get the solution. What is the unit .pdf
Please show all required work to get the solution. What is the unit impulse response h[n] for a
system having H[z] as given in the problem above? What type filter (LP, HP, BP or BE) best
describes the digital filter whose pole-zero plot is shown below? Assume the circle has unity
radius.
Solution
tf = 1/(s-a)2 + b2
it is band pass filter.
O’Sullivan’s arguments for annexation. How does he frame his support.pdf
O’Sullivan’s arguments for annexation. How does he frame his support for such a move and
How does he see the future of America?
Solution
Annexation (Latin ad, to, and nexus, joining) is the political transition of land from the control of
one entity to another. In international law it is the forcible transition of one state\'s territory by
another state or the legal process by which a city acquires land.
O Suulivan was an American columnist and editor who used the term \"manifest destiny\" in
1845 to promote the annexation of Texas and the Oregon Country to the United States.
O\'Sullivan was an influential political writer and advocate for the Democratic Party at that time
and served as US Minister to Portugal during the administration of President Franklin Pierce
(1853–1857), but he largely faded from prominence soon thereafter. He was rescued from
obscurity in the twentieth century after the famous phrase \"manifest destiny\" was traced back to
him..
28 Preganglionic sympathetic neurons arise from the thoracic and lumb.pdf
28 Preganglionic sympathetic neurons arise from the thoracic and lumbar regions of the spinal
cord. A) True B) False
Solution
The answer is True.
Two types of neurons involved in the transmission of any signal through the sympathetic system:
pre-ganglionic and post-ganglionic. The shorter neurorns are called as preganglionic neurons,
which are originate from the thoracolumbar region of the spinal cord specifically at T1 to L2~L3.
1a. Why are sulfur oxidizers obligate acidiphiles 1b. Why are Fe o.pdf
1a. Why are sulfur oxidizers obligate acidiphiles
1b. Why are Fe oxidizers obligate acidophiles
1c. What are sulfur granules and which type of respiratory bacteria accumulate them?
Solution
Ans1(a)
Acidothiobacillus are rod shaped Gramnegative bacteria which are obligate acidophillus because
they reduces sulfur for energy with pH less than 4. And its suevive at moderatetemprature (18 to
28degree c). its oxidation system reduced inorganic sulfur compounds (RISCs).so sulfur
oxidisers are obligate acidiphiles..
In python please help Write Python statements that print the values .pdf
In python please help Write Python statements that print the values of pi and the Euler constant e
in the shown formats: pi = 3.1, e + 2.7 pi = 3.14, e = 2.72 pi = 3.141593e+00, e =
2.718282e+00 pi = 3.14159, e = 2.71828
Solution
b) from collections import namedtuple
Constants = namedtuple(\'Constants\', [\'pi\', \'e\']).
In detail, compare and contrast epithelium and connective tissue..pdf
In detail, compare and contrast epithelium and connective tissue.
Solution
Answer:
Epithelial tissue
Connective tissue
consists of three cell types; squamous, cuboidal and columnar.
The tissue is two or more cells thick.
found above the basement membranes.
Functions to protect the body, secretions, excretions, absorption and allows the body to sense the
outside world.
Eg. Skin, kidney
The cells in the connective tissue are scattered in the matrix.
supplied with a rich network of nerves and blood capillaries
lies below the basal membrane.
Functions: supports, connects, binds or separates other tissues or organs.
Ex. Bone, ligament
Epithelial tissue
Connective tissue
consists of three cell types; squamous, cuboidal and columnar.
The tissue is two or more cells thick.
found above the basement membranes.
Functions to protect the body, secretions, excretions, absorption and allows the body to sense the
outside world.
Eg. Skin, kidney
The cells in the connective tissue are scattered in the matrix.
supplied with a rich network of nerves and blood capillaries
lies below the basal membrane.
Functions: supports, connects, binds or separates other tissues or organs.
Ex. Bone, ligament.
In 1994. the National Basketball Association changed the process of t.pdf
In 1994. the National Basketball Association changed the process of the draft lottery so that the
poorest teams had a much higher probability of getting an early pick. As of 2008. 16 teams
qualify for the playoffs and 14 participate in the draft. To determine the winner. 14 ping pong
balls numbered 1 to 14 arc placed in a hopper and thoroughly mixed. Then four balls arc
randomly selected from the hopper. The team holding the same four numbers, in any order, is
awarded the pick. As an example, if balls 3-5-1-2 were drawn, the team holding this combination
of numbers (1-2-3-5) w ins the pick. (If 11-12-13-14 is drawn, a new set of balls is drawn.) The
balls are returned to the hopper and another set of four balls is used to identify the team receiving
the second pick, ignoring any combinations that belong to the team receiving the first pick.
