Electrophilic addition - hydrogenation H2 Electro.pdf

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Electrophilic addition - hydrogenation H2 Electrophilic substitution -nitrosation, keto - enol tautomerism Nucleophilic addition - addition of HCN to propanone Nucleophilic Substitution (SN1 SN2) - hydrolysis of tert-butyl chloride is a typical SN1 reaction Solution Electrophilic addition - hydrogenation H2 Electrophilic substitution -nitrosation, keto - enol tautomerism Nucleophilic addition - addition of HCN to propanone Nucleophilic Substitution (SN1 SN2) - hydrolysis of tert-butyl chloride is a typical SN1 reaction.

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y\'+y=x It is a linear ordinary differential eqn of the Bernouille form. So integrating factor, IF=exp[integral (dx)]=e^x so y\'e^x+ye^x=xe^x =>d(ye^x)/dx=xe^x =>d(ye^x)=xe^xdx Integrating we have ye^x=integral[xe^xdx] =xintegral[e^xdx]-integral[d(x)/dx{integral(e^xdx)}dx] [integrating by parts] =xe^x-integral[1.e^xdx] =xe^x-integral[e^xdx] =xe^x-e^x+c =>y=x-1+ce^(-x) y(0)=2 =>-1+c=2 =>c=3 so y=x+3e^(-x)-1 y\'+y=e^(-x) IF=exp[integral(dx)]=e^x so y\'e^x+ye^x=1 =>d(ye^x)/dx=1 =>d(ye^x)=dx =>ye^x=x+c =>y=xe^(-x)+ce^(-x) y(0)=1 =>c=1 so y=xe^(-x)+e^(-x) =>y=(x+1)e^(-x) xy\'+2y=10x^2 =>y\'+2y/x=10x IF=exp[integral{(2/x)dx}]=exp[2lnx]=x^2 so y\'x^2+2xy=10x^3 =>d(x^2y)/dx=10x^3 =>d(x^2y)=10x^3dx =>yx^2=integral[10x^3dx]=10x^4/4+c =>y=5x^2/2+cx^(-2) y(1)=3 =>5/2+c=3 =>c=3-5/2=1/2 so y=5x^2/2+1/(2x^2) Solution y\'+y=x It is a linear ordinary differential eqn of the Bernouille form. So integrating factor, IF=exp[integral (dx)]=e^x so y\'e^x+ye^x=xe^x =>d(ye^x)/dx=xe^x =>d(ye^x)=xe^xdx Integrating we have ye^x=integral[xe^xdx] =xintegral[e^xdx]-integral[d(x)/dx{integral(e^xdx)}dx] [integrating by parts] =xe^x-integral[1.e^xdx] =xe^x-integral[e^xdx] =xe^x-e^x+c =>y=x-1+ce^(-x) y(0)=2 =>-1+c=2 =>c=3 so y=x+3e^(-x)-1 y\'+y=e^(-x) IF=exp[integral(dx)]=e^x so y\'e^x+ye^x=1 =>d(ye^x)/dx=1 =>d(ye^x)=dx =>ye^x=x+c =>y=xe^(-x)+ce^(-x) y(0)=1 =>c=1 so y=xe^(-x)+e^(-x) =>y=(x+1)e^(-x) xy\'+2y=10x^2 =>y\'+2y/x=10x IF=exp[integral{(2/x)dx}]=exp[2lnx]=x^2 so y\'x^2+2xy=10x^3 =>d(x^2y)/dx=10x^3 =>d(x^2y)=10x^3dx =>yx^2=integral[10x^3dx]=10x^4/4+c =>y=5x^2/2+cx^(-2) y(1)=3 =>5/2+c=3 =>c=3-5/2=1/2 so y=5x^2/2+1/(2x^2).

y+y=x It is a linear ordinary differential eqn of the Bernouille.pdf

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True Since E union Ec is the whole sample space which has probabilit.pdf

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There are many ethical and legal issues surrounding the US human service system. There are many ethical issues faced by social workers which involves legal matters. They have to disclose confidential information about a person according to legal guideline without client\'s consent. Secondly humanitarian ground sometime become above Legal matters it is difficult for them to abide both simultaneously. Solution There are many ethical and legal issues surrounding the US human service system. There are many ethical issues faced by social workers which involves legal matters. They have to disclose confidential information about a person according to legal guideline without client\'s consent. Secondly humanitarian ground sometime become above Legal matters it is difficult for them to abide both simultaneously..

