(a) NaCl is an ionic compound. The intermolecular forces are electro.pdf

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(a) NaCl is an ionic compound. The intermolecular forces are electrostatic interactions. (b) CCl4 is a non-polar molecular compound. The intermolecular forces are London dispersion forces. (c) CHCl3 is a polar molecular compound. The intermolecular forces are dipole-dipole interactions and London dispersion forces. (d) C(diamond) is a covalent solid. The intermolecular forces are covalent bonds. (e) Au is a metallic solid. The intemolecular interactions are metallic bonds. Solution (a) NaCl is an ionic compound. The intermolecular forces are electrostatic interactions. (b) CCl4 is a non-polar molecular compound. The intermolecular forces are London dispersion forces. (c) CHCl3 is a polar molecular compound. The intermolecular forces are dipole-dipole interactions and London dispersion forces. (d) C(diamond) is a covalent solid. The intermolecular forces are covalent bonds. (e) Au is a metallic solid. The intemolecular interactions are metallic bonds..

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Earth Science Worksheet Chapter 2 1. Which of the following is a mineral as defined by a geologist? a) Boulder b) Concrete c) Sugar d) Salt e) Water 2. Why are boulders not a mineral? a) They are not naturally occurring b) They are organic c) They are not solid d) They do not have an orderly crystalline structure e) They do not have a well-defined chemical composition 3. What determines the physical and chemical properties of an atom? a)The type of bonds b)The number of electrons c)The number of protons d)The number of neutrons e)The isotopic ratio 4. One significant difference between an ionic bond, where electrons are taken from one atom and added to another atom and a covalent or metallic bond where electrons are shared is ___________. a) ionic bonds are stronger than covalent or metallic bonds b) Ionic bonds produce ions but covalent and metallic bonds do not produce ions c) Ionic bonds make a material more malleable than covalent and metallic bonds d) Ionic bonds do not result in the attraction of oppositely charged atoms but covalent and metallic bonds do 5. What is the most abundant element found near the surface of Earth? a) Potassium b) Silicon c) Calcium d) Oxygen e) Hydrogen 6. What do the minerals gold, sulfur, and copper have in common? a) Covalent bonds b) They have the same density and hardness c) They are each composed of a single element d) They all transmit electricity easily because of their bonds 7. The silicon-oxygen tetrahedran, the most fundamental basis for forming minerals, contains: a) Four oxygen atoms and one silicon atom b) Four silicon atoms and one oxygen atom c) Three silicon atoms and one oxygen atom d) One silicon atom, one oxygen atom, one iron atom, and one magnesium atom 8. Which group does feldspar, one of the most common minerals near the surface of Earth, belong to? a) Carbonates b) Oxides c) Silicates d) Evaporates e) Sulfides 9. The definition of an ore deposit depends greatly on ___________ and ___________. a) The presence of metallic bonds and concentration of the mineral b) The presence of metallic bonds and the economics of recovering the mineral c) The concentration of the mineral and the location of the deposit d) The economics of recovering the mineral and the concentration of the deposit 10. The strong tendency of certain minerals to break along smooth, parallel planes is known as_________. a) crystal form b) cracking luster c) streak d) cleavage 11. An atom’s mass number is 13 and its atomic number is 6. How many neutrons are in its nucleus? a) 7 b) 6 c) 13 d) 19 12. The ion at the center of a silicon-oxygen tetrahedron is surrounded by_____. a) four sodium atoms b) four oxygen atoms c) six oxygen atoms d) six sodium ions 13. Atoms of the same element, zinc for example, have the same number of ________. a) neutrons in the outer nuclear shell b) protons in the nucleus c) electrons in the valence bond level d) electrons in the nucleus 14. Wh.

