Tangents drawn from the point P(1, 8) to the circle x2+ y2– 6x – 11 .pdf

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Tangents drawn from the point P(1, 8) to the circle x2+ y2– 6x – 11 = 0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is (A) x2+ y2+ 4x – 6y + 19 = 0 (B) x2+ y2– 4x – 10y + 19 = 0 (C) x2+ y2– 2x + 6y + 19 = 0 (D) x2+ y2– 6x – 4y + 19 = 0 Solution (B) x2 + y2 – 4x – 10y + 19 = 0.

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