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UJI BEDA RERATA ANTAR PERLAKUAN
Menentukan perbedaan di antara masing-masing
perlakuan, setelah dilaksanakan analisis ragam
→ digunakan PEMBANDINGAN BERGANDA

  Pembandingan berganda adalah pembandingan
  berderajat bebas jamak.

  Tujuan pemband. Berganda → mengetahui signifikansi
  pengaruh perlakuan yang satu dengan perlakuan yang lain

Pembandingan Berganda, antara lain:
      I. Uji t dengan Beda Nyata Terkecil ( B.N.T.)
     II. Uji Tukey dengan Beda Nyata Jujur (B.N.J.)
    III. UJI Jarak Berganda Duncan dengan Jarak
              Nyata Terkecil ( J.N.T)
BEDA NYATA TERKECIL = BNT
   (LEAST SIGNIFICANT DIFFERENCE = LSD)
Digunakan:
1. Bila Fhitung > Ftabel
2. Sebaiknya untuk perlakuan ≤ 3 ,
      dengan 2 perlakuan, peluang kesalahan 5%
              3 perlakuan, peluang kesalahan 13%
              6 perlakuan, peluang kesalahan 40%
             10 perlakuan, peluang kesalahan 60%

Peneliti berpikir menggunakan taraf nyata 5%,
tetapi sesungguhnya ia sedang menguji dengan
taraf nyata 13%
Rumus:
  Untuk n A = n = n:
               B



      BNT (α) = t (db galat) x         2 KTG
                (α)
                                         n

  Untuk n ≠ n :
          A    B



     BNT (α) = t (db galat) x KTG ── + 1
                                  1    ──
                (α)               n A nB

  Catatan: t       (db galat)    dicari pada tabel t
                   (α)
CONTOH:
  21 bji tahu
   3 macam bahan               Dari sidik ragam
   7 kali ulangan              diperoleh:
  Rerata bobot untuk             db galat = 18
    perlakuan: A → 70,71         KTG       = 53,7429
                B → 75,89        Fhitung > Ftabel
                C → 86,23

Untuk menunjukkan perbedaan di antara masing -
masing perlakuan tersebut dilakukan uji lebih lanjut
dengan uji BNT
2 KTG
   BNT 5% = t5% (18) x           n

                           2 x 53,7429
            = 2,101    x                  = 8,23
                                 7

                              2 KTG
    BNT 1% = t 1% (18) x        n
                           2 x 53,7429
             = 2,878   x                   = 11,28
                                 7

Catatan: dalam penggunaan BNT, tentukan terlebih
         dahulu taraf nyata yang akan digunakan,
         misalnya untuk α = 0,05.
Langkah selanjutnya:
  - Susun rerata perlakuan → mulai dari yang
  terbesar ke terkecil, atau dari yang terkecil ke
  terbesar.

- Carilah beda (selisih) dari rerata perlakuan tersebut.

                          I. Sistim garis
- Mencari NOTASI
                          II. Sistim jarak
Perla -     Rerata      Beda (Selisih)       BNT
kuan         (x)      (x – A)   (x – B)       5%
  C       86,23 a      15,52 *   10,34 *     8,23
  B       75.89 b       5,18
  A       70,71   b

            C             B          A
          (86,23)      (75,89)     (70,71)

      ………… a……………………………………………
      ……………………………………b……………………
      ………………………………………… … __b…….…
MENCARI NOTASI dengan   SISTIM JARAK
                        86,23
   86,23 a               8,23 = BNT
             a
    ………... 78,00        78,00
  75,89 b
                 b
                        75,89
  70,71 b    b            8,23
   ………….. 67,66          67,66

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Uji beda rerata antar perlakuan 17 maret 12

  • 1. UJI BEDA RERATA ANTAR PERLAKUAN
  • 2. Menentukan perbedaan di antara masing-masing perlakuan, setelah dilaksanakan analisis ragam → digunakan PEMBANDINGAN BERGANDA Pembandingan berganda adalah pembandingan berderajat bebas jamak. Tujuan pemband. Berganda → mengetahui signifikansi pengaruh perlakuan yang satu dengan perlakuan yang lain Pembandingan Berganda, antara lain: I. Uji t dengan Beda Nyata Terkecil ( B.N.T.) II. Uji Tukey dengan Beda Nyata Jujur (B.N.J.) III. UJI Jarak Berganda Duncan dengan Jarak Nyata Terkecil ( J.N.T)
  • 3. BEDA NYATA TERKECIL = BNT (LEAST SIGNIFICANT DIFFERENCE = LSD) Digunakan: 1. Bila Fhitung > Ftabel 2. Sebaiknya untuk perlakuan ≤ 3 , dengan 2 perlakuan, peluang kesalahan 5% 3 perlakuan, peluang kesalahan 13% 6 perlakuan, peluang kesalahan 40% 10 perlakuan, peluang kesalahan 60% Peneliti berpikir menggunakan taraf nyata 5%, tetapi sesungguhnya ia sedang menguji dengan taraf nyata 13%
  • 4. Rumus: Untuk n A = n = n: B BNT (α) = t (db galat) x 2 KTG (α) n Untuk n ≠ n : A B BNT (α) = t (db galat) x KTG ── + 1 1 ── (α) n A nB Catatan: t (db galat) dicari pada tabel t (α)
  • 5. CONTOH: 21 bji tahu 3 macam bahan Dari sidik ragam 7 kali ulangan diperoleh: Rerata bobot untuk db galat = 18 perlakuan: A → 70,71 KTG = 53,7429 B → 75,89 Fhitung > Ftabel C → 86,23 Untuk menunjukkan perbedaan di antara masing - masing perlakuan tersebut dilakukan uji lebih lanjut dengan uji BNT
  • 6. 2 KTG BNT 5% = t5% (18) x n 2 x 53,7429 = 2,101 x = 8,23 7 2 KTG BNT 1% = t 1% (18) x n 2 x 53,7429 = 2,878 x = 11,28 7 Catatan: dalam penggunaan BNT, tentukan terlebih dahulu taraf nyata yang akan digunakan, misalnya untuk α = 0,05.
  • 7. Langkah selanjutnya: - Susun rerata perlakuan → mulai dari yang terbesar ke terkecil, atau dari yang terkecil ke terbesar. - Carilah beda (selisih) dari rerata perlakuan tersebut. I. Sistim garis - Mencari NOTASI II. Sistim jarak
  • 8. Perla - Rerata Beda (Selisih) BNT kuan (x) (x – A) (x – B) 5% C 86,23 a 15,52 * 10,34 * 8,23 B 75.89 b 5,18 A 70,71 b C B A (86,23) (75,89) (70,71) ………… a…………………………………………… ……………………………………b…………………… ………………………………………… … __b…….…
  • 9. MENCARI NOTASI dengan SISTIM JARAK 86,23 86,23 a 8,23 = BNT a ………... 78,00 78,00 75,89 b b 75,89 70,71 b b 8,23 ………….. 67,66 67,66