eOverride - Return the number of elenents in this list -- public int.docx
•Download as DOCX, PDF•
0 likes•2 views
The document describes operations performed on a linked list data structure. It creates a linked list with 1 element, adds 4 more elements, adds 4 more to the front of the list, prints the list and size, then removes the last 3 elements and prints the list, head, tail, and size.
Report
Share
Report
Share
![eOverride / Return the number of elenents in this list */ public int size() f } return size; public
static void main(String[] args) & I/ Create a list var gyLinkedList = new MyLinkedListeinteger
> ( 1 ) //add 4 elements for (int 1 = 1 ; 1 < 5 ; 1 + + ) t myLinkedist.add(1); size: + +
nyLinkedlist.s1ze + "(n") //add 4 more in tront of the list for ( int 1 = 1 ; 1 < 5 : 1 + 4 ) {
myLinkedList, oddFirst (10+1): Systen, out,print ln("List after modifieation " + myLinkedList +
") size: " + nyLinkedList.size + " ( n ) : // remove 3 last elenents for ( int 1 = 0 ; 1 < 3 ; 1 + t ) <
yylinkedList, renoveLast (): System, out.printin("List after renoval: " + mylinkedList + ".) head
elenent = + eytinkedist, head, elewent + tall elenent next, +((erlinkedlist, tail, next I nutl)r
ayLinkedList, tail, next, elenent, tostring(): "nuLl") , stzee "+ myLinkedList.s1ze + "(n")s](https://image.slidesharecdn.com/eoverride-returnthenumberofelenentsinthislist-publicint-230221010742-4e26d21a/85/eOverride-Return-the-number-of-elenents-in-this-list-public-int-docx-1-320.jpg)
Recommended
Hi,I have added the methods and main class as per your requirement.pdf
Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2: The Methods (65 points) Implement all the methods that are marked as Left as
Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
2.(Sorted list array implementation)This sorted list ADT discussed .pdf
2.(Sorted list: array implementation)This sorted list ADT discussed in class should be extended
by the addition of two new methods:
//Interface: ArrayListADT
//works for int
public interface ArrayListADT {
public boolean isEmpty(); //Method to determine whether the list is empty.
public boolean isFull(); //Method to determine whether the list is full.
public int listSize(); //Method to return the number of elements in the list.
public int maxListSize(); //Method to return the maximum size of the list.
public void print(); //Method to output the elements of the list.
public boolean isItemAtEqual(int location, int item); //Method to determine whether item is
the same as the item in the list at location.
public void insertAt(int location, int insertItem); //Method to insert insertItem in the list at
the position
public void insertEnd(int insertItem); //Method to insert insertItem at the end of the list.
public void removeAt(int location); //Method to remove the item from the list at location.
public int retrieveAt(int location); //Method to retrieve the element from the list at location.
public void replaceAt(int location, int repItem); //Method to replace the element in the list at
location with repItem.
public void clearList(); //Method to remove all the elements from the list.
public int search(int searchItem); //Method to determine whether searchItem is in the list.
public void remove(int removeItem); //Method to remove an item from the list.
}
//Class: ArrayListClass implements
//Interface: ArrayListADT
public abstract class ArrayListClass implements ArrayListADT {
protected int length; //to store the length of the list
protected int maxSize; //to store the maximum size of the list
protected int[] list; //array to hold the list elements
//Default constructor
public ArrayListClass() {
maxSize = 100;
length = 0;
list = new int[maxSize];
}
//Alternate Constructor
public ArrayListClass(int size) {
if(size <= 0) {
System.err.println(\"The array size must be positive. Creating an array of size 100.\");
maxSize = 100;
}
else
maxSize = size;
length = 0;
list = new int[maxSize];
}
public boolean isEmpty() {
return (length == 0);
}
public boolean isFull() {
return (length == maxSize);
}
public int listSize() {
return length;
}
public int maxListSize() {
return maxSize;
}
public void print() {
for (int i = 0; i < length; i++)
System.out.print(list[i] + \" \");
System.out.println();
}
public boolean isItemAtEqual(int location, int item) {
if (location < 0 || location >= length) {
System.err.println(\"The location of the item to be compared is out of range.\");
return false;
}
return list[location]== item;
}
public void clearList() {
for (int i = 0; i < length; i++)
list[i] = 0;
length = 0;
System.gc(); //invoke the Java garbage collector
}
public void removeAt(int location) {
if (location < 0 || location >= length)
System.err.println(\"The location of the item to be removed is out of range.\");
else {
for(int i = location; i < length - 1; i++)
list[i] .
public class MyLinkedListltE extends ComparableltEgtg.pdf
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Increase size
}
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node<E> current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node<E> temp = current.next;
current.next = new Node<>(e);
(current.next).next = temp;
size++;
}
}
//Add e to the end of this linkedlist
public void add(E e) {
// Left as Exercise
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
E temp = head.element;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return temp;
}
}
/** Remove the last node and
* return the object that is contained in the removed node. */
public E removeLast() {
if (size == 0) {
return null;
}
else if (size == 1) {
E temp = head.element;
head = tail = null;
size = 0;
return temp;
}
else {
Node<E> current = head;
for (int i = 0; i < size - 2; i++) {
current = current.next;
}
E temp = tail.element;
tail = current;
tail.next = null;
size--;
return temp;
}
}
/** Remove the element at the specified position in this
* list. Return the element that was removed from the list. */
public E remove(int index) {
if (index < 0 || index >= size) {
return null;
}
else if (index == 0) {
return removeFirst();
}
else if (index == size - 1) {
return removeLast();
}
else {
Node<E> previous = head;
for (int i = 1; i < index; i++) {
previous = previous.next;
}
Node<E> current = previous.next;
previous.next = current.next;
size--;
return current.element;
}
}
/** Clear the list */
public void clear() {
size = 0;
head = tail = null;
}
/** Override toString() to return elements in the list in [] separated by , */
public String toString() {
StringBuilder result = new StringBuilder("[");
Node<E> current = head;
for (int i = 0; i < size; i++) {
result.append(current..
import java.util.LinkedList; import java.util.Random; import jav.pdf
import java.util.LinkedList;
import java.util.Random;
import java.util.Scanner;
/**
* author
*
*/
public class LinkedListTest {
/**
* param args
*/
public static void main(String[] args) {
int M, N, Lower, Upper;
Scanner scanner = null;
try {
LinkedList list1 = new LinkedList();
LinkedList list2 = new LinkedList();
LinkedList list3 = new LinkedList();
Random random = new Random();
scanner = new Scanner(System.in);
System.out.print(\"Enter the Lower and Upper bounds:\");
Lower = scanner.nextInt();
Upper = scanner.nextInt();
System.out.print(\"Enter the N value to Insert list1:\");
N = scanner.nextInt();
System.out.print(\"Enter the M value to Insert list2:\");
M = scanner.nextInt();
for (int i = 1; i <= N; i++) {
list1.add(random.nextInt((Upper - Lower) + 1) + Lower);
}
for (int i = 1; i <= M; i++) {
list2.add(random.nextInt((Upper - Lower) + 1) + Lower);
}
System.out.println(\"list1: \" + list1);
System.out.println(\"list2: \" + list2);
System.out.println(\"Minimum elelment in list1 :\" + getMin(list1));
System.out.println(\"Minimum elelment in list2 :\" + getMin(list2));
System.out
.println(\"Count Divisibles by 3 and 5 elelment in list1 :\"
+ countDivisibles(list1));
System.out
.println(\"Count Divisibles by 3 and 5 elelment in list2 :\"
+ countDivisibles(list2));
System.out.println(\"Common Elements From list1 and list2:\"
+ getCommonList(list1, list2));
} catch (Exception e) {
// TODO: handle exception
}
}
/**
* param list
* return
*/
public static int getMin(LinkedList list) {
int min = list.get(0);
for (Integer integer : list) {
if (min > integer) {
min = integer;
}
}
return min;
}
/**
* param list
* return
*/
public static int countDivisibles(LinkedList list) {
int count = 0;
for (Integer integer : list) {
if (integer % 3 == 0 && integer % 5 == 0) {
count++;
}
}
return count;
}
/**
* param list1
* param list2
* return
*/
public static LinkedList getCommonList(LinkedList list1,
LinkedList list2) {
LinkedList list = new LinkedList();
LinkedList listCommon = new LinkedList();
list = (list1.size() > list2.size()) ? list1 : list2;
for (int i = 0; i < list.size(); i++) {
Integer number = list.get(i);
if (list2.contains(number) && list1.contains(number)) {
listCommon.add(number);
}
}
return listCommon;
}
}
OUTPUT:
Enter the Lower and Upper bounds:1 10
Enter the N value to Insert list1:10
Enter the M value to Insert list2:20
list1: [1, 4, 4, 6, 9, 4, 9, 5, 8, 5]
list2: [5, 10, 10, 2, 1, 10, 8, 8, 8, 2, 6, 10, 6, 2, 5, 9, 6, 9, 6, 2]
Minimum elelment in list1 :1
Minimum elelment in list2 :1
Count Divisibles by 3 and 5 elelment in list1 :0
Count Divisibles by 3 and 5 elelment in list2 :0
Common Elements From list1 and list2:[5, 1, 8, 8, 8, 6, 6, 5, 9, 6, 9, 6]
Solution
import java.util.LinkedList;
import java.util.Random;
import java.util.Scanner;
/**
* author
*
*/
public class LinkedListTest {
/**
* param args
*/
public static void main(String[] args) {
int M, N, Lower, Upper;
Scanner scanner = null;
try {
LinkedList list1 = new LinkedList();
L.
