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There are no statements given.SolutionThere are no statements .pdf
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You can use Network Monitor or type netstat -a in your command prompt window. this will list all your conections. Solution You can use Network Monitor or type netstat -a in your command prompt window. this will list all your conections..
You can use Network Monitor or type netstat -a in your command promp.pdf
You can use Network Monitor or type netstat -a in your command promp.pdf
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The answer is: B- Lagging strand. Lagging strand of DNA is synthesized toward the middle of the replication bubble. Solution The answer is: B- Lagging strand. Lagging strand of DNA is synthesized toward the middle of the replication bubble..
The answer is B- Lagging strand.Lagging strand of DNA is synthesi.pdf
The answer is B- Lagging strand.Lagging strand of DNA is synthesi.pdf
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solution in c++ program /* Program to implement a queue using two stacks */ #include #include using namespace std; /* structure of a stack node */ struct sNode { int data; struct sNode *next; }; /* Function to push an item to stack*/ void push(struct sNode** top_ref, int new_data); /* Function to pop an item from stack*/ int pop(struct sNode** top_ref); /* structure of queue having two stacks */ struct queue { struct sNode *stack1; struct sNode *stack2; }; /* Function to enqueue an item to queue */ void enQueue(struct queue *q, int x) { push(&q->stack1, x); } /* Function to dequeue an item from queue */ int deQueue(struct queue *q) { int x; /* If both stacks are empty then error */ if(q->stack1 == NULL && q->stack2 == NULL) { printf(\"Q is empty\"); getchar(); exit(0); } /* Move elements from satck1 to stack 2 only if stack2 is empty */ if(q->stack2 == NULL) { while(q->stack1 != NULL) { x = pop(&q->stack1); push(&q->stack2, x); } } x = pop(&q->stack2); return x; } /* Function to push an item to stack*/ void push(struct sNode** top_ref, int new_data) { /* allocate node */ struct sNode* new_node = (struct sNode*) malloc(sizeof(struct sNode)); if(new_node == NULL) { printf(\"Stack is empty \ \"); getchar(); exit(0); } else{ /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*top_ref); /* move the head to point to the new node */ (*top_ref) = new_node; } } /* Function to pop an item from stack*/ int pop(struct sNode** top_ref) { int res; struct sNode *top; /*If stack is empty then error */ if(*top_ref == NULL) { printf(\"Stack overflow \ \"); getchar(); exit(0); } else { top = *top_ref; res = top->data; *top_ref = top->next; free(top); return res; } } /* Driver function to test anove functions */ int main() { /* Create a queue with items 1 2 3*/ struct queue *q = (struct queue*)malloc(sizeof(struct queue)); q->stack1 = NULL; q->stack2 = NULL; for(int i=0;i<15;i++) { enQueue(q, i); } //enQueue(q, 2); //enQueue(q, 3); //enQueue(q,4); /* Dequeue items */ printf(\"the dequeue items\"); for(int i=0;i<16;i++) { printf(\"%d \", deQueue(q)); //printf(\"%d \", deQueue(q)); } getchar(); } output the dequeue items 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 q is empty Solution solution in c++ program /* Program to implement a queue using two stacks */ #include #include using namespace std; /* structure of a stack node */ struct sNode { int data; struct sNode *next; }; /* Function to push an item to stack*/ void push(struct sNode** top_ref, int new_data); /* Function to pop an item from stack*/ int pop(struct sNode** top_ref); /* structure of queue having two stacks */ struct queue { struct sNode *stack1; struct sNode *stack2; }; /* Function to enqueue an item to queue */ void enQueue(struct queue *q, int x) { push(&q->stack1, x); } /* Function to dequeue an item from queue */ int deQueue(struct queue *q) { int x; /* If both stacks are empty then error */ if(q->stack1 == NULL && q->stack2 == NULL) { printf(\"Q .
solution in c++program Program to implement a queue using two .pdf
solution in c++program Program to implement a queue using two .pdf
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Organs of the digestive tract: 1.Mouth- 2.Tongue- 3.Epiglottis- 4.Pharynx- 5.Oesophagus- 6.Diaphragm- 7.Stomach- Pancreas- 8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large intestine. The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus. (a)Small intestine- 9.Cecum- (b) Large intestine- Specialized structures or cells in the digestive tract: These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes and microfold cells. Solution Organs of the digestive tract: 1.Mouth- 2.Tongue- 3.Epiglottis- 4.Pharynx- 5.Oesophagus- 6.Diaphragm- 7.Stomach- Pancreas- 8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large intestine. The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus. (a)Small intestine- 9.Cecum- (b) Large intestine- Specialized structures or cells in the digestive tract: These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes and microfold cells..
Organs of the digestive tract1.Mouth-2.Tongue-3.Epiglottis-.pdf
Organs of the digestive tract1.Mouth-2.Tongue-3.Epiglottis-.pdf
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a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N. The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H). Solution a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N. The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H)..
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b..pdf
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b..pdf
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u can feed air by possible putting zinc chloride aroud it and the first part of question is incorrect Solution u can feed air by possible putting zinc chloride aroud it and the first part of question is incorrect.
u can feed air by possible putting zinc chloride.pdf
u can feed air by possible putting zinc chloride.pdf
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The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom; however, it influences the overall shape through repulsions. As in methane above, there are four regions of electron density. Therefore, the overall orientation of the regions of electron density is tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E type molecule because the lone pair is represented by an E. The observed shape of the molecule is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to determine molecular geometry. The shape of a molecule is found from the relationship of the atoms even though it can be influenced by lone pairs of electron Solution The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom; however, it influences the overall shape through repulsions. As in methane above, there are four regions of electron density. Therefore, the overall orientation of the regions of electron density is tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E type molecule because the lone pair is represented by an E. The observed shape of the molecule is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to determine molecular geometry. The shape of a molecule is found from the relationship of the atoms even though it can be influenced by lone pairs of electron.