There are many ethical and legal issues surrounding the US human ser.pdf

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The rituals and ceremony that follows the death of a person in order to dispose off the body along with religious fervor is called a funeral. Normally family and friends are the attendees who follow the funerary customs and beliefs based on complex religious practices to remember and respect the dead. Grieving and death rituals vary across cultures and are often heavily influenced by religion (Chachkes & Jennings, 1994; Younoszai, 1993). How and when rituals are practiced vary depending on the country of origin and level of acculturation into the mainstream society. The duration, frequency, and intensity of the grief process may also vary based on the manner of death and the individual family and cultural beliefs (Clements et al., 2003). These rituals give the families and friends a chance to give up the deceased and properly mourn the loss. Common secular motivations for funerals include mourning the deceased, celebrating their life, and offering support and sympathy to the bereaved. Types of funeral rituals based on religions: Assignment topic - Organ donation Organ donation is considered as an honorary way of disposing off a dead body. On deceased donor can save up to eight lives and can save and enhance more than 100 lives through tissue donation. Organs that can be donated after death are the heart, liver, kidneys, lungs, pancreas and small intestines. Tissues include corneas, skin, veins, heart valves, tendons, ligaments and bones. The cornea is the most commonly transplanted tissue. More than 40,000 corneal transplants take place each year in the United States. Most major religions support organ and tissue donation. Typically, religions view organ and tissue donation as acts of charity and goodwill. Costs associated with recovering and processing organs and tissues for transplant are never passed on to the donor family. The family may be expected to pay for medical expenses incurred before death is declared and for expenses involving funeral arrangements. the average North American traditional funeral costs between $7,000 and $10,000. This price range includes the services at the funeral home, burial in a cemetery, and the installation of a headstone. While the cost of organ donation is a widely accepted part of the procedure today, some scholars have analysed the ethical incentives involved in this act rather than its monetary counterpart. There have been instances in the past where the act itself was performed with an altruist motive and the donors were left uncompensated, whether dead or alive. Despite that, there are other ethical incentives apart from a sense of magnanimity that a person feels from organ donation. Board (2002) talks about various forms of such incentives that influence people’s behaviour. A donor medal of honour can be thought of as similar to an award for employee of the month in terms of the satisfaction that it provides to people. Apart from that he also talks about a medical leave for organ donation in order t.

The rituals and ceremony that follows the death of a person in order.pdf

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The primary objective/goal of this paper is to study the effect of wallowing behavior of bisons on the above-ground net primary production (ANPP), plant species richness and diversity and plant life from richness and diversity. Solution The primary objective/goal of this paper is to study the effect of wallowing behavior of bisons on the above-ground net primary production (ANPP), plant species richness and diversity and plant life from richness and diversity..

The primary objectivegoal of this paper is to study the effect of w.pdf

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Symmetry : It is the property where parts of things resembles each other. Bilateral symmetry and radial symmetry are found mostly in animals. Radial symmetry: There is presence of similar body parts that are distributed in circular manner around a central axis e.g. in case of echinoderms and coelenterates .Animals having radial symmetry possess two dorsal and ventral sides instead of right and left sides. Bilateral symmetry: In this case body is divided into two equal parts through central plane. The two equal halves are called right and left e.g. human body which can be divided into two equal parts through sagittal plane. Differences between radial and bilateral symmetry: 1. Radial symmetry possess symmetric axis while as bilateral symmetry has a symmetric plane. 2. In radial symmetry more than two similar portions of the body can be identified while as in bilateral symmetry only two similar portions can be identified. 3. Most of the radially symmetric animals have aquatic habitat while as bilaterally symmetric animals are found in both land and water. 4. Among animals bilateral symmetry is more common as compared to radial symmetry. 5.There is special type of symmetry found in echinoderms known as penta radial symmetry while as bilaterally symmetric animals can be divided in to two parts only. 6. Cnidarians, Echinoderms and unicellular organisms are radially symmetric while as all other phyla in animal kingdom exhibit bilateral symmetry. Solution Symmetry : It is the property where parts of things resembles each other. Bilateral symmetry and radial symmetry are found mostly in animals. Radial symmetry: There is presence of similar body parts that are distributed in circular manner around a central axis e.g. in case of echinoderms and coelenterates .Animals having radial symmetry possess two dorsal and ventral sides instead of right and left sides. Bilateral symmetry: In this case body is divided into two equal parts through central plane. The two equal halves are called right and left e.g. human body which can be divided into two equal parts through sagittal plane. Differences between radial and bilateral symmetry: 1. Radial symmetry possess symmetric axis while as bilateral symmetry has a symmetric plane. 2. In radial symmetry more than two similar portions of the body can be identified while as in bilateral symmetry only two similar portions can be identified. 3. Most of the radially symmetric animals have aquatic habitat while as bilaterally symmetric animals are found in both land and water. 4. Among animals bilateral symmetry is more common as compared to radial symmetry. 5.There is special type of symmetry found in echinoderms known as penta radial symmetry while as bilaterally symmetric animals can be divided in to two parts only. 6. Cnidarians, Echinoderms and unicellular organisms are radially symmetric while as all other phyla in animal kingdom exhibit bilateral symmetry..

