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ЛЕКЦ №4. Äèôôåðåíöèàë òýãøèòãýë.
Äèôôåðåíöèàë òýãøèòãýëä õ¿ðãýäýã áîäëîãóóä.
ßíç á¿ðèéí ¿çýãäëèéã ñóäëàõàä ¿ë õàìààðàõ õóâüñàã÷ x , ò¿¿íýýñ õàìààðñàí
)
(x
y
y = ôóíêö áîëîí ò¿¿íèé óëàìæëàëóóäûã àãóóëñàí òýãøèòãýë ýëáýã
òîõèîëääîã. Y¿íèéã n-ð ýðýìáèéí äèôôåðåíöèàë òýãøèòãýë ãýýä
0
)
,
,
"
,
'
,
,
( )
(
=
n
y
y
y
y
x
F  åðºíõèé õýëáýðòýé áè÷èæ áîëíî. Óã òýãøèòãýëä
îðëóóëàõàä àäèëòãàë áîëãîõ ôóíêöèéã äèôôåðåíöèàë òýãøèòãýëèéí øèéä ãýíý.
Æèøýý 56: Äóðûí )
;
( y
x öýã äýýðõè ø¿ðãýã÷èéí ºíöãèéí êîýôôèöèåíò íü x
2
áàéõ, )
0
;
0
(
O öýãèéã äàéðñàí ìóðóéí òýãøèòãýëèéã îë.
)
(x
y
y = íü áîäëîãûí íºõöëèéã õàíãàñàí ìóðóé áàéã. 
=
= .
' k
tg
y  .
2
' x
y =
áóþó 
= .
2x
dx
dy
.
2xdx
dy = áîëíî. Ñ¿¿ë÷èéí òýíöýòãýëèéã ãèø¿¿í÷ëýí
èíòåãðàë÷èëáàë .
2 2
c
x
xdx
y +
=
=  áóþó .
2
c
x
y +
=
Çóðàã 16.
)
0
;
0
(
O öýãèéã äàéðàõ òóë )
0
(
0 y
= áóþó 
+
= c
2
0
0 0
=
c áîëæ .
2
x
y =
Æèøýý 57: ׺뺺ò óíàëòààð óíàæ áàéãàà áèåèéí õóðä t
g
v 
= áîë çàìûí
òîìú¸îã îë. ).
8
.
9
( 
g
.
' v
s = áóþó 

= .
t
g
v 

= .
t
g
dt
ds
.
gtdt
ds = áîëíî. Ãèø¿¿í÷ëýí
èíòåãðàë÷èëáàë .
2
2
c
gt
tdt
g
gtdt
s +
=
=
= 
 áóþó .
2
2
c
gt
s +
= 0
=
t ¿åä 0
=
s òóë

+
= .
2
0
0
2
c
g
0
=
c áîëæ .
2
2
gt
s =
0
)
'
,
,
( =
y
y
x
F òýãøèòãýëèéã I ýðýìáèéí äèôôåðåíöèàë òýãøèòãýë ãýíý. )
,
(
' y
x
f
y =
òýãøèòãýëèéã óëàìæëàëûíõàà õóâüä áîäîãäñîí I ýðýìáèéí äèôôåðåíöèàë
òýãøèòãýë ãýíý. Äýýðõè æèøýýí¿¿äýýñ ¿çýõýä I ýðýìáèéí äèôôåðåíöèàë
òýãøèòãýëèéí åðºíõèé øèéä )
,
( c
x
y 
= õýëáýðòýé áàéíà. c äóðûí òîãòìîë òîî
òóë äèôôåðåíöèàë òýãøèòãýëèéí øèéä òºãñãºëã¿é îëîí áàéíà. (Òóõàéëáàë
Çóðàã 16). Äóðûí òîãòìîë c -èéí òîäîðõîé óòãàíä ãàðàõ øèéäèéã òóõàéí øèéä
ãýíý. Åðºíõèé øèéäýýñ òóõàéí øèéäèéã ñîíãîõûí òóëä íýìýëò íºõöºë õýðýãòýé.
Èéì íºõöºëèéã àíõíû íºõöºë ãýýä ;
0
0
y
y x
x
=
=
ãýæ áè÷íý.
Õóâüñàã÷ íü ÿëãàãäàõ äèôôåðåíöèàë òýãøèòãýë.
Òîäîðõîéëîëò: 0
)
(
)
(
)
(
)
( 2
2
1
1 =