The ammonia molecule (NH3) has three pairs of ele.pdf
The ammonia molecule (NH3) has three pairs of ele.pdf
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single Solution single.
single S.pdf
single S.pdf
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You can use Network Monitor or type netstat -a in your command prompt window. this will list all your conections. Solution You can use Network Monitor or type netstat -a in your command prompt window. this will list all your conections..
You can use Network Monitor or type netstat -a in your command promp.pdf
You can use Network Monitor or type netstat -a in your command promp.pdf
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The answer is: B- Lagging strand. Lagging strand of DNA is synthesized toward the middle of the replication bubble. Solution The answer is: B- Lagging strand. Lagging strand of DNA is synthesized toward the middle of the replication bubble..
The answer is B- Lagging strand.Lagging strand of DNA is synthesi.pdf
The answer is B- Lagging strand.Lagging strand of DNA is synthesi.pdf
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solution in c++ program /* Program to implement a queue using two stacks */ #include #include using namespace std; /* structure of a stack node */ struct sNode { int data; struct sNode *next; }; /* Function to push an item to stack*/ void push(struct sNode** top_ref, int new_data); /* Function to pop an item from stack*/ int pop(struct sNode** top_ref); /* structure of queue having two stacks */ struct queue { struct sNode *stack1; struct sNode *stack2; }; /* Function to enqueue an item to queue */ void enQueue(struct queue *q, int x) { push(&q->stack1, x); } /* Function to dequeue an item from queue */ int deQueue(struct queue *q) { int x; /* If both stacks are empty then error */ if(q->stack1 == NULL && q->stack2 == NULL) { printf(\"Q is empty\"); getchar(); exit(0); } /* Move elements from satck1 to stack 2 only if stack2 is empty */ if(q->stack2 == NULL) { while(q->stack1 != NULL) { x = pop(&q->stack1); push(&q->stack2, x); } } x = pop(&q->stack2); return x; } /* Function to push an item to stack*/ void push(struct sNode** top_ref, int new_data) { /* allocate node */ struct sNode* new_node = (struct sNode*) malloc(sizeof(struct sNode)); if(new_node == NULL) { printf(\"Stack is empty \ \"); getchar(); exit(0); } else{ /* put in the data */ new_node->data = new_data; /* link the old list off the new node */ new_node->next = (*top_ref); /* move the head to point to the new node */ (*top_ref) = new_node; } } /* Function to pop an item from stack*/ int pop(struct sNode** top_ref) { int res; struct sNode *top; /*If stack is empty then error */ if(*top_ref == NULL) { printf(\"Stack overflow \ \"); getchar(); exit(0); } else { top = *top_ref; res = top->data; *top_ref = top->next; free(top); return res; } } /* Driver function to test anove functions */ int main() { /* Create a queue with items 1 2 3*/ struct queue *q = (struct queue*)malloc(sizeof(struct queue)); q->stack1 = NULL; q->stack2 = NULL; for(int i=0;i<15;i++) { enQueue(q, i); } //enQueue(q, 2); //enQueue(q, 3); //enQueue(q,4); /* Dequeue items */ printf(\"the dequeue items\"); for(int i=0;i<16;i++) { printf(\"%d \", deQueue(q)); //printf(\"%d \", deQueue(q)); } getchar(); } output the dequeue items 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 q is empty Solution solution in c++ program /* Program to implement a queue using two stacks */ #include #include using namespace std; /* structure of a stack node */ struct sNode { int data; struct sNode *next; }; /* Function to push an item to stack*/ void push(struct sNode** top_ref, int new_data); /* Function to pop an item from stack*/ int pop(struct sNode** top_ref); /* structure of queue having two stacks */ struct queue { struct sNode *stack1; struct sNode *stack2; }; /* Function to enqueue an item to queue */ void enQueue(struct queue *q, int x) { push(&q->stack1, x); } /* Function to dequeue an item from queue */ int deQueue(struct queue *q) { int x; /* If both stacks are empty then error */ if(q->stack1 == NULL && q->stack2 == NULL) { printf(\"Q .
solution in c++program Program to implement a queue using two .pdf
solution in c++program Program to implement a queue using two .pdf
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Organs of the digestive tract: 1.Mouth- 2.Tongue- 3.Epiglottis- 4.Pharynx- 5.Oesophagus- 6.Diaphragm- 7.Stomach- Pancreas- 8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large intestine. The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus. (a)Small intestine- 9.Cecum- (b) Large intestine- Specialized structures or cells in the digestive tract: These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes and microfold cells. Solution Organs of the digestive tract: 1.Mouth- 2.Tongue- 3.Epiglottis- 4.Pharynx- 5.Oesophagus- 6.Diaphragm- 7.Stomach- Pancreas- 8.Lower gastro intestinal tract- The lower GI,includes the(a)small intestine and all of the (b)large intestine. The lower GI strats at the pyloric sphicter of the stomach and finishes at the anus. (a)Small intestine- 9.Cecum- (b) Large intestine- Specialized structures or cells in the digestive tract: These include the various cells of the gastric glands,taste cells,pancreatic duct cells enterocytes and microfold cells..
Organs of the digestive tract1.Mouth-2.Tongue-3.Epiglottis-.pdf
Organs of the digestive tract1.Mouth-2.Tongue-3.Epiglottis-.pdf
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a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N. The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H). Solution a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b. BBr3. The B has 3 bonds and no lone pairs, so it is trigonal planar. c. HCN. The C is the central atom and has two bonds (a single to H, triple to N), and no lone pairs, so it is linear. d. The C is the central atom and has three bonds (single to H, double to O), so it is trigonal planar. e. There are two \"central\" N atoms. The first has a single bond to H and double to N, and one lone pair, so it is bent. The second has two bonds (double to each other N), and no lone pairs, so it is linear. H-N=N=N. The first N is bent, the second is linear (so the 3 N atoms all lie in a line, but not the H)..
