2. pecahan

MODUL KECEMERLANGAN MATEMATIK UPSR 2016
PECAHAN
PECAHAN

Pecahan setara / pecahan tak wajar
Penukaran nilai kepada perpuluhan atau peratus
Samakan penyebut / bina nilai pecahan gambar rajah / nilai pecahan
Pecahan dengan operasi yang empat mencari bilangan daripada nilai
pecahan ( x dan ÷ )
Penyelesaian masalah – melibatkan pecahan dan kemahiran lain
PECAHAN
PECAHAN

Pengangka
Penyebut
PECAHAN

PECAHAN WAJAR
PECAHAN

PERMUDAHKAN
PECAHAN

6
2
PECAHAN


6
2
2
2
x 3
x1
=
3
1
PECAHAN

9
6
PECAHAN

Termudah
9
6
=
0 x 3 = 0
1 x 3 = 3
2 x 3 = 6
3 x 3 = 93
2
PECAHAN

9
3
PECAHAN

Termudah
9
3
=
0 x 3 = 0
1 x 3 = 3
2 x 3 = 6
3 x 3 = 93
1
PECAHAN

PECAHAN TIDAK WAJAR
PECAHAN

2
3
PECAHAN

) 32
1
2
1
1
1
2
=
PECAHAN

4
6
PECAHAN

) 64
1
4
2
1
2
4
=
PECAHAN

1
2
4
=
÷2
2÷
=1
1
2
PECAHAN

Tukar kepada nombor bercampur
0 x 4 = 0
1 x 4 = 4
2 x 4 = 8
4
7
) 74
1
4
3
PECAHAN

)74
1
4
3
13
4=
PECAHAN

TUKAR NOMBOR BERCAMPUR
KEPADA PECAHAN TIDAK WAJAR
PECAHAN

2
1
1
PECAHAN

2
1
1 =
2
1
1X
+
=
2
3
PECAHAN

3
1
3 =
3
1
3X
+
=
3
10
PECAHAN

Tukar kepada pecahan tidak wajar
3
2
1
3
x11
3 3
2+
x
2+
5
3
5
PECAHAN

TULIS DALAM PERKATAAN
PECAHAN

Tiga per dua
2
3
PECAHAN

3
2
3
Tiga dua per tiga
PECAHAN

PECAHAN
GARIS NOMBOR

2
1
8
3
8
4
8
5
8
6
8
7
8
3
8
7
PECAHAN

6
5
2
1
6
5
6
6
6
7
6
1
1
PECAHAN

2
1
8
7
8
8
8
7
1
8
8

PECAHAN

PECAHAN

8
1
1
4
3
PECAHAN

4
1
1
2
1
1
PECAHAN

8
5
P Q
P + Q =
PECAHAN
8
4
8
2
8
3

6
1
P Q
Q - P =
PECAHAN
6
2
6
4
6
3

3
8
Tulis pecahan
PECAHAN

Tulis dalam perkataan
Satu per lima
PECAHAN

Tulis dalam nombor bercampur
4
1
4
1
11 + =
PECAHAN

5
2
Nyatakan nilai
1
5
2
5
3
5
4
5
5
5
6
PECAHAN

2
1
5
2

x 2
x2
x5
x5
=
10
11
PECAHAN

0 x 10 = 0
1 x 10 = 10
2 x 10 = 20
) 1110
1
10
1
10
1
1
PECAHAN


8
3
8
2
2/
10
8
7
1
1
PECAHAN

5
2
X 150
150
X 2
300
)5 300
- 30
. . 0
0
.
6 0 x 5 = 0
1 x 5 = 5
2 x 5 = 10
3 x 5 = 15
4 x 5 = 20
5 x 5 = 25
6 x 5 = 30
0
PECAHAN

