8. Reflexive. as the hormone is releases in response to an external .pdf
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8. Reflexive. as the hormone is releases in response to an external stimulus. 9. Trophic response . 10.Anbolic. 11.C. 12.D. Solution 8. Reflexive. as the hormone is releases in response to an external stimulus. 9. Trophic response . 10.Anbolic. 11.C. 12.D..
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3(s) + HClSolution3(s) + HCl.pdf
This chemical reaction involves reacting metallic sodium (3(s)) with hydrochloric acid (HCl) to form a solution. Metallic sodium reacts with hydrochloric acid, dissolving into solution. The unbalanced chemical equation shows metallic sodium (3(s)) reacting with hydrochloric acid (HCl).
#include iostream #include deque #include stdio.h scan.pdf
#include
#include
#include //scanf,printf
#include
#include //istringstream
using namespace std;
//maps
#include \"MapGeneric.h\"
#include \"MapTriple.h\"
#include \"MapAbsoluteValue.h\"
#include \"MapSquare.h\"
//filters
#include \"FilterGeneric.h\"
#include \"filterEven.h\"
#include \"filterPositive.h\"
#include \"filterPositiveTwoDigit.h\"
//reduce
#include \"ReduceGeneric.h\"
#include \"ReduceMinimum.h\"
#include \"ReduceGCD.h\"
int main()
{
deque L,L1,L2;
int i;
string line;
getline(cin,line);
if(line.size() == 0)
return 0;
line.erase(remove(line.begin(), line.end(), \',\'), line.end());
istringstream s(line);
while(s>>i)
{
L.push_back(i);
}
if(L.size() != 20)
return 0;
//converting L -> 3*|L| aka L1
MapTriple triple; MapAbsoluteValue abs;
L1 = triple.map(abs.map(L));
//converting L1 -> positive two digit integers -> even intergers aka L2
filterEven even; filterPositiveTwoDigit p2;
L2 = p2.filter(L1);
if(L2.size() <2)
return 0;
L2 = even.filter(L2);
if(L2.size() <2)
return 0;
//finding the minimum and GCD from L2 respectively
ReduceMinimum min; ReduceGCD gcd;
printf(\"%d %d\ \",min.reduce(L2),gcd.reduce(L2));
}
FilterGeneric.cpp
#include
#include
#include \"FilterGeneric.h\"
using namespace std;
deque FilterGeneric::filter(deque deq)
{
//calling recursive function with deq and its length
select(deq,deq.size()-1);
return filterDeq;
}
//int i is the index that will start from the length of deque till 0
void FilterGeneric::select(deque deq, int i)
{
if(i == 0)
{
bool val = f(deq[i]);
if(val)
filterDeq.push_front(deq[i]);
return;
}
bool val = f(deq[i]);
if(val)
filterDeq.push_front(deq[i]);
return select(deq,i-1);
}
FilterGeneric.h
#ifndef FILTERGENERIC_H
#define FILTERGENERIC_H
#include
class FilterGeneric
{
public:
std::deque filter(std::deque);
void select(std::deque,int);
protected:
//this deque will store the integers after filtration.
std::deque filterDeq;
private:
virtual bool f(int)=0;
};
#endif
MapAbsoluteValue.cpp
#include
#include
#include
#include \"MapGeneric.h\" //base
#include \"MapAbsoluteValue.h\"
using namespace std;
int MapAbsoluteValue::f(int num)
{
return abs(num);
}
MapAbsoluteValue.h
#ifndef MAPABSOLUTEVALUE_H
#define MAPABSOLUTEVALUE_H
#include
//this class will map a given input N, using the function map(input), to |N|
class MapAbsoluteValue: public MapGeneric
{
public:
//overwriting pure virtual function making N -> |N|
int f(int);
private:
};
#endif
MapGeneric.cpp
#include
#include
#include \"MapGeneric.h\"
using namespace std;
deque MapGeneric::map(deque deq)
{
//calling recursive function with deq and its length
calculate(deq,deq.size()-1);
return mapDeq;
}
//int i is the index that will start from the length of deque till 0
void MapGeneric::calculate(deque deq, int i)
{
if(i == 0)
{
int val = f(deq[i]);
mapDeq.push_front(val);
return;
}
int val = f(deq[i]);
mapDeq.push_front(val);
return calculate(deq,i-1);
}
MapGeneric.h
#ifndef MAPGENERIC_H
#define MAPGENERIC_H
#include
class MapGeneric
{
public:
std::deque ma.
This is a great question. The radial velocity met.pdf
This is a great question. The radial velocity method uses Doppler spectroscopy to
detect extrasolar planets, similar to the doppler radar used to track weather! It assumes stars
move a little as a planet orbits them causing a shift in the light spectrum the star produces. B is
true because as the planet orbits it pulls the star toward the observer casing the light to be blue
shifted. C is also true because light gets slightly red shifted. The answer is E.
Solution
This is a great question. The radial velocity method uses Doppler spectroscopy to
detect extrasolar planets, similar to the doppler radar used to track weather! It assumes stars
move a little as a planet orbits them causing a shift in the light spectrum the star produces. B is
true because as the planet orbits it pulls the star toward the observer casing the light to be blue
shifted. C is also true because light gets slightly red shifted. The answer is E..
Viruses are intracellular obligate parasites whic.pdf
Viruses are intracellular obligate parasites which means that they cannot replicate or
express their genes without the help of a living cell. A single virus particle (virion) is in and of
itself essentially inert. It lacks needed components that cells have to reproduce. When a virus
infects a cell, it marshals the cell\'s ribosomes, enzymes and much of the cellular machinery to
replicate. Unlike what we have seen in cellular replication processes such as mitosis and meiosis,
viral replication produces many progeny, that when complete, leave the host cell to infect other
cells in the organism. Viruses may contain double-stranded DNA, double-stranded RNA, single-
stranded DNA or single-stranded RNA. The type of genetic material found in a particular virus
depends on the nature and function of the specific virus. The exact nature of what happens after a
host is infected varies depending on the nature of the virus. The process for double-stranded
DNA, single-stranded DNA, double-stranded RNA and single-stranded RNA viral replication
will differ. For example, double-stranded DNA viruses typically must enter the host cell\'s
nucleus before they can replicate. Single-stranded RNA viruses however, replicate mainly in the
host cell\'s cytoplasm. Once a virus infects its host and the viral progeny components are
produced by the host\'s cellular machinery, the assembly of the viral capsid is a non-enzymatic
process. It is usually spontaneous. Viruses typically can only infect a limited number of hosts
(also known as host range). The \"lock and key\" mechanism is the most common explanation for
this range. Certain proteins on the virus particle must fit certain receptor sites on the particular
host\'s cell surface.
Solution
Viruses are intracellular obligate parasites which means that they cannot replicate or
express their genes without the help of a living cell. A single virus particle (virion) is in and of
itself essentially inert. It lacks needed components that cells have to reproduce. When a virus
infects a cell, it marshals the cell\'s ribosomes, enzymes and much of the cellular machinery to
replicate. Unlike what we have seen in cellular replication processes such as mitosis and meiosis,
viral replication produces many progeny, that when complete, leave the host cell to infect other
cells in the organism. Viruses may contain double-stranded DNA, double-stranded RNA, single-
stranded DNA or single-stranded RNA. The type of genetic material found in a particular virus
depends on the nature and function of the specific virus. The exact nature of what happens after a
host is infected varies depending on the nature of the virus. The process for double-stranded
DNA, single-stranded DNA, double-stranded RNA and single-stranded RNA viral replication
will differ. For example, double-stranded DNA viruses typically must enter the host cell\'s
nucleus before they can replicate. Single-stranded RNA viruses however, replicate mainly in the
host cell\'s cytoplas.
Step1 Na is a more reactive metal than Fe ; so it.pdf
Step1 Na is a more reactive metal than Fe ; so it can displace iron from its salts.But
iron can not displace sodium from its salts .thus there will be no reaction.
Solution
Step1 Na is a more reactive metal than Fe ; so it can displace iron from its salts.But
iron can not displace sodium from its salts .thus there will be no reaction..