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b..pdf
a. BeCl2. The Be has 2 bonds and no lone pairs, so it is linear. b..pdf
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u can feed air by possible putting zinc chloride aroud it and the first part of question is incorrect Solution u can feed air by possible putting zinc chloride aroud it and the first part of question is incorrect.
u can feed air by possible putting zinc chloride.pdf
u can feed air by possible putting zinc chloride.pdf
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The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom; however, it influences the overall shape through repulsions. As in methane above, there are four regions of electron density. Therefore, the overall orientation of the regions of electron density is tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E type molecule because the lone pair is represented by an E. The observed shape of the molecule is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to determine molecular geometry. The shape of a molecule is found from the relationship of the atoms even though it can be influenced by lone pairs of electron Solution The ammonia molecule (NH3) has three pairs of electrons involved in bonding, but there is a lone pair of electrons on the nitrogen atom. It is not bonded with another atom; however, it influences the overall shape through repulsions. As in methane above, there are four regions of electron density. Therefore, the overall orientation of the regions of electron density is tetrahedral. On the other hand, there are only three outer atoms. This is referred to as an AX3E type molecule because the lone pair is represented by an E. The observed shape of the molecule is a trigonal pyramid, because the lone pair is not \"visible\" in experimental methods used to determine molecular geometry. The shape of a molecule is found from the relationship of the atoms even though it can be influenced by lone pairs of electron.
The ammonia molecule (NH3) has three pairs of ele.pdf
The ammonia molecule (NH3) has three pairs of ele.pdf
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single Solution single.
single S.pdf
single S.pdf
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E)Mg2- note: more electron filled in the valence shell, bigger the size is. Solution E)Mg2- note: more electron filled in the valence shell, bigger the size is..
E)Mg2- note more electron filled in the valence.pdf
E)Mg2- note more electron filled in the valence.pdf
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CH4 (methane) molecules only have london dispersion forces. They are nonpolar, so no other IMF\'s will exist in them Solution CH4 (methane) molecules only have london dispersion forces. They are nonpolar, so no other IMF\'s will exist in them.
CH4 (methane) molecules only have london dispersi.pdf
CH4 (methane) molecules only have london dispersi.pdf
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PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate - KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2 lithium hydrogen sulfite - LiHSO3 Solution PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate - KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2 lithium hydrogen sulfite - LiHSO3.
PbCl4 - lead tetra chloride PbSo4 - lead sulfate.pdf
PbCl4 - lead tetra chloride PbSo4 - lead sulfate.pdf
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NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit, but CCl4 has a melting point below zero. Solution NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit, but CCl4 has a melting point below zero..
NiCl2 for sure. None of the rest are soluble in w.pdf
NiCl2 for sure. None of the rest are soluble in w.pdf
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It is polar. That is part of the reason it mixes with water. It is also soluble with nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a charge Solution It is polar. That is part of the reason it mixes with water. It is also soluble with nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a charge.
It is polar. That is part of the reason it mixes .pdf
It is polar. That is part of the reason it mixes .pdf
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D. R-OH Solution D. R-OH.
D. R-OH .pdf
D. R-OH .pdf
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D intermolecular forces are important when the solvent or solute is a liquid or a solid. Solution D intermolecular forces are important when the solvent or solute is a liquid or a solid..
D intermolecular forces are important when the so.pdf
D intermolecular forces are important when the so.pdf
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Do you have an image of the IR? If so it would be much easier to help you out. Solution Do you have an image of the IR? If so it would be much easier to help you out..
Do you have an image of the IR If so it would be.pdf
Do you have an image of the IR If so it would be.pdf
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Cooperativity : Two different theories of the cooperative mechanism were postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or “concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule as it was transformed from one conformation (T) to a second conformation (R) under the influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound, so that changes in one subunit led to distortions in the shape and/or interactions of other subunits of the protein. The KNF model, however, also predicted that in some cases the first ligand to bind could make it more difficult for subsequent ligands to bind. This was called “negative cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative” because binding of one ligand made the binding of subsequent ligands more difficult.The MWC theory allowed no such alternative. Because only the KNF theory fit negatively cooperative enzymes, it is easy to select that model for such enzymes, but because both theories fit positively cooperative enzymes more sophisticated tools must be applied to such cases. Solution Cooperativity : Two different theories of the cooperative mechanism were postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or “concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule as it was transformed from one conformation (T) to a second conformation (R) under the influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound, so that changes in one subunit led to distortions in the shape and/or interactions of other subunits of the protein. The KNF model, however, also predicted that in some cases the first ligand to bind could make it more difficult for subsequent ligands to bind. This was called “negative cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative” because binding of one ligand made the binding of subsequent ligands more difficult.The MWC theory allowed no such alternative. Because only the KNF theory fit negatively cooperative enzymes, it is easy to select that model for such enzymes, but because both theories fit positively cooperative enzymes more sophisticated tools must be applied to such cases..
Cooperativity Two different theories of the coo.pdf
Cooperativity Two different theories of the coo.pdf
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i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II) cyanide iv) Chromium (III) hydroxide v) Iron (III) sulfite vi) Cobalt (II) nitrate vii) Ammonium sulfite viii) Sodium dihyrogen phosphate ix) Potassium permanganate x) Sodium dichromate Hope this helps! :-) Solution i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II) cyanide iv) Chromium (III) hydroxide v) Iron (III) sulfite vi) Cobalt (II) nitrate vii) Ammonium sulfite viii) Sodium dihyrogen phosphate ix) Potassium permanganate x) Sodium dichromate Hope this helps! :-).