6
1
3
1

x2
x2
PECAHAN

2
1
5
2

x2
x2
x5
x5
PECAHAN


3
1
3
1
PECAHAN


3
2
3
2
PECAHAN


6
1
3
2
PECAHAN


2
1
5
2
PECAHAN


3
1
5
2
PECAHAN


8
1
4
1
2
1
PECAHAN


2
1
6
5
3
2
PECAHAN


4
3
5
2
2
1
PECAHAN


6
1
9
5
3
2
PECAHAN


2
1
4
1
3
2
PECAHAN


2
1
2
PECAHAN


3
1
12
PECAHAN


4
1
1
2
1
2
PECAHAN


6
1
1
3
2
2
PECAHAN


3
2
1
4
1
3
2
1
2
PECAHAN


9
1
4
3
1
3
2
1
2
PECAHAN


2
1
1
6
5
3
4
1
2
PECAHAN


4
3
2
5
1
1
8
5
2
PECAHAN


10
3
3
2
1
1
5
3
1
PECAHAN


3
1
1
4
1
2
3
2
1
PECAHAN


3
1
3
2
PECAHAN


5
2
5
7
PECAHAN


3
2
6
5
x 2
x2
6
4
6
5
 =
3
1
PECAHAN


5
3
3
2
PECAHAN


3
2
1
3
3
3
2
3
1
PECAHAN


9
4
1
PECAHAN


5
3
46
PECAHAN


8
6
910
PECAHAN


3
1
4210
PECAHAN


4
1
4
4
3
3
3
( 4 – 1 )
PECAHAN


7
6
5
PECAHAN


6
5
1
6
1
312
11 +

6
5
1
6
7
311

6
5
1
6
1
312

6
2
7
3
1
7
PECAHAN


3
1
1
2
1
220
19

6
2
1
6
3
219

3
1
1
2
1
220
6
1
16
x 3
x 3
x 2
x 2
PECAHAN


3
2
1
4
1
514
19

12
8
1
12
15
513

3
2
1
4
1
514
12
7
7
x 3
x 3
x 4
x 4
+


5
4
1
5
3
6

5
4
1
5
3
65
8
5
4
4


5
3
1
2
1
4

5
3
1
2
1
3
5
10
9
2
x
5x
2x
2x
10
6
10
15
2 
=
PECAHAN


7
5
7
2
1
PECAHAN


7
5
7
2
1
0
9
( 2 + 7 )
PECAHAN


7
5
7
2
1x
+
9
PECAHAN

7
5
7
2
1 

7
5
7
2
7
7
PECAHAN


5
2
1
5
3
4
PECAHAN


5
4
1
5
3
6
PECAHAN


5
3
1
2
1
4
PECAHAN


6
1
1
4
3
24
PECAHAN


4
1
2
4
1
1
4
3
5
PECAHAN


8
1
2
2
1
4
4
3
7
PECAHAN


4
3
2
3
1
3
2
1
7
PECAHAN


2
1
6
1
3
2
PECAHAN


6
1
1
4
3
2
2
1
4
PECAHAN


6
1
1
4
3
25
PECAHAN


6
1
1
4
3
24
6
1
1
4
1
1 
3
12
13
5
x
3x
2x
2x
4
3
24 
=
3
12
296
5

12
1
6=
PECAHAN

8
1
8
3
8
5
8
7
4
1
2
1
4
3
8
2
8
4
8
6
PECAHAN

9
2
9
4
9
5
3
1
3
2
9
3
9
6
PECAHAN

10
1
10
3
8
7
2
1
5
2
5
3
10
2
10
4
10
6
5
1
10
5
PECAHAN

2
1
10
3
5
3
10
4
10
610
5 P
PECAHAN

5
4
5
6
5
5
5
1
1
5
7
5
8
5
9
x
+
PECAHAN

4
1
1
4
8
P1
= 2
x
+
4
5
4
6
4
7
PECAHAN

Lorek 4
1
PECAHAN

Lorek 3
2
PECAHAN

4
3
=
12
3
PECAHAN

20
4
=
5
3
PECAHAN

8
3
=
12
9
PECAHAN

How many triangle represent
of the whole diagram? 8
3
PECAHAN

=
PECAHAN

2
1
of 6
PECAHAN

5
3 of 15
PECAHAN

Reza has RM84. Nana’s money
is of Reza’s money?
Calculate the Nana’s money?
8
3
PECAHAN

8
3
× RM 84 =
PECAHAN

Sani buys 2 kg of flour. He
uses of the flour to bake a
cake. Calculate the mass in
kg of the flour left ?
5
2
PECAHAN

Left =
5
3
× 2 kg
= 1.2 kg
PECAHAN

2
1
÷ 5 =
PECAHAN

10
1
PECAHAN

4
1
÷
12
1
PECAHAN

4
1
x
1
12
PECAHAN

5
3
÷ 6
PECAHAN

30
3
PECAHAN

2
1
÷
4
1
PECAHAN

2
PECAHAN

5
4
÷
3
1
PECAHAN

5
4 x 3
PECAHAN

5
12
PECAHAN

5
2
2
PECAHAN

2
1
1 ÷ 3
PECAHAN

2
3
÷ 3
PECAHAN

2
3
÷
1
3
PECAHAN

2
3
x
3
1
PECAHAN

2
1
PECAHAN

4
3
1 ÷
8
1
PECAHAN

4
7
÷
8
1
PECAHAN

4
7
x
1
8
1
2
PECAHAN

14
PECAHAN

Lina used of RM12
3
1
to buy a book.

Red
BlueBlue
Yellow
Yellow
Green
The total of the books are 360.
3
1
of the book are red.
What is the amount of the rest colour

Lina has RM 12.
3
1
She spends of her money.
How much is her saving ?
3
1 x RM 12 = RM 4

Jony has RM 200.
4
3He gives of his money to his
parent.
How much money is left ?
4
1
4
1
4
3
4
4
 x 200 = RM 50
50
1

Suzi has RM90.
3
1
Zana’s money is of Suzi’s money.
Calculate the total amount of their money ?
RM 90Suzi =
Zana =
Total =
X RM 90 =
3
1
RM 30
RM 90 + RM 30
= RM 120

Zami has RM 240.
6
1
Tuba’s money is of Zami’s money.
Calculate the diffrence of their money ?
RM 240Zami =
Tuba =
Diffrence =
X RM 240
6
1
RM 240 - RM 40
= RM 200
40

2. pecahan

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2. pecahan