A Skeptics guide to functional style javascript
The document discusses functional programming concepts like pure functions, higher order functions, currying, and monads and how they can be applied in JavaScript. It provides examples of transforming iterative array methods like map, filter, and reduce into functional style code using pure functions. While functional programming aims to avoid side effects, the document notes that side effects cannot be fully avoided in JavaScript and functional style is more of a mindset of keeping pieces small and interactions simple.
class Array { public static int getTotal(int[][]numbers ) { .pdf
class Array
{
public static int getTotal(int[][]numbers )
{
int tot=0;
// Lo0op repeats until list ends
for (int row = 0;row < numbers .legth; row++)
for (int col=0 ;col< numbers [row].length; col++)
tot+=numbers [row][col];
return tot;
}
// return avarage
public static double getAvarage(int [][]numbers,int index)
{
double avg;
avg=(double) (getTotal(numbers/(12));
return avg;
}
public static int getRowTotal (int [][] numbers, int index)
{
int tot=0;
// loop repeats until list ends
for (int col=0;col<4;col++)
// Accumulates sum of numbers
tot+= number[index][col];
return tot;
}
public static int getHighest(int [][] numbers, int row)
{
int high= numbers [row][0];
// Loop repeats until list ends
for (int i = 1; i<4; i++)
if (numbers[rows][i]>high )
high = numbers [row] [i];
return high;
}
public static int getLowest (int [][]number,int row)
{
int low = number [row][0];
// Loop repeats until list ends
for(inti = 1 ;i < 4 ;i++)
if (numbers [row][i]
Solution
class ArrayDemo {
// main function
public static void main(String[] arg) {
int[][] list = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } };
// Function call and display data returned
System.out.println(\"total:\" + getTotal(list));
System.out.println(\"Average:\" + getAverage(list));
System.out.println(\"Row 2 value:\" + getRowTotal(list, 2));
System.out.println(\"column3 value:\" + getColumnTotal(list, 3));
System.out.println(\"highest value in row 1 is:\" + getHighest(list, 1));
System.out.println(\"lowest value in row 2 is:\" + getLowest(list, 2));
// exit program
System.exit(0);
}
public static int getTotal(int[][] numbers) {
int tot = 0;
// Lo0op repeats until list ends
for (int row = 0; row < numbers.length; row++)
for (int col = 0; col < numbers[row].length; col++)
tot += numbers[row][col];
return tot;
}
// return average
public static double getAverage(int [][]numbers)
{
double avg;
avg=(double) getTotal(numbers)/12;
return avg;
}
public static int getRowTotal(int[][] numbers, int index) {
int tot = 0;
// loop repeats until list ends
for (int col = 0; col < 4; col++)
// Accumulates sum of numbers
tot += numbers[index][col];
return tot;
}
public static int getHighest(int[][] numbers, int row) {
int high = numbers[row][0];
// Loop repeats until list ends
for (int i = 1; i < 4; i++)
if (numbers[row][i] > high)
high = numbers[row][i];
return high;
}
public static int getLowest(int[][] numbers, int row) {
int low = numbers[row][0];
// Loop repeats until list ends
for (int i = 1; i < 4; i++)
if (numbers[row][i] < low)
low = numbers[row][i];
return low;
}
public static int getColumnTotal(int[][] numbers, int column) {
int sum = 0;
for(int i = 0; i < numbers.length; i++)
sum += numbers[i][column];
return sum;
}
}.
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists have their elements in sorted
order, from lowest to highest. The output list should also be sorted from lowest to highest. Your
algorithm should run in linear time on the length of the output list. Provide an algorithm for your
function Implement and show some samples of your running function
Solution
The algorithm for LinkedList MergeSort is as follows.
The trick in this algorithm is to use a local list to store the value which is pointing to the actual
list to be returned as a result of the function
Step1: START
Step2: GET inputs of list1 and list2
Step3: INITIALIZE mergelist
STEP4: SET mylist = mergelist
Step5: WHILE list1 OR list2 is EMPTY
DO
IF (list1 AND list2) are NOT EMPTY
IF list1.value > list2.value
mylist.next = list2
ELSE
mylist.next = list1
ELSE IF list1 is EMPTY
mylist.next = list2
ELSE
mylist.next = list1
Step6: RETURN mergelist
Step7: STOP
Sample program for the same implemented in C++
//====================================================================
========
// Name : DoublyLinkedList.cpp
// Author : Kaju
// Version : 0.1
// Copyright : This is just an example code
// Description : MergeSort in C++, Ansi-style
//====================================================================
========
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
// struct declaration for node which will hold the integer data with links to previous data and next
data
struct node
{
int data;
struct node *next;
struct node *prev;
};
/*
Class Declaration
*/
class DoublyLinkedList
{
private:
struct node *start; // collection of all the nodes
public:
void create(int value);
int peek();
int delete_head();
void display();
int count();
void mergeSort(DoublyLinkedList list1, DoublyLinkedList list2);
DoublyLinkedList()
{
start = NULL;
}
};
/*
* Add data into the list
*/
void DoublyLinkedList::create(int value)
{
struct node *s, *temp;
temp = new(struct node);
temp->data = value;
temp->next = NULL;
if (start == NULL)
{
temp->prev = NULL;
start = temp;
}
else
{
s = start;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Deletion of the first element from the list
* store the first element in a temp node and then remove it from start.
*/
int DoublyLinkedList::delete_head()
{
struct node *tmp, *q;
int value;
tmp = start;
if(start->next!=NULL)
{
start = start->next;
start->prev = NULL;
}
else
start = NULL;
value = tmp->data;
free(tmp);
return value;
}
/*
* return the first element of Doubly Link List
*/
int DoublyLinkedList::peek()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
}
}
/*
* Display elements of Doubly Link List
*/
void DoublyLinkedList::display()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
q = q->next;
if(q != NULL)
{
cout<<\", \";
}
}
cout<<\"]\"<next;
cnt++;
}
return cnt;
}
/*
* MergeSort - takes two input lists and then based on the.
Recommended
Hi,I have added the methods and main class as per your requirement.pdf
Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2: The Methods (65 points) Implement all the methods that are marked as Left as
Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
2.(Sorted list array implementation)This sorted list ADT discussed .pdf
2.(Sorted list: array implementation)This sorted list ADT discussed in class should be extended
by the addition of two new methods:
//Interface: ArrayListADT
//works for int
public interface ArrayListADT {
public boolean isEmpty(); //Method to determine whether the list is empty.
public boolean isFull(); //Method to determine whether the list is full.
public int listSize(); //Method to return the number of elements in the list.
public int maxListSize(); //Method to return the maximum size of the list.
public void print(); //Method to output the elements of the list.
public boolean isItemAtEqual(int location, int item); //Method to determine whether item is
the same as the item in the list at location.
public void insertAt(int location, int insertItem); //Method to insert insertItem in the list at
the position
public void insertEnd(int insertItem); //Method to insert insertItem at the end of the list.
public void removeAt(int location); //Method to remove the item from the list at location.
public int retrieveAt(int location); //Method to retrieve the element from the list at location.
public void replaceAt(int location, int repItem); //Method to replace the element in the list at
location with repItem.
public void clearList(); //Method to remove all the elements from the list.
public int search(int searchItem); //Method to determine whether searchItem is in the list.
public void remove(int removeItem); //Method to remove an item from the list.
}
//Class: ArrayListClass implements
//Interface: ArrayListADT
public abstract class ArrayListClass implements ArrayListADT {
protected int length; //to store the length of the list
protected int maxSize; //to store the maximum size of the list
protected int[] list; //array to hold the list elements
//Default constructor
public ArrayListClass() {
maxSize = 100;
length = 0;
list = new int[maxSize];
}
//Alternate Constructor
public ArrayListClass(int size) {
if(size <= 0) {
System.err.println(\"The array size must be positive. Creating an array of size 100.\");
maxSize = 100;
}
else
maxSize = size;
length = 0;
list = new int[maxSize];
}
public boolean isEmpty() {
return (length == 0);
}
public boolean isFull() {
return (length == maxSize);
}
public int listSize() {
return length;
}
public int maxListSize() {
return maxSize;
}
public void print() {
for (int i = 0; i < length; i++)
System.out.print(list[i] + \" \");
System.out.println();
}
public boolean isItemAtEqual(int location, int item) {
if (location < 0 || location >= length) {
System.err.println(\"The location of the item to be compared is out of range.\");
return false;
}
return list[location]== item;
}
public void clearList() {
for (int i = 0; i < length; i++)
list[i] = 0;
length = 0;
System.gc(); //invoke the Java garbage collector
}
public void removeAt(int location) {
if (location < 0 || location >= length)
System.err.println(\"The location of the item to be removed is out of range.\");
else {
for(int i = location; i < length - 1; i++)
list[i] .
public class MyLinkedListltE extends ComparableltEgtg.pdf
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Increase size
}
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node<E> current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node<E> temp = current.next;
current.next = new Node<>(e);
(current.next).next = temp;
size++;
}
}
//Add e to the end of this linkedlist
public void add(E e) {
// Left as Exercise
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
E temp = head.element;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return temp;
}
}
/** Remove the last node and
* return the object that is contained in the removed node. */
public E removeLast() {
if (size == 0) {
return null;
}
else if (size == 1) {
E temp = head.element;
head = tail = null;
size = 0;
return temp;
}
else {
Node<E> current = head;
for (int i = 0; i < size - 2; i++) {
current = current.next;
}
E temp = tail.element;
tail = current;
tail.next = null;
size--;
return temp;
}
}
/** Remove the element at the specified position in this
* list. Return the element that was removed from the list. */
public E remove(int index) {
if (index < 0 || index >= size) {
return null;
}
else if (index == 0) {
return removeFirst();
}
else if (index == size - 1) {
return removeLast();
}
else {
Node<E> previous = head;
for (int i = 1; i < index; i++) {
previous = previous.next;
}
Node<E> current = previous.next;
previous.next = current.next;
size--;
return current.element;
}
}
/** Clear the list */
public void clear() {
size = 0;
head = tail = null;
}
/** Override toString() to return elements in the list in [] separated by , */
public String toString() {
StringBuilder result = new StringBuilder("[");
Node<E> current = head;
for (int i = 0; i < size; i++) {
result.append(current..
import java.util.LinkedList; import java.util.Random; import jav.pdf
import java.util.LinkedList;
import java.util.Random;
import java.util.Scanner;
/**
* author
*
*/
public class LinkedListTest {
/**
* param args
*/
public static void main(String[] args) {
int M, N, Lower, Upper;
Scanner scanner = null;
try {
LinkedList list1 = new LinkedList();
LinkedList list2 = new LinkedList();
LinkedList list3 = new LinkedList();
Random random = new Random();
scanner = new Scanner(System.in);
System.out.print(\"Enter the Lower and Upper bounds:\");
Lower = scanner.nextInt();
Upper = scanner.nextInt();
System.out.print(\"Enter the N value to Insert list1:\");
N = scanner.nextInt();
System.out.print(\"Enter the M value to Insert list2:\");
M = scanner.nextInt();
for (int i = 1; i <= N; i++) {
list1.add(random.nextInt((Upper - Lower) + 1) + Lower);
}
for (int i = 1; i <= M; i++) {
list2.add(random.nextInt((Upper - Lower) + 1) + Lower);
}
System.out.println(\"list1: \" + list1);
System.out.println(\"list2: \" + list2);
System.out.println(\"Minimum elelment in list1 :\" + getMin(list1));
System.out.println(\"Minimum elelment in list2 :\" + getMin(list2));
System.out
.println(\"Count Divisibles by 3 and 5 elelment in list1 :\"
+ countDivisibles(list1));
System.out
.println(\"Count Divisibles by 3 and 5 elelment in list2 :\"
+ countDivisibles(list2));
System.out.println(\"Common Elements From list1 and list2:\"
+ getCommonList(list1, list2));
} catch (Exception e) {
// TODO: handle exception
}
}
/**
* param list
* return
*/
public static int getMin(LinkedList list) {
int min = list.get(0);
for (Integer integer : list) {
if (min > integer) {
min = integer;
}
}
return min;
}
/**
* param list
* return
*/
public static int countDivisibles(LinkedList list) {
int count = 0;
for (Integer integer : list) {
if (integer % 3 == 0 && integer % 5 == 0) {
count++;
}
}
return count;
}
/**
* param list1
* param list2
* return
*/
public static LinkedList getCommonList(LinkedList list1,
LinkedList list2) {
LinkedList list = new LinkedList();
LinkedList listCommon = new LinkedList();
list = (list1.size() > list2.size()) ? list1 : list2;
for (int i = 0; i < list.size(); i++) {
Integer number = list.get(i);
if (list2.contains(number) && list1.contains(number)) {
listCommon.add(number);
}
}
return listCommon;
}
}
OUTPUT:
Enter the Lower and Upper bounds:1 10
Enter the N value to Insert list1:10
Enter the M value to Insert list2:20
list1: [1, 4, 4, 6, 9, 4, 9, 5, 8, 5]
list2: [5, 10, 10, 2, 1, 10, 8, 8, 8, 2, 6, 10, 6, 2, 5, 9, 6, 9, 6, 2]
Minimum elelment in list1 :1
Minimum elelment in list2 :1
Count Divisibles by 3 and 5 elelment in list1 :0
Count Divisibles by 3 and 5 elelment in list2 :0
Common Elements From list1 and list2:[5, 1, 8, 8, 8, 6, 6, 5, 9, 6, 9, 6]
Solution
import java.util.LinkedList;
import java.util.Random;
import java.util.Scanner;
/**
* author
*
*/
public class LinkedListTest {
/**
* param args
*/
public static void main(String[] args) {
int M, N, Lower, Upper;
Scanner scanner = null;
try {
LinkedList list1 = new LinkedList();
L.