Second ionization is compared to removing electro.pdf
Second ionization is compared to removing electron from the atom second time. If
the atom has reach noble gas configuration after first ionization, then it will be very difficult to
remove electrons from it. You can see that Na after removal of one electron obtains the noble
gas configuration. Hence, Na has the greatest second ionization table. My text contained chart of
ratio comparing second/first ionization. If you look at that chart you can see your answer clearly.
Hope this helps!
Solution
Second ionization is compared to removing electron from the atom second time. If
the atom has reach noble gas configuration after first ionization, then it will be very difficult to
remove electrons from it. You can see that Na after removal of one electron obtains the noble
gas configuration. Hence, Na has the greatest second ionization table. My text contained chart of
ratio comparing second/first ionization. If you look at that chart you can see your answer clearly.
Hope this helps!.
oxidizing reagent CuCl2 reducing reagent Fe not.pdf
oxidizing reagent: CuCl2 reducing reagent: Fe note: the oxidation state of Cu in
CuCl2 is +2 , while that in Cu is zero the OS of Fe in Fe is zero, the OS of Fe in FeCl2 is +2.
Solution
oxidizing reagent: CuCl2 reducing reagent: Fe note: the oxidation state of Cu in
CuCl2 is +2 , while that in Cu is zero the OS of Fe in Fe is zero, the OS of Fe in FeCl2 is +2..
On the following organic compounds,CH3CH2NH2 andC.pdf
On the following organic compounds,CH3CH2NH2 andCH3CONH2 is base. Both
of them got thetendency to attract H+ ions to form -NH3+ compound. CH3COOH is the acid. It
will release H+ ionsto form CH3COO- ions. While CH3CHOdoesnt have the tendency to attract
or release H+ions. Most acidic, CH3COOH. Compare CH3CH2NH2 andCH3CONH2. Oxygen
in theCH3CONH2 will attract the electrons towardoxygen molecule. This reduce the negativity
of compound. Therefore,it got less ability to attract H+ ions.CH3CH2NH2 is more basic
toCH3CONH2. So, the least acidic isCH3CH2NH2 (which is most basicamong 4)
Solution
On the following organic compounds,CH3CH2NH2 andCH3CONH2 is base. Both
of them got thetendency to attract H+ ions to form -NH3+ compound. CH3COOH is the acid. It
will release H+ ionsto form CH3COO- ions. While CH3CHOdoesnt have the tendency to attract
or release H+ions. Most acidic, CH3COOH. Compare CH3CH2NH2 andCH3CONH2. Oxygen
in theCH3CONH2 will attract the electrons towardoxygen molecule. This reduce the negativity
of compound. Therefore,it got less ability to attract H+ ions.CH3CH2NH2 is more basic
toCH3CONH2. So, the least acidic isCH3CH2NH2 (which is most basicamong 4).
Recommended
3(s) + HClSolution3(s) + HCl.pdf
This chemical reaction involves reacting metallic sodium (3(s)) with hydrochloric acid (HCl) to form a solution. Metallic sodium reacts with hydrochloric acid, dissolving into solution. The unbalanced chemical equation shows metallic sodium (3(s)) reacting with hydrochloric acid (HCl).
#include iostream #include deque #include stdio.h scan.pdf
#include
#include
#include //scanf,printf
#include
#include //istringstream
using namespace std;
//maps
#include \"MapGeneric.h\"
#include \"MapTriple.h\"
#include \"MapAbsoluteValue.h\"
#include \"MapSquare.h\"
//filters
#include \"FilterGeneric.h\"
#include \"filterEven.h\"
#include \"filterPositive.h\"
#include \"filterPositiveTwoDigit.h\"
//reduce
#include \"ReduceGeneric.h\"
#include \"ReduceMinimum.h\"
#include \"ReduceGCD.h\"
int main()
{
deque L,L1,L2;
int i;
string line;
getline(cin,line);
if(line.size() == 0)
return 0;
line.erase(remove(line.begin(), line.end(), \',\'), line.end());
istringstream s(line);
while(s>>i)
{
L.push_back(i);
}
if(L.size() != 20)
return 0;
//converting L -> 3*|L| aka L1
MapTriple triple; MapAbsoluteValue abs;
L1 = triple.map(abs.map(L));
//converting L1 -> positive two digit integers -> even intergers aka L2
filterEven even; filterPositiveTwoDigit p2;
L2 = p2.filter(L1);
if(L2.size() <2)
return 0;
L2 = even.filter(L2);
if(L2.size() <2)
return 0;
//finding the minimum and GCD from L2 respectively
ReduceMinimum min; ReduceGCD gcd;
printf(\"%d %d\ \",min.reduce(L2),gcd.reduce(L2));
}
FilterGeneric.cpp
#include
#include
#include \"FilterGeneric.h\"
using namespace std;
deque FilterGeneric::filter(deque deq)
{
//calling recursive function with deq and its length
select(deq,deq.size()-1);
return filterDeq;
}
//int i is the index that will start from the length of deque till 0
void FilterGeneric::select(deque deq, int i)
{
if(i == 0)
{
bool val = f(deq[i]);
if(val)
filterDeq.push_front(deq[i]);
return;
}
bool val = f(deq[i]);
if(val)
filterDeq.push_front(deq[i]);
return select(deq,i-1);
}
FilterGeneric.h
#ifndef FILTERGENERIC_H
#define FILTERGENERIC_H
#include
class FilterGeneric
{
public:
std::deque filter(std::deque);
void select(std::deque,int);
protected:
//this deque will store the integers after filtration.
std::deque filterDeq;
private:
virtual bool f(int)=0;
};
#endif
MapAbsoluteValue.cpp
#include
#include
#include
#include \"MapGeneric.h\" //base
#include \"MapAbsoluteValue.h\"
using namespace std;
int MapAbsoluteValue::f(int num)
{
return abs(num);
}
MapAbsoluteValue.h
#ifndef MAPABSOLUTEVALUE_H
#define MAPABSOLUTEVALUE_H
#include
//this class will map a given input N, using the function map(input), to |N|
class MapAbsoluteValue: public MapGeneric
{
public:
//overwriting pure virtual function making N -> |N|
int f(int);
private:
};
#endif
MapGeneric.cpp
#include
#include
#include \"MapGeneric.h\"
using namespace std;
deque MapGeneric::map(deque deq)
{
//calling recursive function with deq and its length
calculate(deq,deq.size()-1);
return mapDeq;
}
//int i is the index that will start from the length of deque till 0
void MapGeneric::calculate(deque deq, int i)
{
if(i == 0)
{
int val = f(deq[i]);
mapDeq.push_front(val);
return;
}
int val = f(deq[i]);
mapDeq.push_front(val);
return calculate(deq,i-1);
}
MapGeneric.h
#ifndef MAPGENERIC_H
#define MAPGENERIC_H
#include
class MapGeneric
{
public:
std::deque ma.
This is a great question. The radial velocity met.pdf
This is a great question. The radial velocity method uses Doppler spectroscopy to
detect extrasolar planets, similar to the doppler radar used to track weather! It assumes stars
move a little as a planet orbits them causing a shift in the light spectrum the star produces. B is
true because as the planet orbits it pulls the star toward the observer casing the light to be blue
shifted. C is also true because light gets slightly red shifted. The answer is E.
Solution
This is a great question. The radial velocity method uses Doppler spectroscopy to
detect extrasolar planets, similar to the doppler radar used to track weather! It assumes stars
move a little as a planet orbits them causing a shift in the light spectrum the star produces. B is
true because as the planet orbits it pulls the star toward the observer casing the light to be blue
shifted. C is also true because light gets slightly red shifted. The answer is E..
Viruses are intracellular obligate parasites whic.pdf
Viruses are intracellular obligate parasites which means that they cannot replicate or
express their genes without the help of a living cell. A single virus particle (virion) is in and of
itself essentially inert. It lacks needed components that cells have to reproduce. When a virus
infects a cell, it marshals the cell\'s ribosomes, enzymes and much of the cellular machinery to
replicate. Unlike what we have seen in cellular replication processes such as mitosis and meiosis,
viral replication produces many progeny, that when complete, leave the host cell to infect other
cells in the organism. Viruses may contain double-stranded DNA, double-stranded RNA, single-
stranded DNA or single-stranded RNA. The type of genetic material found in a particular virus
depends on the nature and function of the specific virus. The exact nature of what happens after a
host is infected varies depending on the nature of the virus. The process for double-stranded
DNA, single-stranded DNA, double-stranded RNA and single-stranded RNA viral replication
will differ. For example, double-stranded DNA viruses typically must enter the host cell\'s
nucleus before they can replicate. Single-stranded RNA viruses however, replicate mainly in the
host cell\'s cytoplasm. Once a virus infects its host and the viral progeny components are
produced by the host\'s cellular machinery, the assembly of the viral capsid is a non-enzymatic
process. It is usually spontaneous. Viruses typically can only infect a limited number of hosts
(also known as host range). The \"lock and key\" mechanism is the most common explanation for
this range. Certain proteins on the virus particle must fit certain receptor sites on the particular
host\'s cell surface.
