15.0mL = 0.015L phenylacetic acid 0.50mol/L *0.015= 0.0075 mol phenylacetic acid 20.0mL= 0.020L sodium phenylacetate 0.40mol/L * 0.020L=.008 mol sodium phenylacetate due to the fact that this acts as a buffer Using henderson hasselblach pH= pKa + log(base/acid) and finding that the pKa of phenylaceticacid is 4.28 pH= 4.28 + log (.008/.0075) pH= 4.28 + 0.093 pH= 4.373 Solution 15.0mL = 0.015L phenylacetic acid 0.50mol/L *0.015= 0.0075 mol phenylacetic acid 20.0mL= 0.020L sodium phenylacetate 0.40mol/L * 0.020L=.008 mol sodium phenylacetate due to the fact that this acts as a buffer Using henderson hasselblach pH= pKa + log(base/acid) and finding that the pKa of phenylaceticacid is 4.28 pH= 4.28 + log (.008/.0075) pH= 4.28 + 0.093 pH= 4.373.

1. 15.0mL = 0.015L phenylacetic acid 0.50mol/L *0.015= 0.0075 mol phenylacetic
acid 20.0mL= 0.020L sodium phenylacetate 0.40mol/L * 0.020L=.008 mol sodium
phenylacetate due to the fact that this acts as a buffer Using henderson hasselblach pH= pKa +
log(base/acid) and finding that the pKa of phenylaceticacid is 4.28 pH= 4.28 + log (.008/.0075)
pH= 4.28 + 0.093 pH= 4.373
Solution
15.0mL = 0.015L phenylacetic acid 0.50mol/L *0.015= 0.0075 mol phenylacetic
acid 20.0mL= 0.020L sodium phenylacetate 0.40mol/L * 0.020L=.008 mol sodium
phenylacetate due to the fact that this acts as a buffer Using henderson hasselblach pH= pKa +
log(base/acid) and finding that the pKa of phenylaceticacid is 4.28 pH= 4.28 + log (.008/.0075)
pH= 4.28 + 0.093 pH= 4.373