+
 dy
y
x
f
dx
y
x
f 
 õýëáýðèéí òýãøèòãýëèéã I
ýðýìáèéí õóâüñàã÷ íü ÿëãàãäàõ äèôôåðåíöèàë òýãøèòãýë (ÕßÄÒ) ãýíý.
Óã òýãøèòãýëèéã 0
)
(
)
(
)
(
)
(
1
2
2
1
=
+ dy
y
y
dx
x
f
x
f


õýëáýðò øèëæ¿¿ëýýä ãèø¿¿í÷ëýí
èíòåãðàë÷èëáàë ;
)
(
)
(
)
(
)
(
1
2
2
1
c
dy
y
y
dx
x
f
x
f
=
+ 
 

ãýæ åðºíõèé øèéä îëäîíî.
Æèøýý 58: ;
0
=
+ ydy
xdx äèôôåðåíöèàë òýãøèòãýëèéã áîä.

=
+ 0
ydy
xdx 
=
+ 
 c
ydy
xdx

=
+ c
y
x
2
2
2
2
.
2
2
c
y
x =
+
Æèøýý 59: ;
ydx
xdy = äèôôåðåíöèàë òýãøèòãýëèéã áîä.

= ydx
xdy 
=
x
dx
y
dy

= 
 x
dx
y
dy

+
= c
x
y ln
ln 
+
= c
x
y ln
ln
ln

= cx
y ln
ln .
cx
y =
Áîäëîãî 4: (Áèåèéí õºðºõ õóóëü). Áèåèéí õºðºõ õóðä íü îð÷íû òåìïåðàòóð áà
áèåèéí òåìïåðàòóðûí ÿëãàâàðòàé ïðîïîðöèîíàëü áàéíà. Òàñàëãààíû
òåìïåðàòóð C

20 áàéã. Óã òàñàëãààíä áàéãàà áèå 20 ìèíóòàä C

100 -ýýñ C

60
òåìïåðàòóðòàé áîëñîí áîë áèåèéí õºðºõ õóóëèéã îë.
T - t ìîìåíò äàõü áèåèéí òåìïåðàòóð, t - õóãàöàà ãýâýë )
(t
T
T = íü áèäíèé
îëîõ ¸ñòîé ôóíêö þì.
Óã ôóíêöèéí õóâüä )
20
( C
T
k
dt
dT 
−
= òýãøèòãýë, ;
100
0
=
=
t
T áà ;
60
20
=
=
t
T íýìýëò
íºõöë¿¿ä áèåëíý. Ýíä k - ïðîïîðöèîíàëèéí êîýôôèöèåíò.

−
= )
20
( C
T
k
dt
dT 

=
−
kdt
T
dT
20

=
− 
 dt
k
T
dT
20

+
=
− c
kt
T 20
ln

+
=
− c
e
T kt
ln
ln
20
ln 
=
− kt
ce
T 20 .
20 kt
ce
T +
= ;
100
0
=
=
t
T ãýäãýýñ

+
= 0
20
100 ce .
80
=
c áîëæ ( ).
80
20
t
k
e
T +
= ;
60
20
=
=
t
T ãýäãýýñ
( ) 
+
=
20
80
20
60 k
e 
=
−
20
1
2
k
e .
2
80
20 20
t
T
−