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I think you are missing an S species in the first equation. Are you trying to from H2SO4 and not H2O on the right side? 1) I2 + H2SO3 +H2O => 2HI + H2SO4 I2 is neutral; IN HI, I becomes I- (I is more electronegative than H); I is reduced S starts as the sulfite ion [SO3]2-. O has -2 charge. so S_charge + 3*(-2) = -2. S_charge = +4. In H2SO4, S is [SO4]2-. S_charge + 4*(-2) = -2; S_charge = +6 Sulfur is oxidized 2) C + 4HNO3 -> CO2 + 4NO2 + 2H2O C is oxidized from 0 to +4 in CO2 N is reduced from +5 in HNO3 to +4 in NO2 (use the same method as previous; in HNO3; [NO3]- because H is +1; N_charge + 3*-2 = -1; N_charge is +5. for NO2; N_charge + 2*-2 = 0 (neutral); N_charge = +4 3) 2FeCl3 + H2S => 2FeCl2 + 2HCl + S S exists as -2 in H2S, and becomes 0 in S; it is oxidized (it has lost 2 electrons) Fe exists as +3 in FeCl3 (Cl as Cl-) and becomes +2 in FeCl2; it is reduced (gains 1 electrons) Solution I think you are missing an S species in the first equation. Are you trying to from H2SO4 and not H2O on the right side? 1) I2 + H2SO3 +H2O => 2HI + H2SO4 I2 is neutral; IN HI, I becomes I- (I is more electronegative than H); I is reduced S starts as the sulfite ion [SO3]2-. O has -2 charge. so S_charge + 3*(-2) = -2. S_charge = +4. In H2SO4, S is [SO4]2-. S_charge + 4*(-2) = -2; S_charge = +6 Sulfur is oxidized 2) C + 4HNO3 -> CO2 + 4NO2 + 2H2O C is oxidized from 0 to +4 in CO2 N is reduced from +5 in HNO3 to +4 in NO2 (use the same method as previous; in HNO3; [NO3]- because H is +1; N_charge + 3*-2 = -1; N_charge is +5. for NO2; N_charge + 2*-2 = 0 (neutral); N_charge = +4 3) 2FeCl3 + H2S => 2FeCl2 + 2HCl + S S exists as -2 in H2S, and becomes 0 in S; it is oxidized (it has lost 2 electrons) Fe exists as +3 in FeCl3 (Cl as Cl-) and becomes +2 in FeCl2; it is reduced (gains 1 electrons).

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Until 2001, the 40-year-old Halamka also worked as an emergency room physician, but he gave that up to take on the additional responsibilities of being CIO of Harvard Medical School in 2002. Two months later, Beth Israel Deaconess experienced one of the worst health-care IT disasters ever. Over four days, Halamka’s network crashed repeatedly, forcing the hospital to revert to the paper patient-records system that it had abandoned years ago. Lab reports that doctors normally had in hand within 45 minutes took as long as five hours to process. \"Everything’s the Web,\" Halamka says now. \"If you don’t have the Web, you’re down.\" Hospitals come alive early. By 7 a.m., doctors and nurses started to send some of Beth Israel Deaconess’s 100,000 daily e-mails. The pharmacy began filling prescriptions, transferring the first bits of the 40 terabytes that traverse the network daily. Some of the 3,000 daily lab reports were beginning to move. By 8 a.m., the network again started acting as if it were flying into a headwind. Halamka realized the network had settled down the night before only because hardly anyone was using it. When the workday began in earnest, CPU usage spiked. The network started flapping. The problem hadn’t been fixed. Halamka’s team scrambled to find other possible sources of the trouble. One suspect was CareGroup’s network of outlying hospitals in Cambridge, Needham, Ayer and elsewhere in Massachusetts. They operated as a distinct network that plugged into Beth Israel Deaconess. The community hospitals’ network was sluggish, and a billing application wasn’t working, according to Jeanette Clough, CEO of Mount Auburn Hospital in Cambridge, which serves as the hub for the outlying hospitals’ network. To fix the problem, the CAP team decided to put a Cisco 6509 router between the core network and PACS, eliminating spanning tree protocol and its seven-hop limitation. (The 6509 also has switching capabilities, so the team decided to kill three switches inside PACS and use the 6509 for that too.) At noon, Epstein came in to lend a hand...and walked into 1978. Epstein worked the copier, then sorted a three-inch stack of microbiology reports and handed them to runners who took them to patients’ rooms where they were left for doctors. (There were about 450 patients at the hospital.) In time, the chaos gave way to a loosely defined routine, which was slower than normal and far more harried. The pre-IT generation, Sands says, adapted quickly. For the IT generation, himself included, it was an unnerving transition. He was reminded of a short story by the Victorian author E.M. Forster, \"The Machine Stops,\" about a world that depends upon an Ÿber-computer to sustain human life. Eventually, those who designed the computer die and no one is left who knows how it works. \"We depend upon the network, but we also take it for granted,\" Sands says. \"It’s a credit to [Halamka] that we operate with a mind-set that the computers never go down. And that.

