2. The switch has been closed for a long time and is opened at t = 0. Find i(t) for t > o. Solution we know that at t=0 current i=10/2=5 (1) after apply kvl wee find that l*di/dt+3i+5i=10 so to solve this differential eq we find that i=2+(e^(-5/3t+c)/5) to put eq. (1) we find that e^c=15 so final answer at t>0 i(t)=2+(e^(-5/3t+15)/5).