A Skeptics guide to functional style javascript
The document discusses functional programming concepts like pure functions, higher order functions, currying, and monads and how they can be applied in JavaScript. It provides examples of transforming iterative array methods like map, filter, and reduce into functional style code using pure functions. While functional programming aims to avoid side effects, the document notes that side effects cannot be fully avoided in JavaScript and functional style is more of a mindset of keeping pieces small and interactions simple.
class Array { public static int getTotal(int[][]numbers ) { .pdf
class Array
{
public static int getTotal(int[][]numbers )
{
int tot=0;
// Lo0op repeats until list ends
for (int row = 0;row < numbers .legth; row++)
for (int col=0 ;col< numbers [row].length; col++)
tot+=numbers [row][col];
return tot;
}
// return avarage
public static double getAvarage(int [][]numbers,int index)
{
double avg;
avg=(double) (getTotal(numbers/(12));
return avg;
}
public static int getRowTotal (int [][] numbers, int index)
{
int tot=0;
// loop repeats until list ends
for (int col=0;col<4;col++)
// Accumulates sum of numbers
tot+= number[index][col];
return tot;
}
public static int getHighest(int [][] numbers, int row)
{
int high= numbers [row][0];
// Loop repeats until list ends
for (int i = 1; i<4; i++)
if (numbers[rows][i]>high )
high = numbers [row] [i];
return high;
}
public static int getLowest (int [][]number,int row)
{
int low = number [row][0];
// Loop repeats until list ends
for(inti = 1 ;i < 4 ;i++)
if (numbers [row][i]
Solution
class ArrayDemo {
// main function
public static void main(String[] arg) {
int[][] list = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 } };
// Function call and display data returned
System.out.println(\"total:\" + getTotal(list));
System.out.println(\"Average:\" + getAverage(list));
System.out.println(\"Row 2 value:\" + getRowTotal(list, 2));
System.out.println(\"column3 value:\" + getColumnTotal(list, 3));
System.out.println(\"highest value in row 1 is:\" + getHighest(list, 1));
System.out.println(\"lowest value in row 2 is:\" + getLowest(list, 2));
// exit program
System.exit(0);
}
public static int getTotal(int[][] numbers) {
int tot = 0;
// Lo0op repeats until list ends
for (int row = 0; row < numbers.length; row++)
for (int col = 0; col < numbers[row].length; col++)
tot += numbers[row][col];
return tot;
}
// return average
public static double getAverage(int [][]numbers)
{
double avg;
avg=(double) getTotal(numbers)/12;
return avg;
}
public static int getRowTotal(int[][] numbers, int index) {
int tot = 0;
// loop repeats until list ends
for (int col = 0; col < 4; col++)
// Accumulates sum of numbers
tot += numbers[index][col];
return tot;
}
public static int getHighest(int[][] numbers, int row) {
int high = numbers[row][0];
// Loop repeats until list ends
for (int i = 1; i < 4; i++)
if (numbers[row][i] > high)
high = numbers[row][i];
return high;
}
public static int getLowest(int[][] numbers, int row) {
int low = numbers[row][0];
// Loop repeats until list ends
for (int i = 1; i < 4; i++)
if (numbers[row][i] < low)
low = numbers[row][i];
return low;
}
public static int getColumnTotal(int[][] numbers, int column) {
int sum = 0;
for(int i = 0; i < numbers.length; i++)
sum += numbers[i][column];
return sum;
}
}.
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists have their elements in sorted
order, from lowest to highest. The output list should also be sorted from lowest to highest. Your
algorithm should run in linear time on the length of the output list. Provide an algorithm for your
function Implement and show some samples of your running function
Solution
The algorithm for LinkedList MergeSort is as follows.
The trick in this algorithm is to use a local list to store the value which is pointing to the actual
list to be returned as a result of the function
Step1: START
Step2: GET inputs of list1 and list2
Step3: INITIALIZE mergelist
STEP4: SET mylist = mergelist
Step5: WHILE list1 OR list2 is EMPTY
DO
IF (list1 AND list2) are NOT EMPTY
IF list1.value > list2.value
mylist.next = list2
ELSE
mylist.next = list1
ELSE IF list1 is EMPTY
mylist.next = list2
ELSE
mylist.next = list1
Step6: RETURN mergelist
Step7: STOP
Sample program for the same implemented in C++
//====================================================================
========
// Name : DoublyLinkedList.cpp
// Author : Kaju
// Version : 0.1
// Copyright : This is just an example code
// Description : MergeSort in C++, Ansi-style
//====================================================================
========
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
// struct declaration for node which will hold the integer data with links to previous data and next
data
struct node
{
int data;
struct node *next;
struct node *prev;
};
/*
Class Declaration
*/
class DoublyLinkedList
{
private:
struct node *start; // collection of all the nodes
public:
void create(int value);
int peek();
int delete_head();
void display();
int count();
void mergeSort(DoublyLinkedList list1, DoublyLinkedList list2);
DoublyLinkedList()
{
start = NULL;
}
};
/*
* Add data into the list
*/
void DoublyLinkedList::create(int value)
{
struct node *s, *temp;
temp = new(struct node);
temp->data = value;
temp->next = NULL;
if (start == NULL)
{
temp->prev = NULL;
start = temp;
}
else
{
s = start;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Deletion of the first element from the list
* store the first element in a temp node and then remove it from start.
*/
int DoublyLinkedList::delete_head()
{
struct node *tmp, *q;
int value;
tmp = start;
if(start->next!=NULL)
{
start = start->next;
start->prev = NULL;
}
else
start = NULL;
value = tmp->data;
free(tmp);
return value;
}
/*
* return the first element of Doubly Link List
*/
int DoublyLinkedList::peek()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
}
}
/*
* Display elements of Doubly Link List
*/
void DoublyLinkedList::display()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
q = q->next;
if(q != NULL)
{
cout<<\", \";
}
}
cout<<\"]\"<next;
cnt++;
}
return cnt;
}
/*
* MergeSort - takes two input lists and then based on the.
Please help solve this in C++ So the program is working fin.pdf
Please help solve this in C++. So the program is working fine but when submitting it, it gives me a
code -11, and I believe the problem is that after inserting the numbers it removes them one by one
until the last in the list, and when it tries to remove the last number in the list that is when it
counters the problem. Below is the full code but you just need to change something in the
SortedNumberList.h file under the bool remove function.
4.18 LAB: Sorted number list implementation with linked lists Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on
the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: - a double data value, - a pointer to the next node, and - a pointer to the
previous node. Each member variable is protected. So code outside of the class must use the
provided getter and setter member functions to get or set a member variable. Node.h is read only,
since no changes are required. Step 2: Implement the Insert() member function A class for a
sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList
class's Insert() member function. The function must create a new node with the parameter value,
then insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 2347.2586, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 2335.547.2586Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77154263.5 then output is: List after inserting 77 : 77 List after
inserting 15 : 1577 List after inserting -42 : -421577 List after inserting 63.5: -421563.577 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove(0 member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is
841972841961 then output is: List after inserting 84: 84 List after inserting 72 : 7284 List after
inserting 19: 1972 84 List after inserting 61: 1961 : 72 8 List after removing 19: 6172 84 List after
removing 84: 6172Current file: main.cpp - // Insert each value and show the sorted List's contents
after each insertion sortedNumberList list; for (auto term : terms) { doubl.
Implement the additional 5 methods as indicated in the LinkedList fi.pdf
Implement a minimum spanning tree using Boruvka\'s algorithm.
Implement a minimum spanning tree using Boruvka\'s algorithm.
Solution
The psuedo code is as follows:
1 Graph input = /* read input */;
2 UnionFind uf (input.getNodes ());
3 Workset ws = input.getNodes();
4 foreach (Node n : ws) {
5 Edge e = minWeight (input.getOutEdges (n));
6 Node rep1 = uf.find (e.src);
7 Node rep2 = uf.find (e.dst);
8 if (rep1 != rep2) {
9 e.markInMST();
10 Node rep = uf.union (rep1, rep2);
11 ws.add (rep)
12 }
13 }.
Linked list1
A linked list is a data structure that stores elements in memory locations that are linked using pointers. Each element contains a data field and a pointer to the next element. Elements are added by allocating memory and linking the new element to an existing element using its pointer. Elements can be inserted at the front or end of the list and traversed using a pointer that walks through each element. Functions are used to initialize, insert, print, find, and delete elements from the linked list.
linked List.docx vhjgvjhvgjhjhbbjkhkjhkjh
This C code defines structures for nodes and linked lists. It provides functions for creating nodes, inserting nodes at the beginning or end of a linked list, deleting nodes with a specific value, searching for a node, and displaying the linked list. These functions are used in the main function to demonstrate manipulating a linked list, including inserting nodes, deleting nodes, and searching.
The MyLinkedList class used in Listing 24.6 is a one-way directional .docx
The document describes modifying an existing Node class to create a doubly linked list implementation called TwoWayLinkedList. The Node class is updated to include a previous node reference. TwoWayLinkedList extends an existing abstract list class and implements list iterator methods to traverse the list in both directions. It overrides common list methods like add, remove, and size.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
Below is a given ArrayList class and Main class Your Dreams Our Mission/tuto...
FOR MORE CLASSES VISIT
www.tutorialoutlet.com
Below is a given ArrayList class and Main class in search algorithms. Please modify the existing program so it can time the sequential search and the binary search methods several times each for randomly generated values, and record the results in a table. Do not time individual searches, but groups of them. For example, time 100 searches together or 1,000 searches together. Compare the running times of these two search methods that are obtained during the experiment.
Data type list_methods_in_python
Lists in Python can be created using square brackets and allow storing multiple data types. Lists have numerous built-in methods for manipulating list elements and metadata. Common list methods allow adding and removing elements, sorting and reversing lists, copying lists, and accessing elements by index. Lists are a fundamental Python data type for storing and manipulating sequences of data.
