The document outlines the plumbing design requirements for the Metro International Hotel, detailing key specifications such as water requirements, tank sizes, and motor specifications. It provides calculations for total fixture units, water demand, and the necessary dimensions for both underground and overhead water tanks. Additionally, it includes information on pressure and pipe sizing to ensure efficient water supply to the hotel facilities.

1. Plumbing
Design
Of
HOTEL
METRO
INTERNATIONAL

2. Name:
PUJA CHOWDHURY
Registration No:
2015333511
Name:
MD. MASUD REZA APU
Registration No:
2015333510
Name:
ORKA CHANDA
Registration No:
2015333512
Name:
NASIF AHMED
Registration No:
2015333515
Name:
ARIFUL KARIM RIZVI
Registration No:
2015333516
Name:
BODRUN YEASMIN
Registration No:
2015333518
Name:
MD. MUNIB HOSSAIN
Registration No:
2015333519

3. 01
02 03
04
A R E A
Some Text Goes Here.
S T O R I E S
4 stories, market on 1st Story
R O O M S
50 rooms, 2 Conference, 1 Restaurant
L A Y O U T
Room, Conference, Restaurant
Group B

4. Group B

5. 1
2
34
5
6
FIXTURE
UNIT
UNDERGROUND
WATER TANK
DESIGN
Overhead
Tank design
Riser
design
Water pump
capacity
Pipe
sizing
Group B

6. Group B

7. Lavatory
Water Closet
Shower Head
Total
Total Fixtures Unit = 204 x 4 (storied)
= 816 unit
17 x 1
6 x 17
17 x 3
=
=
=
17 unit
102 unit
51 unit
204 unit
=
=
=
=
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8. 4 Room
12 Room
24 Room
6 Room
2 Room
2 Room
2 Room
Total Person = 116
Total Occupants = 116 + 40 (Staff)
= 156
≈160
Group B

9. So, Total water requirement
For Hotels,
Per Person Needed 300 Lpcd
= (160 x 300)
= 48000 liters
= 48 𝑚3
Group B

10. Normally for shift supply 2/3 rd of one day requirement can be used
So, Volume of water tank = (2/3) x 48 = 32 𝑚3
Assume depth 1.5 m and length 5 m
Then,
1.5 x 5 x width = 32m
Take Size Of Underground Water Tank = 5 m X 4.5 m X 1.5 m
So, width = 4.26m
≈4.5m
Group B

11. Take Size Of Over Head Tank = 4 m X 3 m X 1.5 m
Normally for shift supply 1/3 of one day requirement can be used
So, volume of tank = (1/3) x 48 = 16 𝑚3
Assume , Length 4m & width 3m
Then Depth ,
4 x 3x h = 16
= 1.33m
≈ 1.5 m
Group B
h

12. Group B
FIXTURE
UNIT
PRESSURE
PIPE
DIA

13. As we know,
Main line pressure – friction loss – static head – 4 + motor pressure = 0
Now, 60–(20% of 40 ft ) x 0 .433 –(40 +30% of 40 ft ) x 0.433 – 4 + motor pressure = 0
Motor pressure = - 30.02
( Negative value so, no extra pressure needed )
ֶ
Group B

14. Fixture unit = 816 unit
So, the demand
Q
1.85
d
4.87
(10.28)
1.85
d
4.87
= 163 GPM ( From graph)
= 10.2837 L/sec ( 1 GPM = 0,0631 L/sec )
(20% of 40 )x 0.433 32.87 x=
=8 x 0.433 32.87 x
d = 3.85 cm
≈ 4 cm
So, the riser pipe dia is 4 cm Group B

15. H . P. of motor =
0.735 x η
x Q x Hwɣ
9.81 x (10.28/1000) x (40/3.28)
0.735 x 0.70
=
= 2.39 H.P.
≈ 3 H.P.
We can use one 3 H.P. motor or three 1 H.P. motors
Group B

16. 3
Head loss = (20% of total height) x 0 .433
= ( 20% of 40 ft) x 0.433
= 3.464
From the graph the dia meter of the pipe is 3 in.
And, the water demand is 163 GPM
Group B

17. THANK
YOU
Group B