SlideShare a Scribd company logo
1 of 24
9-5 Evaluating
Expressions with
    Integers
         Math Notes
  Algebra and Functions 1.2
Review
Evaluate - To evaluate is to replace the
variable with a given value to come to a
final answer.



  n=7                   n + 9
  given value            expression
Review
Evaluate - To evaluate is to replace the
variable with a given value to come to a
final answer.



  n=                    7 + 9
  given value            expression
Review
Evaluate - To evaluate is to replace the
variable with a given value to come to a
final answer.



  n=                    7 + 9=
  given value            expression
Review
Evaluate - To evaluate is to replace the
variable with a given value to come to a
final answer.



  n=                    7 + 9 = 16
  given value            expression
Evaluate x + 9 for x = 12


x + 9              x = 12
Evaluate x + 9 for x = 12


x + 9                      x = 12
STEP ONE: Substitute negative 12 for x
Evaluate x + 9 for x = 12


12 + 9                     x=
STEP ONE: Substitute negative 12 for x
Evaluate x + 9 for x = 12


12 + 9                     x=
STEP ONE: Substitute negative 12 for x
    STEP TWO: Draw 12 negatives
Evaluate x + 9 for x = 12


12 + 9                     x=
STEP ONE: Substitute negative 12 for x
    STEP TWO: Draw 12 negatives


 ------------
Evaluate x + 9 for x = 12


    12 + 9                      x=
     STEP ONE: Substitute negative 12 for x
         STEP TWO: Draw 12 negatives
STEP THREE: The “+” means add. Add 9 negatives

      ------------
Evaluate x + 9 for x = 12


    12 + 9                      x=
     STEP ONE: Substitute negative 12 for x
         STEP TWO: Draw 12 negatives
STEP THREE: The “+” means add. Add 9 negatives

      ------------
        - - ------ -
Evaluate x + 9 for x = 12


    12 + 9                      x=
     STEP ONE: Substitute negative 12 for x
         STEP TWO: Draw 12 negatives
STEP THREE: The “+” means add. Add 9 negatives

      ------------
        - - ------ -
         How many altogether?
Evaluate x + 9 for x = 12


    12 + 9                      x=
     STEP ONE: Substitute negative 12 for x
         STEP TWO: Draw 12 negatives
STEP THREE: The “+” means add. Add 9 negatives

      ------------
        - - ------ -
         How many altogether?
                                  21
Evaluate y - +10 for y =   5
     +
x - 10                y= 5
Evaluate y - +10 for y =         5
      +
x - 10                     y= 5
STEP ONE: Substitute negative 5 for x
Evaluate y - +10 for y =         5
      +
5 - 10                     y=
STEP ONE: Substitute negative 5 for x
Evaluate y - +10 for y =         5
      +
5 - 10                     y=
STEP ONE: Substitute negative 5 for x
    STEP TWO: Draw 5 negatives
Evaluate y - +10 for y =         5
      +
5 - 10                     y=
STEP ONE: Substitute negative 5 for x
    STEP TWO: Draw 5 negatives




          -----
Evaluate y - +10 for y =         5
             +
     5 - 10                       y=
       STEP ONE: Substitute negative 5 for x
           STEP TWO: Draw 5 negatives
STEP TWO: The “-” means take away, but there are
 NO positives to take away, BORROW that amount.

                 -----
Evaluate y - +10 for y =         5
             +
     5 - 10                       y=
       STEP ONE: Substitute negative 5 for x
           STEP TWO: Draw 5 negatives
STEP TWO: The “-” means take away, but there are
 NO positives to take away, BORROW that amount.

            -----
          ++++++++++
          ----------
Evaluate y - +10 for y =         5
             +
     5 - 10                       y=
       STEP ONE: Substitute negative 5 for x
           STEP TWO: Draw 5 negatives
STEP TWO: The “-” means take away, but there are
 NO positives to take away, BORROW that amount.

            -----
          ++++++++++
          ----------
       STEP THREE: Take away 10 positives.
            What are you left with?
Evaluate y - +10 for y =         5
             +
     5 - 10                       y=
       STEP ONE: Substitute negative 5 for x
           STEP TWO: Draw 5 negatives
STEP TWO: The “-” means take away, but there are
 NO positives to take away, BORROW that amount.

