1. Justin Andrews<br />ACSG 520<br />Assignment #6<br />4. The pair of sockets used are 161, and 162.<br />5. Both sockets used in this case are 69.<br />6. a. 8 bytes.<br />b. 65,535 bytes.<br />c. The minimum size would be seen as 8 (header) + 20 (IP header’s length) = 28<br />d. The maximum size can be seen as 65,535 – 20 (IP header’s length) = 65,515<br />7. 16 + 8 (header) = 24. Ratio is 16/24 = 2/3<br />8. 24 + 20 (IP header) = 44. Ratio is 16/44 = 4/11<br />9. 16/44 = 4/11<br />10. a. 0045 = 69, the source port number.<br />b. DF00 = 57344 + 3840 = 61184, the destination port number.<br />c. 0058 = 88 bytes.<br />d. 88 – 8 = 80 bytes.<br />e. The packet is directed from server to client, in this case.<br />f. The client process is TFTP.<br />