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Atlas Advertising Atlas Advertising is a regional advertising agency with oces in Boston, New York, Providence, Washington, D.C., and Philadelphia. 1. Describe the types of networks you think they would have (e.g., LANs, BNs, WANs) and where they are likely to be located. 2. What types of standard proto-cols and technologies do you think they are using at each layer (e.g., see Figure 1-5)? Solution 1. Within their offices,internally they will use local area network (LAN) to communicate among themselves.In the same city ,if they have another office,they can use metropolitian area network(MAN),which is used to communicate in a city or within a cities.For their offices in other cities,they will use WAN(Wide area network)which is used for communication worldwide . 2. The standard protocols and technologies used are TCP-IP for the wired transmission and UDP for wireless Transmission.

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Which of the following characteristics of living organisms absolutely disqualifies viruses as alive? A. Reproduction B. Ability to move C. Utilizing energy D. Evolutionary adaptation E. Cellular organization Solution A. Reproduction is characteristic that disqualifies viruses as alive; as for this they are dependent on other living cells. They can reproduce on their own. for ex. a bacteriophage infects a bacterial cell by injecting its DNA to bacterial cell. when that piece of viral DNA gets replicated with bacterial DNA, the bacterial cell expresses all viral genes which are necessary to make new viral cells, on getting them mature the bacterial cell brusts to release those viral cells. thus a life of viruse is dependent on a other living cell for reproduction..

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there is a serious outbreak of staph aureus in the hospital. A convenient way to determine where this microbe may be lurking is to sample swabs and place them on: a maccokey agar b sulfide indole motility medium c mannitol salt agar d EMB e all of the above Solution Answer is C Mannitol salt agar Convenient way to determine where staph aureus may be lurking is to sample swabs and place them on: Mannitol salt agar. Staphylococcus aureus usually ferments mannitol.

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Timer Notes obiect and the dashed arrow the image. The rectangle shows the position o In the four diagrams below, the solid arrow represents the an SINGLE OPTICAL ELEMENT. Match each diagram with the appropriate optical element. First, is it a Lens or a Mirror? For a SINGLE ELEMENT, a Real image (RI) is always inverted, a Virtual image is always upright. Tries Post MacBook Air Solution a) the optical element is converging lens since the image is virtual and inverted . For a mirror the virtual image is always erect b) diverging lens real image and erect . for a concave mirror real image is always inverted c) plane mirror image is virtual and of same size d)convex mirror image is virtual and smaller than the object.

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Representatives from four different colleges of UM- Dearborn will be seated in a row. There are 4 representatives from College of \'Art Sciences, and Letter\', 3 from college of \'Business\', 5 from College of \'Education, Health and Human Services\', and 6 from \'College of Engineering and Computer Science\'. Representatives will be seated according to their colleges (identities of each representative is not important). In how many different ways will these representatives be seated? Solution 4 from college of \'arts sciences and letter\' arranged in 4! ways =24 ways 3 from college of \'business\' arranged in 3! ways = 6 ways 5 from college of \'education health and human sevices\' arranged in 5! ways = 120 ways 6 from college of \'engineering and computer science\' arranged in 6! ways = 720 ways And these four college can be arranged in 4! ways i.e., 24 ways So total = 24*24*6*120*720 = 298598400 ways.

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Problem asks me to prove Uniqueness but I\'m not sure how to do it! From my ODE\'s and PDE\"s Class Solution Uniqueness arguments are identical for both both problems (in general, for this category of equations): Let u and v are two solutions satisfying (the reduced Helmholtz) equations ) an elliptic equation and the boundary conditons (Dirichlet and Neumann). By linearlity u-v satisfies the elliptic equation with boundary conditions zero. Applying the maximum principle to u-v yields u-v =0 throughout. Hence the uniqueness..

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please send edited code Main.java package part2; import java.util.Random; public class Main { static final int NUM = 10; public static void main(String[] args) { EZ.initialize(600, 600); Data [] datapoints = new Data[NUM]; Random rg = new Random(); for (int i=0; i Solution Main.java -------------- import java.util.Random; public class Main { static final int NUM = 10; public static void main(String[] args) { Data [] datapoints = new Data[NUM]; Random rg = new Random(); for (int i=0; i.

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Inhaling and exhaling Label the figure that shows \"INHALATION\" and the figure that shows \"EXHALATION\" in targets (a) and (b). Then drag the other labels to the appropriate locations on the figures. Solution a)Inhalation b)Exhalation c)External intercoastal muscles contract d)Air enters body e)Air leaves body f)Internal intercoastal muscles contract g)Diaphragm contracts(moves down) h)Diaphram relaxes(moves up).