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The Final Accounts of non-trading concerns consists of: 1. Receipts and Payments Account 2. Income and Expenditure Account, and 3. Balance Sheet. 1. Receipts and Payments Account: It is a Real Account. It is a consolidated summary of Cash Book. It is prepared at the end of the accounting period. All cash receipts are recorded on the debit side and all cash payments are recorded on the credit side. Cash Book consisting of entries of receipts and payments in a chronological order while the Receipts and payments is a summary of total cash receipts and cash payments. It starts with opening balance of Cash and Bank and ends with closing balance of Cash and Bank. It does not take into account outstanding amounts of receipts and payments. Receipts and Payments may be of Capi tal or Revenue nature; they may relate to the current or previous year or subsequent year; so long as they are actually received or paid, they must appear in this account. Features of Receipts and Payment Account, In Brief: 1. It starts with opening balance and ends with closing balance 2. It is the summary of cash and bank transactions. 3. Actual cash transactions are entered. 4. It includes capital as well as revenue items. 5. It follows cash system of accounting 6. It shows cash position and excludes all non-cash items. 7. It is a real account. 8. It does not take any income/expense outstanding at the beginning or at the end. 2. Income and Expenditure Account: It is a Nominal Account. It is in the form of Profit and Loss Account. It is concerned with only revenue items—expenses and incomes. It records all losses and expenses on its debit side and all incomes and gains on its credit side. Of the incomes and expenses of revenue nature, only the portion pertaining to the current year is shown in the Income and Expenditure Account i.e. amount relating to the previous year or future year are excluded. Again, the incomes and expenses of current year, whether received or not, must be shown. In other words, incomes and expenses have to be adjusted for both out-standing and pre- payments. All non-cash items, Depreciation, Bad Debts, Provision for Doubtful Debts etc. are taken into account. The difference between the debit side and the credit side is either surplus or deficit for the year concerned and the difference will be transferred to the Capital Fund (also called General Fund or Accumulated Fund) appearing in Balance Sheet. Features of Income and Expenditure Account, In Brief: 1. It is prepared in lieu of Profit and Loss Account. 2. It is a nominal account. 3. It is based on mercantile system of accounting. 4. There is no opening balance. 5. It ends with Surplus or Deficit. 6. It excludes all capital income and capital expenses. 7. It includes only revenue items. 8. It records all expenses whether paid or not, and all incomes whether received or not. 3. Balance Sheet: Balance Sheet in case of non-trading concern is prepared in the usual manner and consists of all liabilities and .