Solution
Viruses are intracellular obligate parasites which means that they cannot replicate or
express their genes without the help of a living cell. A single virus particle (virion) is in and of
itself essentially inert. It lacks needed components that cells have to reproduce. When a virus
infects a cell, it marshals the cell\'s ribosomes, enzymes and much of the cellular machinery to
replicate. Unlike what we have seen in cellular replication processes such as mitosis and meiosis,
viral replication produces many progeny, that when complete, leave the host cell to infect other
cells in the organism. Viruses may contain double-stranded DNA, double-stranded RNA, single-
stranded DNA or single-stranded RNA. The type of genetic material found in a particular virus
depends on the nature and function of the specific virus. The exact nature of what happens after a
host is infected varies depending on the nature of the virus. The process for double-stranded
DNA, single-stranded DNA, double-stranded RNA and single-stranded RNA viral replication
will differ. For example, double-stranded DNA viruses typically must enter the host cell\'s
nucleus before they can replicate. Single-stranded RNA viruses however, replicate mainly in the
host cell\'s cytoplas.
Step1 Na is a more reactive metal than Fe ; so it.pdf
Step1 Na is a more reactive metal than Fe ; so it can displace iron from its salts.But
iron can not displace sodium from its salts .thus there will be no reaction.
Solution
Step1 Na is a more reactive metal than Fe ; so it can displace iron from its salts.But
iron can not displace sodium from its salts .thus there will be no reaction..
Second ionization is compared to removing electro.pdf
Second ionization is compared to removing electron from the atom second time. If
the atom has reach noble gas configuration after first ionization, then it will be very difficult to
remove electrons from it. You can see that Na after removal of one electron obtains the noble
gas configuration. Hence, Na has the greatest second ionization table. My text contained chart of
ratio comparing second/first ionization. If you look at that chart you can see your answer clearly.
Hope this helps!
Solution
Second ionization is compared to removing electron from the atom second time. If
the atom has reach noble gas configuration after first ionization, then it will be very difficult to
remove electrons from it. You can see that Na after removal of one electron obtains the noble
gas configuration. Hence, Na has the greatest second ionization table. My text contained chart of
ratio comparing second/first ionization. If you look at that chart you can see your answer clearly.
Hope this helps!.
oxidizing reagent CuCl2 reducing reagent Fe not.pdf
oxidizing reagent: CuCl2 reducing reagent: Fe note: the oxidation state of Cu in
CuCl2 is +2 , while that in Cu is zero the OS of Fe in Fe is zero, the OS of Fe in FeCl2 is +2.
Solution
oxidizing reagent: CuCl2 reducing reagent: Fe note: the oxidation state of Cu in
CuCl2 is +2 , while that in Cu is zero the OS of Fe in Fe is zero, the OS of Fe in FeCl2 is +2..
On the following organic compounds,CH3CH2NH2 andC.pdf
On the following organic compounds,CH3CH2NH2 andCH3CONH2 is base. Both
of them got thetendency to attract H+ ions to form -NH3+ compound. CH3COOH is the acid. It
will release H+ ionsto form CH3COO- ions. While CH3CHOdoesnt have the tendency to attract
or release H+ions. Most acidic, CH3COOH. Compare CH3CH2NH2 andCH3CONH2. Oxygen
in theCH3CONH2 will attract the electrons towardoxygen molecule. This reduce the negativity
of compound. Therefore,it got less ability to attract H+ ions.CH3CH2NH2 is more basic
toCH3CONH2. So, the least acidic isCH3CH2NH2 (which is most basicamong 4)
Solution
On the following organic compounds,CH3CH2NH2 andCH3CONH2 is base. Both
of them got thetendency to attract H+ ions to form -NH3+ compound. CH3COOH is the acid. It
will release H+ ionsto form CH3COO- ions. While CH3CHOdoesnt have the tendency to attract
or release H+ions. Most acidic, CH3COOH. Compare CH3CH2NH2 andCH3CONH2. Oxygen
in theCH3CONH2 will attract the electrons towardoxygen molecule. This reduce the negativity
of compound. Therefore,it got less ability to attract H+ ions.CH3CH2NH2 is more basic
toCH3CONH2. So, the least acidic isCH3CH2NH2 (which is most basicamong 4).
Moseley showed that there were gaps in the atomic.pdf
Moseley showed that there were gaps in the atomic number sequence at numbers
43, 61, 72, and 75. These spaces are now known, respectively, to be the places of the radioactive
synthetic elements technetium and promethium, and also the last two quite rare naturally-
occurring stable elements hafnium (discovered 1923) and rhenium (discovered 1925). Nothing
about these four elements was known of in Moseley\'s lifetime, not even their very existence.
Based on the intuition of a very experienced chemist, Dimitri Mendeleev had predicted the
existence of a missing element in the Periodic Table, which was later found to be filled by
technetium, and Bohuslav Brauner had predicted the existence of another missing element in this
Table, which was later found to be filled by promethium. Henry Moseley\'s experiments
confirmed these predictions, by showing exactly what the missing atomic numbers were, 43 and
61. In addition, Moseley predicted the two more undiscovered elements, those with the atomic
numbers 72 and 75, and he gave very strong evidence that there were no other gaps in the
Periodic Table between the elements aluminium (atomic number 13) and gold (atomic number
79).
Solution
Moseley showed that there were gaps in the atomic number sequence at numbers
43, 61, 72, and 75. These spaces are now known, respectively, to be the places of the radioactive
synthetic elements technetium and promethium, and also the last two quite rare naturally-
occurring stable elements hafnium (discovered 1923) and rhenium (discovered 1925). Nothing
about these four elements was known of in Moseley\'s lifetime, not even their very existence.
Based on the intuition of a very experienced chemist, Dimitri Mendeleev had predicted the
existence of a missing element in the Periodic Table, which was later found to be filled by
technetium, and Bohuslav Brauner had predicted the existence of another missing element in this
Table, which was later found to be filled by promethium. Henry Moseley\'s experiments
confirmed these predictions, by showing exactly what the missing atomic numbers were, 43 and
61. In addition, Moseley predicted the two more undiscovered elements, those with the atomic
numbers 72 and 75, and he gave very strong evidence that there were no other gaps in the
Periodic Table between the elements aluminium (atomic number 13) and gold (atomic number
79)..
Lewis Structures A structural formula in which el.pdf
Lewis Structures A structural formula in which electrons are represented by dots;
two dots between atoms represent a covalent bond. Also known as electron-dot formula or Lewis
formula. Covalent Bond A chemical bond formed by the sharing of one or more electrons,
especially pairs of electrons, between atoms. Ionic Bond A chemical bond between two ions
with opposite charges, characteristic of salts. Also called electrovalent bond. Resonance The
property of a compound having simultaneously the characteristics of two or more structural
forms that differ only in the distribution of electrons. Such compounds are highly stable and
cannot be properly represented by a single structural formula. Polarity Tendency of a molecule,
or compound, to be attracted or repelled by electrical charges because of an asymmetrical
arrangement of atoms around the nucleus. Dipole Moment A dipole moment is the development
of an electronic charge in a molecule by virtue of it structure and components. Bond Energy The
average value of specific bond dissociation energies that have been measured from different
molecules of a given type Valence shell electron pair repulsion (VSEPR) theory is a model in
chemistry used to predict the shape of individual molecules based upon the extent of electron-
pair electrostatic repulsion.It is also named Gillespie–Nyholm theory after its two main
developers The premise of VSEPR is that the valence electron pairs surrounding an atom
mutually repel each other, and will therefore adopt an arrangement that minimizes this repulsion,
thus determining the molecular geometry. The number of electron pairs surrounding an atom,
both bonding and nonbonding, is called its steric number.