Symmetry It is the property where parts of things resembles each o.pdf

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struct procedure { Date dateOfProcedure; int procedureID; int procedureProviderID; }; Data.h #include #include class Date { friend ostream& operator<<( ostream &, const Date & ); // allows easy output to a ostream public: Date( int m = 1, int d = 1, int y = 1900 ); // constructor, note the default values void setDate( int, int, int ); // set the date const Date &operator+=( int ); // add days, modify object bool leapYear( int) const; // is this a leap year? bool endOfMonth( int ) const; // is this end of month? int getMonth ( ) const; int getDay ( ) const; int getYear ( ) const; string getMonthString( ) const; private: int month; int day; int year; static const int days[]; // array of days per month static const string monthName[]; // array of month names void helpIncrement(); // utility function }; #endif Data.cpp // Member function definitions for Date class in separate date.cpp #include #include \"date.h\" #include // Initialize static members at file scope; // one class-wide copy. const int Date::days[] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 }; const string Date::monthName[] = { \"January\", \"February\", \"March\", \"April\", \"May\", \"June\", \"July\", \"August\", \"September\", \"October\", \"November\", \"December\" }; // Date constructor Date::Date(int m, int d, int y) { setDate(m, d, y); } // Set the date void Date::setDate(int mm, int dd, int yy) { month = (mm >= 1 && mm <= 12) ? mm : 1; year = (yy >=1900&& yy <= 2100) ? yy : 1900; // test for a leap year if (month == 2 && leapYear(year)) day = (dd >= 1 && dd <= 29) ? dd : 1; else day =(dd >= 1 && dd <= days[month]) ? dd : 1; } // Add a specific number of days to a date const Date &Date::operator+=(int additionalDays) { for (int i = 0; i < additionalDays; i++) helpIncrement(); return *this; // enables cascading } // If the year is leap year, return true; // otherwise, return false bool Date::leapYear(int testYear) const { if (testYear % 400 == 0 || (testYear %100 != 0 && testYear % 4 == 0)) return true; // a leap year else return false; // not a leap year } // Determine if the day is the end of the month bool Date::endOfMonth(int testDay) const { if (month == 2 && leapYear(year)) return (testDay == 29); // last day of Feb. in leap year else return (testDay == days[month]); } // Function to help increment the date void Date::helpIncrement() { if (!endOfMonth(day)) { // date is not at the end of the month day++; } else if (month < 12) { // date is at the end of the month, but month < 12 day = 1; ++month; } else { // end of month and year: last day of the year day = 1; month = 1; ++year; } } // Overloaded output operator ostream &operator<<(ostream& output, const Date &d) { output << d.monthName[d.month] << \' \' << d.day << \", \"<< d.year; return output; // enables cascading } int Date::getMonth() const // { Public: int month[20]; If(month[]!=”/0”) Cout<<”Enter Month :-<>month; Elseif (month[]<12) { Cout<>month[]; else return month; } int Date::getDay() const // { Pu.

struct procedure { Date dateOfProcedure; int procedureID.pdf

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Slide to depict the basic layout of the pages in the website. Usiing.pdf

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People who are mentally and emotionally healthy haveSolutionP.pdf