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sickel cell anemia is caused by recessive allele. frequency of sickel cell allele is 0.1. according to Hardy-Weinberg law frequency of sickel cell allele (Recessive allele) (ss) = 0.1 = q2 q = square root of 0.1 = 0.316 then p = 1 - q = 1 - 0.316 = 0.684 p = frequency of healthy allele = 0.684 Frequency of healthy allele = 0.684 2.Ans. how many people in a population of 10,000 will have sickel cell anemia. sickel cell anemia (ss) = (0.316)(0.316)(10,000) = 999 people have sickel cell anemia. 3.Ans. how many people in a population of 10,000 will be sickel cell carriers. sickel cell carriers (Ss) = 2pq = 2 (0.316)(0.684)(10,000) = 4323 people are sickel cell carriers 4.Ans. mutations occurs and new allele introduced into the population. small population which causes genetic drift. the above TWO conditions we would NOT expect Hardy-Weinberg equlibrium to be maintained. 3. Alkaptonuria caused by recessive allele. survey revels that 5 in 50 people have Alkaptonuria a. if a population of 50 people if is caused by Recessive allele and 5 in 50 people have Alkaptonuria = q2 is 5/50 or 0.1 q2 = 0.1 then q = square root of 0.1 = 0.316 q = 0.316 p = 1 - q =0.684 p = 0.684 b. Heterozygous to Alkaptonuria = 2pq 2pq = 2(0.684) (0.316) (50) = 22 people are Hetrozygous for Alkaptonuria Allele C. Homozygous Dominant = AA =p2 AA = (0.684)(0.684)(50) = 23 people have Heterozygous Dominant Solution sickel cell anemia is caused by recessive allele. frequency of sickel cell allele is 0.1. according to Hardy-Weinberg law frequency of sickel cell allele (Recessive allele) (ss) = 0.1 = q2 q = square root of 0.1 = 0.316 then p = 1 - q = 1 - 0.316 = 0.684 p = frequency of healthy allele = 0.684 Frequency of healthy allele = 0.684 2.Ans. how many people in a population of 10,000 will have sickel cell anemia. sickel cell anemia (ss) = (0.316)(0.316)(10,000) = 999 people have sickel cell anemia. 3.Ans. how many people in a population of 10,000 will be sickel cell carriers. sickel cell carriers (Ss) = 2pq = 2 (0.316)(0.684)(10,000) = 4323 people are sickel cell carriers 4.Ans. mutations occurs and new allele introduced into the population. small population which causes genetic drift. the above TWO conditions we would NOT expect Hardy-Weinberg equlibrium to be maintained. 3. Alkaptonuria caused by recessive allele. survey revels that 5 in 50 people have Alkaptonuria a. if a population of 50 people if is caused by Recessive allele and 5 in 50 people have Alkaptonuria = q2 is 5/50 or 0.1 q2 = 0.1 then q = square root of 0.1 = 0.316 q = 0.316 p = 1 - q =0.684 p = 0.684 b. Heterozygous to Alkaptonuria = 2pq 2pq = 2(0.684) (0.316) (50) = 22 people are Hetrozygous for Alkaptonuria Allele C. Homozygous Dominant = AA =p2 AA = (0.684)(0.684)(50) = 23 people have Heterozygous Dominant.

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ConvertingSeconds.java import java.util.Scanner; public class ConvertingSeconds { public static void main(String[] args) { //Declaring variables int fromseconds,hours,minutes,seconds,toSeconds; //Scanner class Object is used to read the inputs entered by the user Scanner sc=new Scanner(System.in); //getting the number of seconds entered by the user System.out.print(\"Enter Total Number of Seconds :\"); fromseconds=sc.nextInt(); //calling the method secondTime() by passing the seconds as arguments String str=secondTime(fromseconds); //Converting the string to String array where \',\' is the delimeter String arr[]=str.split(\",\"); //Converting the String into integer hours=Integer.parseInt(arr[0]); minutes=Integer.parseInt(arr[1]); seconds=Integer.parseInt(arr[2]); //calling the method inSeconds by passing the hours,minutes,seconds as arguments toSeconds=inSeconds(hours,minutes,seconds); //Displaying the hours,minutes,seconds to seconds System.out.println(hours+\" hours \"+minutes+\" minutes \"+seconds+\" seconds corresponds to \"+toSeconds+\" seconds\"); } /*This method will converts the hours,minutes,seconds to seconds * Params:hours,minutes,seconds * Return:totalSeconds */ private static int inSeconds(int hours, int minutes, int seconds) { //Converting the hours,minutes and seconds to totalseconds int totSeconds=hours*3600+minutes*60+seconds; return totSeconds; } /*This method will converts the seconds to hours,minutes,seconds * Params:total Seconds * Return:String */ private static String secondTime(int totseconds) { //Declaring variable int secs=totseconds; //calculating the number of hours int hours=totseconds/3600; totseconds=totseconds-(hours*3600); //calculating the number of minutes int minutes=totseconds/60; totseconds=totseconds-(minutes*60); //Calculating the number of seconds int seconds=totseconds; //displaying the total seconds to hours,minutes,seconds System.out.println(secs+\" Seconds corresponds to \"+hours+\" hours \"+minutes+\" minutes \"+seconds+\" seconds\"); return hours+\",\"+minutes+\",\"+seconds; } } _____________________________________________ Output: Enter Total Number of Seconds :10000 10000 Seconds corresponds to 2 hours 46 minutes 40 seconds 2 hours 46 minutes 40 seconds corresponds to 10000 seconds _____________________________________________ Output1: Enter Total Number of Seconds :15000 15000 Seconds corresponds to 4 hours 10 minutes 0 seconds 4 hours 10 minutes 0 seconds corresponds to 15000 seconds _________________________________________Thank You Solution ConvertingSeconds.java import java.util.Scanner; public class ConvertingSeconds { public static void main(String[] args) { //Declaring variables int fromseconds,hours,minutes,seconds,toSeconds; //Scanner class Object is used to read the inputs entered by the user Scanner sc=new Scanner(System.in); //getting the number of seconds entered by the user System.out.print(\"Enter Total Number of Seconds :\"); fromseconds=sc.nextInt(); //calling the method seco.

