here heat capacity of calorimeter = (50 x 4.186 x ( 37.92 - 29.11 ) - 50 x 4.186 x ( 29.11 - 20.91 ))/dt = 127.673/dt where dt is the change in temp .. it is not given so i have mentioned it as dt Solution here heat capacity of calorimeter = (50 x 4.186 x ( 37.92 - 29.11 ) - 50 x 4.186 x ( 29.11 - 20.91 ))/dt = 127.673/dt where dt is the change in temp .. it is not given so i have mentioned it as dt.