+
= áîëíî.
Áîäëîãî 5: (Öàöðàã èäýâõò çàäðàëûí õóóëü). Ðàäèéí çàäðàëûí õóðä íü
òóõàéí ìîìåíò äàõü ò¿¿íèé ìàññòàé ïðîïîðöèîíàëü áàéíà. Àíõ ðàäè 0
m
ìàññòàé áàéñàí áà çàäàð÷ ýõýëñýíýýñ õîéø 1590 æèëèéí (õàãàñ çàäðàëûí æèë)
äàðàà
2
0
m
ìàññòàé áîëñîí áîë çàäðàëûí õóóëèéã îë.
X - t ìîìåíò äàõü ðàäèéí ìàññ, t - õóãàöàà ãýâýë )
(t
X
X = íü áèäíèé îëîõ
¸ñòîé ôóíêö.









=
=
=
=
=
2
0
1590
0
0
m
X
m
X
kX
dt
dX
t
t

= kX
dt
dX

= kdt
X
dX

= 
 dt
k
X
dX
;
kt
ce
X = 
=
= 0
0
m
X t

= 0
0
k
ce
m ;
0
m
c =
болж ;
0
kt
e
m
X = 
=
=
2
0
1590
m
X t

= k
e
m
m 1590
0
0
2

=
−
1590
1
2
k
e ;
2 1590
0
t
m
X
−

= болно.
Áîäëîãî 6: (Áàêòåðèéí ºñºõ õóóëü). Áàêòåðèéí ºñºõ õóóëü íü ò¿¿íèé òîî
õýìæýýòýé ïðîïîðöèîíàëü áàéíà. Àíõ 100 áàêòåð áàéãààä 4-í öàãèéí äàðàà
ãóðàâ äàõèí ºññºí áîë ò¿¿íèé ºñºõ õóóëèéã îë. 8 öàãèéí äàðààõü áàêòåðèéí òîîã
îë.
X - t ìîìåíò äàõü áàêòåðèéí òîî, t - õóãàöàà ãýâýë )
(t
X
X = íü îëîõ ¸ñòîé
ôóíêö.







=
=
=
=
=
300
100
4
0
t
t
X
X
kX
dt
dX

= kX
dt
dX

= kdt
X
dX

= 
 dt
k
X
dX
;
kt
ce
X = 
=
=
100
0
t
X 
= 0
100 k
ce
;
100
=
c болж ;
100 kt
e
X = 
=
=
300
4
t
X 
= k
e4
100
300 
= 4
1
3
k
e ;
3
100 4
t
X 
= болно.
;
8
=
t үед .
900
3
100
3
100 2
4
8
=

=

=
X
Áîäëîãî 7: (Óóñìàëûí êîíöåíòðàöè). Ñàâàíä 10%-èéí 100 ëèòð äàâñíû
óóñìàë áàéâ. Ìèíóò á¿ðä 30ë óñ ñàâàíä îðæ, 20ë óóñìàë ãàäàãøèëæ áàéâàë t
ìèíóòàä ñàâàíä áàéãàà äàâñíû õýìæýýã îë.
Çóðàã 17.
X - t ìîìåíò äàõü äàâñíû õýìæýý, t - õóãàöàà ãýâýë )
(t
X
X = íü îëîõ ¸ñòîé
ôóíêö.
t ìîìåíò äàõü óóñìàëûí õýìæýý
;
10
100
20
30
100 t
t
t
v +
=
−
+
= áàéíà.
t ìîìåíò äàõü äàâñíû õýìæýý
;
20
10
100
dt
t
X

+
áàéíà.
Äàâñíû ººð÷ëºëò ;
10
2
t
Xdt
dX
+
=
− áàéíà.