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Before Attempting to measure risk aversion, following two factors should be considered: 1 ) Estimating probabilities: It includes measuring the future events based on their possibility of occurrence. generally, the Probabilities are assigned based on past experiences. 2) Life tables and estimates: it includes the estimation of the amount of risk undertaken by the investors in their previous investment. By looking at their investment history and analyzing behavior, this table can be prepared. Solution Before Attempting to measure risk aversion, following two factors should be considered: 1 ) Estimating probabilities: It includes measuring the future events based on their possibility of occurrence. generally, the Probabilities are assigned based on past experiences. 2) Life tables and estimates: it includes the estimation of the amount of risk undertaken by the investors in their previous investment. By looking at their investment history and analyzing behavior, this table can be prepared..

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Answer: The general circumstance for retaining outside experts is where the auditor requires a special skill or knowledge outside of accounting or auditing, the auditors feel they do not have the level of expertise, or they may want an additional opinion. PCAOB interim Using the Work of a Specialist provides guidance and recognizes that auditors are not expected to be experts in all areas, auditors may encounter material matters which are complex or subjective, and an auditor may use the work of a specialist as evidential matter to evaluate financial statement assertions (PCAOB AU 336, 2010). In the case of auditing pensions, the auditors would most likely use an actuary as a specialist as the auditors would not be expected to have that level of expertise. The actuary would be knowledgeable of the entire pension development process and be able to more quickly comprehend the nuances of the actuarial assumptions and mechanics of the calculations. For example, some of the tasks that the actuary would be involved with the company on for pensions includes the measurement of pension obligations, assignment of plan obligations to time periods, development of a cost allocation procedure, development of a contribution allocation procedure, determination of types and levels of benefits, projection of pension obligations, projection of plan costs or contributions (AAA, 2010). Much of the financial impact of pensions is based on going from current known data (number employees, salaries, etc.) through a number of assumptions (how many years work, how many years collect a pension, mortality rates, what rate able to invest funds at, etc.) to develop the most likely funding needs over time to provide the retirement benefits as agreed to cover the pension expenses. Outside of determining the current employees, salaries, etc., almost everything else is an assumption. How do we make the most appropriate and best assumption to ensure having dollars available in the future? How much do we need to put aside now that will grow and cover the pension requirements? This is where the audit firm should employ an actuary to examine the actuarial-type assumptions made by the company on its employees and current retirees to see if they are reasonable assumptions given the company’s data. The actuary would be able to help examine the pension plan assets, the investments, the effective earning rates from the investments (in comparison to the discount rate being used), the projected pension expenses, and the resultant pension plan funding situation. The actuary’s review should be able to assist the auditor in identifying potential issue areas for the auditor’s further examination. Solution Answer: The general circumstance for retaining outside experts is where the auditor requires a special skill or knowledge outside of accounting or auditing, the auditors feel they do not have the level of expertise, or they may want an additional opinion. PCAOB interim Using the Work of a S.

