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dy/dx=1+y/x solve the ODE
Solution
dy/dx - y/x = 1
dy/dx + (-1/x)y = 1
Integrating factor = e^(integral of (-1/x)*dx)
IF = e^(integral of -1/x)
IF = e^-ln(x)
IF = e^ln(1/x)
IF = 1/x
So, multiply the DE all over by the IF :
(1/x) * [dy/dx - y/x = 1]
d/dx(y * 1/x) = 1/x
Integrating :
y*(1/x) = intergal of (1/x)
y/x = ln|x| + C
y = xln|x| + Cx ---> ANSWER

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dydx=1+yx solve the ODE Solutiondydx - yx = 1dydx + (-1.pdf

  • 1. dy/dx=1+y/x solve the ODE Solution dy/dx - y/x = 1 dy/dx + (-1/x)y = 1 Integrating factor = e^(integral of (-1/x)*dx) IF = e^(integral of -1/x) IF = e^-ln(x) IF = e^ln(1/x) IF = 1/x So, multiply the DE all over by the IF : (1/x) * [dy/dx - y/x = 1] d/dx(y * 1/x) = 1/x Integrating : y*(1/x) = intergal of (1/x) y/x = ln|x| + C y = xln|x| + Cx ---> ANSWER