1. A hexagonal prism with a base of 25mm and an axis of 60mm long is resting on one of its base corners on the horizontal plane (H.P.). 2. The axis of the prism is inclined at 45 degrees to the H.P. 3. Using the change of position method, projections are drawn showing: a) the prism in vertical position (V.P.), b) projecting the front view, c) rotating the axis to 45 degrees, and d) projecting points to their final positions.

1. CREATED BY : GUIDED BY:
1.Gajera Vishal R.(37) Mr. Vishal Sukhadiya
2.Garud Shailesh S.(38) Mr. Brijesh Surati
3.Gaur Jyotirmay O.(39)
4.Gohil Hardik M. (40)
A Hexagonal Prism

2. Hexagonal Prisms
 Hexagonal prisms are
similar to cylinders
but instead of having
a circular cross
section they are
hexagonal.

3. 25
a,1
b,1
c,1
d,1
e,1f,1
x Y
Problem: Draw the projections of a hexagonal prism of base 25 side and
axis 60 long, when it is resting on one of its corners of the base on H.P.
The axis of the solid is inclined at 450 to H.P. Follow the change of position
method
Step 1:-Draw a
hexagonal prism of
base 25 side and
axis 60 long at V.P.

4. 25
11,a1
21,b1 31,c1
41,d1
51,e161,f1
x Y
60
a1’
f1’,b1’ e1’,c1’
d1’
11’ 61’,21’ 51’,31’ 41’
Step 2:-Project the F.V
which will be a
rectangular of longer
side same as the
length of axis.

5. 25
11,a1
21,b1 31,c1
41,d1
51,e161,f1
x Y
60
a1’ f1’,b1’ e1’,c1’
d1’
11’ 61’,21’ 51’,31’ 41’
11’
61’,21’
51’,31’
41’
d1’
e1’,c1’
f1’,b1’
a1’
45deg
Step 3:- The axis of
the solid is inclined
at 450 to H.P

6. 25
11,a1
21,b1 31,c1
41,d1
51,e161,f1
x Y
60
a1’ f1’,b1’ e1’,c1’
d1’
11’ 61’,21’ 51’,31’ 41’
11’
61’,21’
51’,31’
41’
d1’
e1’,c1’
f1’,b1’
a1’
1
2 3
4
56
a
b c
d
e
f
45deg
Step 4:-Project the points from final stage F.V.
vertically down and project the points from
intermediate stage T.V. and parallel to the XY line.

7. X Y
X1
Y1
o’
o
Fv
Tv
Aux.Tv
450
Problem :A hexagonal prism of
base side 30 mm longand axis 40 mm long,
is standing on Hp on it’s base with
one base edge // to Vp.
A tetrahedron is placed centrally
on the top of it.The base of tetrahedron is
a triangle formed by joining alternate corners
of top of prism..Draw projections of both solids.
Project an auxiliary Tv on AIP 450 inclined to Hp.
a’ b’ d’c’ e’f’
a
b c
d
ef
a1
b1
c1
d1
e1
f1
o1

8. STEPS:
1.Draw a regular hexagon as Tv of standing prism With one side // to xy
and name the top points.Project it’s Fv – a rectangle and name it’s top.
2.Now join it’s alternate corners a-c-e and the triangle formed is base
of a tetrahedron as said.
3.Locate center of this triangle & locate apex o
4.Extending it’s axis line upward mark apex o’
5.By cutting TL of edge of tetrahedron equal to a-c. and complete Fv
of tetrahedron.
6.Draw an AIP ( x1y1) 450 inclined to xyAnd project Aux.Tv on it by using
similar
7.Steps like previous problem.

9. Problem: A hexagonal prism of side base 30 and length of axis 75, is resting on a
corner of its base on H.P, with the longer edge containing that corner, inclined to
H.P at 300. It is cut by a section plane parallel to H.P and passing through the
mid-point of the axis. Draw the front and sectional top views of the solid.

10. Problem: A hexagonal prism of base 25 side and axis 45 long, is positioned with
one of its base edges on H.P such that, the axis is inclined at 300 to H.P and 450
to V.P. Draw its projections. Follow the change of position method.

11. Problem: Draw the projections of a hexagonal prism of base 25 side and
axis 60 long, when it is resting on one of its corners of the base on H.P.
The axis of the solid is inclined at 450 to H.P. Follow the change of
position method