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How can a topologically associating domain (TAD) mutation effect more that one gene? Explain why a TAD mutation shouldn\'t have any effect on the normal shape of a protein? And what seems to be one of the normal functions of a TAD.? Solution Topological associated domain are genome region whose DNA sequence prefrentially contact each other. TAD is a fundamental structural unit that regulates elements to their cognate promoters.Function: TAD are critical for accurate gene expression Any aleration can lead to disease.

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7. Wet ear wax (W) is dominant over dry ear wax (w) W=wet ear wax w=dry ear wax a. A 3:1 phenotypic ratio of F1 progeny indicates that the parents are of what genotype? b. A 1:1 phenotypic ratio of F1 progeny indicates that the parents are of what genotype? Solution Ans: This is the result of a problem common in trying to determine the nature of inheritance patterns in humans. The results are combined from offspring from several families. Thus the sticky x sticky cross includes families in which parents may be (AA x AA; Aa X AA). aa x aa..

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Examine your opinion on the death penalty. Defend why you are for the death penalty or against it. Be sure to be specific in your defense on your stance. Solution Death penalty or execution is govt. sanctioned punishment by death.Iam in favour of death penalty as:- 1.) Detterent to crime:- Death penalty is given to criminals who do first degree crimes ike murder , terrorism and espionage.It produces a strong detterent effect on crime and criminals. 2) Fear of death:- Though death is inevitable we all still fear it. Imposing death punishment for brutal crimes like rapes and murders will definately make the criminal think twice before committing a crime. 3) No escape:- A criminal murderer or serial killer can escape imprisonment in the long run leading to more crime and threat to society.. Death penalty puts an end to crime. 4) Saves lifes:- Death penalty produces a strong detterent effect on crime and criminals and hence saves lifes..

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Do you think that knowing about aggression between groups of chimpanzees is useful in understanding conflicts between human societies? Why or why not? Solution In many primates where the range is small , contact with one or more groups of the same species is a very common feature. However the nature of these encounters varies from species to species. Primate groups remain permanently in a specific locality which is described as there home range. Members of the same group exist in this range however it is not necessary that the individuals of the group should remain in the same range but may change over to other ranges and join a new community. This home range consists of a central core area with highest concentration of the predictable resources and represent the region where the group is more likely to be found.It also represents the territory of the group which is defended against intrusion. There may be overlapping of the home range between the groups but not the core area. Territoriality is a behavior exhibited by many primates to protect their home range. This is seen extensively where the home ranges are small and permits patrolling and protection of the territory. Biological continuum refers to the fact that the organisms are related through common ancestry and the behavioral traits seen in one organisms are seen in others also but in varying degrees. The man is considered to be a highly evolved social organism with a huge brain and thinking capacity. He is more related to chimpanzees and the main difference between us and the other primates is that the difference in behavior is merely quantitative and not qualitative. Interactions between groups of chimpanzees include aggression, display chasing and sometimes violent fighters also. Male chimpanzees are highly intolerable to unfamiliar chimpanzees, specially males and aggressively defend their territories and resources. Lethal aggression is a common feature among the chimpanzees. It is common in groups of male chimpanzees which do patrolling around their territory. Sometimes they are also accompanied by one or two females. During this patrolling, they exhibit silent movement, stop frequently, sniff around and climb tall trees and sit on them for hours together to survey the area. They appear to be tense during such situations and any sudden sound causes them to exhibit nervous behavior like touching each other for reassurance or embrace each other. When they encounter members of another community, They exhibit some form of aggression till the other group retreats. Chimpanzees are also known to exhibit cruelty, and aggression combined with compassion, tenderness and altruism which is comparable to human behavior, but the main difference is that chimpanzees are not aware of the suffering they inflict on others while humans do. Thus, the behavior of chimpanzees can be more related to human behavior, but the difference lies in quantitative than qualitative.

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Diana’s Death Unraveled Hemophilia causes a lack of blood clotting, but Diana died from overactive blood clotting. Factor V Leiden is the most common hereditary hypercoagulability disorder amongst Eurasians. About 5% of Caucasians in North America are affected, and it is inherited as an autosomal dominant mutation that causes high levels of clotting Factor V. It can cause deep vein thrombosis (blood clot in the vein), pain, life-threatening strokes, and heart attacks. 1. Based on the types of mutations we’ve discussed so far in class, which does Factor V Leiden fall into? (1pt) 2. Kevin Keller’s aunt’s husband and his girl cousin have died of heart attacks, but his mother, sister, and brother are fine. Lisa Keller’s uncle is fine, but her aunt had multiple miscarriages before she died. Her mother suffered from deep vein thrombosis, and her grandfather died of a heart attack. Recall that Lisa has a brother with hemophilia C and an unaffected sister. Create a pedigree diagramming these relationships. (3 pts) b. Who do you think is more likely to carry the Factor V Leiden mutation? (1 pt) a. Kevin Keller b. Lisa Keller c. Both c. What do you think happened with the Morrison’s and Keller’s when Olivia and Diana were young? (2 pt) 3. There is enough research evidence to support phenotypic changes in hemophiliacs with Factor V Leiden mutations. Based on what we’ve discussed in chapter 4, what are some suggestions as to why this might happen? Be sure to describe the normal symptoms of hemophilia and how protein levels are affected to support your answer. (3pts) Solution 1. Missense substitution mutation leads to Factor V Leiden . The gene which codes to the factor is F5. A mutation of this gene where Guanine is substituted by Adenine which results in the changing of amino acid Arginine to Glutamine. I am not sure of the answers for the remaining questions. Please post those questions again for other experts to answer. Thank you..