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. Other classes are not
modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
import java.util.ArrayList; import java.util.List;public class S.pdf
import java.util.ArrayList;
import java.util.List;
public class SearchList {
/**
* param args
*/
public static void main(String[] args) {
List list = new ArrayList();
list.add(3);
list.add(3);
list.add(1);
System.out.println(\"Search element 3 in list [3,3,1] :\"
+ search(list, 3));
System.out.println(\"Search element 5 in list [3,3,1] :\"
+ search(list, 5));
}
/**
* method to find the index of element in the list
* param list
* param element
* return
*/
public static int search(List list, Object element) {
int index = -1;
if (list == null || element == null)
throw new NullPointerException();
else {
int searchElement = (int) element;
for (int i = 0; i < list.size(); i++) {
int number = (int) list.get(i);
if (number == searchElement) {
index = i;
}
}
}
return index;
}
}
OUTPUT:
Search element 3 in list [3,3,1] :1
Search element 5 in list [3,3,1] :-1
Solution
import java.util.ArrayList;
import java.util.List;
public class SearchList {
/**
* param args
*/
public static void main(String[] args) {
List list = new ArrayList();
list.add(3);
list.add(3);
list.add(1);
System.out.println(\"Search element 3 in list [3,3,1] :\"
+ search(list, 3));
System.out.println(\"Search element 5 in list [3,3,1] :\"
+ search(list, 5));
}
/**
* method to find the index of element in the list
* param list
* param element
* return
*/
public static int search(List list, Object element) {
int index = -1;
if (list == null || element == null)
throw new NullPointerException();
else {
int searchElement = (int) element;
for (int i = 0; i < list.size(); i++) {
int number = (int) list.get(i);
if (number == searchElement) {
index = i;
}
}
}
return index;
}
}
OUTPUT:
Search element 3 in list [3,3,1] :1
Search element 5 in list [3,3,1] :-1.
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Write a JAVA LinkedListRec class that has the following methods: size, empty, insertBefore,
insertAfter, addAtHead, addAtEnd, remove, replace, peekFront, peekEnd, removeFront,
removeEnd, toString. Use recursion to implement most of these methods. Write a driver to test
your implemented LinkedListRec class methods.
Solution
import java.util.Scanner;
public class LinkedListRec {
int data;
LinkedListRec prev=null,next=null;
int size(LinkedListRec l)//method which returns the length of the list
{
if(l==null)return 0;
return 1+size(l.next);
}
boolean empty(LinkedListRec l)//method checks whether the list is empty or not...
{
if(l==null)return true;
else return false;
}
LinkedListRec insertBefore(LinkedListRec l,int value,int num_insertbefore)//method which
adds a new number before the given number..
{
if(l==null)return l;
if(l.data == num_insertbefore)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.prev==null)
{
n.next = l;
l=n;
}
else
{
n.prev = l.prev;
n.next= l;
l.prev = n;
}
return l;
}
return insertBefore(l.next,value,num_insertbefore);
}
LinkedListRec insertAfter(LinkedListRec l,int value,int num_insertafter)//method which adds
the new number after the given number
{
if(l==null)return l;
if(l.data == num_insertafter)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.next==null)
{
l.next = n;
n.prev = l;
}
else
{
n.next = l.next;
l.next.prev = n;
n.prev = l;
}
return l;
}
return insertAfter(l.next,value,num_insertafter);
}
LinkedListRec addAtHead(LinkedListRec l,int value)//method which adds a new number at
the head position of the list...
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.next = l;
l=n;
return l;
}
LinkedListRec addAtEnd(LinkedListRec l,int value)//method which adds a new number at
the end position of the list...
{
if(l==null){ l = new LinkedListRec();l.data = value;return l;}
if(l.next==null)
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.prev = l;
l.next = n;
return l;
}
return addAtEnd(l.next,value);
}
LinkedListRec remove(LinkedListRec l,int value)//method which removes given numbet
from the list....
{
if(l==null)return l;
if(l.data == value)
{
if(l.prev!=null){
l.prev = l.next;
}
else
l=l.next;
return l;
}
return remove(l.next,value);
}
boolean replace(LinkedListRec l,int value,int newvalue)//method which replaces current
number with new number,...
{
if(l==null)return false;
if(l.data == value)
{
l.data = newvalue;
return true;
}
return replace(l.next,value,newvalue);
}
int peekFront(LinkedListRec l)//method which returns the first value of the list...
{
if(l!=null)
return l.data;
else return -1;
}
int peekEnd(LinkedListRec l)//method which returns the last value of the list........
{
if(l==null)return -1;
if(l.next == null)return l.data;
return peekEnd(l.next);
}
LinkedListRec removeFront(LinkedListRec l)//method which removes the first element of the
list..
{
if(l==null)return l;
l=l.next;
return l;
}
boolean removeEnd(LinkedListRec l)//method which removes the last element o.
dynamicList.ppt
The document discusses implementing a sorted linked list data structure in C++. It describes how to insert a new node into the linked list in the correct sorted position by finding the previous and current nodes between which the new node should be inserted. The key steps are to create a new node, find the previous and current nodes using a while loop, and connect the new node by updating the next pointers of the previous and current nodes.
Code
The document discusses several sorting and search algorithms:
1) Binary search and binary search with recursion find a target value in a sorted array by repeatedly dividing the array range in half and comparing the middle element to the target.
2) Linear search compares each element of an unsorted array to the target.
3) Insertion sort divides an array into sorted and unsorted parts, inserting elements from the unsorted part into the sorted part.
4) Selection sort finds the minimum element in the unsorted part and swaps it into the sorted position in each iteration.
5) Merge sort recursively splits the array into single elements and then merges the sorted parts back together.
Question 1,2,4 ------------------------------------Please check.pdf
Question 1,2,4 :-
-----------------------------------
Please check comments in Programme
#include
/**
* Method for Linear Search
* Loop through given array and search for given key
* IF found return index and stop
* else -1 will be returned at the end
*
*/
int search(int array[],int key,int size){
int index = -1;
for (int c = 0; c < size; c++)
{
if (array[c] == key) /* if required element found */
{
printf(\"%d is present at location %d.\ \", key, c+1);
index = c;
break;
}
}
if(index == -1)
printf(\"%d is not found.\ \", key);
return index;
}
/**
* Function for Binary search
* Binary search is used only for sorted arrays
* Check key with element at middle position
* if key == then return middle positon
* if key > middle position , apply same for sub array range from [middle...last]
* if key < middle position , apply same for sub array range from [0..middle]
*
*/
int binary_search(int array[],int key,int start,int end){
int index = -1;
int first = start;
int last = end;
int middle = (first+last)/2;
while (first <= last) {
//Print array between first nad last for each step
printf(\"Start binary search step.\ \");
for(int i = first ; i < last ; i++){
printf(\"Binary search step element.%d\ \",array[i]);
}
printf(\"Stop binary search step.\ \");
if (array[middle] < key)
first = middle + 1;
else if (array[middle] == key) {
index = middle;
printf(\"%d found at location %d.\ \", key, middle+1);
break;
}
else
last = middle - 1;
middle = (first + last)/2;
}
return index;
}
/**
* Recursive linear search
* Instead of for loop call same method with next index
* first pass 0, check if key found at index 0, if not found call same method with index 1 .....
*/
int linear_search_recursive(int array[],int key,int size,int index){
if(array[index] == key){
printf(\"%d found at location %d.\ \",key, index);
return index;
}
else if (index >= size-1){
return -1;
}
else{
return linear_search_recursive(array,key,size,++index);
}
}
/**
* Recursive Binary Search
* Recursively call Binary Search , check key found at element middle
* if key == then return middle positon
* if key > middle position , call recursive method for sub array range from [middle...last]
* if key < middle position , call recursive method for sub array range from [0..middle]
*/
int binary_search_recursive(int array[],int key,int start,int end){
//Key not found
if(start> end){
return -1;
}
int index = -1;
int first = start;
int last = end;
int middle = (first+last)/2;
//Print array between first nad last for each step
printf(\"Start binary search step.\ \");
for(int i = first ; i < last ; i++){
printf(\"Binary search step element.%d\ \",array[i]);
}
printf(\"Stop binary search step.\ \");
if (array[middle] < key){
first = middle + 1;
return binary_search_recursive(array,key,first,last) ;
}else if (array[middle] == key) {
printf(\"%d found at location %d.\ \", key, middle+1);
return middle;
}
else{
last = middle - 1;
return binary_search_recursive(array,key,first,last) ;
}
return -1;
}
/**
*Function t.
Unit 4 python -list methods
The document provides information on various list methods in Python like list creation, accessing items from lists, slicing lists, and common list methods like append(), count(), extend(), index(), insert(), pop(), copy(), remove(), reverse(), and sort(). It includes the syntax and examples to demonstrate how each method works on lists. Various programs are given to showcase inserting, removing, sorting, copying and reversing elements in lists using the different list methods.
SOURCE CODEimport java.util.Iterator;public class CircularLinke.pdf
SOURCE CODE:
import java.util.Iterator;
public class CircularLinkedList implements Iterable {
Node head , tail;
int size;
CircularLinkedList() {
head = null;
tail = null;
size = 0;
}
public boolean add(E e) {
Node ele = new Node(e);
ele.next = head;
if(head == null)
{
head = ele;
ele.next = head;
tail = head;
}
else
{
tail.next = ele;
tail = ele;
}
size++;
return true;
}
public boolean add(int index, E e){
Node ele = new Node(e);
Node ptr = head;
index = index - 1 ;
for (int i = 1; i < size - 1; i++)
{
if (i == index)
{
Node tmp = ptr.next;
ptr.next = ele;
ele.next = tmp;
break;
}
ptr = ptr.next;
}
size++ ;
return true;
}
private Node getNode(int index ) {
return null;
}
public E remove(int index) {
Node ret;
if (size == 1 && index == 1)
{
ret = head;
head = null;
tail = null;
size = 0;
return ret.getElement();
}
if (index == 1)
{
ret = head;
head = head.next;
tail.next = head;
size--;
return ret.getElement();
}
if (index == size)
{
Node s = head;
Node t = head;
while (s != tail)
{
t = s;
s = s.next;
}
ret = tail;
tail = head;
tail = t;
size --;
return ret.getElement();
}
Node ptr = head;
index = index - 1 ;
for (int i = 1; i < size - 1; i++)
{
if (i == index)
{
Node tmp = ptr.next;
tmp = tmp.next;
ptr.next = tmp;
break;
}
ptr = ptr.next;
}
size-- ;
return ptr.getElement();
}
public String toString()
{
Node current = head;
String result = \"\";
if(size == 0){
return \"\";
}
if(size == 1) {
return head.getElement().toString();
}
else{
do{
result = result + current.getElement().toString();
result = result + \" ==> \";
current = current.next;
} while(current != head);
}
return result;
}
public Iterator iterator() {
return new ListIterator();
}
private class ListIterator implements Iterator{
Node nextItem;
Node prev;
int index;
@SuppressWarnings(\"unchecked\")
public ListIterator(){
nextItem = (Node) head;
index = 0;
}
public boolean hasNext() {
return size != 0;
}
public E next() {
prev = nextItem;
nextItem = nextItem.next;
index = (index + 1) % size;
return prev.getElement();
}
public void remove() {
int target;
if(nextItem == head) {
target = size - 1;
} else{
target = index - 1;
index--;
}
CircularLinkedList.this.remove(target); //calls the above class
}
}
// Solve the problem in the main method
// The answer of n = 13, k = 2 is
// the 11th person in the ring (index 10)
public static void main(String[] args){
CircularLinkedList l = new CircularLinkedList();
int n=13;
int k=2;
for(int i=1;i<=n;i++)
l.add(Integer.valueOf(i));
int j = 13,i=0;
while(j>0)
{
System.out.println(l.toString());
i = i + k;
if(i>j)
i = k;
l.remove(i);
j--;
}
}
}
OUTPUT:
1 ==> 2 ==> 3 ==> 4 ==> 5 ==> 6 ==> 7 ==> 8 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 5 ==> 6 ==> 7 ==> 8 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 6 ==> 7 ==> 8 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 6 ==> 7 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 6 ==> 7 ==> 9 ==> 10 ==> 12 ==> 13 ==>
1 ==> 4 ==> 6 ==> 7 ==> 9 ==> 10 ==> 12 ==> 13 ==>
1 ==> 4.
