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1. If the distribution of IQ is centered at 100 , and has a standard deviation of 10, then what is the
IQ Z-score of someone who has an IQ of 116?
A) 1.6
B) -1.6
C) 16
D) 0.8
E) Cannot determine
2. Bob did not study for his exam and got a z-score of -2.25. The exam had a mean of 24 and a
standard deviation of 4. What score did Bob get?
A) 15
B) 19
C) 24
D) 18
E) 11
3. In a population of people where the average weight is 160 and the standard deviation is 10,
what proportion of the people have a weight above 170?
A) 0.16
B) 0.84
C) 0.5
D) 0.34
E) Cannot determine
Solution
(1) Z=(X-mean)/s =(116-100)/10=1.6
Answer: A) 1.6
(2) Z=(X-mean)/s =-2.25
--> (X-24)/4 =-2.25
--> X = 24-4*2.25 = 15
Answer: A) 15
(3)P(X>170) = P(Z>(170-160)/10) =P(Z>1) =0.1586
Answer: A) 0.16

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1. If the distribution of IQ is centered at 100 , and has a standard.pdf

  • 1. 1. If the distribution of IQ is centered at 100 , and has a standard deviation of 10, then what is the IQ Z-score of someone who has an IQ of 116? A) 1.6 B) -1.6 C) 16 D) 0.8 E) Cannot determine 2. Bob did not study for his exam and got a z-score of -2.25. The exam had a mean of 24 and a standard deviation of 4. What score did Bob get? A) 15 B) 19 C) 24 D) 18 E) 11 3. In a population of people where the average weight is 160 and the standard deviation is 10, what proportion of the people have a weight above 170? A) 0.16 B) 0.84 C) 0.5 D) 0.34 E) Cannot determine
  • 2. Solution (1) Z=(X-mean)/s =(116-100)/10=1.6 Answer: A) 1.6 (2) Z=(X-mean)/s =-2.25 --> (X-24)/4 =-2.25 --> X = 24-4*2.25 = 15 Answer: A) 15 (3)P(X>170) = P(Z>(170-160)/10) =P(Z>1) =0.1586 Answer: A) 0.16