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A fair coin is tossed two times in succession.The set of equally likely outcomes is {HH,HT,TH,TT}.find the probability of getting the same outcome on each toss. Solution P(getting same outcome) = P(getting either HH or TT) = number of samples having HH or TT / total number of samples. Number of samples having HH or TT = 2 Total number of samples = 4 therefore P(getting the same outcome) = 2/4 = 0.5.

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A fair coin is tossed two times in succession.The set of equally likely outcomes is {HH,HT,TH,TT}.find the probability of getting the same outcome on each toss. Solution P(getting same outcome) = P(getting either HH or TT) = number of samples having HH or TT / total number of samples. Number of samples having HH or TT = 2 Total number of samples = 4 therefore P(getting the same outcome) = 2/4 = 0.5

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A fair coin is tossed two times in succession.The set of equally lik.pdf

  • 1. A fair coin is tossed two times in succession.The set of equally likely outcomes is {HH,HT,TH,TT}.find the probability of getting the same outcome on each toss. Solution P(getting same outcome) = P(getting either HH or TT) = number of samples having HH or TT / total number of samples. Number of samples having HH or TT = 2 Total number of samples = 4 therefore P(getting the same outcome) = 2/4 = 0.5