technoplogy

1. Chap. 2 Problem 3
The structure of the peptide and the charges of all functional groups
at pH 7 are shown in the figure. The net charge is -1.
The addition of a phosphate to the tyrosine adds 2 negative charges,
so the net charge would become -3. Most phosphorylation reactions in
cells result from transfer the -phosphate of ATP to the acceptor,
with a large negative ∆G.
F
X Phe (F)

2. Chap. 2 Problem 9
Ammonia is a weak base that can pick up protons at acidic pH. Thus
ammonia is protonated inside lysosomes forming ammonium ion. The
[H+] of the lysosome compartment decreases, and thus the pH of the
lysosome increases.

3. Chap. 2 Meaning of the Kd
Example: Protein (P) binding to DNA (D)
P + D  P.D
Kd = [P][D]/[P.D]
What is the ratio of [D]/[P.D] for different values of [P]?
[P] = 0.1 x Kd [D]/[P.D] = 10/1
[P] = Kd [D]/[P.D] = 1/1
[P] = 10 x Kd [D]/[P.D] = 1/10
This shows that the DNA binding site is about 10% occupied when the
concentration of [P] is 10-fold lower than the Kd, 50% occupied when
[P] is the same as the Kd, and 90% occupied when [P] is 10-fold
greater than the Kd.

4. Chap. 2 Derivation of the HH Equation
HA  H+ + A-
Ka = [H+][A-]/[HA]
Take the log of both sides of the equation.
log Ka = log [H+][A-]/[HA]
Rearrange
log Ka = log [H+] + log [A-]/[HA]
Rearrange again
log [H+] = log Ka - log [A-]/[HA]
Multiply both sides by -1
-log [H+] = -log Ka + log [A-]/[HA]
Substitute pH and pKa
pH = pKa + log [A-]/[HA]

5. Chap. 2 Problem 11
What is the ionization state of phosphoric acid in the cytoplasm & why
is phosphoric acid a physiologically important compound?
The pH of the cytosol is 7.2. This happens to be equivalent to pKa2 of
phosphoric acid. (Refer to Fig. 2.28, next slide)
The relevant equilibrium reaction therefore is
H2PO4
-  H+ + HPO4
2-
The Henderson Hasselbach Eq is
pH = pKa + log [HPO4
2-]/[H2PO4
-]
Since pH = pKa2 = 7.2, the HH Eq becomes
100 = [HPO4
2-]/[H2PO4
-]
And
1/1 = [HPO4
2-]/[H2PO4
-]
Thus, these 2 compounds are present at a 50/50 ratio in solution.
Phosphoric acid is physiologically important because it serves as the
buffering agent in the cytosol.

6. pKa2
Fig. 2.28