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Part A:- iv) Parietal Cells Explanation :- The lining of the stomach is consists of tough, Hydrochloric acid producing cells, which are termed as Parietal cells. Part B :- iv) Colon Explanation :- The large part of Intestine is the colon, which absorbs excess water, salts from the digested food. Part C iv) Bile salts : Bile salts along with monoglycerides of the fats assist the diffusion of fat globules into the intestinal epithelium of the small intestine, so that it forms chylomicrons and transported through ER by the formation of Micelle into Lacteal membrane. Part D iii) Liver This is largest gland in the body, which conisist of storage of majority of nutrients, which supplied into blood. Part E i) Pancreas : The majority of the digestive enzymes like Trypsin, Chymotrypsin, Pancreatic lipase are produced from Pancrease, so this is termed so. Part F iv) D increase surface area and enchance digestion and absorption of nutrients in small intestine. The small intestine consists of many 1,00,000 of small finger like projections called Villi, which increase area of absorption and digestion of the digested food material into blood stream. Solution Part A:- iv) Parietal Cells Explanation :- The lining of the stomach is consists of tough, Hydrochloric acid producing cells, which are termed as Parietal cells. Part B :- iv) Colon Explanation :- The large part of Intestine is the colon, which absorbs excess water, salts from the digested food. Part C iv) Bile salts : Bile salts along with monoglycerides of the fats assist the diffusion of fat globules into the intestinal epithelium of the small intestine, so that it forms chylomicrons and transported through ER by the formation of Micelle into Lacteal membrane. Part D iii) Liver This is largest gland in the body, which conisist of storage of majority of nutrients, which supplied into blood. Part E i) Pancreas : The majority of the digestive enzymes like Trypsin, Chymotrypsin, Pancreatic lipase are produced from Pancrease, so this is termed so. Part F iv) D increase surface area and enchance digestion and absorption of nutrients in small intestine. The small intestine consists of many 1,00,000 of small finger like projections called Villi, which increase area of absorption and digestion of the digested food material into blood stream..

Part A-iv) Parietal CellsExplanation - The lining of the stoma.pdf

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Microplate capture and detection assay is used to detect the specific protein-DNA interactions and identifies the proteins. The method includes immobilization of DNA probes on the surface of microplates (having wells) coated with streptavidin. The cellular extract, prepared in binding buffer, is added for enough time to facilitate binding protein to bind to the oligonucleotide followed by washing of wells several times to remove nonspecifically bound proteins. A protein specific antibody is used for detection of protein. Comparison of advantages and disadvantages of microplate capture and detection assay and EMSA: A: Advantages 1: Microplate capture and detection assay is highly sensitive, fast and throughput technique that is based on ELISA while EMSA is based on comparative velocity of migration of DNA-protein complexes through non denaturing gel electrophoresis. 2: Both techniques can skip the use of radioacitve probes by using biotinylated or fluorescently labeled DNA probes. 3: EMSA uses DNA probe mutational analysis for testing the binding affinity of proteins. 4: Though EMSA can detect the presence of low quantities of DNA binding proteins from lysates, Microplate capture and detection assay can detect even lesser abundance of protein in the well by using with enzyme-labeled antibodies and a chemiluminescent substrate. Disadvantages: 1: Both techniques require supershift antibodies i.e. antibodies which can selectively bind to DNA bound native proteins. 2: The technique gives little information about corresponding changes in transcription factor- DNA. 3: The techniques have been used for a few target proteins so far while EMSA is applicable under in vitro conditions only. Solution Microplate capture and detection assay is used to detect the specific protein-DNA interactions and identifies the proteins. The method includes immobilization of DNA probes on the surface of microplates (having wells) coated with streptavidin. The cellular extract, prepared in binding buffer, is added for enough time to facilitate binding protein to bind to the oligonucleotide followed by washing of wells several times to remove nonspecifically bound proteins. A protein specific antibody is used for detection of protein. Comparison of advantages and disadvantages of microplate capture and detection assay and EMSA: A: Advantages 1: Microplate capture and detection assay is highly sensitive, fast and throughput technique that is based on ELISA while EMSA is based on comparative velocity of migration of DNA-protein complexes through non denaturing gel electrophoresis. 2: Both techniques can skip the use of radioacitve probes by using biotinylated or fluorescently labeled DNA probes. 3: EMSA uses DNA probe mutational analysis for testing the binding affinity of proteins. 4: Though EMSA can detect the presence of low quantities of DNA binding proteins from lysates, Microplate capture and detection assay can detect even lesser abundance of protein in the well by us.