Similarly, the team receiving the third pick is identified. The remaining 11 teams are awarded the
remaining picks in order of their rankings. Ranking the teams from worst (1) to best (14). the
number of combinations awarded each team in the lottery is shown in the table that follows. Let
X be the pick the worst team gets from this lottery.
Solution.
special B.ed 2nd year old paper_20240531.pdf
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A. User
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C. Global Configuration
D. Setup
E. All of the above
Solution
B is correct. You can run the show running-config command in Privileged (Enable) modes.
A, C, D, and E are incorrect. A, C, and D are incorrect because the show running-
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What is meant by \"star activity\" with respect to a restriction enzyme.
I just need a 1-2 sentence explanation
Solution
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Type III hypersensitivities are also referred to as immune complex mediated hypersensitivities.
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Solution
Hypersensitive is the group of unfavourable reactions produced by the normal Immune system. It
includes allergies and Autoimmunity. Type-III immunity is immune complex mediated diseases
that include Serum sickness, Rheumatoid arthritis etc. The mediators are IgG, complement and
Neutrophills.
7. Answer is Macrophages.
8. False: Prior sensitization with allergin, leads to IgE production, then they bind to mast cells.
Again encounter wits same allergin, bind to these mast cell bound IgE. Finally leads to
degranulation and Type-1 hypersensitivity.
9. All three types of cells: Macrophages, NK cells and Neutrophils.
True, False, Uncertain with Explanation(a) Including an interacti.pdf
True, False, Uncertain with Explanation:
(a) Including an interaction term between two independent variables, X1 and X2, allows for the
measurement of the effect of a unit increase in X1 and X2, above and beyond the sum of the
individual effects of a unit increase in the two variables alone.
Solution
When an interaction is present, the lines in a graph of the means will not be parallel. Another
way of describing the interaction is to say that the effects of one factor are not the same at all
levels of the other factor.Also we woll say that “the simple effects are different,” because a
simple effect looks at the effects of one factor at each level of the other factor.
An interaction effect is a change in the simple main effect of one variable over levels of the
second. An A X B or A BY B interaction is a change in the simple main effect of B over levels
of A or the change in the simple main effect of A over levels of B.In either case the cell means
cannot be modeled simply by knowing the size of the main effects. An additional set of
parameters must be used to explain the differences between the cell means. These parameters are
collectively called an interaction.
If interaction is significant, determine whether interactions are important. If not, can examine
main effects
If interaction present & important, determine whether interaction is simple or complex.
. For simple interactions, can still talk about the main effects of A at each level of B
For complex interaction, must simply consider all pairs of levels as separate treatments.
If interaction effects are very small compared to main effects or only apparent in a small number
of treatments, then they are probably unimportant.
We can proceed by keeping interaction in the model, but using marginal means for each
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The interaction effect is so large and/or pervasive that main effects cannot be interpreted on their
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This is TRUE statement..
Traits that are detrimental to the long-term survival of an individu.pdf
Traits that are detrimental to the long-term survival of an individual can occur in a population
(select all that apply):
a. if they arise due to a mutation.
b. Never
c. when the trait increases an individual\'s chance of reproducing.
d. because there has to be variation in the population.
e. if they enter the population through gene flow from another habitat where the traits are
favorable.
Solution
a. if they arise due to a mutation.
d. because there has to be variation in the population..
The sampling distribution of the sample mean is the probability dist.pdf
The sampling distribution of the sample mean is the probability distribution of all
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b. the normal population parameters and their probability of occurrence..
c. the possible sample means and their probability of occurrence.
d. sample means.
Solution
sample means..
The lantana has which inflorescence morphology type campanulte tub.pdf
The lantana has which inflorescence morphology type? campanulte tubular cruciform rotate
ligulate The rose has which inflorescence morphology type? campanulte tubular cruciform
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Multiple Aggregate
Solution
19- lantana has campanulate inflorescence
20-Rotate
21-Multiple fruit or false fruit.
The intensity of the sound of traffic at a busy intersection was mea.pdf
The intensity of the sound of traffic at a busy intersection was measured at 2.0 × 101 W/m2. Find
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Solution
Sound intensity of traffic at a busy intersection is given by I = 2×10^1 W/m².
Now,
Reference sound intensity Io = 10^12 W/m² (Threshold of hearing)
Reference sound intensity level LIo = 0 dB (Threshold of hearing level)
we need to find sound intensity level LI in dB when entering sound intensity I = 2×10^1 W/m².
Sound intensity level LI = 10×log (I / Io) dB = 10×log (2×10^1 / 10^12)=10*11.30 dB
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The garden pea is described as \"self-fertilizing.\" What does this mean and why was this
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Solution
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The main other resons for mendal success are.
