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Step1 pH =2 ; [H+] = 1 x10^-2 moleslitre Step2 .pdf

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Step1 pH =2 ; [H+] = 1 x10^-2 moles/litre Step2 pH=4 ; [H+] = 1x10^-4 moles/litre Step3 Useing M1 V1 =M2V2 ; V2 = 11.6 x [1x10^-2]/[1x10^-4] = 1160 ml Step4 Volume of water added = 1160 - 11.6 = 1148.4 ml Solution Step1 pH =2 ; [H+] = 1 x10^-2 moles/litre Step2 pH=4 ; [H+] = 1x10^-4 moles/litre Step3 Useing M1 V1 =M2V2 ; V2 = 11.6 x [1x10^-2]/[1x10^-4] = 1160 ml Step4 Volume of water added = 1160 - 11.6 = 1148.4 ml.

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Step1 pH =2 ; [H+] = 1 x10^-2 moles/litre Step2 pH=4 ; [H+] = 1x10^-4 moles/litre Step3 Useing M1 V1 =M2V2 ; V2 = 11.6 x [1x10^-2]/[1x10^-4] = 1160 ml Step4 Volume of water added = 1160 - 11.6 = 1148.4 ml Solution Step1 pH =2 ; [H+] = 1 x10^-2 moles/litre Step2 pH=4 ; [H+] = 1x10^-4 moles/litre Step3 Useing M1 V1 =M2V2 ; V2 = 11.6 x [1x10^-2]/[1x10^-4] = 1160 ml Step4 Volume of water added = 1160 - 11.6 = 1148.4 ml

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Step1 pH =2 ; [H+] = 1 x10^-2 moleslitre Step2 .pdf

  • 1. Step1 pH =2 ; [H+] = 1 x10^-2 moles/litre Step2 pH=4 ; [H+] = 1x10^-4 moles/litre Step3 Useing M1 V1 =M2V2 ; V2 = 11.6 x [1x10^-2]/[1x10^-4] = 1160 ml Step4 Volume of water added = 1160 - 11.6 = 1148.4 ml Solution Step1 pH =2 ; [H+] = 1 x10^-2 moles/litre Step2 pH=4 ; [H+] = 1x10^-4 moles/litre Step3 Useing M1 V1 =M2V2 ; V2 = 11.6 x [1x10^-2]/[1x10^-4] = 1160 ml Step4 Volume of water added = 1160 - 11.6 = 1148.4 ml