            -----
          ----------
       STEP THREE: Take away 10 positives.
            What are you left with?
Evaluate y - +10 for y =         5
             +
     5 - 10                       y=
       STEP ONE: Substitute negative 5 for x
           STEP TWO: Draw 5 negatives
STEP TWO: The “-” means take away, but there are
 NO positives to take away, BORROW that amount.

            -----
          ----------
       STEP THREE: Take away 10 positives.
            What are you left with?            15

More Related Content

Viewers also liked

Viewers also liked (8)

Operations with integers
Operations with integersOperations with integers
Operations with integers
 
Operations with integers
Operations with integersOperations with integers
Operations with integers
 
Recognizing patterns of organization
Recognizing patterns of organizationRecognizing patterns of organization
Recognizing patterns of organization
 
Scatter Plot
Scatter PlotScatter Plot
Scatter Plot
 
Scatter plots
Scatter plotsScatter plots
Scatter plots
 
Recognizing Patterns in Literature
Recognizing Patterns in LiteratureRecognizing Patterns in Literature
Recognizing Patterns in Literature
 
pattern of organization
pattern of organizationpattern of organization
pattern of organization
 
scatter diagram
 scatter diagram scatter diagram
scatter diagram
 

Similar to 9-5 Evaluating Expressions with Integers

Subtraction equations
Subtraction equationsSubtraction equations
Subtraction equationsMs. Jones
 
Day 4 evaluating with add and subtract
Day 4 evaluating with add and subtractDay 4 evaluating with add and subtract
Day 4 evaluating with add and subtractErik Tjersland
 
Solving equations one & two step
Solving equations   one & two stepSolving equations   one & two step
Solving equations one & two stepchrystal_brinson
 
Unit 2 post assessment
Unit 2 post assessmentUnit 2 post assessment
Unit 2 post assessmentAnnie cox
 
exercise 1.1 , 1.2 7th maths
exercise 1.1 , 1.2  7th  maths exercise 1.1 , 1.2  7th  maths
exercise 1.1 , 1.2 7th maths My brain
 
3.1 equation add & subt 1
3.1  equation add & subt 13.1  equation add & subt 1
3.1 equation add & subt 1bweldon
 
A1 ch02 01 practice with video
A1 ch02 01 practice with videoA1 ch02 01 practice with video
A1 ch02 01 practice with videomcarlinjr0303
 
Solving one step equations
Solving one step equationsSolving one step equations
Solving one step equationsmcarlinjr0303
 
2.2 add integers ws day 2
2.2 add integers   ws day 22.2 add integers   ws day 2
2.2 add integers ws day 2bweldon
 
31 32review Equation Steps
31 32review Equation Steps31 32review Equation Steps
31 32review Equation Stepstaco40
 
Order of Operations (MDAS Rules) Math 4
Order of Operations (MDAS Rules) Math 4Order of Operations (MDAS Rules) Math 4
Order of Operations (MDAS Rules) Math 4menchreo
 
Proj 8 Tanya Graded
Proj 8 Tanya GradedProj 8 Tanya Graded
Proj 8 Tanya Gradedtanyaahogan
 
Solving equations using addition and subtraction
Solving equations using addition and subtractionSolving equations using addition and subtraction
Solving equations using addition and subtractionmcarlinjr0303
 
6 4 Absolute Value And Graphing
6 4 Absolute Value And Graphing6 4 Absolute Value And Graphing
6 4 Absolute Value And Graphingtaco40
 
Moving Terms
Moving TermsMoving Terms
Moving Termsmrsbmath
 

Similar to 9-5 Evaluating Expressions with Integers (20)

Subtraction equations
Subtraction equationsSubtraction equations
Subtraction equations
 
Day 4 evaluating with add and subtract
Day 4 evaluating with add and subtractDay 4 evaluating with add and subtract
Day 4 evaluating with add and subtract
 
Solving equations one & two step
Solving equations   one & two stepSolving equations   one & two step
Solving equations one & two step
 
Unit 2 post assessment
Unit 2 post assessmentUnit 2 post assessment
Unit 2 post assessment
 
exercise 1.1 , 1.2 7th maths
exercise 1.1 , 1.2  7th  maths exercise 1.1 , 1.2  7th  maths
exercise 1.1 , 1.2 7th maths
 