Write a program to find the number of comparisons using the binary se.docx
The document describes a program to compare the number of comparisons needed for binary search versus sequential search on an array of 1000 randomly generated elements. It includes functions to fill the array, perform sequential, binary, and binary with sequential search, and output the number of comparisons for each. The program prompts the user for elements to search for in different locations of the array and outputs the results.
Kotlin collections
The document discusses Kotlin collections and aggregate operations on collections. It explains that Kotlin collections can be mutable or immutable, and by default collections are immutable unless specified as mutable. It then covers various aggregate operations that can be performed on collections like any, all, count, fold, foldRight, forEach, max, min, none etc and provides code examples for each operation.
Linked List
Singly linked lists, doubly linked lists, and circular linked lists are types of linked data structures. Singly linked lists contain nodes with a data field and a next pointer. Doubly linked lists contain additional previous pointers. Circular linked lists connect the last node to the first node, making the list cyclic. Pseudocode is provided for common linked list operations like insertion, deletion, searching, on different positions in the lists.
lists8.pptx of chapter 12 IP Basic Python
This document discusses lists in Python. It begins by defining lists as collections of items indexed from 0 to n-1, where n is the number of items. It then covers creating and initializing lists, accessing list items using indexes and slicing, updating and manipulating lists, adding and deleting items from lists, basic list operations, and important list methods. It provides examples for each topic and ends with some example programs involving lists like finding the largest/mean value in a list and linear search.
Exercise 4-1 (Algo) Computing revenues- expenses- and income LO C1 Fil.docx
Exercise 4-1 (Algo) Computing revenues, expenses, and income LO C1 Fill in the blanks in the following separate income statements a through e .
.
Exercise 3- -10 marks- Draw a 4-bit Serial In- Serial Out register usi.docx
Exercise 3. [10 marks] Draw a 4-bit Serial In, Serial Out register using SR flip-flops. For example, the below diagram represents a Parallel In, Parallel Out n -bit register using D flip-flops.
.
More Related Content
Similar to eOverride - Return the number of elenents in this list -- public int.docx
Please help solve this in C++ So the program is working fin.pdf
Please help solve this in C++. So the program is working fine but when submitting it, it gives me a
code -11, and I believe the problem is that after inserting the numbers it removes them one by one
until the last in the list, and when it tries to remove the last number in the list that is when it
counters the problem. Below is the full code but you just need to change something in the
SortedNumberList.h file under the bool remove function.
4.18 LAB: Sorted number list implementation with linked lists Step 1: Inspect the Node.h file
Inspect the class declaration for a doubly-linked list node in Node.h. Access Node.h by clicking on
the orange arrow next to main.cpp at the top of the coding window. The Node class has three
member variables: - a double data value, - a pointer to the next node, and - a pointer to the
previous node. Each member variable is protected. So code outside of the class must use the
provided getter and setter member functions to get or set a member variable. Node.h is read only,
since no changes are required. Step 2: Implement the Insert() member function A class for a
sorted, doubly-linked list is declared in SortedNumberList.h. Implement the SortedNumberList
class's Insert() member function. The function must create a new node with the parameter value,
then insert the node into the proper sorted position in the linked list. Ex: Suppose a
SortedNumberList's current list is 2347.2586, then Insert(33.5) is called. A new node with data
value 33.5 is created and inserted between 23 and 47.25, thus preserving the list's sorted order
and yielding: 2335.547.2586Step 3: Test in develop mode Code in main() takes a space-
separated list of numbers and inserts each into a SortedNumberList. The list is displayed after
each insertion. Ex: If input is 77154263.5 then output is: List after inserting 77 : 77 List after
inserting 15 : 1577 List after inserting -42 : -421577 List after inserting 63.5: -421563.577 Try
various program inputs, ensuring that each outputs a sorted list. Step 4: Implement the Remove()
member function Implement the SortedNumberList class's Remove(0 member function. The
function takes a parameter for the number to be removed from the list. If the number does not
exist in the list, the list is not changed and false is returned. Otherwise, the first instance of the
number is removed from the list and true is returned. Uncomment the commented-out part in
main() that reads a second input line and removes numbers from the list. Test in develop mode to
ensure that insertion and removal both work properly, then submit code for grading. Ex: If input is
841972841961 then output is: List after inserting 84: 84 List after inserting 72 : 7284 List after
inserting 19: 1972 84 List after inserting 61: 1961 : 72 8 List after removing 19: 6172 84 List after
removing 84: 6172Current file: main.cpp - // Insert each value and show the sorted List's contents
after each insertion sortedNumberList list; for (auto term : terms) { doubl.
Implement the additional 5 methods as indicated in the LinkedList fi.pdf
Implement a minimum spanning tree using Boruvka\'s algorithm.
Implement a minimum spanning tree using Boruvka\'s algorithm.
Solution
The psuedo code is as follows:
1 Graph input = /* read input */;
2 UnionFind uf (input.getNodes ());
3 Workset ws = input.getNodes();
4 foreach (Node n : ws) {
5 Edge e = minWeight (input.getOutEdges (n));
6 Node rep1 = uf.find (e.src);
7 Node rep2 = uf.find (e.dst);
8 if (rep1 != rep2) {
9 e.markInMST();
10 Node rep = uf.union (rep1, rep2);
11 ws.add (rep)
12 }
13 }.
Linked list1
A linked list is a data structure that stores elements in memory locations that are linked using pointers. Each element contains a data field and a pointer to the next element. Elements are added by allocating memory and linking the new element to an existing element using its pointer. Elements can be inserted at the front or end of the list and traversed using a pointer that walks through each element. Functions are used to initialize, insert, print, find, and delete elements from the linked list.
linked List.docx vhjgvjhvgjhjhbbjkhkjhkjh
This C code defines structures for nodes and linked lists. It provides functions for creating nodes, inserting nodes at the beginning or end of a linked list, deleting nodes with a specific value, searching for a node, and displaying the linked list. These functions are used in the main function to demonstrate manipulating a linked list, including inserting nodes, deleting nodes, and searching.
The MyLinkedList class used in Listing 24.6 is a one-way directional .docx
The document describes modifying an existing Node class to create a doubly linked list implementation called TwoWayLinkedList. The Node class is updated to include a previous node reference. TwoWayLinkedList extends an existing abstract list class and implements list iterator methods to traverse the list in both directions. It overrides common list methods like add, remove, and size.
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a problem with the nodes, as it is
posting errors with the nodes.
please help me with this problem. thank you.
public class LinkLists {
/* only need to store a single pointer to the node at the head
* of the list.
* The pointer is null if the list is empty.
* Also record the size of the list.
*/
protected Node head;
/* invariant: size is the number of nodes in the list pointed to by head */
protected int size;
/* no-arguments default constructor creates an empty list */
public LinkLists() {
head = null; // start with an empty list
size = 0;
}
/* accessor method */
public int size() {
return size;
}
/* value to add to the end of the list
*/
public void add(T value) {
head = addAtEnd(head, value);
size++;
}
/* node of the list to which the value should be added
* value to add to the end of the list
*/
private Node addAtEnd(Node node, T value) {
if (node == null) { // special case
return new Node(value, null);
} else if (node.getNext() == null) { // other special case
node.setNext(new Node(value, null));
} else {
addAtEnd(node.getNext(), value);
}
return node;
}
/* iterative implementation of the same method
* value to add to the end of the list
*/
public void add2(T value) {
if (head == null) {
head = new Node(value, null);
} else {
Node node = head; // guaranteed not to be null initially
while (node.getNext() != null) {
node = node.getNext(); // guaranteed not to be null here
}
// now, node.getNext() is guaranteed to be null
// similar to the second special case in addAtEnd
node.setNext(new Node(value, null));
}
size++;
}
public void remove(int position) throws BadItemCountException {
if ((position < 1) || (position > size)) {
throw new
BadItemCountException(\"invalid position \" + position +
\", only 1..\" + size + \" available\");
}
if (position == 1) {
head = head.getNext();
} else {
Node node = head;
for (int i = 2; i < position; i++) {
node = node.getNext();
}
node.setNext(node.getNext().getNext());
}
size--; // one less item
}
public String toString() {
return toString(head);
}
private String toString(Node node) {
if (node == null) {
return \"\";
} else {
return node.getValue() + \"\ \" + toString(node.getNext());
}
}
public static void main(String[] args) {
/* create two empty lists, make sure they print out correctly */
LinkLists list1 = new LinkLists();
LinkLists list2 = new LinkLists();
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* insert some items, keep checking */
list1.add(\"hello\");
list1.add(\"world\");
list2.add(\"foo\");
list2.add(\"bar\");
list2.add(\"baz\");
System.out.println(\"list1 = \'\" + list1 + \"\', list2 = \'\" + list2 + \"\'\");
System.out.println(\"list1.size() = \" + list1.size() +
\", list2.size() = \" + list2.size());
/* remove an item at an invalid position */
boolean caught = false;
try {
list2.remove(4);
} catch .
Below is a given ArrayList class and Main class Your Dreams Our Mission/tuto...
FOR MORE CLASSES VISIT
www.tutorialoutlet.com
Below is a given ArrayList class and Main class in search algorithms. Please modify the existing program so it can time the sequential search and the binary search methods several times each for randomly generated values, and record the results in a table. Do not time individual searches, but groups of them. For example, time 100 searches together or 1,000 searches together. Compare the running times of these two search methods that are obtained during the experiment.
Data type list_methods_in_python
Lists in Python can be created using square brackets and allow storing multiple data types. Lists have numerous built-in methods for manipulating list elements and metadata. Common list methods allow adding and removing elements, sorting and reversing lists, copying lists, and accessing elements by index. Lists are a fundamental Python data type for storing and manipulating sequences of data.