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Ans: Consolidated financial statements are the aggregated or combined figure of statements between a parent company and its subsidiaries. Consolidated balance sheet As on 31/12/2020 Assets P S Total Current assets: Cash 70,000 28,000 98,000 Accounts receivable 210,000 224,000 434,000 Inventory 252,000 140,000 392,000 532,000 392,000 924,000 Noncurrent assets: Land 140,000 -- 140,000 Equipment 7,000,000 3,780,000 10,780,000 Amortization, equipment (2,478,000) (1,736,000) (4,214,000) Investment in S 1,120,000 -- 1,120,000 5,782,000 2,044,000 7,826,000 Total assets 6,314,000 2,436,000 8,750,000 Liabilities and shareholders equity: Current liabilities: Accounts payable 630,000 280,000 910,000 Noncurrent liabilities: Loan payable 420,000 700,000 1,120,000 1,050,000 980,000 2,030,000 Shareholders equity: Share capital 1,680,000 420,000 2,100,000 Retained earnings 3,584,000 1,036,000 4,620,000 5,264,000 1,456,000 6,720,000 6,314,000 2,436,000 8,750,000 Consolidated income statement For the year ended 31/12/2020 Particulars P S Total Revenue: Sales 2,804,200 2,100,000 4,904,200 Royalties 210,000 -- 210,000 Dividends 100,800 -- 100,800 3,115,000 2,100,000 5,215,000 Expenses: Cost of sales 1,680,000 1,260,000 2,940,000 Other 784,000 575,400 1,359,400 2,464,000 1,835,400 4,299,400 Net income 651,000 264,600 915,600 Retained earnings statement For the year ended 31/12/2020 P S Total Opening retained earnings 3,353,000 897,400 4,250,400 Net income 651,000 264,600 915,600 Dividends declared (420,000) (126,000) (546,000) Closing retained earnings 3,584,000 1,036,000 4,620,000 Figures are added. P + S = Total. Assets P S Total Current assets: Cash 70,000 28,000 98,000 Accounts receivable 210,000 224,000 434,000 Inventory 252,000 140,000 392,000 532,000 392,000 924,000 Noncurrent assets: Land 140,000 -- 140,000 Equipment 7,000,000 3,780,000 10,780,000 Amortization, equipment (2,478,000) (1,736,000) (4,214,000) Investment in S 1,120,000 -- 1,120,000 5,782,000 2,044,000 7,826,000 Total assets 6,314,000 2,436,000 8,750,000 Liabilities and shareholders equity: Current liabilities: Accounts payable 630,000 280,000 910,000 Noncurrent liabilities: Loan payable 420,000 700,000 1,120,000 1,050,000 980,000 2,030,000 Shareholders equity: Share capital 1,680,000 420,000 2,100,000 Retained earnings 3,584,000 1,036,000 4,620,000 5,264,000 1,456,000 6,720,000 6,314,000 2,436,000 8,750,000 Solution Ans: Consolidated financial statements are the aggregated or combined figure of statements between a parent company and its subsidiaries. Consolidated balance sheet As on 31/12/2020 Assets P S Total Current assets: Cash 70,000 28,000 98,000 Accounts receivable 210,000 224,000 434,000 Inventory 252,000 140,000 392,000 532,000 392,000 924,000 Noncurrent assets: Land 140,000 -- 140,000 Equipment 7,000,000 3,780,000 10,780,000 Amortization, equipment (2,478,000) (1,736,000) (4,214,000) Investment in S 1,120,000 -- 1,120,000 5,782,000 2,044,000 7,826,000 Total assets 6,314,000 2,436,00.

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