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II).pdf
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II).pdf
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Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients. They are evolved from the split with chimpanzees. So all Homo termed species are Hominin. From the given picture, there are five hominin species coexisted 1.7 million years ago. Their names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo habilis. Solution Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients. They are evolved from the split with chimpanzees. So all Homo termed species are Hominin. From the given picture, there are five hominin species coexisted 1.7 million years ago. Their names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo habilis..
Hominin is the subtribe of tribe Hominini. These belong to modern hu.pdf
Hominin is the subtribe of tribe Hominini. These belong to modern hu.pdf
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Heat evolved = mass of water x specific heat capacity x temperature change = 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol Solution Heat evolved = mass of water x specific heat capacity x temperature change = 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol.
Heat evolved = mass of water x specific heat capacity x temperature .pdf
Heat evolved = mass of water x specific heat capacity x temperature .pdf
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D. Primary lymphatic structure are sites where white blood cells are produced and/or mature. secondary lymphatic structure are where immune response are initiated. Solution D. Primary lymphatic structure are sites where white blood cells are produced and/or mature. secondary lymphatic structure are where immune response are initiated..
D. Primary lymphatic structure are sites where white blood cells are.pdf
D. Primary lymphatic structure are sites where white blood cells are.pdf
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domain: (-inf,inf) range: [-4,inf) x intercept: (1,0) and (5,0) y intercept: (0,5) increasing interval: (3,INF) decreasing interval: (0,3) constant interval: (-INF,0) at x=3 we have a minima f(-2)=5 at x=2 and at x=4, f(x)=-3 function is neither even nor odd Solution domain: (-inf,inf) range: [-4,inf) x intercept: (1,0) and (5,0) y intercept: (0,5) increasing interval: (3,INF) decreasing interval: (0,3) constant interval: (-INF,0) at x=3 we have a minima f(-2)=5 at x=2 and at x=4, f(x)=-3 function is neither even nor odd.
domain (-inf,inf) range [-4,inf) x intercept (1,0) and (5,0.pdf
domain (-inf,inf) range [-4,inf) x intercept (1,0) and (5,0.pdf
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Earlier a place value notation number system had evolved over a lengthy period with a number base of 60. It allowed arbitrarily large numbers and fractions to be represented and so proved to be the foundation of more high powered mathematical development. Number problems such as that of the Pythagorean triples (a,b,c) with a2+b2 = c2 were studied from at least 1700 BC. Systems of linear equations were studied in the context of solving number problems. Quadratic equations were also studied and these examples led to a type of numerical algebra. Geometric problems relating to similar figures, area and volume were also studied and values obtained for π. The Babylonian basis of mathematics was inherited by the Greeks and independent development by the Greeks began from around 450 BC. Zeno of Elea\'s paradoxes led to the atomic theory of Democritus. A more precise formulation of concepts led to the realisation that the rational numbers did not suffice to measure all lengths. A geometric formulation of irrational numbers arose. Studies of area led to a form of integration. The theory of conic sections shows a high point in pure mathematical study by Apollonius. Further mathematical discoveries were driven by the astronomy, for example the study of trigonometry. The major Greek progress in mathematics was from 300 BC to 200 AD. After this time progress continued in Islamic countries. Mathematics flourished in particular in Iran, Syria and India. This work did not match the progress made by the Greeks but in addition to the Islamic progress, it did preserve Greek mathematics. From about the 11th Century Adelard of Bath, then later Fibonacci, brought this Islamic mathematics and its knowledge of Greek mathematics back into Europe. Major progress in mathematics in Europe began again at the beginning of the 16th Century with Pacioli, then Cardan, Tartaglia and Ferrari with the algebraic solution of cubic and quartic equations. Copernicus and Galileo revolutionised the applications of mathematics to the study of the universe. The progress in algebra had a major psychological effect and enthusiasm for mathematical research, in particular research in algebra, spread from Italy to Stevin in Belgium and Viète in France. The 17th Century saw Napier, Briggs and others greatly extend the power of mathematics as a calculatory science with his discovery of logarithms. Cavalieri made progress towards the calculus with his infinitesimal methods and Descartes added the power of algebraic methods to geometry. Progress towards the calculus continued with Fermat, who, together with Pascal, began the mathematical study of probability. However the calculus was to be the topic of most significance to evolve in the 17th Century. Newton, building on the work of many earlier mathematicians such as his teacher Barrow, developed the calculus into a tool to push forward the study of nature. His work contained a wealth of new discoveries showing the interaction between mathemat.
Earlier a place value notation number system had evolved over a leng.pdf
Earlier a place value notation number system had evolved over a leng.pdf
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Cyclohexanone is slightly soluble in water. NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in the aqueous layer is decreased. This will increase the partition coefficient and more cyclohexanone will be extracted into the organic layer. Thus the extraction of cyclohexanone will be more efficient. Solution Cyclohexanone is slightly soluble in water. NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in the aqueous layer is decreased. This will increase the partition coefficient and more cyclohexanone will be extracted into the organic layer. Thus the extraction of cyclohexanone will be more efficient..