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. Other classes are not
modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
import java.util.ArrayList; import java.util.List;public class S.pdf
import java.util.ArrayList;
import java.util.List;
public class SearchList {
/**
* param args
*/
public static void main(String[] args) {
List list = new ArrayList();
list.add(3);
list.add(3);
list.add(1);
System.out.println(\"Search element 3 in list [3,3,1] :\"
+ search(list, 3));
System.out.println(\"Search element 5 in list [3,3,1] :\"
+ search(list, 5));
}
/**
* method to find the index of element in the list
* param list
* param element
* return
*/
public static int search(List list, Object element) {
int index = -1;
if (list == null || element == null)
throw new NullPointerException();
else {
int searchElement = (int) element;
for (int i = 0; i < list.size(); i++) {
int number = (int) list.get(i);
if (number == searchElement) {
index = i;
}
}
}
return index;
}
}
OUTPUT:
Search element 3 in list [3,3,1] :1
Search element 5 in list [3,3,1] :-1
Solution
import java.util.ArrayList;
import java.util.List;
public class SearchList {
/**
* param args
*/
public static void main(String[] args) {
List list = new ArrayList();
list.add(3);
list.add(3);
list.add(1);
System.out.println(\"Search element 3 in list [3,3,1] :\"
+ search(list, 3));
System.out.println(\"Search element 5 in list [3,3,1] :\"
+ search(list, 5));
}
/**
* method to find the index of element in the list
* param list
* param element
* return
*/
public static int search(List list, Object element) {
int index = -1;
if (list == null || element == null)
throw new NullPointerException();
else {
int searchElement = (int) element;
for (int i = 0; i < list.size(); i++) {
int number = (int) list.get(i);
if (number == searchElement) {
index = i;
}
}
}
return index;
}
}
OUTPUT:
Search element 3 in list [3,3,1] :1
Search element 5 in list [3,3,1] :-1.
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Write a JAVA LinkedListRec class that has the following methods: size, empty, insertBefore,
insertAfter, addAtHead, addAtEnd, remove, replace, peekFront, peekEnd, removeFront,
removeEnd, toString. Use recursion to implement most of these methods. Write a driver to test
your implemented LinkedListRec class methods.
Solution
import java.util.Scanner;
public class LinkedListRec {
int data;
LinkedListRec prev=null,next=null;
int size(LinkedListRec l)//method which returns the length of the list
{
if(l==null)return 0;
return 1+size(l.next);
}
boolean empty(LinkedListRec l)//method checks whether the list is empty or not...
{
if(l==null)return true;
else return false;
}
LinkedListRec insertBefore(LinkedListRec l,int value,int num_insertbefore)//method which
adds a new number before the given number..
{
if(l==null)return l;
if(l.data == num_insertbefore)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.prev==null)
{
n.next = l;
l=n;
}
else
{
n.prev = l.prev;
n.next= l;
l.prev = n;
}
return l;
}
return insertBefore(l.next,value,num_insertbefore);
}
LinkedListRec insertAfter(LinkedListRec l,int value,int num_insertafter)//method which adds
the new number after the given number
{
if(l==null)return l;
if(l.data == num_insertafter)
{
LinkedListRec n = new LinkedListRec();
n.data = value;
if(l.next==null)
{
l.next = n;
n.prev = l;
}
else
{
n.next = l.next;
l.next.prev = n;
n.prev = l;
}
return l;
}
return insertAfter(l.next,value,num_insertafter);
}
LinkedListRec addAtHead(LinkedListRec l,int value)//method which adds a new number at
the head position of the list...
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.next = l;
l=n;
return l;
}
LinkedListRec addAtEnd(LinkedListRec l,int value)//method which adds a new number at
the end position of the list...
{
if(l==null){ l = new LinkedListRec();l.data = value;return l;}
if(l.next==null)
{
LinkedListRec n = new LinkedListRec();
n.data=value;
n.prev = l;
l.next = n;
return l;
}
return addAtEnd(l.next,value);
}
LinkedListRec remove(LinkedListRec l,int value)//method which removes given numbet
from the list....
{
if(l==null)return l;
if(l.data == value)
{
if(l.prev!=null){
l.prev = l.next;
}
else
l=l.next;
return l;
}
return remove(l.next,value);
}
boolean replace(LinkedListRec l,int value,int newvalue)//method which replaces current
number with new number,...
{
if(l==null)return false;
if(l.data == value)
{
l.data = newvalue;
return true;
}
return replace(l.next,value,newvalue);
}
int peekFront(LinkedListRec l)//method which returns the first value of the list...
{
if(l!=null)
return l.data;
else return -1;
}
int peekEnd(LinkedListRec l)//method which returns the last value of the list........
{
if(l==null)return -1;
if(l.next == null)return l.data;
return peekEnd(l.next);
}
LinkedListRec removeFront(LinkedListRec l)//method which removes the first element of the
list..
{
if(l==null)return l;
l=l.next;
return l;
}
boolean removeEnd(LinkedListRec l)//method which removes the last element o.
dynamicList.ppt
The document discusses implementing a sorted linked list data structure in C++. It describes how to insert a new node into the linked list in the correct sorted position by finding the previous and current nodes between which the new node should be inserted. The key steps are to create a new node, find the previous and current nodes using a while loop, and connect the new node by updating the next pointers of the previous and current nodes.
Code
The document discusses several sorting and search algorithms:
1) Binary search and binary search with recursion find a target value in a sorted array by repeatedly dividing the array range in half and comparing the middle element to the target.
2) Linear search compares each element of an unsorted array to the target.
3) Insertion sort divides an array into sorted and unsorted parts, inserting elements from the unsorted part into the sorted part.
4) Selection sort finds the minimum element in the unsorted part and swaps it into the sorted position in each iteration.
5) Merge sort recursively splits the array into single elements and then merges the sorted parts back together.
Question 1,2,4 ------------------------------------Please check.pdf
Question 1,2,4 :-
-----------------------------------
Please check comments in Programme
#include
/**
* Method for Linear Search
* Loop through given array and search for given key
* IF found return index and stop
* else -1 will be returned at the end
*
*/
int search(int array[],int key,int size){
int index = -1;
for (int c = 0; c < size; c++)
{
if (array[c] == key) /* if required element found */
{
printf(\"%d is present at location %d.\ \", key, c+1);
index = c;
break;
}
}
if(index == -1)
printf(\"%d is not found.\ \", key);
return index;
}
/**
* Function for Binary search
* Binary search is used only for sorted arrays
* Check key with element at middle position
* if key == then return middle positon
* if key > middle position , apply same for sub array range from [middle...last]
* if key < middle position , apply same for sub array range from [0..middle]
*
*/
int binary_search(int array[],int key,int start,int end){
int index = -1;
int first = start;
int last = end;
int middle = (first+last)/2;
while (first <= last) {
//Print array between first nad last for each step
printf(\"Start binary search step.\ \");
for(int i = first ; i < last ; i++){
printf(\"Binary search step element.%d\ \",array[i]);
}
printf(\"Stop binary search step.\ \");
if (array[middle] < key)
first = middle + 1;
else if (array[middle] == key) {
index = middle;
printf(\"%d found at location %d.\ \", key, middle+1);
break;
}
else
last = middle - 1;
middle = (first + last)/2;
}
return index;
}
/**
* Recursive linear search
* Instead of for loop call same method with next index
* first pass 0, check if key found at index 0, if not found call same method with index 1 .....
*/
int linear_search_recursive(int array[],int key,int size,int index){
if(array[index] == key){
printf(\"%d found at location %d.\ \",key, index);
return index;
}
else if (index >= size-1){
return -1;
}
else{
return linear_search_recursive(array,key,size,++index);
}
}
/**
* Recursive Binary Search
* Recursively call Binary Search , check key found at element middle
* if key == then return middle positon
* if key > middle position , call recursive method for sub array range from [middle...last]
* if key < middle position , call recursive method for sub array range from [0..middle]
*/
int binary_search_recursive(int array[],int key,int start,int end){
//Key not found
if(start> end){
return -1;
}
int index = -1;
int first = start;
int last = end;
int middle = (first+last)/2;
//Print array between first nad last for each step
printf(\"Start binary search step.\ \");
for(int i = first ; i < last ; i++){
printf(\"Binary search step element.%d\ \",array[i]);
}
printf(\"Stop binary search step.\ \");
if (array[middle] < key){
first = middle + 1;
return binary_search_recursive(array,key,first,last) ;
}else if (array[middle] == key) {
printf(\"%d found at location %d.\ \", key, middle+1);
return middle;
}
else{
last = middle - 1;
return binary_search_recursive(array,key,first,last) ;
}
return -1;
}
/**
*Function t.
Unit 4 python -list methods
The document provides information on various list methods in Python like list creation, accessing items from lists, slicing lists, and common list methods like append(), count(), extend(), index(), insert(), pop(), copy(), remove(), reverse(), and sort(). It includes the syntax and examples to demonstrate how each method works on lists. Various programs are given to showcase inserting, removing, sorting, copying and reversing elements in lists using the different list methods.
SOURCE CODEimport java.util.Iterator;public class CircularLinke.pdf
SOURCE CODE:
import java.util.Iterator;
public class CircularLinkedList implements Iterable {
Node head , tail;
int size;
CircularLinkedList() {
head = null;
tail = null;
size = 0;
}
public boolean add(E e) {
Node ele = new Node(e);
ele.next = head;
if(head == null)
{
head = ele;
ele.next = head;
tail = head;
}
else
{
tail.next = ele;
tail = ele;
}
size++;
return true;
}
public boolean add(int index, E e){
Node ele = new Node(e);
Node ptr = head;
index = index - 1 ;
for (int i = 1; i < size - 1; i++)
{
if (i == index)
{
Node tmp = ptr.next;
ptr.next = ele;
ele.next = tmp;
break;
}
ptr = ptr.next;
}
size++ ;
return true;
}
private Node getNode(int index ) {
return null;
}
public E remove(int index) {
Node ret;
if (size == 1 && index == 1)
{
ret = head;
head = null;
tail = null;
size = 0;
return ret.getElement();
}
if (index == 1)
{
ret = head;
head = head.next;
tail.next = head;
size--;
return ret.getElement();
}
if (index == size)
{
Node s = head;
Node t = head;
while (s != tail)
{
t = s;
s = s.next;
}
ret = tail;
tail = head;
tail = t;
size --;
return ret.getElement();
}
Node ptr = head;
index = index - 1 ;
for (int i = 1; i < size - 1; i++)
{
if (i == index)
{
Node tmp = ptr.next;
tmp = tmp.next;
ptr.next = tmp;
break;
}
ptr = ptr.next;
}
size-- ;
return ptr.getElement();
}
public String toString()
{
Node current = head;
String result = \"\";
if(size == 0){
return \"\";
}
if(size == 1) {
return head.getElement().toString();
}
else{
do{
result = result + current.getElement().toString();
result = result + \" ==> \";
current = current.next;
} while(current != head);
}
return result;
}
public Iterator iterator() {
return new ListIterator();
}
private class ListIterator implements Iterator{
Node nextItem;
Node prev;
int index;
@SuppressWarnings(\"unchecked\")
public ListIterator(){
nextItem = (Node) head;
index = 0;
}
public boolean hasNext() {
return size != 0;
}
public E next() {
prev = nextItem;
nextItem = nextItem.next;
index = (index + 1) % size;
return prev.getElement();
}
public void remove() {
int target;
if(nextItem == head) {
target = size - 1;
} else{
target = index - 1;
index--;
}
CircularLinkedList.this.remove(target); //calls the above class
}
}
// Solve the problem in the main method
// The answer of n = 13, k = 2 is
// the 11th person in the ring (index 10)
public static void main(String[] args){
CircularLinkedList l = new CircularLinkedList();
int n=13;
int k=2;
for(int i=1;i<=n;i++)
l.add(Integer.valueOf(i));
int j = 13,i=0;
while(j>0)
{
System.out.println(l.toString());
i = i + k;
if(i>j)
i = k;
l.remove(i);
j--;
}
}
}
OUTPUT:
1 ==> 2 ==> 3 ==> 4 ==> 5 ==> 6 ==> 7 ==> 8 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 5 ==> 6 ==> 7 ==> 8 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 6 ==> 7 ==> 8 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 6 ==> 7 ==> 9 ==> 10 ==> 11 ==> 12 ==> 13 ==>
1 ==> 3 ==> 4 ==> 6 ==> 7 ==> 9 ==> 10 ==> 12 ==> 13 ==>
1 ==> 4 ==> 6 ==> 7 ==> 9 ==> 10 ==> 12 ==> 13 ==>
1 ==> 4.