3.1 equation add & subt 1
3.1  equation add & subt 13.1  equation add & subt 1
3.1 equation add & subt 1
 
A1 ch02 01 practice with video
A1 ch02 01 practice with videoA1 ch02 01 practice with video
A1 ch02 01 practice with video
 
Solving one step equations
Solving one step equationsSolving one step equations
Solving one step equations
 
Simple Equations I
Simple Equations ISimple Equations I
Simple Equations I
 
2.2 add integers ws day 2
2.2 add integers   ws day 22.2 add integers   ws day 2
2.2 add integers ws day 2
 
31 32review Equation Steps
31 32review Equation Steps31 32review Equation Steps
31 32review Equation Steps
 
Order of Operations (MDAS Rules) Math 4
Order of Operations (MDAS Rules) Math 4Order of Operations (MDAS Rules) Math 4
Order of Operations (MDAS Rules) Math 4
 
Proj 8 Tanya Graded
Proj 8 Tanya GradedProj 8 Tanya Graded
Proj 8 Tanya Graded
 
Solving equations using addition and subtraction
Solving equations using addition and subtractionSolving equations using addition and subtraction
Solving equations using addition and subtraction
 
D.e.v
D.e.vD.e.v
D.e.v
 
6 4 Absolute Value And Graphing
6 4 Absolute Value And Graphing6 4 Absolute Value And Graphing
6 4 Absolute Value And Graphing
 
Elimination
EliminationElimination
Elimination
 
Msm1 fl ch11_08
Msm1 fl ch11_08Msm1 fl ch11_08
Msm1 fl ch11_08
 
Moving Terms
Moving TermsMoving Terms
Moving Terms
 
Class Presentation Math 1
Class Presentation Math 1Class Presentation Math 1
Class Presentation Math 1
 

More from Mel Anthony Pepito

Lesson 16: Inverse Trigonometric Functions
Lesson 16: Inverse Trigonometric FunctionsLesson 16: Inverse Trigonometric Functions
Lesson 16: Inverse Trigonometric FunctionsMel Anthony Pepito
 
Lesson 11: Implicit Differentiation
Lesson 11: Implicit DifferentiationLesson 11: Implicit Differentiation
Lesson 11: Implicit DifferentiationMel Anthony Pepito
 
Lesson 12: Linear Approximation
Lesson 12: Linear ApproximationLesson 12: Linear Approximation
Lesson 12: Linear ApproximationMel Anthony Pepito
 
Lesson 13: Related Rates Problems
Lesson 13: Related Rates ProblemsLesson 13: Related Rates Problems
Lesson 13: Related Rates ProblemsMel Anthony Pepito
 
Lesson 14: Derivatives of Logarithmic and Exponential Functions
Lesson 14: Derivatives of Logarithmic and Exponential FunctionsLesson 14: Derivatives of Logarithmic and Exponential Functions
Lesson 14: Derivatives of Logarithmic and Exponential FunctionsMel Anthony Pepito
 
Lesson 15: Exponential Growth and Decay
Lesson 15: Exponential Growth and DecayLesson 15: Exponential Growth and Decay
Lesson 15: Exponential Growth and DecayMel Anthony Pepito
 
Lesson 17: Indeterminate Forms and L'Hôpital's Rule
Lesson 17: Indeterminate Forms and L'Hôpital's RuleLesson 17: Indeterminate Forms and L'Hôpital's Rule
Lesson 17: Indeterminate Forms and L'Hôpital's RuleMel Anthony Pepito
 
Lesson18 -maximum_and_minimum_values_slides
Lesson18 -maximum_and_minimum_values_slidesLesson18 -maximum_and_minimum_values_slides
Lesson18 -maximum_and_minimum_values_slidesMel Anthony Pepito
 
Lesson 19: The Mean Value Theorem
Lesson 19: The Mean Value TheoremLesson 19: The Mean Value Theorem
Lesson 19: The Mean Value TheoremMel Anthony Pepito
 
Lesson 25: The Definite Integral
Lesson 25: The Definite IntegralLesson 25: The Definite Integral
Lesson 25: The Definite IntegralMel Anthony Pepito
 