Cyclohexanone is slightly soluble in water.NaCl is added to make t.pdf
Cyclohexanone is slightly soluble in water.NaCl is added to make t.pdf
brijmote
amniotic eggs evolved primarily as an adaptation to a. protect the developing embryo while the parents sits on it b. protect the developing embryo from predators c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER d. allow the embryo to remain protected while the parent is out gathering food e. to provide a nice compact case that is easy to boil and subsequently eat ============================================================= Amniotes :They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are recognized from the anamniotes (fishes and creatures of land and water), which commonly lay their eggs in water. Amniotes are tetrapods (relatives of four-limbed and backboned creatures) that are portrayed by having an egg outfitted with an amnion, an adjustment to lay eggs ashore as opposed to in water as the anamniotes (counting frogs) regularly do. Amniotes incorporate synapsids (warm blooded creatures alongside their wiped out family) and sauropsids (reptiles and winged creatures), and additionally their predecessors. Amniote developing lives, whether laid as eggs or conveyed by the female, are ensured and supported by a few broad layers. In eutherian warm blooded creatures, (for example, people), these films incorporate the amniotic sac that encompasses the embryo. These embryonic films and the absence of a larval stage recognize amniotes from tetrapod creatures of land and water shedding is controlled by trademark hormones called ecdysteroids the fingernail skin has 3 layers epicuticle, exocuticle, and endocuticle epicuticle is trilaminate alpha-chitin in internal layer Some taxa have lost the genuine coelom and have gotten to be blastocoelic (pseudocoelomic). Arthropods are eucoelomic, however in develop creatures the coelom is incredibly diminished. The open circulatory framework utilizes an optionally delivered pit, the hemocoel. Valentine (2004) recommends that another synapomorphic character is immediate advancement or improvement in which hatchlings are comparative when all is said in done frame to the develop grown-up, a character that has changed altogether in numerous arthropod bunches. Solution amniotic eggs evolved primarily as an adaptation to a. protect the developing embryo while the parents sits on it b. protect the developing embryo from predators c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER d. allow the embryo to remain protected while the parent is out gathering food e. to provide a nice compact case that is easy to boil and subsequently eat ============================================================= Amniotes :They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are recognized from the anamniotes (.
amniotic eggs evolved primarily as an adaptation toa. protect the .pdf
amniotic eggs evolved primarily as an adaptation toa. protect the .pdf
brijmote
Code: #include #include struct node { int data; struct node* next; }; typedef struct node * immense_int_t; void insert_front(immense_int_t head, char c); void print(immense_int_t head); immense_int_t add(immense_int_t head1, immense_int_t head2); immense_int_t sub(immense_int_t head1, immense_int_t head2); int main() { char s[1000],c; int i; immense_int_t head1 = malloc(sizeof(struct node));//dummy node for ease of coding immense_int_t head2 = malloc(sizeof(struct node));// dummy node for ease of coding head1->next = head2->next = NULL; immense_int_t result ; scanf(\"%s\",s); for(i=0;s[i]!=\'\\0\';i++) insert_front(head1,s[i]);// put input into linked list scanf(\"%s\",s); for(i=0;s[i]!=\'\\0\';i++) insert_front(head2,s[i]);// put input into linked list scanf(\"%s\",s); switch(s[0]) { case \'+\': result = add(head1->next,head2->next); break; case \'\"\': result = sub(head1->next,head2->next); break; } print(result->next);// print from dummy next node printf(\"\ \"); return 0; } void insert_front(immense_int_t head, char c) { immense_int_t node = malloc(sizeof(struct node)); node->data = c-\'0\'; node->next = head->next; head->next = node; } void print(immense_int_t head) { if(head==NULL) return; print(head->next); printf(\"%d\",head->data); } immense_int_t add(immense_int_t head1, immense_int_t head2) { immense_int_t result = malloc(sizeof(struct node)); immense_int_t temp, temp1; temp = malloc(sizeof(struct node)); result->next = temp; temp1 = temp; int carry =0; while(head1 && head2) { temp->data = (head1->data + head2->data + carry)%10; carry = (head1->data + head2->data + carry)/10 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head1 = head1->next; head2 = head2->next; } while(head1) // if number of digits of first are more than second { temp->data = (head1->data + carry)%10; carry = (head1->data + carry)/10 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head1 = head1->next; } while(head2)// if number of digits of second are more than first { temp->data = (head2->data + carry)%10; carry = (head2->data + carry)/10 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head2 = head2->next; } if(carry)// if the number of digits in result is more than number of digits in both the numbers { temp->data = carry; temp1->next = temp; temp1 = temp; } temp1->next = NULL; return result; } immense_int_t sub(immense_int_t head1, immense_int_t head2) { immense_int_t result = malloc(sizeof(struct node)); immense_int_t temp, temp1; temp = malloc(sizeof(struct node)); result->next = temp; temp1 = temp; int borrow =0; while(head1 && head2) { temp->data = (head1->data - head2->data - borrow + 10)%10; borrow = (head1->data - head2->data - borrow) < 0? 1:0 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head1 = head1->next; head2 = head2->next; } while(head1)// if number of digits of first are more than second { temp->data = (head1->data - borrow)%10; borrow = (head1->da.
Code#include stdio.h #includemalloc.h struct node { .pdf
Code#include stdio.h #includemalloc.h struct node { .pdf
brijmote
All are correct. Solution All are correct..
All are correct.SolutionAll are correct..pdf
All are correct.SolutionAll are correct..pdf
brijmote
a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose and D-Galactose - C4 epimers c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose Solution a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose and D-Galactose - C4 epimers c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose.
a) Anomeric carbon The carbonyl carbon found in the open chain . Eg.pdf
a) Anomeric carbon The carbonyl carbon found in the open chain . Eg.pdf
brijmote
This presentation is from the Paper 208: Comparative Literature & Translation Studies, Unit 3: A.K. Ramanujan, “On Translating a Tamil Poem”, Collected Essays of A.K. Ramanujan, ed Vinay Dharwadkar. Oxford University Press, 1999 and I choose the topic Comparative Literature in the Digital Age.
On_Translating_a_Tamil_Poem_by_A_K_Ramanujan.pptx
On_Translating_a_Tamil_Poem_by_A_K_Ramanujan.pptx
Pooja Bhuva
Chinese philosophy
Philosophy of china and it's charactistics
Philosophy of china and it's charactistics
hameyhk98
More Related Content
More from brijmote
E)Mg2- note: more electron filled in the valence shell, bigger the size is. Solution E)Mg2- note: more electron filled in the valence shell, bigger the size is..