Write a program to find the number of comparisons using the binary se.docx
The document describes a program to compare the number of comparisons needed for binary search versus sequential search on an array of 1000 randomly generated elements. It includes functions to fill the array, perform sequential, binary, and binary with sequential search, and output the number of comparisons for each. The program prompts the user for elements to search for in different locations of the array and outputs the results.
Kotlin collections
The document discusses Kotlin collections and aggregate operations on collections. It explains that Kotlin collections can be mutable or immutable, and by default collections are immutable unless specified as mutable. It then covers various aggregate operations that can be performed on collections like any, all, count, fold, foldRight, forEach, max, min, none etc and provides code examples for each operation.
Linked List
Singly linked lists, doubly linked lists, and circular linked lists are types of linked data structures. Singly linked lists contain nodes with a data field and a next pointer. Doubly linked lists contain additional previous pointers. Circular linked lists connect the last node to the first node, making the list cyclic. Pseudocode is provided for common linked list operations like insertion, deletion, searching, on different positions in the lists.
lists8.pptx of chapter 12 IP Basic Python
This document discusses lists in Python. It begins by defining lists as collections of items indexed from 0 to n-1, where n is the number of items. It then covers creating and initializing lists, accessing list items using indexes and slicing, updating and manipulating lists, adding and deleting items from lists, basic list operations, and important list methods. It provides examples for each topic and ends with some example programs involving lists like finding the largest/mean value in a list and linear search.
Similar to eOverride - Return the number of elenents in this list -- public int.docx (20)
Please help solve this in C++ So the program is working fin.pdf
Please help solve this in C++ So the program is working fin.pdf
Implement the additional 5 methods as indicated in the LinkedList fi.pdf
Implement the additional 5 methods as indicated in the LinkedList fi.pdf
The MyLinkedList class used in Listing 24.6 is a one-way directional .docx
The MyLinkedList class used in Listing 24.6 is a one-way directional .docx
hi i have to write a java program involving link lists. i have a pro.pdf
hi i have to write a java program involving link lists. i have a pro.pdf
Below is a given ArrayList class and Main class Your Dreams Our Mission/tuto...
Below is a given ArrayList class and Main class Your Dreams Our Mission/tuto...
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. O.pdf
import java.util.ArrayList; import java.util.List;public class S.pdf
import java.util.ArrayList; import java.util.List;public class S.pdf
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Write a JAVA LinkedListRec class that has the following methods siz.pdf
Question 1,2,4 ------------------------------------Please check.pdf
Question 1,2,4 ------------------------------------Please check.pdf
SOURCE CODEimport java.util.Iterator;public class CircularLinke.pdf
SOURCE CODEimport java.util.Iterator;public class CircularLinke.pdf
Write a program to find the number of comparisons using the binary se.docx
Write a program to find the number of comparisons using the binary se.docx
More from akilaha
Exercise 4-1 (Algo) Computing revenues- expenses- and income LO C1 Fil.docx
Exercise 4-1 (Algo) Computing revenues, expenses, and income LO C1 Fill in the blanks in the following separate income statements a through e .
.
Exercise 3- -10 marks- Draw a 4-bit Serial In- Serial Out register usi.docx
Exercise 3. [10 marks] Draw a 4-bit Serial In, Serial Out register using SR flip-flops. For example, the below diagram represents a Parallel In, Parallel Out n -bit register using D flip-flops.
.
Exercise 2-4 At this point- we discussed sequence- decomposition- and.docx
Exercise 2.4 At this point, we discussed sequence, decomposition, and specialization
relations between business processes. Can you think of other types of relations
that are useful to distinguish between processes?
Hint. Think about the purpose of identifying the relations between business
processes.
.
Exercise 2- Apply the following operations in binary system (using 8 b.docx
The document describes binary operations using 8-bit representations: (1) The two's complement of binary 11 is the 8-bit binary number with the bits of 11 flipped and 1 added; (2) Binary addition of 10 and 13 results in the sum of the corresponding bits; (3) Binary multiplication of 6 and 4 results in the product of the corresponding bits.
ExE RCise The Integumentary System Name Ubininebate Basic Structure of.docx
ExE RCise The Integumentary System Name Ubininebate Basic Structure of the Skin 1. Coenplete the following siaterikents ty witing the appoptianewort or alvase on the blank one. 1. The supericalingon of the skin is the comgorad of (B) werdi) 1ssue 2. The deeper region titiae is the compentd of cennective tisuse. 3. The mast numenus cell of the cpidermb s the 4. The two primary layers of the dernis de the deems, composed of areolar connective tosee, and the - denris, coriposed of deroe ereqular connection tiswe. 2. Four protective functions of the shin ate a. i. 3. Usang the key thoices, chease all responses thet apply to the following descriptions. Some tertis are ased more than ance. a. stratum basaln d. streturn hucidum 9 mesicular dermos. b. strotum comeum e. itratum sgitonum c. stratum granulosum. 1. papiliary dirima 1. lejer of tramtucent celt in inick tein contaning dead keratinoevtes 2. two kyers containg dead cebb. 3. dermof layer tespotible for fongerpints 4. epidermal layer exhbiting the most repd celdision 5. layer including seaklike dead ceh, full of keratin, that constantly slovgh off 6. laye named for the numerous granulies present. 7. Locatian of relanosytes and tactie ecithe cial celk: 8. area where wehike pre-keratin filaments fist appeor 9. deep layer of the dermis 10. Lyen that secretes a glyolidid that preventisater loss fom the soin 4. Label the intequmentay strumtures and areas indicated in the diag an 5. Labol the layers of the epidermis in thick ikin. Then, complete the statements that follow. a. Glands that respond to nising andiogen ievels are the glands. bi are epitermal cells that pry a role in the immune response. c. Tactile corpuscles are located in the d. corpuncles are located daep in the dermis: 6. What substance is manufactured in the skin and plays a role in calcium absorption elsewhere in the body? Accessory Organs of the Skin 1 try musdes ataathed to hail foliden, that pull the has uprigh duing fight of toid 2. sweat gand with a role in terotratule cootod. 3. theati formed of bothesthelio and cornactive form 4. Kesi numetous type of medteroduong glind, found manly in te pubic ard axillary meguons 5. prizarily diadherasiniced cels itwo respories from key 6. specalsed norve endings that repond to temperature touch, efc. 7. secretel a liericant for hair and skin 9. Describe two integumentary wasem mechantims thit hede requlate body tempenatuse. 10. Several structures of the haif are losed below. lifentify euch by malching its leter with the applopelate area on the photemicrograph
.
Ex 4- People tend to use lower case letters in computer code to denote.docx
Ex 4. People tend to use lower case letters in computer code to denote variables. Here we sometimes use capital letters such as X . Why do we do that? (Hint: how are rvs denoted in books?)
.
Every employee of the company has access to HRIS of that firm- True Fa.docx
Every employee of the company has access to HRIS of that firm. True False Question 9 (1 point) Work practices means refers to set ways of doing work, True False Question 10 (1 point) Connectivity is one of the technological forces facing Canadian businesses. True False Question 11 (1 point) Absenteeism refers to how many employees got promoted in the company. True False
.
Event A occurs with probability 0-51- Event B occurs with probability.docx
Event A occurs with probability 0.51 . Event B occurs with probability 0.14 . Events A and B are independent. P ( A B ) means "A and B"; P ( A B ) means "A or B". Find: a) P ( A B ) b) P ( A B ) c) P ( A B ) d) P ( A c B )
.
Events A and B are mutually exclusive- Which of the following statemen.docx
Events A and B are mutually exclusive. Which of the following statements is also true? A and B are also independent P ( A B ) = P ( A ) P ( B ) P ( A B ) = P ( A ) + P ( B ) P ( A B ) = P ( A ) + P ( B )
.
Eve has just discovered and decrypted the file that associates each us.docx
Eve has just discovered and decrypted the file that associates each user-id with its 32-bit random salt value, and she has also discovered and decrypted the password file, which contains the salted and hashed passwords for the 100 people in her building. If she has a dictionary of 500,000 words and she is confident all 100 people have passwords from this dictionary, what is the size of her search space for performing a dictionary attack on their passwords?
.
Evaluate the sustainability of IT services- devices and day-to-day ope.docx
Nestle's IT services, devices, and daily operations need to be evaluated for sustainability, including calculating the carbon footprint and electronic waste generated. A report must be written on the carbon footprint and materials used in Nestle's information and communications technology operations. The report must follow the guidelines in Australia's 2010 National Carbon Offset Standard published by the Department of Climate Change and Energy Efficiency.
euil- her tobil oost of producing quith- e- Herneit is C-25-000+509 Ho.docx
euil. her tobil oost of producing quith. e. Herneit is C = 25.000 + 509 How mayy ouits dses Kase need to sal for vertical integraton to be a proftatil decieion?
.
Ethicai hackiers are hered to evaluate and dedend agelnet theats woth.docx
Ethicai hackiers are hered to evaluate and dedend agelnet theats woth the iffe hing organkesis ginatanoain stch 2 Mue aneti stion 3 What boe of hacken are most assedalid win toos afacks, Hestry owet, and waras? The acamtior in Feowningls vided sed asp) 1s dert the wer is a potential nueat and provide an anor code and cialonas autpot ambel Daniet is angaged in "phialing"; wich probably means that he busing. as an arack vedse
.