Solution
Lewis Structures A structural formula in which electrons are represented by dots;
two dots between atoms represent a covalent bond. Also known as electron-dot formula or Lewis
formula. Covalent Bond A chemical bond formed by the sharing of one or more electrons,
especially pairs of electrons, between atoms. Ionic Bond A chemical bond between two ions
with opposite charges, characteristic of salts. Also called electrovalent bond. Resonance The
property of a compound having simultaneously the characteristics of two or more structural
forms that differ only in the distribution of electrons. Such compounds are highly stable and
cannot be properly represented by a single structural formula. Polarity Tendency of a molecule,
or compound, to be attracted or repelled by electrical charges because of an asymmetrical
arrangement of atoms around the nucleus. Dipole Moment A dipole moment is the development
of an electronic charge in a molecule by virtue of it structure and components. Bond Energy The
average value of specific bond dissociation energies that have been measured from different
molecules of a given type Valence shell electron pair repulsion (VSEPR) theory is a model in
chemistry used to predict the shape of individual molecules based upon the extent of electr.
fluorine , oxygen , chlorine , sulphor ,phophorus.pdf
fluorine , oxygen , chlorine , sulphor ,phophorus
Solution
fluorine , oxygen , chlorine , sulphor ,phophorus.
CuS is insoluble. NaCl stays in solution. so cor.pdf
CuS is insoluble. NaCl stays in solution. so correct answer is C
Solution
CuS is insoluble. NaCl stays in solution. so correct answer is C.
When you have an acidic solution like you do, (because the H+ and th.pdf
When you have an acidic solution like you do, (because the H+ and the F- dissociate very
readily), there is an abundance of H and F on the product side. However, with the addition of
more F- the solution is the forced back to the left to reach the same equilibrium that was found
before. (Also take note that you have a 0.1M solution) Like so:
HF --> H+ + F-
in a aqueous solution there are H3O+ molecules and OH-.
Even though HF has a high level of dissociation it will not dissociate completely.
so when F is added the solution runs to the left because it has been added on the right.
The reason that it reacts with the H3O is because it is more basic than the H and the F reacts with
the most basic.
Hope this helps.
Solution
When you have an acidic solution like you do, (because the H+ and the F- dissociate very
readily), there is an abundance of H and F on the product side. However, with the addition of
more F- the solution is the forced back to the left to reach the same equilibrium that was found
before. (Also take note that you have a 0.1M solution) Like so:
HF --> H+ + F-
in a aqueous solution there are H3O+ molecules and OH-.
Even though HF has a high level of dissociation it will not dissociate completely.
so when F is added the solution runs to the left because it has been added on the right.
The reason that it reacts with the H3O is because it is more basic than the H and the F reacts with
the most basic.
Hope this helps..
Type III secretion system- Complex structure helps the bacteria to e.pdf
Type III secretion system- Complex structure helps the bacteria to escape the host immune
system.
Solution
Type III secretion system- Complex structure helps the bacteria to escape the host immune
system..
The OECD has produced a considerable amount of analytical work addre.pdf
The OECD has produced a considerable amount of analytical work addressing the issue of
incentives for attracting foreign direct investment (FDI). This list, compiled in the context of a
2002 project undertaken by the Investment Committee, provides an overview of this work which
is indicative, rather than exhaustive, of the large body of work undertaken by several OECD
bodies in this area.
The Economics of International Investment Incentives , 2001
This paper, prepared by Professor Magnus Blomstr
Solution
The OECD has produced a considerable amount of analytical work addressing the issue of
incentives for attracting foreign direct investment (FDI). This list, compiled in the context of a
2002 project undertaken by the Investment Committee, provides an overview of this work which
is indicative, rather than exhaustive, of the large body of work undertaken by several OECD
bodies in this area.
The Economics of International Investment Incentives , 2001
This paper, prepared by Professor Magnus Blomstr.
Q2. RAM holds the running configuration.Q4. The startup configurat.pdf
Q2. RAM holds the running configuration.
Q4. The startup configuration file is stored in NVRAM/ROM.
Q7. There are three elements of communication: the message sender, the feedback, and the
message receiver.
Q8. From the privileged exec mode of the router named ITT330, save the configuration to
NVRAM, prompt ___ command ___. What is the short version of this command.
Solution
Q2. RAM holds the running configuration.
Q4. The startup configuration file is stored in NVRAM/ROM.
Q7. There are three elements of communication: the message sender, the feedback, and the
message receiver.
Q8. From the privileged exec mode of the router named ITT330, save the configuration to
NVRAM, prompt ___ command ___. What is the short version of this command..
AnswerIn population 1, only homozygous dominant population is pre.pdf
Answer:
In population 1, only homozygous dominant population is present.
In population 2, only heterozygous dominant population is present.
Solution
Answer:
In population 1, only homozygous dominant population is present.
In population 2, only heterozygous dominant population is present..
P=VI=(10)(2)=20W absorbed+ve power means absorbed -ve power means .pdf
P=VI=(10)(2)=20W absorbed
+ve power means absorbed -ve power means supplied.
Solution
P=VI=(10)(2)=20W absorbed
+ve power means absorbed -ve power means supplied..
Option D is the answerSolutionOption D is the answer.pdf
Option D is the answer. The document states that Option D is the correct answer to an unknown question. It then repeats that Option D is the answer.
A.True B.True C.True D.False .pdf
This document contains a multiple choice question with 4 options: A, B, C and D. The solution provided states that options A, B and C are true, while option D is false.
Mean = (sum of the observations)(Total no. of observations)= (12+.pdf
Mean = (sum of the observations)/(Total no. of observations)
= (12+20+10+15+20)/5 = 15.4
Thus mean = 15.4
Solution
Mean = (sum of the observations)/(Total no. of observations)
= (12+20+10+15+20)/5 = 15.4
Thus mean = 15.4.
Here is the codeimport java.util.; public class HelloWorld{p.pdf
Here is the code:
import java.util.*;
public class HelloWorld{
public static void main(String []args){
LinkedList ll1 = new LinkedList();
LinkedList ll3 = new LinkedList();
LinkedList ll2 = new LinkedList(); // comdine list
int i=0,j=0;
ll1.add(2); // adding elements to list1
ll1.add(3);
ll1.add(5);
ll1.add(7);
ll1.add(9);
ll2.add(4); // adding elements to list 2
ll2.add(6);
ll2.add(7);
ll2.add(8);
ll2.add(12);
while(ll1.size() > i && ll2.size()> j) // exits when any of list size exceeds
{
if(ll1.get(i) <= ll2.get(j)) // check which element is lower
{
ll3.add(ll1.get(i)); // if ll1 element is lower then add to ll3
i++;
}
else if(ll1.get(i) >= ll2.get(j))
{
ll3.add(ll2.get(j));// if ll2 element is lower then add to ll3
j++;
}
}
if(ll1.size() > i) // adding the rest of elements
{
while(ll1.size() > i)
{
ll3.add(ll1.get(i));
i++;
}
}
else if(ll2.size()> j)
{
while(ll2.size() > j)
{
ll3.add(ll2.get(j));
j++;
}
}
System.out.println(\"The Conbined of two list data is \"+ ll3);
}
}
Output:
The Conbined of two list data is [2, 3, 4, 5, 6, 7, 7, 8, 9, 12]
Solution
Here is the code:
import java.util.*;
public class HelloWorld{
public static void main(String []args){
LinkedList ll1 = new LinkedList();
LinkedList ll3 = new LinkedList();
LinkedList ll2 = new LinkedList(); // comdine list
int i=0,j=0;
ll1.add(2); // adding elements to list1
ll1.add(3);
ll1.add(5);
ll1.add(7);
ll1.add(9);
ll2.add(4); // adding elements to list 2
ll2.add(6);
ll2.add(7);
ll2.add(8);
ll2.add(12);
while(ll1.size() > i && ll2.size()> j) // exits when any of list size exceeds
{
if(ll1.get(i) <= ll2.get(j)) // check which element is lower
{
ll3.add(ll1.get(i)); // if ll1 element is lower then add to ll3
i++;
}
else if(ll1.get(i) >= ll2.get(j))
{
ll3.add(ll2.get(j));// if ll2 element is lower then add to ll3
j++;
}
}
if(ll1.size() > i) // adding the rest of elements
{
while(ll1.size() > i)
{
ll3.add(ll1.get(i));
i++;
}
}
else if(ll2.size()> j)
{
while(ll2.size() > j)
{
ll3.add(ll2.get(j));
j++;
}
}
System.out.println(\"The Conbined of two list data is \"+ ll3);
}
}
Output:
The Conbined of two list data is [2, 3, 4, 5, 6, 7, 7, 8, 9, 12].