+
=
−
t
Xdt
dX
10
2

+
−
=
t
dt
X
dX
10
2
;
)
10
( 2
t
c
X
+
= 
=
=
10
0
t
X 
+
= 2
)
0
10
(
10
c
;
1000
=
c
болж ;
)
10
(
1000
2
t
X
+
=
Áîäëîãî 8: (II ýðýìáèéí õèìèéí óðâàë).
.
5
2
3
5
2
3
спирт
Этилийн
натри
Ацетат
гидрооксид
Натрийн
эфир
цуугийн
Этилийн
OH
H
C
COONa
CH
NaOH
H
COOC
CH +
→
+
Äýýðõè õèìèéí óðâàëûí õóâüä àíõ ýòèë öóóãèéí ýôèð 0.01, íàòðèéí ãèäðîîêñèä
0.002 õýìæýýòýé áàéñàí áà 23 ìèíóòûí äàðàà ýòèë öóóãèéí ýôèðèéí 10% íü
õîðîãäñîí áîë ò¿¿íèé 15% íü õîðîãäîõ õóãàöààã îë.
Ñàíàìæ: Õî¸ð áîäèñ èæèë õýìæýýòýé õîðîãäîíî. (Èæèë õóâèàð áèø).
X - t ìîìåíò äàõü ýòèë öóóãèéí ýôèðèéí õýìæýý, t - õóãàöàà ãýâýë )
(t
X
X = íü
îëîõ ¸ñòîé ôóíêö.
t ìîìåíò äàõü óðâàëûí õóðä .
dt
dX
II ýðýìáèéí õèìèéí óðâàëûí õóâüä
).
002
.
0
)(
01
.
0
( X
X
k
dt
dX
−
−
= áàéíà.

−
−
= )
002
.
0
)(
01
.
0
( X
X
k
dt
dX

=
−
−
kdt
X
X
dX
)
002
.
0
)(
01
.
0
(

=
−
− 
 dt
k
X
X
dX
)
002
.
0
)(
01
.
0
(
;
01
.
0
002
.
0
ln
125 c
kt
X
X
+
=
−
−
− 
=
=
0
0
t
X ;
2
.
0
ln
125
−
=
c
болж
;
2
.
0
ln
125
01
.
0
002
.
0
ln
125 −
=
−
−
− kt
X
X
буюу
.
002
.
0
)
01
.
0
(
2
.
0
ln
125 kt
X
X
=
−
−

=
=
001
.
0
23
t
X 
=
−
−
k
23
001
.
0
002
.
0
)
001
.
0
01
.
0
(
2
.
0
ln
125 
= ;
8
.
1
ln
23
125
k
.
8
.
1
ln
23
125
002
.
0
)
01
.
0
(
2
.
0
ln
125 t
X
X
=
−
−
;
0015
.
0
=
X үед 
=
−
−
.
8
.
1
ln
23
125
0015
.
0
002
.
0
)
0015
.
0
01
.
0
(
2
.
0
ln
125 t
9
.
47

t мин.

