dy/dx=1+y/x solve the ODE Solution dy/dx - y/x = 1 dy/dx + (-1/x)y = 1 Integrating factor = e^(integral of (-1/x)*dx) IF = e^(integral of -1/x) IF = e^-ln(x) IF = e^ln(1/x) IF = 1/x So, multiply the DE all over by the IF : (1/x) * [dy/dx - y/x = 1] d/dx(y * 1/x) = 1/x Integrating : y*(1/x) = intergal of (1/x) y/x = ln|x| + C y = xln|x| + Cx ---> ANSWER.