lead has a 2+ charge in lead(II) nitrate, and nitrate has a negative one charge. For the compound to be electrically neutral, we need one lead ion and two nitrate polyatomic ions. Nitrate is NO3- (side note: nitrite is NO2-) Pb(NO3)2 the compound has this many atoms Pb 2N 6O we need 1lead*207.2g/mole of lead + 2nitrogen*14.01 g/mole nitrogen + 6oxygen*16g/mole oxygen to have a mole. This is 331.22g/mole We only have 50.0 g. We have less than a mole. This means we need to arrange 50 and 331.22 and have the result be less than one: 50.0g/331.22g/mole = 0.151 moles We have 0.151 moles of lead(II) nitrate notice also that the units work out when we divide with the g in the numerator and the g/mole in the denominator. g/(g/mole) = g*(mole/g) = mole 2.5 moles of copper (I) sulfate. The \"ate\" form of sulfate has 4 oxygens (you need to memorize this for the various polyatomic ions) and is SO4 2- Copper(I) has a 1+ charge. To get a neutral compound takes two copper 1+ ions. Cu2SO4 is the formula Cu = 63.46 g/mole S = 32.07 g/mole O = 16 g/mole In 2.5 moles of Cu2SO4 we have 2.5*(2*63.46 + 1*32.07 + 4*16)g since one mole has 2 coppers, one sulfur, and four oxygens. = 557.475 g Since we have 2 sig figs in our number of moles, we should have 2 in our answer, so 560 g would be the answer. Solution lead has a 2+ charge in lead(II) nitrate, and nitrate has a negative one charge. For the compound to be electrically neutral, we need one lead ion and two nitrate polyatomic ions. Nitrate is NO3- (side note: nitrite is NO2-) Pb(NO3)2 the compound has this many atoms Pb 2N 6O we need 1lead*207.2g/mole of lead + 2nitrogen*14.01 g/mole nitrogen + 6oxygen*16g/mole oxygen to have a mole. This is 331.22g/mole We only have 50.0 g. We have less than a mole. This means we need to arrange 50 and 331.22 and have the result be less than one: 50.0g/331.22g/mole = 0.151 moles We have 0.151 moles of lead(II) nitrate notice also that the units work out when we divide with the g in the numerator and the g/mole in the denominator. g/(g/mole) = g*(mole/g) = mole 2.5 moles of copper (I) sulfate. The \"ate\" form of sulfate has 4 oxygens (you need to memorize this for the various polyatomic ions) and is SO4 2- Copper(I) has a 1+ charge. To get a neutral compound takes two copper 1+ ions. Cu2SO4 is the formula Cu = 63.46 g/mole S = 32.07 g/mole O = 16 g/mole In 2.5 moles of Cu2SO4 we have 2.5*(2*63.46 + 1*32.07 + 4*16)g since one mole has 2 coppers, one sulfur, and four oxygens. = 557.475 g Since we have 2 sig figs in our number of moles, we should have 2 in our answer, so 560 g would be the answer..