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ЛЕКЦ №4.pdf

  • 1. ЛЕКЦ №4. Äèôôåðåíöèàë òýãøèòãýë. Äèôôåðåíöèàë òýãøèòãýëä õ¿ðãýäýã áîäëîãóóä. ßíç á¿ðèéí ¿çýãäëèéã ñóäëàõàä ¿ë õàìààðàõ õóâüñàã÷ x , ò¿¿íýýñ õàìààðñàí ) (x y y = ôóíêö áîëîí ò¿¿íèé óëàìæëàëóóäûã àãóóëñàí òýãøèòãýë ýëáýã òîõèîëääîã. Y¿íèéã n-ð ýðýìáèéí äèôôåðåíöèàë òýãøèòãýë ãýýä 0 ) , , " , ' , , ( ) ( = n y y y y x F  åðºíõèé õýëáýðòýé áè÷èæ áîëíî. Óã òýãøèòãýëä îðëóóëàõàä àäèëòãàë áîëãîõ ôóíêöèéã äèôôåðåíöèàë òýãøèòãýëèéí øèéä ãýíý. Æèøýý 56: Äóðûí ) ; ( y x öýã äýýðõè ø¿ðãýã÷èéí ºíöãèéí êîýôôèöèåíò íü x 2 áàéõ, ) 0 ; 0 ( O öýãèéã äàéðñàí ìóðóéí òýãøèòãýëèéã îë. ) (x y y = íü áîäëîãûí íºõöëèéã õàíãàñàí ìóðóé áàéã.  = = . ' k tg y  . 2 ' x y = áóþó  = . 2x dx dy . 2xdx dy = áîëíî. Ñ¿¿ë÷èéí òýíöýòãýëèéã ãèø¿¿í÷ëýí èíòåãðàë÷èëáàë . 2 2 c x xdx y + = =  áóþó . 2 c x y + = Çóðàã 16. ) 0 ; 0 ( O öýãèéã äàéðàõ òóë ) 0 ( 0 y = áóþó  + = c 2 0 0 0 = c áîëæ . 2 x y = Æèøýý 57: ׺뺺ò óíàëòààð óíàæ áàéãàà áèåèéí õóðä t g v  = áîë çàìûí òîìú¸îã îë. ). 8 . 9 (  g . ' v s = áóþó   = . t g v   = . t g dt ds . gtdt ds = áîëíî. Ãèø¿¿í÷ëýí èíòåãðàë÷èëáàë . 2 2 c gt tdt g gtdt s + = = =   áóþó . 2 2 c gt s + = 0 = t ¿åä 0 = s òóë  + = . 2 0 0 2 c g 0 = c áîëæ . 2 2 gt s = 0 ) ' , , ( = y y x F òýãøèòãýëèéã I ýðýìáèéí äèôôåðåíöèàë òýãøèòãýë ãýíý. ) , ( ' y x f y = òýãøèòãýëèéã óëàìæëàëûíõàà õóâüä áîäîãäñîí I ýðýìáèéí äèôôåðåíöèàë òýãøèòãýë ãýíý. Äýýðõè æèøýýí¿¿äýýñ ¿çýõýä I ýðýìáèéí äèôôåðåíöèàë òýãøèòãýëèéí åðºíõèé øèéä ) , ( c x y  = õýëáýðòýé áàéíà. c äóðûí òîãòìîë òîî òóë äèôôåðåíöèàë òýãøèòãýëèéí øèéä òºãñãºëã¿é îëîí áàéíà. (Òóõàéëáàë Çóðàã 16). Äóðûí òîãòìîë c -èéí òîäîðõîé óòãàíä ãàðàõ øèéäèéã òóõàéí øèéä ãýíý. Åðºíõèé øèéäýýñ òóõàéí øèéäèéã ñîíãîõûí òóëä íýìýëò íºõöºë õýðýãòýé. Èéì íºõöºëèéã àíõíû íºõöºë ãýýä ; 0 0 y y x x = = ãýæ áè÷íý. Õóâüñàã÷ íü ÿëãàãäàõ äèôôåðåíöèàë òýãøèòãýë. Òîäîðõîéëîëò: 0 ) ( ) ( ) ( ) ( 2 2 1 1 =  +  dy y x f dx y x f   õýëáýðèéí òýãøèòãýëèéã I ýðýìáèéí õóâüñàã÷ íü ÿëãàãäàõ äèôôåðåíöèàë òýãøèòãýë (ÕßÄÒ) ãýíý.