Microplate capture and detection assay is used to detect the specifi.pdf

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C. Amide - Organic functional group found in Nylon D. Amine - Organic functional group found in peptide bonds A. Polyethylene terephtalate - Used to make soda bottles B. High density polyethylene - Used to make milk jugs Solution C. Amide - Organic functional group found in Nylon D. Amine - Organic functional group found in peptide bonds A. Polyethylene terephtalate - Used to make soda bottles B. High density polyethylene - Used to make milk jugs.

C. Amide - Organic functional group found in Nylo.pdf

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H2PO4^-ThereforeP has Oxidation state = +7H has oxidation stat.pdf

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First of all this program has compilation errors. Line 14: Wilma Line 15:Fred, Pebbles, Barney, Bam-Bam, Betty ____________________________________ The Index of the ArrayList Starts from 0 Till line 11, the elements in the Array list are: [Fred, Barney, Wilma, Betty] In line 12,we are adding \"BaM-Bam\" at index 3 [Fred, Barney, Wilma, Bam-Bam, Betty] In Line 13, we are adding \"Pebbles\" at index 1 [Fred, Pebbles, Barney, Wilma, Bam-Bam, Betty] When this statement in the line 14 is executed System.out.println(peopleList.remove(3)); This line will removes And displays Wilma The line 15 will displays the elements in the array list: Fred, Pebbles, Barney, Bam-Bam, Betty In line 17 it is wrong atement.The program wont compile. suppose if it is collections.sort(null) we will get null pointer exception. Then line 19 will not get executed. Solution First of all this program has compilation errors. Line 14: Wilma Line 15:Fred, Pebbles, Barney, Bam-Bam, Betty ____________________________________ The Index of the ArrayList Starts from 0 Till line 11, the elements in the Array list are: [Fred, Barney, Wilma, Betty] In line 12,we are adding \"BaM-Bam\" at index 3 [Fred, Barney, Wilma, Bam-Bam, Betty] In Line 13, we are adding \"Pebbles\" at index 1 [Fred, Pebbles, Barney, Wilma, Bam-Bam, Betty] When this statement in the line 14 is executed System.out.println(peopleList.remove(3)); This line will removes And displays Wilma The line 15 will displays the elements in the array list: Fred, Pebbles, Barney, Bam-Bam, Betty In line 17 it is wrong atement.The program wont compile. suppose if it is collections.sort(null) we will get null pointer exception. Then line 19 will not get executed..

First of all this program has compilation errors.Line 14 WilmaL.pdf

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Code import java.awt.; import javax.swing.; import java.aw.pdf

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C and D. TCP/IP, or Transmission Control Protocol/Internet Protocol, is the basic communication protocol for the Internet and is also used on private networks such as intranets (web environments within a company) or extranets (web environments between two or more business partners or between a vendor and customers). NetBIOS, or Network Basic Input/Output System, is a program that allows computers to communicate on local area networks, or LANs, but does not support transport into wide area networks, or WANs, such as the Internet. Solution C and D. TCP/IP, or Transmission Control Protocol/Internet Protocol, is the basic communication protocol for the Internet and is also used on private networks such as intranets (web environments within a company) or extranets (web environments between two or more business partners or between a vendor and customers). NetBIOS, or Network Basic Input/Output System, is a program that allows computers to communicate on local area networks, or LANs, but does not support transport into wide area networks, or WANs, such as the Internet..

