The document outlines the expectations and objectives for a science class focused on electromagnetic waves, highlighting the importance of responsibility, kindness, and active participation. It details mathematical relationships between wavelength, frequency, and the speed of light, alongside example problems demonstrating these concepts. Additionally, it explains the inverse relationship between frequency and wavelength of electromagnetic waves.

1. WELCOME TO SCIENCE
CLASS!

2. Friendly Reminders:
1. Let us be responsible students.
2. Let us be kind and polite.
3. Let us participate actively.
4. Let us learn, enjoy and thankful
5. Let us always give Glory to God.

3. VERBAL and
VISUAL WORD
GAME

4. DEFINITION

5. DEFINITION

6. c= 3 x 108
m/s
a fundamental physical
constant that is the speed at
which electromagnetic
radiation travels in a vacuum.

7. the capacity to do
work.

8. VOCABULARY TERMS VISUAL REPRESENTATION
ELECTROMAGNETIC WAVES- are disturbances that transfer
energy through field.

9. OBJECTIVES:
1. Explain the relationship between
wavelength and frequency of a wave.
2. Compute for the frequency and
wavelength of a wave.
3. Apply basic mathematical
concept in solving problem.

10. •ELECTROMAGNETIC
WAVES can be
described by their
wavelengths,
energy, and
frequency. All three
describe a different
property of light,
yet they are related
to each other
mathematically.

11. EQUATION
• f = frequency
• c = speed of light
• λ = wavelength
(c= 3 x 108
m/s)

13. RULES IN SCIENTIFIC NOTATIONS

20. WORD PROBLEM GAME

21. 1. What is the wavelength of
light waves with frequency of 6
x 1014
Hz?

22. Negative sign (-) moving to
the right add one (1).
Given:
c = 3 x 108
m/s
f = 6 x 1014
Hz?
Find: λ = ?
Solution:
λ = c/f
= 3 x 108
m/s
6 x 1014
Hz
= 0.5 x 10-6
m
= 5.0 x 10-7
m

23. 2. Calculate the wavelength of
radiation with a frequency of
5.0 x 1014
Hz?

24. Negative sign (-) moving to
the right add one (1).
Given:
c = 3 x 108
m/s
f = 5.0 x 1014
Hz?
Find: λ = ?
Solution:
λ = c/f
= 3 x 108
m/s
5.0 x 1014
Hz
= 0.6 x 10-6
m
= 6.0 x 10-7
m

25. 2. What is the frequency of
radio wave with a wavelength
of 20 m?

26. Given:
c = 3 x 108
m/s
λ = 20 m
Find: f = ?
Solution:
f = c/ λ
= 3 x 108
m/s
20 m
= 0.15 x 108
Hz
= 1.5 x 107
Hz?
Positive sign (+) moving to
the right minus one (1).

27. 3. What is the frequency of a
radio wave with wavelength of
1.0 x 10-3
m?

28. Given:
c = 3 x 108
m/s
λ = 1.0 x 10-3
m
Find: f = ?
Solution:
f = c/ λ
= 3 x 108
m/s
1.0 x 10-3
m
= 3.0 x 1011
Hz

30. Sample Problem:
1. What is the frequency of
electromagnetic wave with a
wavelength 3.8 x 10-7
meters?

31. Sample Problem:
2. What is the wavelength of
the wave with a frequency of
3 x 109
Hertz?

32. As the frequency of the wave
increases, wavelengths decreases.
In problem number 1, how do varying wavelengths
affect the frequency of a wave?
As wavelengths decreases, the frequency of the
waves increases.
In problem number 2, how do varying frequencies
affect the wavelength of a wave?

33. Therefore, the higher the
frequency of an electromagnetic
wave, the more electromagnetic
energy it carries. Interestingly, the
frequency of an electromagnetic
wave is inversely proportional to its
wavelength, which means that the
larger the frequency of such wave,
the shorter its wavelength, and vice
versa.