HO SolutionHO .pdf
This short document contains a chemical formula written twice. The formula appears to represent an alcohol molecule, with two hydrogen atoms bonded to an oxygen atom that is double bonded to another oxygen atom. The document does not provide any other context or information.
Hi, Please find my code##### Sequence.java ##############import.pdf
Hi, Please find my code:
##### Sequence.java ##############
import java.util.ArrayList;
public class Sequence {
private ArrayList values;
public Sequence(){
values= new ArrayList();
}
public void add(int n){
values.add(n);
}
// return copy of list
public ArrayList getSequence(){
ArrayList copyList = new ArrayList<>(values.size());
for (Integer x : values) {
copyList.add(x);
}
return copyList;
}
public String toString(){
return values.toString();
}
public Sequence append(Sequence other){
Sequence res = new Sequence();
for(Integer x : values)
res.add(x);
for(Integer x:other.getSequence())
res.add(x);
return res;
}
public Sequence merge(Sequence other){
int i=0, j=0;
ArrayList otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList.get(j)){
mergeSeq.add(otherList.get(j));
j++;
}else{ // both have same value
mergeSeq.add(values.get(i));
i++;
j++;
}
}
while(i < values.size()){
mergeSeq.add(values.get(i));
i++;
}
while(j < otherList.size()){
mergeSeq.add(otherList.get(j));
j++;
}
return mergeSeq;
}
}
############ SequenceTest.java ###############
public class SequenceTest {
public static void main(String[] args) {
Sequence s1 = new Sequence();
Sequence s2 = new Sequence();
s1.add(1);
s1.add(4);
s1.add(9);
s1.add(16);
s2.add(9);
s2.add(7);
s2.add(4);
s2.add(9);
s2.add(11);
Sequence s3 = s1.merge(s2);
System.out.println(\"S1: \"+s1.toString());
System.out.println(\"S2: \"+s2.toString());
System.out.println(\"S1+S2: \"+s3.toString());
Sequence s4 = new Sequence();
s4.add(4);
s4.add(9);
s4.add(14);
s4.add(15);
s4.add(16);
s4.add(20);
s4.add(22);
Sequence s5 = s1.mergeNoDuplicates(s4);
System.out.println(\"S4: \"+s4.toString());
System.out.println(\"S1+S4(no duplicate): \"+s5.toString());
}
}
/*
Sample Output:
S1: [1, 4, 9, 16]
S2: [9, 7, 4, 9, 11]
S1+S2: [1, 9, 4, 7, 9, 4, 16, 9, 11]
S4: [4, 9, 14, 15, 16, 20, 22]
S1+S4(no duplicate): [1, 4, 9, 14, 15, 16, 20, 22]
*/
Solution
Hi, Please find my code:
##### Sequence.java ##############
import java.util.ArrayList;
public class Sequence {
private ArrayList values;
public Sequence(){
values= new ArrayList();
}
public void add(int n){
values.add(n);
}
// return copy of list
public ArrayList getSequence(){
ArrayList copyList = new ArrayList<>(values.size());
for (Integer x : values) {
copyList.add(x);
}
return copyList;
}
public String toString(){
return values.toString();
}
public Sequence append(Sequence other){
Sequence res = new Sequence();
for(Integer x : values)
res.add(x);
for(Integer x:other.getSequence())
res.add(x);
return res;
}
public Sequence merge(Sequence other){
int i=0, j=0;
ArrayList otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList.get(j)){
mergeSeq.add(otherList.get(j));
j++;
}else{ // both have same value
mergeSeq.add(values.get(i));
i++;
j++;
}
}
while(i < values.size(.
A unit cell is like a brick in a wall, its the ba.pdf
A unit cell is like a brick in a wall, its the basic unit which on repeating again and
again u get the crystal lattice of the solid
Solution
A unit cell is like a brick in a wall, its the basic unit which on repeating again and
again u get the crystal lattice of the solid.
Equation of dissociation of hydrocyanic acid, HCN will be given as.pdf
Equation of dissociation of hydrocyanic acid, HCN will be given as:
HA < ---------> H+ + A–
Let is the degree of ionization of HA
Initial concentration:
[HA] = 0.0825
[H+] = 0
[A–] = 0
Equilibrium concentration:
[HA] = 0.0825 (1 – )
H+] = 0.0825
[A–] = 0.0825
Ka = [H+] [CN–] / [HCN]
1.20 x 10 ^ -2= (0.0825 ) (0.0825 ) / 0.0825 (1 – )
As, 1 – 1
Therefore, 1.20 x 10 ^ -2= (0.0825) 2
= (1.20 x 10 ^ -2/ 0.0825)1/2
= 0.381
Hence, percent ionization = 38.1 %
Solution
Equation of dissociation of hydrocyanic acid, HCN will be given as:
HA < ---------> H+ + A–
Let is the degree of ionization of HA
Initial concentration:
[HA] = 0.0825
[H+] = 0
[A–] = 0
Equilibrium concentration:
[HA] = 0.0825 (1 – )
H+] = 0.0825
[A–] = 0.0825
Ka = [H+] [CN–] / [HCN]
1.20 x 10 ^ -2= (0.0825 ) (0.0825 ) / 0.0825 (1 – )
As, 1 – 1
Therefore, 1.20 x 10 ^ -2= (0.0825) 2
= (1.20 x 10 ^ -2/ 0.0825)1/2
= 0.381
Hence, percent ionization = 38.1 %.
Delphi can work as prediction method if it overcomes disadvantages o.pdf
Delphi can work as prediction method if it overcomes disadvantages of prediction market.
Delphi seems to have these advantages over prediction markets: 1) It can be used for a much
broader range of problems, since there is no need to judge the outcome of a situation in order to
determine pay-offs for participants.2) Many people lack the understanding of how markets work
or how to translate their expectations into market prices. It is easier for people to reveal their
opinions in Delphi.3) It can be challenging, if not impossible, to formulate some problems as
contracts in prediction markets. It is easier to address complex issues and to obtain predictions by
asking direct questions of a Delphi panel.
4)It is easier to maintain confidentiality with Delphi. For markets, it may be morally
objectionable to benefit from trading on the outcome of critical issues. 5)Prediction markets are
vulnerable to speculative attacks mounted in order to manipulate the results. A Delphi
administrator, on the other hand, can choose panellists who are likely to reveal their true beliefs
and exclude extreme values from the calculation of the Delphi forecast either directly or by
calculating a median rather than a mean.6) The opportunity to provide comments or reasons for
judgments allows Delphi participants to introduce new ideas into the discussion. And the
transparent exchange of knowledge allows experts to learn while participating in the Delphi
process.7) The transparent exchange of knowledge reveals information that has already been
taken into account. This helps Delphi panels avoid two undesirable features of predictions
markets: the inefficiency of each participant independently searching for information, and
cascades. A cascade is a cumulative and excessive price movement that occurs when some
participants, assuming that a shift in price is due to new information, react; and then others react
to the reactions.8) Delphi requires only 5 to 20 experts who have agreed to participate and should
therefore be superior to thin markets (those with few participants) where the incentive to trade,
and thereby reveal information, is weak .
Solution
Delphi can work as prediction method if it overcomes disadvantages of prediction market.
Delphi seems to have these advantages over prediction markets: 1) It can be used for a much
broader range of problems, since there is no need to judge the outcome of a situation in order to
determine pay-offs for participants.2) Many people lack the understanding of how markets work
or how to translate their expectations into market prices. It is easier for people to reveal their
opinions in Delphi.3) It can be challenging, if not impossible, to formulate some problems as
contracts in prediction markets. It is easier to address complex issues and to obtain predictions by
asking direct questions of a Delphi panel.
4)It is easier to maintain confidentiality with Delphi. For markets, it may be morally
objectionable to benefit from trading on.