C and D. TCPIP, or Transmission Control ProtocolInternet Protocol,.pdf

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Answer is,D. Greater activation of left hemisphere blood flow.Op.pdf

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Answer : Real Estate Life Cycle is having 3 stages at Universal level i.e. Pre- development stage, Development Stage and Developed stage. 1) Pre development stage - It is stage when the land is raw and there is no structure on it, betting at such location would be risky as defining the value in future is difficult. since the area may be devoid of people but would come in future based on government policies or any other attraction for people to come and live. 2) Development stage - It will come after the area or land has been defined for development, that will attract developers to create buildings or structure and suddenly will shoot the prices of land. 3) Developed stage - When the inventory is ready and it needs to be sold to the buyers, it is the end satge of cycle and everyone can come to get benefit from it. But the pricing are speculative at this stage and based on the supply and demand of the property. Why these are important for investment and finance purpose Pre development stage, it is difficult to predict time taken for its conversion and hence most illiquid stage, buying at this point would be a risk. Development Stage, prediction is easy and developer would gonna sell it may be after development or during construction . So easy to predict but reward may not be that much. Developed stage can be risky as it is based more n speculation, if demand is more investment can be beneficial but if not then it will be a risky investment. Solution Answer : Real Estate Life Cycle is having 3 stages at Universal level i.e. Pre- development stage, Development Stage and Developed stage. 1) Pre development stage - It is stage when the land is raw and there is no structure on it, betting at such location would be risky as defining the value in future is difficult. since the area may be devoid of people but would come in future based on government policies or any other attraction for people to come and live. 2) Development stage - It will come after the area or land has been defined for development, that will attract developers to create buildings or structure and suddenly will shoot the prices of land. 3) Developed stage - When the inventory is ready and it needs to be sold to the buyers, it is the end satge of cycle and everyone can come to get benefit from it. But the pricing are speculative at this stage and based on the supply and demand of the property. Why these are important for investment and finance purpose Pre development stage, it is difficult to predict time taken for its conversion and hence most illiquid stage, buying at this point would be a risk. Development Stage, prediction is easy and developer would gonna sell it may be after development or during construction . So easy to predict but reward may not be that much. Developed stage can be risky as it is based more n speculation, if demand is more investment can be beneficial but if not then it will be a risky investment..

Answer Real Estate Life Cycle is having 3 stages at Universal leve.pdf

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2002ASolution2002A.pdf

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1.static int HORIZONTAL_WRAP 2. Container view controllers are most often used to facilitate navigation and to create new user interface types based on existing content. Examples of container view controllers in UIKit includeUINavigationController, UITabBarController, and UISplitViewController, all of which facilitate navigation between different parts of your user interface. 3. Andoid supports .png(preferred),.jpg(accepteble),.gif(discouraged) 4.Each element in an array is called an Element 5.For Eclipse, typically all you need to do is set up a folder somewhere within your source code directory. For instance, if the directory containing your source is /src then you can create a /src/resources folder to place your images/files in. Then, within your class you do a getResource(\"/resources/image.png\") to retrieve it. 6.Native apps have the ability to use device-specific hardware and software, meaning that native apps can take advantage of the latest technology available on mobile devices such as a global positioning system (GPS) and camera. The main similarity is that both emulated mobile apps and Web apps run on servers external to the mobile device and require the use of a browser on the mobile device to display and then use the app user interface (UI). 7.Marshmallow 6.0-6.0.1 8.This ColorModel class supports two representations of pixel values. A pixel value can be a single 32-bit int or an array of primitive types. 9.By changing the android:label field in your application node in AndroidManifest.xml. 10.\"android:layout_span” to span view in 2 cells, and “android:layout_column” to display the view in specified column. 11.1.ListActivity.java 2.activity__twopane.xml 3.activity__list.xml 4.ListFragment.java 5.DetailActivity.java 13. 14.A dp is a density-independent pixel that corresponds to the physical size of a pixel at 160 dpi. An sp is the same base unit, but is scaled by the user\'s preferred text size (it\'s a scale- independent pixel), so you should use this measurement unit when defining text size (but never for layout sizes). 15.Tween animation calculates the animation with information such as the start point, end point, size, rotation, and other common aspects of an animation. 16.Setting a View\'s size to wrap_content will force it to expand only far enough to contain the values (or child controls) it contains. For controls -- like text boxes (TextView) or images (ImageView) -- this will wrap the text or image being shown. For layout elements it will resize the layout to fit the controls / layouts added as its children. 17.An animation defined in XML that modifies properties of the target object, such as background color or alpha value, over a set amount of time. 18.9-patch image Solution 1.static int HORIZONTAL_WRAP 2. Container view controllers are most often used to facilitate navigation and to create new user interface types based on existing content. Examples of container view controllers in UIKit includeUINavigationController.

1.static int HORIZONTAL_WRAP2. Container view controllers are most.pdf

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