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Create a new java class called ListNode. Implement ListNode as a generic version of IntNode. public class ListNode { } Create a generic class called Queue, which is a linked list implementation of a queue data type. Queue must have the following methods: • public void enqueue(T value){} This method should add a new node to the back of the queue. • public T dequeue(){} This method should remove a node from the front of the queue and return its value • public T peek(){} This method should return the value of the front node without removing it from the queue Create a new generic class called Stack, which is a linked list implementation of a stack data type. Stack must have the following methods: • public void push(T value){} This method should add a new node to the top of the stack. • public T pop(){} This method should remove a node from the top of the stack and return its integer value • public T peek(){} This method should return the integer value of the top node without removing it from the stack Solution import java.util.Iterator; public class LinkedList extends AbstractList { private ListNode front; // refers to first node in list (null if empty) public LinkedList() { front = null; // null front means empty } public void add(int index, E value) { if (index == 0) { // insert at the front front = new ListNode(value, front); } else { ListNode current = goTo(index - 1); ListNode newNode = new ListNode(value, current.next); current.next = newNode; } } public E get(int index) { ListNode current = goTo(index); return current.data; } public int indexOf(E value) { int index = 0; ListNode current = front; while (current != null) { if (current.data == value) { return index; } index++; current = current.next; } return -1; } public Iterator iterator() { return new LinkedListIterator(); } public void remove(int index) { if (index == 0) { // removing from the front front = front.next; } else { ListNode current = goTo(index - 1); current.next = current.next.next; // deletes the node } } public void set(int index, E value) { ListNode current = goTo(index); current.data = value; } public int size() { int count = 0; ListNode current = front; while (current != null) { current = current.next; count++; } return count; } public String toString() { if (front == null) { return \"[]\"; } else { String result = \"[\" + front.data; ListNode current = front.next; while (current != null) { result += \", \" + current.data; current = current.next; } result += \"]\"; return result; } } private ListNode goTo(int index) { ListNode current = front; for (int i = 0; i < index; i++) { current = current.next; } return current; } public class ListNode { public E data; public ListNode next; public ListNode(E data) { this.data = data; this.next = null; } public ListNode(E data, ListNode next) { this.data = data; this.next = next; } } private class LinkedListIterator implements Iterator { private ListNode current; // current position in list public LinkedListIterator() { current = f.

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Briefly describe the two competing theories regarding the origin of Homo sapiens and its distributional expansion from its origin in Africa. What does the genetic data say about these two hypothesis, which genes are most useful for these analyses and why? Given a large section of a genome, say a complete chromosome, how could you locate genes? Given a large section of a gene, say a complete exon, how could you determine reading frame? Solution 1. There are many competing therapies for the origin of Homo sapiens. Two such theories are Multi-regional hypothesis and Out of Africa 2 model. Multi-regional Hypothesis: The multi-regional hypothesis argues that our early hominid ancestors, including Homo ergaster and Homo heidelbergensis, migrated out of Africa and thus the evolution of modern humans took place in different parts of the world, a process termed regional continuity. This theory places great emphasis on the notion of steady evolutionary alterations or changes that happen in different regions and produce diverse variations of the species. Evolution of this kind is kept at a regular rate due to an amalgamation of cultural progress and ‘gene flow’ or interbreeding, thus keeping all lineages evolving at the same time. This process is characterized as parallel evolution, which suggests a subtle morphological resemblance between populations of species who are geographically separated. Out of Africa 2 model: It is widely recognized among both archaeological and anthropological academics that archaic Homo populations did leave Africa in an initial phase of globalisation, called the Out of Africa 1 model. Following this, the population replacement hypothesis maintains that modern humans evolved in Africa from the ancestral hominids that did not travel out of this continent in the first stage of global colonisation. It is then argued in this model that once evolved as anatomically modern humans, Homo sapiens travelled out of Africa to explore, colonise and rapidly replace the archaic Homo population. This movement suggests a second wave of hominid species emerging from Africa, thus the title: the Out of Africa 2 model..

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