E)Mg2- note more electron filled in the valence.pdf
E)Mg2- note more electron filled in the valence.pdf
brijmote
CH4 (methane) molecules only have london dispersion forces. They are nonpolar, so no other IMF\'s will exist in them Solution CH4 (methane) molecules only have london dispersion forces. They are nonpolar, so no other IMF\'s will exist in them.
CH4 (methane) molecules only have london dispersi.pdf
CH4 (methane) molecules only have london dispersi.pdf
brijmote
PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate - KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2 lithium hydrogen sulfite - LiHSO3 Solution PbCl4 - lead tetra chloride PbSo4 - lead sulfate KClO - potassium hypochlorite Mg(C2H3O2)2 - magnesium acetate copper( I ) chlorate - CuCl potassium permanganate - KMnO4 lead(II) chromate - PbCrO4 calcium fluoride - CaF2 iron(II) phosphate - Fe3(PO4)2 lithium hydrogen sulfite - LiHSO3.
PbCl4 - lead tetra chloride PbSo4 - lead sulfate.pdf
PbCl4 - lead tetra chloride PbSo4 - lead sulfate.pdf
brijmote
NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit, but CCl4 has a melting point below zero. Solution NiCl2 for sure. None of the rest are soluble in water at all except CCl4 a tiny bit, but CCl4 has a melting point below zero..
NiCl2 for sure. None of the rest are soluble in w.pdf
NiCl2 for sure. None of the rest are soluble in w.pdf
brijmote
It is polar. That is part of the reason it mixes with water. It is also soluble with nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a charge Solution It is polar. That is part of the reason it mixes with water. It is also soluble with nonpolar substances like hydrocarbons because of the two methyl side groups. hence it has a charge.
It is polar. That is part of the reason it mixes .pdf
It is polar. That is part of the reason it mixes .pdf
brijmote
D. R-OH Solution D. R-OH.
D. R-OH .pdf
D. R-OH .pdf
brijmote
D intermolecular forces are important when the solvent or solute is a liquid or a solid. Solution D intermolecular forces are important when the solvent or solute is a liquid or a solid..
D intermolecular forces are important when the so.pdf
D intermolecular forces are important when the so.pdf
brijmote
Do you have an image of the IR? If so it would be much easier to help you out. Solution Do you have an image of the IR? If so it would be much easier to help you out..
Do you have an image of the IR If so it would be.pdf
Do you have an image of the IR If so it would be.pdf
brijmote
Cooperativity : Two different theories of the cooperative mechanism were postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or “concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule as it was transformed from one conformation (T) to a second conformation (R) under the influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound, so that changes in one subunit led to distortions in the shape and/or interactions of other subunits of the protein. The KNF model, however, also predicted that in some cases the first ligand to bind could make it more difficult for subsequent ligands to bind. This was called “negative cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative” because binding of one ligand made the binding of subsequent ligands more difficult.The MWC theory allowed no such alternative. Because only the KNF theory fit negatively cooperative enzymes, it is easy to select that model for such enzymes, but because both theories fit positively cooperative enzymes more sophisticated tools must be applied to such cases. Solution Cooperativity : Two different theories of the cooperative mechanism were postulated. One was the theory of Monod, Wyman, and Changeux,MWC model (“symmetry”or “concerted”or “the two-state” model),and the other was the theory of Koshland, Nemethy, and FilmerKNF model (“induced fit”or“sequential”model). The MWC model proposed that the subunits changed shape in a concerted manner to preserve the symmetry of the entire molecule as it was transformed from one conformation (T) to a second conformation (R) under the influence of ligand. The KNF model postulated that each subunit changed shape as ligand bound, so that changes in one subunit led to distortions in the shape and/or interactions of other subunits of the protein. The KNF model, however, also predicted that in some cases the first ligand to bind could make it more difficult for subsequent ligands to bind. This was called “negative cooperativity” because there was (a) “cooperativity” between the subunits and (b) “negative” because binding of one ligand made the binding of subsequent ligands more difficult.The MWC theory allowed no such alternative. Because only the KNF theory fit negatively cooperative enzymes, it is easy to select that model for such enzymes, but because both theories fit positively cooperative enzymes more sophisticated tools must be applied to such cases..
Cooperativity Two different theories of the coo.pdf
Cooperativity Two different theories of the coo.pdf
brijmote
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II) cyanide iv) Chromium (III) hydroxide v) Iron (III) sulfite vi) Cobalt (II) nitrate vii) Ammonium sulfite viii) Sodium dihyrogen phosphate ix) Potassium permanganate x) Sodium dichromate Hope this helps! :-) Solution i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II) cyanide iv) Chromium (III) hydroxide v) Iron (III) sulfite vi) Cobalt (II) nitrate vii) Ammonium sulfite viii) Sodium dihyrogen phosphate ix) Potassium permanganate x) Sodium dichromate Hope this helps! :-).
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II).pdf
i) Lithium oxide ii) Sodium hypochlorite iii) Strontium (II).pdf
brijmote
Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients. They are evolved from the split with chimpanzees. So all Homo termed species are Hominin. From the given picture, there are five hominin species coexisted 1.7 million years ago. Their names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo habilis. Solution Hominin is the subtribe of tribe Hominini. These belong to modern human (Homo) ancients. They are evolved from the split with chimpanzees. So all Homo termed species are Hominin. From the given picture, there are five hominin species coexisted 1.7 million years ago. Their names are Homo ergaster, Homo sapiens, Homo neanderthalensis, Homo erectus and Homo habilis..