Lesson22 -optimization_problems_slides
Lesson22 -optimization_problems_slidesLesson22 -optimization_problems_slides
Lesson22 -optimization_problems_slidesMel Anthony Pepito
 
Lesson 26: Evaluating Definite Integrals
Lesson 26: Evaluating Definite IntegralsLesson 26: Evaluating Definite Integrals
Lesson 26: Evaluating Definite IntegralsMel Anthony Pepito
 
Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus Mel Anthony Pepito
 
Lesson 28: Integration by Subsitution
Lesson 28: Integration by SubsitutionLesson 28: Integration by Subsitution
Lesson 28: Integration by SubsitutionMel Anthony Pepito
 
Lesson 3: Limits (Section 21 slides)
Lesson 3: Limits (Section 21 slides)Lesson 3: Limits (Section 21 slides)
Lesson 3: Limits (Section 21 slides)Mel Anthony Pepito
 

More from Mel Anthony Pepito (20)

Lesson 16: Inverse Trigonometric Functions
Lesson 16: Inverse Trigonometric FunctionsLesson 16: Inverse Trigonometric Functions
Lesson 16: Inverse Trigonometric Functions
 
Lesson 11: Implicit Differentiation
Lesson 11: Implicit DifferentiationLesson 11: Implicit Differentiation
Lesson 11: Implicit Differentiation
 
Lesson 12: Linear Approximation
Lesson 12: Linear ApproximationLesson 12: Linear Approximation
Lesson 12: Linear Approximation
 
Lesson 13: Related Rates Problems
Lesson 13: Related Rates ProblemsLesson 13: Related Rates Problems
Lesson 13: Related Rates Problems
 
Lesson 14: Derivatives of Logarithmic and Exponential Functions
Lesson 14: Derivatives of Logarithmic and Exponential FunctionsLesson 14: Derivatives of Logarithmic and Exponential Functions
Lesson 14: Derivatives of Logarithmic and Exponential Functions
 
Lesson 15: Exponential Growth and Decay
Lesson 15: Exponential Growth and DecayLesson 15: Exponential Growth and Decay
Lesson 15: Exponential Growth and Decay
 
Lesson 17: Indeterminate Forms and L'Hôpital's Rule
Lesson 17: Indeterminate Forms and L'Hôpital's RuleLesson 17: Indeterminate Forms and L'Hôpital's Rule
Lesson 17: Indeterminate Forms and L'Hôpital's Rule
 
Lesson 21: Curve Sketching
Lesson 21: Curve SketchingLesson 21: Curve Sketching
Lesson 21: Curve Sketching
 
Lesson18 -maximum_and_minimum_values_slides
Lesson18 -maximum_and_minimum_values_slidesLesson18 -maximum_and_minimum_values_slides
Lesson18 -maximum_and_minimum_values_slides
 
Lesson 19: The Mean Value Theorem
Lesson 19: The Mean Value TheoremLesson 19: The Mean Value Theorem
Lesson 19: The Mean Value Theorem
 
Lesson 25: The Definite Integral
Lesson 25: The Definite IntegralLesson 25: The Definite Integral
Lesson 25: The Definite Integral
 
Lesson22 -optimization_problems_slides
Lesson22 -optimization_problems_slidesLesson22 -optimization_problems_slides
Lesson22 -optimization_problems_slides
 
Lesson 24: Area and Distances
Lesson 24: Area and DistancesLesson 24: Area and Distances
Lesson 24: Area and Distances
 
Lesson 23: Antiderivatives
Lesson 23: AntiderivativesLesson 23: Antiderivatives
Lesson 23: Antiderivatives
 
Lesson 26: Evaluating Definite Integrals
Lesson 26: Evaluating Definite IntegralsLesson 26: Evaluating Definite Integrals
Lesson 26: Evaluating Definite Integrals
 
Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus
 
Introduction
IntroductionIntroduction
Introduction
 
Lesson 28: Integration by Subsitution
Lesson 28: Integration by SubsitutionLesson 28: Integration by Subsitution
Lesson 28: Integration by Subsitution
 
Introduction
IntroductionIntroduction
Introduction
 
Lesson 3: Limits (Section 21 slides)
Lesson 3: Limits (Section 21 slides)Lesson 3: Limits (Section 21 slides)
Lesson 3: Limits (Section 21 slides)
 