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T=2*pi*(L/32)^.5
Squaring on both sides
(T/(2*pi))^2=L/32
Given time =4 sec
L/32= (4/(2pi))^2
L/32= 4/10
L=128/10
L=12.8
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The assumption that arrivals follow a Poisson probability distribution is equivalent to the
assumption that the time between arrivals has
a normal probability distribution
an exponential probability distribution
a uniform probability distribution
a Poisson probability distributiona.
a normal probability distributionb.
an exponential probability distributionc.
a uniform probability distributiond.
a Poisson probability distribution
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The assumption that arrivals follow a Poisson probability distribution is equivalent to the
assumption that the time between arrivals has b. an exponential probability distribution.
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Some yeasts process xylitol and some cannot. The ability to process xylitol is dominant… so
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Prove the identify on the left is equal to the right (sin x - cos x) (sin x + cos x^) = - cos x
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(sinx-cosx)(sinx+cosx) = -cosx
the identity you have proved is wrong
you can verify it by substituting x = pi/4
sin(pi/4) = 1/sqrt(2)
cos(pi/4) = 1/sqrt(2)
sinx - cosx = 0
which makes lhs = 0
rhs = -cosx = -1/sqrt(2)
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Please show all required work to get the solution. What is the unit impulse response h[n] for a
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O’Sullivan’s arguments for annexation. How does he frame his support.pdf
O’Sullivan’s arguments for annexation. How does he frame his support for such a move and
How does he see the future of America?
Solution
Annexation (Latin ad, to, and nexus, joining) is the political transition of land from the control of
one entity to another. In international law it is the forcible transition of one state\'s territory by
another state or the legal process by which a city acquires land.
O Suulivan was an American columnist and editor who used the term \"manifest destiny\" in
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O\'Sullivan was an influential political writer and advocate for the Democratic Party at that time
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28 Preganglionic sympathetic neurons arise from the thoracic and lumb.pdf
28 Preganglionic sympathetic neurons arise from the thoracic and lumbar regions of the spinal
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Solution
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1a. Why are sulfur oxidizers obligate acidiphiles 1b. Why are Fe o.pdf
1a. Why are sulfur oxidizers obligate acidiphiles
1b. Why are Fe oxidizers obligate acidophiles
1c. What are sulfur granules and which type of respiratory bacteria accumulate them?
Solution
Ans1(a)
Acidothiobacillus are rod shaped Gramnegative bacteria which are obligate acidophillus because
they reduces sulfur for energy with pH less than 4. And its suevive at moderatetemprature (18 to
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In python please help Write Python statements that print the values .pdf
In python please help Write Python statements that print the values of pi and the Euler constant e
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Solution
b) from collections import namedtuple
Constants = namedtuple(\'Constants\', [\'pi\', \'e\']).
In detail, compare and contrast epithelium and connective tissue..pdf
In detail, compare and contrast epithelium and connective tissue.
Solution
Answer:
Epithelial tissue
Connective tissue
consists of three cell types; squamous, cuboidal and columnar.
The tissue is two or more cells thick.
found above the basement membranes.
Functions to protect the body, secretions, excretions, absorption and allows the body to sense the
outside world.
Eg. Skin, kidney
The cells in the connective tissue are scattered in the matrix.
supplied with a rich network of nerves and blood capillaries
lies below the basal membrane.
Functions: supports, connects, binds or separates other tissues or organs.
Ex. Bone, ligament
Epithelial tissue
Connective tissue
consists of three cell types; squamous, cuboidal and columnar.
The tissue is two or more cells thick.
found above the basement membranes.
Functions to protect the body, secretions, excretions, absorption and allows the body to sense the
outside world.
Eg. Skin, kidney
The cells in the connective tissue are scattered in the matrix.
supplied with a rich network of nerves and blood capillaries
lies below the basal membrane.
Functions: supports, connects, binds or separates other tissues or organs.
Ex. Bone, ligament.
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randomly selected from the hopper. The team holding the same four numbers, in any order, is
awarded the pick. As an example, if balls 3-5-1-2 were drawn, the team holding this combination
of numbers (1-2-3-5) w ins the pick. (If 11-12-13-14 is drawn, a new set of balls is drawn.) The
balls are returned to the hopper and another set of four balls is used to identify the team receiving
the second pick, ignoring any combinations that belong to the team receiving the first pick.
Similarly, the team receiving the third pick is identified. The remaining 11 teams are awarded the
remaining picks in order of their rankings. Ranking the teams from worst (1) to best (14). the
number of combinations awarded each team in the lottery is shown in the table that follows. Let
X be the pick the worst team gets from this lottery.
Solution.
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