Competetion is a very common phenomenon observed in ecological syste.pdf
Competetion is a very common phenomenon observed in ecological systems. Competetion can
be of two types, intra-specific or inter-specific in nature. These two types of competeions differ
in mode, nature and behaviour. The major conceptual differences are deciphered as given below:
1. Nature of competetion: As the name suggests, intra-specific competetion arises between
individuals of same species, for example, competetion for space below a tree for residence
between ants is intra-specific competetion. On the other hand, inter-specific competetion arises
between individuals of different species. For example, competetion between ants and local grass
variety for space below a tree for sustainance of life is inter-specific competetion.
2. Severity: The extent of severity on intra-specific competetion is very high as compared to
interspecific competetion. This is because individuals of same species have similar kind of needs
to sustain life and thus possess very high competetion among each other for limited amount of
resources availabale. On the other hand, when two individuals of different species compete for a
single resource, they end up either acquiring it terminally or distribute it mutually so as to
promote ecological balance.
3. Ecological adaptivity: The nature of adaptation an organism displays determines the extent
and nature of competetion it will possess. This implies that at a given geographical area,
individuals showing more adaptive responses will be able to subside the competetion and
dominate that geographical area. For example, at extremely high altitudes, plant varities which
could sustain conditions of drought, temperature shifts and low oxygen availabaility are able to
survive competetively as compared to those plant varities of same/different species which cannot
adapt themselves.
Thus, these basic concepts must be analysed thoroughly when considering and
understanding intraspecific and interspecific competition in an ecological system.
Solution
Competetion is a very common phenomenon observed in ecological systems. Competetion can
be of two types, intra-specific or inter-specific in nature. These two types of competeions differ
in mode, nature and behaviour. The major conceptual differences are deciphered as given below:
1. Nature of competetion: As the name suggests, intra-specific competetion arises between
individuals of same species, for example, competetion for space below a tree for residence
between ants is intra-specific competetion. On the other hand, inter-specific competetion arises
between individuals of different species. For example, competetion between ants and local grass
variety for space below a tree for sustainance of life is inter-specific competetion.
2. Severity: The extent of severity on intra-specific competetion is very high as compared to
interspecific competetion. This is because individuals of same species have similar kind of needs
to sustain life and thus possess very high competetion among each.
Advanced Java[Extra Concepts, Not Difficult].docx
This is part 2 of my Java Learning Journey. This contains Hashing, ArrayList, LinkedList, Date and Time Classes, Calendar Class and more.
Pengantar Penggunaan Flutter - Dart programming language1.pptx
Pengantar Penggunaan Flutter - Dart programming language1.pptx
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Moseley showed that there were gaps in the atomic.pdf
Moseley showed that there were gaps in the atomic number sequence at numbers
43, 61, 72, and 75. These spaces are now known, respectively, to be the places of the radioactive
synthetic elements technetium and promethium, and also the last two quite rare naturally-
occurring stable elements hafnium (discovered 1923) and rhenium (discovered 1925). Nothing
about these four elements was known of in Moseley\'s lifetime, not even their very existence.
Based on the intuition of a very experienced chemist, Dimitri Mendeleev had predicted the
existence of a missing element in the Periodic Table, which was later found to be filled by
technetium, and Bohuslav Brauner had predicted the existence of another missing element in this
Table, which was later found to be filled by promethium. Henry Moseley\'s experiments
confirmed these predictions, by showing exactly what the missing atomic numbers were, 43 and
61. In addition, Moseley predicted the two more undiscovered elements, those with the atomic
numbers 72 and 75, and he gave very strong evidence that there were no other gaps in the
Periodic Table between the elements aluminium (atomic number 13) and gold (atomic number
79).
Solution
Moseley showed that there were gaps in the atomic number sequence at numbers
43, 61, 72, and 75. These spaces are now known, respectively, to be the places of the radioactive
synthetic elements technetium and promethium, and also the last two quite rare naturally-
occurring stable elements hafnium (discovered 1923) and rhenium (discovered 1925). Nothing
about these four elements was known of in Moseley\'s lifetime, not even their very existence.
Based on the intuition of a very experienced chemist, Dimitri Mendeleev had predicted the
existence of a missing element in the Periodic Table, which was later found to be filled by
technetium, and Bohuslav Brauner had predicted the existence of another missing element in this
Table, which was later found to be filled by promethium. Henry Moseley\'s experiments
confirmed these predictions, by showing exactly what the missing atomic numbers were, 43 and
61. In addition, Moseley predicted the two more undiscovered elements, those with the atomic
numbers 72 and 75, and he gave very strong evidence that there were no other gaps in the
Periodic Table between the elements aluminium (atomic number 13) and gold (atomic number
79)..
Lewis Structures A structural formula in which el.pdf
Lewis Structures A structural formula in which electrons are represented by dots;
two dots between atoms represent a covalent bond. Also known as electron-dot formula or Lewis
formula. Covalent Bond A chemical bond formed by the sharing of one or more electrons,
especially pairs of electrons, between atoms. Ionic Bond A chemical bond between two ions
with opposite charges, characteristic of salts. Also called electrovalent bond. Resonance The
property of a compound having simultaneously the characteristics of two or more structural
forms that differ only in the distribution of electrons. Such compounds are highly stable and
cannot be properly represented by a single structural formula. Polarity Tendency of a molecule,
or compound, to be attracted or repelled by electrical charges because of an asymmetrical
arrangement of atoms around the nucleus. Dipole Moment A dipole moment is the development
of an electronic charge in a molecule by virtue of it structure and components. Bond Energy The
average value of specific bond dissociation energies that have been measured from different
molecules of a given type Valence shell electron pair repulsion (VSEPR) theory is a model in
chemistry used to predict the shape of individual molecules based upon the extent of electron-
pair electrostatic repulsion.It is also named Gillespie–Nyholm theory after its two main
developers The premise of VSEPR is that the valence electron pairs surrounding an atom
mutually repel each other, and will therefore adopt an arrangement that minimizes this repulsion,
thus determining the molecular geometry. The number of electron pairs surrounding an atom,
both bonding and nonbonding, is called its steric number.
Solution
Lewis Structures A structural formula in which electrons are represented by dots;
two dots between atoms represent a covalent bond. Also known as electron-dot formula or Lewis
formula. Covalent Bond A chemical bond formed by the sharing of one or more electrons,
especially pairs of electrons, between atoms. Ionic Bond A chemical bond between two ions
with opposite charges, characteristic of salts. Also called electrovalent bond. Resonance The
property of a compound having simultaneously the characteristics of two or more structural
forms that differ only in the distribution of electrons. Such compounds are highly stable and
cannot be properly represented by a single structural formula. Polarity Tendency of a molecule,
or compound, to be attracted or repelled by electrical charges because of an asymmetrical
arrangement of atoms around the nucleus. Dipole Moment A dipole moment is the development
of an electronic charge in a molecule by virtue of it structure and components. Bond Energy The
average value of specific bond dissociation energies that have been measured from different
molecules of a given type Valence shell electron pair repulsion (VSEPR) theory is a model in
chemistry used to predict the shape of individual molecules based upon the extent of electr.
fluorine , oxygen , chlorine , sulphor ,phophorus.pdf
fluorine , oxygen , chlorine , sulphor ,phophorus
Solution
fluorine , oxygen , chlorine , sulphor ,phophorus.
CuS is insoluble. NaCl stays in solution. so cor.pdf
CuS is insoluble. NaCl stays in solution. so correct answer is C
Solution
CuS is insoluble. NaCl stays in solution. so correct answer is C.
When you have an acidic solution like you do, (because the H+ and th.pdf
When you have an acidic solution like you do, (because the H+ and the F- dissociate very
readily), there is an abundance of H and F on the product side. However, with the addition of
more F- the solution is the forced back to the left to reach the same equilibrium that was found
before. (Also take note that you have a 0.1M solution) Like so:
HF --> H+ + F-
in a aqueous solution there are H3O+ molecules and OH-.
Even though HF has a high level of dissociation it will not dissociate completely.
so when F is added the solution runs to the left because it has been added on the right.
The reason that it reacts with the H3O is because it is more basic than the H and the F reacts with
the most basic.
Hope this helps.
