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conductivity = k. no of ions in solution NaI = N.pdf

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conductivity = k. no of ions in solution NaI = Na+ + I- = 2 species K2SO4 = 2K+ + SO42- = 3 species conductivity 0.015 M K2SO4 = 3 x 12000 /2 = 18,000 units Solution conductivity = k. no of ions in solution NaI = Na+ + I- = 2 species K2SO4 = 2K+ + SO42- = 3 species conductivity 0.015 M K2SO4 = 3 x 12000 /2 = 18,000 units.

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conductivity = k. no of ions in solution NaI = Na+ + I- = 2 species K2SO4 = 2K+ + SO42- = 3 species conductivity 0.015 M K2SO4 = 3 x 12000 /2 = 18,000 units Solution conductivity = k. no of ions in solution NaI = Na+ + I- = 2 species K2SO4 = 2K+ + SO42- = 3 species conductivity 0.015 M K2SO4 = 3 x 12000 /2 = 18,000 units

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  • 1. conductivity = k. no of ions in solution NaI = Na+ + I- = 2 species K2SO4 = 2K+ + SO42- = 3 species conductivity 0.015 M K2SO4 = 3 x 12000 /2 = 18,000 units Solution conductivity = k. no of ions in solution NaI = Na+ + I- = 2 species K2SO4 = 2K+ + SO42- = 3 species conductivity 0.015 M K2SO4 = 3 x 12000 /2 = 18,000 units