9-5 Evaluating Expressions with Integers

  • 1. 9-5 Evaluating Expressions with Integers Math Notes Algebra and Functions 1.2
  • 2. Review Evaluate - To evaluate is to replace the variable with a given value to come to a final answer. n=7 n + 9 given value expression
  • 3. Review Evaluate - To evaluate is to replace the variable with a given value to come to a final answer. n= 7 + 9 given value expression
  • 4. Review Evaluate - To evaluate is to replace the variable with a given value to come to a final answer. n= 7 + 9= given value expression
  • 5. Review Evaluate - To evaluate is to replace the variable with a given value to come to a final answer. n= 7 + 9 = 16 given value expression
  • 6. Evaluate x + 9 for x = 12 x + 9 x = 12
  • 7. Evaluate x + 9 for x = 12 x + 9 x = 12 STEP ONE: Substitute negative 12 for x
  • 8. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x
  • 9. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x STEP TWO: Draw 12 negatives
  • 10. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x STEP TWO: Draw 12 negatives ------------
  • 11. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x STEP TWO: Draw 12 negatives STEP THREE: The “+” means add. Add 9 negatives ------------
  • 12. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x STEP TWO: Draw 12 negatives STEP THREE: The “+” means add. Add 9 negatives ------------ - - ------ -
  • 13. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x STEP TWO: Draw 12 negatives STEP THREE: The “+” means add. Add 9 negatives ------------ - - ------ - How many altogether?
  • 14. Evaluate x + 9 for x = 12 12 + 9 x= STEP ONE: Substitute negative 12 for x STEP TWO: Draw 12 negatives STEP THREE: The “+” means add. Add 9 negatives ------------ - - ------ - How many altogether? 21
  • 15. Evaluate y - +10 for y = 5 + x - 10 y= 5
  • 16. Evaluate y - +10 for y = 5 + x - 10 y= 5 STEP ONE: Substitute negative 5 for x
  • 17. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x
  • 18. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives
  • 19. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives -----
  • 20. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives STEP TWO: The “-” means take away, but there are NO positives to take away, BORROW that amount. -----
  • 21. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives STEP TWO: The “-” means take away, but there are NO positives to take away, BORROW that amount. ----- ++++++++++ ----------
  • 22. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives STEP TWO: The “-” means take away, but there are NO positives to take away, BORROW that amount. ----- ++++++++++ ---------- STEP THREE: Take away 10 positives. What are you left with?
  • 23. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives STEP TWO: The “-” means take away, but there are NO positives to take away, BORROW that amount. ----- ---------- STEP THREE: Take away 10 positives. What are you left with?
  • 24. Evaluate y - +10 for y = 5 + 5 - 10 y= STEP ONE: Substitute negative 5 for x STEP TWO: Draw 5 negatives STEP TWO: The “-” means take away, but there are NO positives to take away, BORROW that amount. ----- ---------- STEP THREE: Take away 10 positives. What are you left with? 15

Editor's Notes

  1. \n
  2. \n
  3. \n
  4. \n
  5. \n
  6. \n
  7. \n
  8. \n
  9. \n
  10. \n
  11. \n
  12. \n
  13. \n
  14. \n
  15. \n
  16. \n
  17. \n
  18. \n
  19. \n
  20. \n
  21. \n
  22. \n
  23. \n
  24. \n
  25. \n
  26. \n
  27. \n
  28. \n
  29. \n
  30. \n
  31. \n
  32. \n
  33. \n
  34. \n
  35. \n
  36. \n
  37. \n
  38. \n
  39. \n
  40. \n
  41. \n
  42. \n
  43. \n
  44. \n
  45. \n
  46. \n
  47. \n
  48. \n
  49. \n
  50. \n
  51. \n
  52. \n
  53. \n
  54. \n
  55. \n
  56. \n
  57. \n
  58. \n
  59. \n
  60. \n
  61. \n
  62. \n
  63. \n
  64. \n
  65. \n
  66. \n
  67. \n
  68. \n
  69. \n
  70. \n
  71. \n
  72. \n
  73. \n
  74. \n
  75. \n