Hominin is the subtribe of tribe Hominini. These belong to modern hu.pdf
Hominin is the subtribe of tribe Hominini. These belong to modern hu.pdf
brijmote
Heat evolved = mass of water x specific heat capacity x temperature change = 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol Solution Heat evolved = mass of water x specific heat capacity x temperature change = 101 x 4.186 x (24.7 - 21.0) = 1564 J = 1.564 kJ Enthalpy of reaction = -1.564/2.00 = -0.782 kJ/mol.
Heat evolved = mass of water x specific heat capacity x temperature .pdf
Heat evolved = mass of water x specific heat capacity x temperature .pdf
brijmote
D. Primary lymphatic structure are sites where white blood cells are produced and/or mature. secondary lymphatic structure are where immune response are initiated. Solution D. Primary lymphatic structure are sites where white blood cells are produced and/or mature. secondary lymphatic structure are where immune response are initiated..
D. Primary lymphatic structure are sites where white blood cells are.pdf
D. Primary lymphatic structure are sites where white blood cells are.pdf
brijmote
domain: (-inf,inf) range: [-4,inf) x intercept: (1,0) and (5,0) y intercept: (0,5) increasing interval: (3,INF) decreasing interval: (0,3) constant interval: (-INF,0) at x=3 we have a minima f(-2)=5 at x=2 and at x=4, f(x)=-3 function is neither even nor odd Solution domain: (-inf,inf) range: [-4,inf) x intercept: (1,0) and (5,0) y intercept: (0,5) increasing interval: (3,INF) decreasing interval: (0,3) constant interval: (-INF,0) at x=3 we have a minima f(-2)=5 at x=2 and at x=4, f(x)=-3 function is neither even nor odd.
domain (-inf,inf) range [-4,inf) x intercept (1,0) and (5,0.pdf
domain (-inf,inf) range [-4,inf) x intercept (1,0) and (5,0.pdf
brijmote
Earlier a place value notation number system had evolved over a lengthy period with a number base of 60. It allowed arbitrarily large numbers and fractions to be represented and so proved to be the foundation of more high powered mathematical development. Number problems such as that of the Pythagorean triples (a,b,c) with a2+b2 = c2 were studied from at least 1700 BC. Systems of linear equations were studied in the context of solving number problems. Quadratic equations were also studied and these examples led to a type of numerical algebra. Geometric problems relating to similar figures, area and volume were also studied and values obtained for π. The Babylonian basis of mathematics was inherited by the Greeks and independent development by the Greeks began from around 450 BC. Zeno of Elea\'s paradoxes led to the atomic theory of Democritus. A more precise formulation of concepts led to the realisation that the rational numbers did not suffice to measure all lengths. A geometric formulation of irrational numbers arose. Studies of area led to a form of integration. The theory of conic sections shows a high point in pure mathematical study by Apollonius. Further mathematical discoveries were driven by the astronomy, for example the study of trigonometry. The major Greek progress in mathematics was from 300 BC to 200 AD. After this time progress continued in Islamic countries. Mathematics flourished in particular in Iran, Syria and India. This work did not match the progress made by the Greeks but in addition to the Islamic progress, it did preserve Greek mathematics. From about the 11th Century Adelard of Bath, then later Fibonacci, brought this Islamic mathematics and its knowledge of Greek mathematics back into Europe. Major progress in mathematics in Europe began again at the beginning of the 16th Century with Pacioli, then Cardan, Tartaglia and Ferrari with the algebraic solution of cubic and quartic equations. Copernicus and Galileo revolutionised the applications of mathematics to the study of the universe. The progress in algebra had a major psychological effect and enthusiasm for mathematical research, in particular research in algebra, spread from Italy to Stevin in Belgium and Viète in France. The 17th Century saw Napier, Briggs and others greatly extend the power of mathematics as a calculatory science with his discovery of logarithms. Cavalieri made progress towards the calculus with his infinitesimal methods and Descartes added the power of algebraic methods to geometry. Progress towards the calculus continued with Fermat, who, together with Pascal, began the mathematical study of probability. However the calculus was to be the topic of most significance to evolve in the 17th Century. Newton, building on the work of many earlier mathematicians such as his teacher Barrow, developed the calculus into a tool to push forward the study of nature. His work contained a wealth of new discoveries showing the interaction between mathemat.
Earlier a place value notation number system had evolved over a leng.pdf
Earlier a place value notation number system had evolved over a leng.pdf
brijmote
Cyclohexanone is slightly soluble in water. NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in the aqueous layer is decreased. This will increase the partition coefficient and more cyclohexanone will be extracted into the organic layer. Thus the extraction of cyclohexanone will be more efficient. Solution Cyclohexanone is slightly soluble in water. NaCl is added to make the aqueous medium more polar so that the solubility of cyclohexanone in the aqueous layer is decreased. This will increase the partition coefficient and more cyclohexanone will be extracted into the organic layer. Thus the extraction of cyclohexanone will be more efficient..
