Temperature change A puddle holds 150 g of water. If 0.50 g of water evaporates from the surface, what is the approximate temperature change of the remaining water? (Lf = 540 cal/g) Solution The heat energy used up on account of evaporation 0.50 gram of water = 0.50gm*540ca/gm =270 cal. Therefore the loss of heat by remaining (150-0.50 = 149.5) gram water is 270 calories. So the decrease degree in temperature of puddle water = 270/(147.5 ) = 1.806 C..

1. Temperature change
A puddle holds 150 g of water. If 0.50 g of water evaporates from the surface, what is the
approximate temperature change of the remaining water? (Lf = 540 cal/g)
Solution
The heat energy used up on account of evaporation 0.50 gram of water = 0.50gm*540ca/gm
=270 cal.
Therefore the loss of heat by remaining (150-0.50 = 149.5) gram water is 270 calories.
So the decrease degree in temperature of puddle water = 270/(147.5 ) = 1.806 C.