Solution
When you have an acidic solution like you do, (because the H+ and the F- dissociate very
readily), there is an abundance of H and F on the product side. However, with the addition of
more F- the solution is the forced back to the left to reach the same equilibrium that was found
before. (Also take note that you have a 0.1M solution) Like so:
HF --> H+ + F-
in a aqueous solution there are H3O+ molecules and OH-.
Even though HF has a high level of dissociation it will not dissociate completely.
so when F is added the solution runs to the left because it has been added on the right.
The reason that it reacts with the H3O is because it is more basic than the H and the F reacts with
the most basic.
Hope this helps..
Type III secretion system- Complex structure helps the bacteria to e.pdf
Type III secretion system- Complex structure helps the bacteria to escape the host immune
system.
Solution
Type III secretion system- Complex structure helps the bacteria to escape the host immune
system..
The OECD has produced a considerable amount of analytical work addre.pdf
The OECD has produced a considerable amount of analytical work addressing the issue of
incentives for attracting foreign direct investment (FDI). This list, compiled in the context of a
2002 project undertaken by the Investment Committee, provides an overview of this work which
is indicative, rather than exhaustive, of the large body of work undertaken by several OECD
bodies in this area.
The Economics of International Investment Incentives , 2001
This paper, prepared by Professor Magnus Blomstr
Solution
The OECD has produced a considerable amount of analytical work addressing the issue of
incentives for attracting foreign direct investment (FDI). This list, compiled in the context of a
2002 project undertaken by the Investment Committee, provides an overview of this work which
is indicative, rather than exhaustive, of the large body of work undertaken by several OECD
bodies in this area.
The Economics of International Investment Incentives , 2001
This paper, prepared by Professor Magnus Blomstr.
Q2. RAM holds the running configuration.Q4. The startup configurat.pdf
Q2. RAM holds the running configuration.
Q4. The startup configuration file is stored in NVRAM/ROM.
Q7. There are three elements of communication: the message sender, the feedback, and the
message receiver.
Q8. From the privileged exec mode of the router named ITT330, save the configuration to
NVRAM, prompt ___ command ___. What is the short version of this command.
Solution
Q2. RAM holds the running configuration.
Q4. The startup configuration file is stored in NVRAM/ROM.
Q7. There are three elements of communication: the message sender, the feedback, and the
message receiver.
Q8. From the privileged exec mode of the router named ITT330, save the configuration to
NVRAM, prompt ___ command ___. What is the short version of this command..
AnswerIn population 1, only homozygous dominant population is pre.pdf
Answer:
In population 1, only homozygous dominant population is present.
In population 2, only heterozygous dominant population is present.
Solution
Answer:
In population 1, only homozygous dominant population is present.
In population 2, only heterozygous dominant population is present..
P=VI=(10)(2)=20W absorbed+ve power means absorbed -ve power means .pdf
P=VI=(10)(2)=20W absorbed
+ve power means absorbed -ve power means supplied.
Solution
P=VI=(10)(2)=20W absorbed
+ve power means absorbed -ve power means supplied..
Option D is the answerSolutionOption D is the answer.pdf
Option D is the answer. The document states that Option D is the correct answer to an unknown question. It then repeats that Option D is the answer.
A.True B.True C.True D.False .pdf
This document contains a multiple choice question with 4 options: A, B, C and D. The solution provided states that options A, B and C are true, while option D is false.
Mean = (sum of the observations)(Total no. of observations)= (12+.pdf
Mean = (sum of the observations)/(Total no. of observations)
= (12+20+10+15+20)/5 = 15.4
Thus mean = 15.4
Solution
Mean = (sum of the observations)/(Total no. of observations)
= (12+20+10+15+20)/5 = 15.4
Thus mean = 15.4.
Here is the codeimport java.util.; public class HelloWorld{p.pdf
Here is the code:
import java.util.*;
public class HelloWorld{
public static void main(String []args){
LinkedList ll1 = new LinkedList();
LinkedList ll3 = new LinkedList();
LinkedList ll2 = new LinkedList(); // comdine list
int i=0,j=0;
ll1.add(2); // adding elements to list1
ll1.add(3);
ll1.add(5);
ll1.add(7);
ll1.add(9);
ll2.add(4); // adding elements to list 2
ll2.add(6);
ll2.add(7);
ll2.add(8);
ll2.add(12);
while(ll1.size() > i && ll2.size()> j) // exits when any of list size exceeds
{
if(ll1.get(i) <= ll2.get(j)) // check which element is lower
{
ll3.add(ll1.get(i)); // if ll1 element is lower then add to ll3
i++;
}
else if(ll1.get(i) >= ll2.get(j))
{
ll3.add(ll2.get(j));// if ll2 element is lower then add to ll3
j++;
}
}
if(ll1.size() > i) // adding the rest of elements
{
while(ll1.size() > i)
{
ll3.add(ll1.get(i));
i++;
}
}
else if(ll2.size()> j)
{
while(ll2.size() > j)
{
ll3.add(ll2.get(j));
j++;
}
}
System.out.println(\"The Conbined of two list data is \"+ ll3);
}
}
Output:
The Conbined of two list data is [2, 3, 4, 5, 6, 7, 7, 8, 9, 12]
Solution
Here is the code:
import java.util.*;
public class HelloWorld{
public static void main(String []args){
LinkedList ll1 = new LinkedList();
LinkedList ll3 = new LinkedList();
LinkedList ll2 = new LinkedList(); // comdine list
int i=0,j=0;
ll1.add(2); // adding elements to list1
ll1.add(3);
ll1.add(5);
ll1.add(7);
ll1.add(9);
ll2.add(4); // adding elements to list 2
ll2.add(6);
ll2.add(7);
ll2.add(8);
ll2.add(12);
while(ll1.size() > i && ll2.size()> j) // exits when any of list size exceeds
{
if(ll1.get(i) <= ll2.get(j)) // check which element is lower
{
ll3.add(ll1.get(i)); // if ll1 element is lower then add to ll3
i++;
}
else if(ll1.get(i) >= ll2.get(j))
{
ll3.add(ll2.get(j));// if ll2 element is lower then add to ll3
j++;
}
}
if(ll1.size() > i) // adding the rest of elements
{
while(ll1.size() > i)
{
ll3.add(ll1.get(i));
i++;
}
}
else if(ll2.size()> j)
{
while(ll2.size() > j)
{
ll3.add(ll2.get(j));
j++;
}
}
System.out.println(\"The Conbined of two list data is \"+ ll3);
}
}
Output:
The Conbined of two list data is [2, 3, 4, 5, 6, 7, 7, 8, 9, 12].
HO SolutionHO .pdf
This short document contains a chemical formula written twice. The formula appears to represent an alcohol molecule, with two hydrogen atoms bonded to an oxygen atom that is double bonded to another oxygen atom. The document does not provide any other context or information.