Cyclohexanone is slightly soluble in water.NaCl is added to make t.pdf
Cyclohexanone is slightly soluble in water.NaCl is added to make t.pdf
brijmote
amniotic eggs evolved primarily as an adaptation to a. protect the developing embryo while the parents sits on it b. protect the developing embryo from predators c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER d. allow the embryo to remain protected while the parent is out gathering food e. to provide a nice compact case that is easy to boil and subsequently eat ============================================================= Amniotes :They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are recognized from the anamniotes (fishes and creatures of land and water), which commonly lay their eggs in water. Amniotes are tetrapods (relatives of four-limbed and backboned creatures) that are portrayed by having an egg outfitted with an amnion, an adjustment to lay eggs ashore as opposed to in water as the anamniotes (counting frogs) regularly do. Amniotes incorporate synapsids (warm blooded creatures alongside their wiped out family) and sauropsids (reptiles and winged creatures), and additionally their predecessors. Amniote developing lives, whether laid as eggs or conveyed by the female, are ensured and supported by a few broad layers. In eutherian warm blooded creatures, (for example, people), these films incorporate the amniotic sac that encompasses the embryo. These embryonic films and the absence of a larval stage recognize amniotes from tetrapod creatures of land and water shedding is controlled by trademark hormones called ecdysteroids the fingernail skin has 3 layers epicuticle, exocuticle, and endocuticle epicuticle is trilaminate alpha-chitin in internal layer Some taxa have lost the genuine coelom and have gotten to be blastocoelic (pseudocoelomic). Arthropods are eucoelomic, however in develop creatures the coelom is incredibly diminished. The open circulatory framework utilizes an optionally delivered pit, the hemocoel. Valentine (2004) recommends that another synapomorphic character is immediate advancement or improvement in which hatchlings are comparative when all is said in done frame to the develop grown-up, a character that has changed altogether in numerous arthropod bunches. Solution amniotic eggs evolved primarily as an adaptation to a. protect the developing embryo while the parents sits on it b. protect the developing embryo from predators c. prevent the developing embryo from drying out in a terrestrial environment--ANSWER d. allow the embryo to remain protected while the parent is out gathering food e. to provide a nice compact case that is easy to boil and subsequently eat ============================================================= Amniotes :They are a clade of tetrapod vertebrates including the reptiles, flying creatures, and warm blooded animals that lay their eggs ashore or hold the prepared egg inside the mother. They are recognized from the anamniotes (.
amniotic eggs evolved primarily as an adaptation toa. protect the .pdf
amniotic eggs evolved primarily as an adaptation toa. protect the .pdf
brijmote
Code: #include #include struct node { int data; struct node* next; }; typedef struct node * immense_int_t; void insert_front(immense_int_t head, char c); void print(immense_int_t head); immense_int_t add(immense_int_t head1, immense_int_t head2); immense_int_t sub(immense_int_t head1, immense_int_t head2); int main() { char s[1000],c; int i; immense_int_t head1 = malloc(sizeof(struct node));//dummy node for ease of coding immense_int_t head2 = malloc(sizeof(struct node));// dummy node for ease of coding head1->next = head2->next = NULL; immense_int_t result ; scanf(\"%s\",s); for(i=0;s[i]!=\'\\0\';i++) insert_front(head1,s[i]);// put input into linked list scanf(\"%s\",s); for(i=0;s[i]!=\'\\0\';i++) insert_front(head2,s[i]);// put input into linked list scanf(\"%s\",s); switch(s[0]) { case \'+\': result = add(head1->next,head2->next); break; case \'\"\': result = sub(head1->next,head2->next); break; } print(result->next);// print from dummy next node printf(\"\ \"); return 0; } void insert_front(immense_int_t head, char c) { immense_int_t node = malloc(sizeof(struct node)); node->data = c-\'0\'; node->next = head->next; head->next = node; } void print(immense_int_t head) { if(head==NULL) return; print(head->next); printf(\"%d\",head->data); } immense_int_t add(immense_int_t head1, immense_int_t head2) { immense_int_t result = malloc(sizeof(struct node)); immense_int_t temp, temp1; temp = malloc(sizeof(struct node)); result->next = temp; temp1 = temp; int carry =0; while(head1 && head2) { temp->data = (head1->data + head2->data + carry)%10; carry = (head1->data + head2->data + carry)/10 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head1 = head1->next; head2 = head2->next; } while(head1) // if number of digits of first are more than second { temp->data = (head1->data + carry)%10; carry = (head1->data + carry)/10 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head1 = head1->next; } while(head2)// if number of digits of second are more than first { temp->data = (head2->data + carry)%10; carry = (head2->data + carry)/10 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head2 = head2->next; } if(carry)// if the number of digits in result is more than number of digits in both the numbers { temp->data = carry; temp1->next = temp; temp1 = temp; } temp1->next = NULL; return result; } immense_int_t sub(immense_int_t head1, immense_int_t head2) { immense_int_t result = malloc(sizeof(struct node)); immense_int_t temp, temp1; temp = malloc(sizeof(struct node)); result->next = temp; temp1 = temp; int borrow =0; while(head1 && head2) { temp->data = (head1->data - head2->data - borrow + 10)%10; borrow = (head1->data - head2->data - borrow) < 0? 1:0 ; temp1->next = temp; temp1 = temp; temp = malloc(sizeof(struct node)); head1 = head1->next; head2 = head2->next; } while(head1)// if number of digits of first are more than second { temp->data = (head1->data - borrow)%10; borrow = (head1->da.
Code#include stdio.h #includemalloc.h struct node { .pdf
Code#include stdio.h #includemalloc.h struct node { .pdf
brijmote
All are correct. Solution All are correct..
All are correct.SolutionAll are correct..pdf
All are correct.SolutionAll are correct..pdf
brijmote
a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose and D-Galactose - C4 epimers c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose Solution a) Anomeric carbon: The carbonyl carbon found in the open chain . Eg. C1 of Glucose b) Epimers: Closely realted sugars, but differeing at only one carbon position. Eg: D-Glucose and D-Galactose - C4 epimers c) Aldose: Carbohydrates with aldehyde functional group. Eg. Glucose d) Ketose: Carbohydrates with ketone functional group. Eg: Fructose e) Reducing sugars : which are capable of reducing Ferric and curpric ions. Eg. Glucose, Ribose.
a) Anomeric carbon The carbonyl carbon found in the open chain . Eg.pdf
a) Anomeric carbon The carbonyl carbon found in the open chain . Eg.pdf
brijmote
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There are no statements given.SolutionThere are no statements .pdf
1.
There are no
statements given. Solution There are no statements given.
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