Essay question - A few years ago Angelina Jolie had a double mastectom.docx
Essay question - A few years ago Angelina Jolie had a double mastectomy because of results from a genetic test. Describe the science of the test and the reason for her decision. Should cancer gene screening tests be a routine part of health care checkups?
Detailed answer in essay format.
.
Essentials of Human Resources Please a new answer not one posted How w.docx
Essentials of Human Resources
Please a new answer not one posted
How would you conduct a complete background investigation on applicants for the job of school bus driver to minimize concerns about negligent hiring?
Essentials of Human Resources
Please a new answer not one posted
.
Essay - How data mining and social network analysis were implemented (.docx
Essay
- How data mining and social network analysis were implemented
(eg: scope of techniques, departmental policies, framework design, roles of employees, departments, reporting)
- Business transformation with data mining and social network analysis as solution
.
Error Control involves taking one of three actions- (1) Toss the frame.docx
Error Control involves taking one of three actions: (1) Toss the frame/packet; (2) asking to resend he frame/packet that was in error; (3) correct the error without retransmission. Discuss the advantages/disadvantages for each of these scenarios.
What is the single greatest advantage of having a checksum for only the IP header?
Why is cyclic redundancy checksum (CRC) implemented for Ethernet and for wireless frames as an error control technique?
.
erieski- 0-470-760-29 fuire in the liot b-2-4 Tres oy.docx
This very short document appears to contain random letters and numbers that do not form coherent words or sentences. It does not provide any clear essential information that could be summarized in 3 sentences or less.
Eroms tle following Triel Bolance of ABC compeny- Prepure Trading and.docx
Eroms tle following Triel Bolance of A BC compeny. Prepure Trading and hofit and loss accounts of the Lear Ended (i) stoch an 3 s 2 Manch 2 wa was value al at h. 150 w . (2) hisurance was frefaid to the extent of you. (3) O/s tiabilitieswene: Salarus Rs 2no. Taxes 130 (4) Defreiate Brilding at 2% P.a.
.
Erika categorized her spending for this month into four categories- Re.docx
Erika categorized her spending for this month into four categories: Rent, Food, Fun, and Other. The percents she spent in each category are pictured here. If Erika spent a total of $2900 this month, how much did she spend on Fun? $ Question Help: Video
.
More from akilaha (20)
Exercise 4-1 (Algo) Computing revenues- expenses- and income LO C1 Fil.docx
Exercise 4-1 (Algo) Computing revenues- expenses- and income LO C1 Fil.docx
Exercise 3- -10 marks- Draw a 4-bit Serial In- Serial Out register usi.docx
Exercise 3- -10 marks- Draw a 4-bit Serial In- Serial Out register usi.docx
Exercise 2-4 At this point- we discussed sequence- decomposition- and.docx
Exercise 2-4 At this point- we discussed sequence- decomposition- and.docx
Exercise 2- Apply the following operations in binary system (using 8 b.docx
Exercise 2- Apply the following operations in binary system (using 8 b.docx
ExE RCise The Integumentary System Name Ubininebate Basic Structure of.docx
ExE RCise The Integumentary System Name Ubininebate Basic Structure of.docx
Ex 4- People tend to use lower case letters in computer code to denote.docx
Ex 4- People tend to use lower case letters in computer code to denote.docx
Every employee of the company has access to HRIS of that firm- True Fa.docx
Every employee of the company has access to HRIS of that firm- True Fa.docx
Event A occurs with probability 0-51- Event B occurs with probability.docx
Event A occurs with probability 0-51- Event B occurs with probability.docx
Events A and B are mutually exclusive- Which of the following statemen.docx
Events A and B are mutually exclusive- Which of the following statemen.docx
Eve has just discovered and decrypted the file that associates each us.docx
Eve has just discovered and decrypted the file that associates each us.docx
Evaluate the sustainability of IT services- devices and day-to-day ope.docx
Evaluate the sustainability of IT services- devices and day-to-day ope.docx
euil- her tobil oost of producing quith- e- Herneit is C-25-000+509 Ho.docx
euil- her tobil oost of producing quith- e- Herneit is C-25-000+509 Ho.docx
Ethicai hackiers are hered to evaluate and dedend agelnet theats woth.docx
Ethicai hackiers are hered to evaluate and dedend agelnet theats woth.docx
Essay question - A few years ago Angelina Jolie had a double mastectom.docx
Essay question - A few years ago Angelina Jolie had a double mastectom.docx
Essentials of Human Resources Please a new answer not one posted How w.docx
Essentials of Human Resources Please a new answer not one posted How w.docx
Essay - How data mining and social network analysis were implemented (.docx
Essay - How data mining and social network analysis were implemented (.docx
Error Control involves taking one of three actions- (1) Toss the frame.docx
Error Control involves taking one of three actions- (1) Toss the frame.docx
erieski- 0-470-760-29 fuire in the liot b-2-4 Tres oy.docx
erieski- 0-470-760-29 fuire in the liot b-2-4 Tres oy.docx
Eroms tle following Triel Bolance of ABC compeny- Prepure Trading and.docx
Eroms tle following Triel Bolance of ABC compeny- Prepure Trading and.docx
Erika categorized her spending for this month into four categories- Re.docx
Erika categorized her spending for this month into four categories- Re.docx
Recently uploaded
ANATOMY AND BIOMECHANICS OF HIP JOINT.pdf
it describes the bony anatomy including the femoral head , acetabulum, labrum . also discusses the capsule , ligaments . muscle that act on the hip joint and the range of motion are outlined. factors affecting hip joint stability and weight transmission through the joint are summarized.
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Aberdeen
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is special for master students (MIBS & MIFB) in UUM. Also useful for readers who are interested in the topic of contemporary Islamic banking.
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
Denis is a dynamic and results-driven Chief Information Officer (CIO) with a distinguished career spanning information systems analysis and technical project management. With a proven track record of spearheading the design and delivery of cutting-edge Information Management solutions, he has consistently elevated business operations, streamlined reporting functions, and maximized process efficiency.
Certified as an ISO/IEC 27001: Information Security Management Systems (ISMS) Lead Implementer, Data Protection Officer, and Cyber Risks Analyst, Denis brings a heightened focus on data security, privacy, and cyber resilience to every endeavor.
His expertise extends across a diverse spectrum of reporting, database, and web development applications, underpinned by an exceptional grasp of data storage and virtualization technologies. His proficiency in application testing, database administration, and data cleansing ensures seamless execution of complex projects.
What sets Denis apart is his comprehensive understanding of Business and Systems Analysis technologies, honed through involvement in all phases of the Software Development Lifecycle (SDLC). From meticulous requirements gathering to precise analysis, innovative design, rigorous development, thorough testing, and successful implementation, he has consistently delivered exceptional results.
Throughout his career, he has taken on multifaceted roles, from leading technical project management teams to owning solutions that drive operational excellence. His conscientious and proactive approach is unwavering, whether he is working independently or collaboratively within a team. His ability to connect with colleagues on a personal level underscores his commitment to fostering a harmonious and productive workplace environment.
Date: May 29, 2024
Tags: Information Security, ISO/IEC 27001, ISO/IEC 42001, Artificial Intelligence, GDPR
-------------------------------------------------------------------------------
Find out more about ISO training and certification services
Training: ISO/IEC 27001 Information Security Management System - EN | PECB
ISO/IEC 42001 Artificial Intelligence Management System - EN | PECB
General Data Protection Regulation (GDPR) - Training Courses - EN | PECB
Webinars: https://pecb.com/webinars
Article: https://pecb.com/article
-------------------------------------------------------------------------------
For more information about PECB:
Website: https://pecb.com/
LinkedIn: https://www.linkedin.com/company/pecb/
Facebook: https://www.facebook.com/PECBInternational/
Slideshare: http://www.slideshare.net/PECBCERTIFICATION
Community pharmacy- Social and preventive pharmacy UNIT 5
Covered community pharmacy topic of the subject Social and preventive pharmacy for Diploma and Bachelor of pharmacy
BBR 2024 Summer Sessions Interview Training
Qualitative research interview training by Professor Katrina Pritchard and Dr Helen Williams
DRUGS AND ITS classification slide share
Any substance (other than food) that is used to prevent, diagnose, treat, or relieve symptoms of a
disease or abnormal condition
Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
Let’s explore the intersection of technology and equity in the final session of our DEI series. Discover how AI tools, like ChatGPT, can be used to support and enhance your nonprofit's DEI initiatives. Participants will gain insights into practical AI applications and get tips for leveraging technology to advance their DEI goals.
How to Fix the Import Error in the Odoo 17
An import error occurs when a program fails to import a module or library, disrupting its execution. In languages like Python, this issue arises when the specified module cannot be found or accessed, hindering the program's functionality. Resolving import errors is crucial for maintaining smooth software operation and uninterrupted development processes.
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...National Information Standards Organization (NISO)
This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.Digital Artifact 1 - 10VCD Environments Unit
Digital Artifact 1 - 10VCD Environments Unit - NGV Pavilion Concept Design
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS Template 2023-2024 by: Irene S. Rueco
Recently uploaded (20)
Pride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School District
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
What is Digital Literacy? A guest blog from Andy McLaughlin, University of Ab...
Digital Artefact 1 - Tiny Home Environmental Design
Digital Artefact 1 - Tiny Home Environmental Design
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Azure Interview Questions and Answers PDF By ScholarHat
Azure Interview Questions and Answers PDF By ScholarHat
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
ISO/IEC 27001, ISO/IEC 42001, and GDPR: Best Practices for Implementation and...
Community pharmacy- Social and preventive pharmacy UNIT 5
Community pharmacy- Social and preventive pharmacy UNIT 5
Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
Executive Directors Chat Leveraging AI for Diversity, Equity, and Inclusion
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
RPMS TEMPLATE FOR SCHOOL YEAR 2023-2024 FOR TEACHER 1 TO TEACHER 3
eOverride - Return the number of elenents in this list -- public int.docx
- 1. eOverride / Return the number of elenents in this list */ public int size() f } return size; public static void main(String[] args) & I/ Create a list var gyLinkedList = new MyLinkedListeinteger > ( 1 ) //add 4 elements for (int 1 = 1 ; 1 < 5 ; 1 + + ) t myLinkedist.add(1); size: + + nyLinkedlist.s1ze + "(n") //add 4 more in tront of the list for ( int 1 = 1 ; 1 < 5 : 1 + 4 ) { myLinkedList, oddFirst (10+1): Systen, out,print ln("List after modifieation " + myLinkedList + ") size: " + nyLinkedList.size + " ( n ) : // remove 3 last elenents for ( int 1 = 0 ; 1 < 3 ; 1 + t ) < yylinkedList, renoveLast (): System, out.printin("List after renoval: " + mylinkedList + ".) head elenent = + eytinkedist, head, elewent + tall elenent next, +((erlinkedlist, tail, next I nutl)r ayLinkedList, tail, next, elenent, tostring(): "nuLl") , stzee "+ myLinkedList.s1ze + "(n")s