  • 2. Óã òýãøèòãýëèéã 0 ) ( ) ( ) ( ) ( 1 2 2 1 = + dy y y dx x f x f   õýëáýðò øèëæ¿¿ëýýä ãèø¿¿í÷ëýí èíòåãðàë÷èëáàë ; ) ( ) ( ) ( ) ( 1 2 2 1 c dy y y dx x f x f = +     ãýæ åðºíõèé øèéä îëäîíî. Æèøýý 58: ; 0 = + ydy xdx äèôôåðåíöèàë òýãøèòãýëèéã áîä.  = + 0 ydy xdx  = +   c ydy xdx  = + c y x 2 2 2 2 . 2 2 c y x = + Æèøýý 59: ; ydx xdy = äèôôåðåíöèàë òýãøèòãýëèéã áîä.  = ydx xdy  = x dx y dy  =   x dx y dy  + = c x y ln ln  + = c x y ln ln ln  = cx y ln ln . cx y = Áîäëîãî 4: (Áèåèéí õºðºõ õóóëü). Áèåèéí õºðºõ õóðä íü îð÷íû òåìïåðàòóð áà áèåèéí òåìïåðàòóðûí ÿëãàâàðòàé ïðîïîðöèîíàëü áàéíà. Òàñàëãààíû òåìïåðàòóð C  20 áàéã. Óã òàñàëãààíä áàéãàà áèå 20 ìèíóòàä C  100 -ýýñ C  60 òåìïåðàòóðòàé áîëñîí áîë áèåèéí õºðºõ õóóëèéã îë. T - t ìîìåíò äàõü áèåèéí òåìïåðàòóð, t - õóãàöàà ãýâýë ) (t T T = íü áèäíèé îëîõ ¸ñòîé ôóíêö þì. Óã ôóíêöèéí õóâüä ) 20 ( C T k dt dT  − = òýãøèòãýë, ; 100 0 = = t T áà ; 60 20 = = t T íýìýëò íºõöë¿¿ä áèåëíý. Ýíä k - ïðîïîðöèîíàëèéí êîýôôèöèåíò.  − = ) 20 ( C T k dt dT   = − kdt T dT 20  = −   dt k T dT 20  + = − c kt T 20 ln  + = − c e T kt ln ln 20 ln  = − kt ce T 20 . 20 kt ce T + = ; 100 0 = = t T ãýäãýýñ  + = 0 20 100 ce . 80 = c áîëæ ( ). 80 20 t k e T + = ; 60 20 = = t T ãýäãýýñ ( )  + = 20 80 20 60 k e  = − 20 1 2 k e . 2 80 20 20 t T −  + = áîëíî. Áîäëîãî 5: (Öàöðàã èäýâõò çàäðàëûí õóóëü). Ðàäèéí çàäðàëûí õóðä íü òóõàéí ìîìåíò äàõü ò¿¿íèé ìàññòàé ïðîïîðöèîíàëü áàéíà. Àíõ ðàäè 0 m ìàññòàé áàéñàí áà çàäàð÷ ýõýëñýíýýñ õîéø 1590 æèëèéí (õàãàñ çàäðàëûí æèë) äàðàà 2 0 m ìàññòàé áîëñîí áîë çàäðàëûí õóóëèéã îë. X - t ìîìåíò äàõü ðàäèéí ìàññ, t - õóãàöàà ãýâýë ) (t X X = íü áèäíèé îëîõ ¸ñòîé ôóíêö.          = = = = = 2 0 1590 0 0 m X m X kX dt dX t t
  • 3.  = kX dt dX  = kdt X dX  =   dt k X dX ; kt ce X =  = = 0 0 m X t  = 0 0 k ce m ; 0 m c = болж ; 0 kt e m X =  = = 2 0 1590 m X t  = k e m m 1590 0 0 2  = − 1590 1 2 k e ; 2 1590 0 t m X −  = болно. Áîäëîãî 6: (Áàêòåðèéí ºñºõ õóóëü). Áàêòåðèéí ºñºõ õóóëü íü ò¿¿íèé òîî õýìæýýòýé ïðîïîðöèîíàëü áàéíà. Àíõ 100 áàêòåð áàéãààä 4-í öàãèéí äàðàà ãóðàâ äàõèí ºññºí áîë ò¿¿íèé ºñºõ õóóëèéã îë. 8 öàãèéí äàðààõü áàêòåðèéí òîîã îë. X - t ìîìåíò äàõü áàêòåðèéí òîî, t - õóãàöàà ãýâýë ) (t X X = íü îëîõ ¸ñòîé ôóíêö.        = = = = = 300 100 4 0 t t X X kX dt dX  = kX dt dX  = kdt X dX  =   dt k X dX ; kt ce X =  = = 100 0 t X  = 0 100 k ce ; 100 = c болж ; 100 kt e X =  = = 300 4 t X  = k e4 100 300  = 4 1 3 k e ; 3 100 4 t X  = болно. ; 8 = t үед . 900 3 100 3 100 2 4 8 =  =  = X Áîäëîãî 7: (Óóñìàëûí êîíöåíòðàöè). Ñàâàíä 10%-èéí 100 ëèòð äàâñíû óóñìàë áàéâ. Ìèíóò á¿ðä 30ë óñ ñàâàíä îðæ, 20ë óóñìàë ãàäàãøèëæ áàéâàë t ìèíóòàä ñàâàíä áàéãàà äàâñíû õýìæýýã îë. Çóðàã 17. X - t ìîìåíò äàõü äàâñíû õýìæýý, t - õóãàöàà ãýâýë ) (t X X = íü îëîõ ¸ñòîé ôóíêö. t ìîìåíò äàõü óóñìàëûí õýìæýý ; 10 100 20 30 100 t t t v + = − + = áàéíà. t ìîìåíò äàõü äàâñíû õýìæýý ; 20 10 100 dt t X  + áàéíà. Äàâñíû ººð÷ëºëò ; 10 2 t Xdt dX + = − áàéíà.  + = − t Xdt dX 10 2  + − = t dt X dX 10 2 ; ) 10 ( 2 t c X + =  = = 10 0 t X  + = 2 ) 0 10 ( 10 c ; 1000 = c болж ; ) 10 ( 1000 2 t X + =
  • 4.
  • 5. Áîäëîãî 8: (II ýðýìáèéí õèìèéí óðâàë). . 5 2 3 5 2 3 спирт Этилийн натри Ацетат гидрооксид Натрийн эфир цуугийн Этилийн OH H C COONa CH NaOH H COOC CH + → + Äýýðõè õèìèéí óðâàëûí õóâüä àíõ ýòèë öóóãèéí ýôèð 0.01, íàòðèéí ãèäðîîêñèä 0.002 õýìæýýòýé áàéñàí áà 23 ìèíóòûí äàðàà ýòèë öóóãèéí ýôèðèéí 10% íü õîðîãäñîí áîë ò¿¿íèé 15% íü õîðîãäîõ õóãàöààã îë. Ñàíàìæ: Õî¸ð áîäèñ èæèë õýìæýýòýé õîðîãäîíî. (Èæèë õóâèàð áèø). X - t ìîìåíò äàõü ýòèë öóóãèéí ýôèðèéí õýìæýý, t - õóãàöàà ãýâýë ) (t X X = íü îëîõ ¸ñòîé ôóíêö. t ìîìåíò äàõü óðâàëûí õóðä . dt dX II ýðýìáèéí õèìèéí óðâàëûí õóâüä ). 002 . 0 )( 01 . 0 ( X X k dt dX − − = áàéíà.  − − = ) 002 . 0 )( 01 . 0 ( X X k dt dX  = − − kdt X X dX ) 002 . 0 )( 01 . 0 (  = − −   dt k X X dX ) 002 . 0 )( 01 . 0 ( ; 01 . 0 002 . 0 ln 125 c kt X X + = − − −  = = 0 0 t X ; 2 . 0 ln 125 − = c болж ; 2 . 0 ln 125 01 . 0 002 . 0 ln 125 − = − − − kt X X буюу . 002 . 0 ) 01 . 0 ( 2 . 0 ln 125 kt X X = − −  = = 001 . 0 23 t X  = − − k 23 001 . 0 002 . 0 ) 001 . 0 01 . 0 ( 2 . 0 ln 125  = ; 8 . 1 ln 23 125 k . 8 . 1 ln 23 125 002 . 0 ) 01 . 0 ( 2 . 0 ln 125 t X X = − − ; 0015 . 0 = X үед  = − − . 8 . 1 ln 23 125 0015 . 0 002 . 0 ) 0015 . 0 01 . 0 ( 2 . 0 ln 125 t 9 . 47  t мин.