Hi, Please find my code##### Sequence.java ##############import.pdf
Hi, Please find my code:
##### Sequence.java ##############
import java.util.ArrayList;
public class Sequence {
private ArrayList values;
public Sequence(){
values= new ArrayList();
}
public void add(int n){
values.add(n);
}
// return copy of list
public ArrayList getSequence(){
ArrayList copyList = new ArrayList<>(values.size());
for (Integer x : values) {
copyList.add(x);
}
return copyList;
}
public String toString(){
return values.toString();
}
public Sequence append(Sequence other){
Sequence res = new Sequence();
for(Integer x : values)
res.add(x);
for(Integer x:other.getSequence())
res.add(x);
return res;
}
public Sequence merge(Sequence other){
int i=0, j=0;
ArrayList otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList.get(j)){
mergeSeq.add(otherList.get(j));
j++;
}else{ // both have same value
mergeSeq.add(values.get(i));
i++;
j++;
}
}
while(i < values.size()){
mergeSeq.add(values.get(i));
i++;
}
while(j < otherList.size()){
mergeSeq.add(otherList.get(j));
j++;
}
return mergeSeq;
}
}
############ SequenceTest.java ###############
public class SequenceTest {
public static void main(String[] args) {
Sequence s1 = new Sequence();
Sequence s2 = new Sequence();
s1.add(1);
s1.add(4);
s1.add(9);
s1.add(16);
s2.add(9);
s2.add(7);
s2.add(4);
s2.add(9);
s2.add(11);
Sequence s3 = s1.merge(s2);
System.out.println(\"S1: \"+s1.toString());
System.out.println(\"S2: \"+s2.toString());
System.out.println(\"S1+S2: \"+s3.toString());
Sequence s4 = new Sequence();
s4.add(4);
s4.add(9);
s4.add(14);
s4.add(15);
s4.add(16);
s4.add(20);
s4.add(22);
Sequence s5 = s1.mergeNoDuplicates(s4);
System.out.println(\"S4: \"+s4.toString());
System.out.println(\"S1+S4(no duplicate): \"+s5.toString());
}
}
/*
Sample Output:
S1: [1, 4, 9, 16]
S2: [9, 7, 4, 9, 11]
S1+S2: [1, 9, 4, 7, 9, 4, 16, 9, 11]
S4: [4, 9, 14, 15, 16, 20, 22]
S1+S4(no duplicate): [1, 4, 9, 14, 15, 16, 20, 22]
*/
Solution
Hi, Please find my code:
##### Sequence.java ##############
import java.util.ArrayList;
public class Sequence {
private ArrayList values;
public Sequence(){
values= new ArrayList();
}
public void add(int n){
values.add(n);
}
// return copy of list
public ArrayList getSequence(){
ArrayList copyList = new ArrayList<>(values.size());
for (Integer x : values) {
copyList.add(x);
}
return copyList;
}
public String toString(){
return values.toString();
}
public Sequence append(Sequence other){
Sequence res = new Sequence();
for(Integer x : values)
res.add(x);
for(Integer x:other.getSequence())
res.add(x);
return res;
}
public Sequence merge(Sequence other){
int i=0, j=0;
ArrayList otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList = other.getSequence();
Sequence mergeSeq = new Sequence();
while(i otherList.get(j)){
mergeSeq.add(otherList.get(j));
j++;
}else{ // both have same value
mergeSeq.add(values.get(i));
i++;
j++;
}
}
while(i < values.size(.
A unit cell is like a brick in a wall, its the ba.pdf
A unit cell is like a brick in a wall, its the basic unit which on repeating again and
again u get the crystal lattice of the solid
Solution
A unit cell is like a brick in a wall, its the basic unit which on repeating again and
again u get the crystal lattice of the solid.
Equation of dissociation of hydrocyanic acid, HCN will be given as.pdf
Equation of dissociation of hydrocyanic acid, HCN will be given as:
HA < ---------> H+ + A–
Let is the degree of ionization of HA
Initial concentration:
[HA] = 0.0825
[H+] = 0
[A–] = 0
Equilibrium concentration:
[HA] = 0.0825 (1 – )
H+] = 0.0825
[A–] = 0.0825
Ka = [H+] [CN–] / [HCN]
1.20 x 10 ^ -2= (0.0825 ) (0.0825 ) / 0.0825 (1 – )
As, 1 – 1
Therefore, 1.20 x 10 ^ -2= (0.0825) 2
= (1.20 x 10 ^ -2/ 0.0825)1/2
= 0.381
Hence, percent ionization = 38.1 %
Solution
Equation of dissociation of hydrocyanic acid, HCN will be given as:
HA < ---------> H+ + A–
Let is the degree of ionization of HA
Initial concentration:
[HA] = 0.0825
[H+] = 0
[A–] = 0
Equilibrium concentration:
[HA] = 0.0825 (1 – )
H+] = 0.0825
[A–] = 0.0825
Ka = [H+] [CN–] / [HCN]
1.20 x 10 ^ -2= (0.0825 ) (0.0825 ) / 0.0825 (1 – )
As, 1 – 1
Therefore, 1.20 x 10 ^ -2= (0.0825) 2
= (1.20 x 10 ^ -2/ 0.0825)1/2
= 0.381
Hence, percent ionization = 38.1 %.
Delphi can work as prediction method if it overcomes disadvantages o.pdf
Delphi can work as prediction method if it overcomes disadvantages of prediction market.
Delphi seems to have these advantages over prediction markets: 1) It can be used for a much
broader range of problems, since there is no need to judge the outcome of a situation in order to
determine pay-offs for participants.2) Many people lack the understanding of how markets work
or how to translate their expectations into market prices. It is easier for people to reveal their
opinions in Delphi.3) It can be challenging, if not impossible, to formulate some problems as
contracts in prediction markets. It is easier to address complex issues and to obtain predictions by
asking direct questions of a Delphi panel.
4)It is easier to maintain confidentiality with Delphi. For markets, it may be morally
objectionable to benefit from trading on the outcome of critical issues. 5)Prediction markets are
vulnerable to speculative attacks mounted in order to manipulate the results. A Delphi
administrator, on the other hand, can choose panellists who are likely to reveal their true beliefs
and exclude extreme values from the calculation of the Delphi forecast either directly or by
calculating a median rather than a mean.6) The opportunity to provide comments or reasons for
judgments allows Delphi participants to introduce new ideas into the discussion. And the
transparent exchange of knowledge allows experts to learn while participating in the Delphi
process.7) The transparent exchange of knowledge reveals information that has already been
taken into account. This helps Delphi panels avoid two undesirable features of predictions
markets: the inefficiency of each participant independently searching for information, and
cascades. A cascade is a cumulative and excessive price movement that occurs when some
participants, assuming that a shift in price is due to new information, react; and then others react
to the reactions.8) Delphi requires only 5 to 20 experts who have agreed to participate and should
therefore be superior to thin markets (those with few participants) where the incentive to trade,
and thereby reveal information, is weak .
Solution
Delphi can work as prediction method if it overcomes disadvantages of prediction market.
Delphi seems to have these advantages over prediction markets: 1) It can be used for a much
broader range of problems, since there is no need to judge the outcome of a situation in order to
determine pay-offs for participants.2) Many people lack the understanding of how markets work
or how to translate their expectations into market prices. It is easier for people to reveal their
opinions in Delphi.3) It can be challenging, if not impossible, to formulate some problems as
contracts in prediction markets. It is easier to address complex issues and to obtain predictions by
asking direct questions of a Delphi panel.
4)It is easier to maintain confidentiality with Delphi. For markets, it may be morally
objectionable to benefit from trading on.
Competetion is a very common phenomenon observed in ecological syste.pdf
Competetion is a very common phenomenon observed in ecological systems. Competetion can
be of two types, intra-specific or inter-specific in nature. These two types of competeions differ
in mode, nature and behaviour. The major conceptual differences are deciphered as given below:
1. Nature of competetion: As the name suggests, intra-specific competetion arises between
individuals of same species, for example, competetion for space below a tree for residence
between ants is intra-specific competetion. On the other hand, inter-specific competetion arises
between individuals of different species. For example, competetion between ants and local grass
variety for space below a tree for sustainance of life is inter-specific competetion.
2. Severity: The extent of severity on intra-specific competetion is very high as compared to
interspecific competetion. This is because individuals of same species have similar kind of needs
to sustain life and thus possess very high competetion among each other for limited amount of
resources availabale. On the other hand, when two individuals of different species compete for a
single resource, they end up either acquiring it terminally or distribute it mutually so as to
promote ecological balance.
3. Ecological adaptivity: The nature of adaptation an organism displays determines the extent
and nature of competetion it will possess. This implies that at a given geographical area,
individuals showing more adaptive responses will be able to subside the competetion and
dominate that geographical area. For example, at extremely high altitudes, plant varities which
could sustain conditions of drought, temperature shifts and low oxygen availabaility are able to
survive competetively as compared to those plant varities of same/different species which cannot
adapt themselves.
Thus, these basic concepts must be analysed thoroughly when considering and
understanding intraspecific and interspecific competition in an ecological system.
Solution
Competetion is a very common phenomenon observed in ecological systems. Competetion can
be of two types, intra-specific or inter-specific in nature. These two types of competeions differ
in mode, nature and behaviour. The major conceptual differences are deciphered as given below:
1. Nature of competetion: As the name suggests, intra-specific competetion arises between
individuals of same species, for example, competetion for space below a tree for residence
between ants is intra-specific competetion. On the other hand, inter-specific competetion arises
between individuals of different species. For example, competetion between ants and local grass
variety for space below a tree for sustainance of life is inter-specific competetion.
2. Severity: The extent of severity on intra-specific competetion is very high as compared to
interspecific competetion. This is because individuals of same species have similar kind of needs
to sustain life and thus possess very high competetion among each.
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