1) The document shows conversions between decimal, hexadecimal, octal, binary, and BCD representations of numbers using both the classical method (multiplications and divisions) and the weighted method. 2) As an example, 5375 in decimal is converted to 14FF in hexadecimal, 12377 in octal, and 1010011111111 in binary using the classical method. 3) The document also converts 166 decimal to A6 hexadecimal and 246 octal using the classical method.

1. Ejerciciostarea21 DavidOteiza:
Por el métodoclásico(multiplicaciones,divisionesoporsu código).
5375 (10) = 14FF (Hex) = 12377 (Oct) = 1010011111111 (2) = 0101 0011 0111 0101 (BCD)
Hex = 14FF
5375/16 = 335 R= F
335/16 = 20 R= F
20/16= 1 R= 4
1/16 = 0 R= 1
Oct = 12377
12377/8 = 671 R=7
671/8 = 83 R= 7
83/8= 10 R= 3
10/8 = 1 R= 2
1/8 = 0 R= 1
166 (10)= A6 (Hex) = 246 (Oct) = 10100110 (2) = 0001 0110 0110 (BCD)
Hex = 10*161 + 6*160 = 166
Oct = 246
166/8= 20 R= 6
20/8 = 2 R= 4
2/8 = 0 R= 2
2. Por el métodode pesos
Con nueve dígitosde aproximación
0.00350 (10) = Hex = (Oct) = (2) = (BCD)
(10)= Hex = (Oct) = 0.011 (2) = (BCD)