LDME U3 Post #6

1. Unit 3 Post
Question # 6

2. 5 + 4x < 3x + 8
Our goal:
Get x by itself on the left side of the inequality sign.

3. 5 + 4x < 3x +8
- 3x - 3x
Step 1:
Subtract 3x on both sides so that the variable is on the left side
of the inequality sign.

4. 5 + x < 8
- 5 - 5
Step 2:
Subtract 5 on both sides so that the constants are on the right
side of the inequality sign.

5. x < 3
Final Answer:
X is by itself on the left side and the constant is on the right
side by itself.