hypochlorous acid,[H+]=Ka*c =3.5*10^-5*0.0428 =1.22*10^-3M POH=-log(M1V1-M2V2)/(V1+V2) =-log(0.0117*50-1.22*10^-3*50)/(50+50) =-log(5.24*10^-3)=2.281 PH=14-2.281=11.72 Solution hypochlorous acid,[H+]=Ka*c =3.5*10^-5*0.0428 =1.22*10^-3M POH=-log(M1V1-M2V2)/(V1+V2) =-log(0.0117*50-1.22*10^-3*50)/(50+50) =-log(5.24*10^-3)=2.281 PH=14-2.281=11.72.