Inventory information for Part 311 of Splish Corp- discloses the follo.pdf
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Inventory information for Part 311 of Splish Corp. discloses the following information for the month of June. Assuming that the perpetual inventory method is used and costs are computed at the time of each withdrawal, what is the gross profit if the inventory is valued at FIFO? Gross profit (FIFO).
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please help and make clear which question is being answered please! thank you
You are to discover the chromosomal location (autosomal or X linked) and mode of inheritance
for two new fly mutations swiss cheese (sc) and dachshund (da) The homozygous swiss cheese
(scsc) phenotype has holes in it's brain The homozygous dachshund (dada) has short legs
PARENTS Cross Male double homozygous mutants sc da with Female wild wild SC DA are to
be crossed BUT FIRST you don't know if either gene is on the X chromosome Parental diploid
genotypes could be: male scscdada female SCSCDADA if Both genes autosomal or Male
XscYdada female XSCXSCDADA if sc on the X chromosome and da autosomal or Male
scscXdaY female SCSCXDAXDA if da on the X chromosome and sc autosomal What are the
expected phenotypes and phenotype ratios for each of the above three F1 x F1 Punnett squares
assuming: (REMEMBER FOR X-LINKED CROSSES THE PHENOTYPE RATIO MIGHT BE
DIFFERENT FOR THE 8 MALES FROM THE RESULTANT 8 FEMALES) Predictions Use
this area to create PHENOTYPE PREDICTIONS that reflect the above Punnett squares for the
F2 generation if the inheritance of the mutant trait is: (Label clearly the phenotype).
REMEMBER: Example for Mendelian dominant recessive there are 4 possibles. DO ALL
FOUR a) both WILD alleles are DOMINANT b) both MUTANT alleles are DOMINANT c)
ONE MUTANT allele is DOMINANT and WILD allele for other gene are DOMINANT d)
Reverse of c For autosomal Punnett - dominant or recessive, For two sex linked Punnett -
dominant or recessive, incomplete dominant (for both sex linked and autosomal) (take a guess on
what phenotype might look like), lethal dominant as embryo (sex linked and autosomal) IS THIS
EVEN POSSIBLE lethal recessive as embryo. ( sex linked and autosomal) IS THIS EVEN
POSSIBLE.
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for two new fly mutations swiss cheese (sc) and dachshund (da) The homozygous swiss cheese
(scsc) phenotype has holes in it's brain The homozygous dachshund (dada) has short legs
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be crossed BUT FIRST you don't know if either gene is on the X chromosome Parental diploid
genotypes could be: male scscdada female SCSCDADA if Both genes autosomal or Male
XscYdada female XSCXSCDADA if sc on the X chromosome and da autosomal or Male
scscXdaY female SCSCXDAXDA if da on the X chromosome and sc autosomal What are the
expected phenotypes and phenotype ratios for each of the above three F1 x F1 Punnett squares
assuming: (REMEMBER FOR X-LINKED CROSSES THE PHENOTYPE RATIO MIGHT BE
DIFFERENT FOR THE 8 MALES FROM THE RESULTANT 8 FEMALES) Predictions Use
this area to create PHENOTYPE PREDICTIONS that reflect the above Punnett squares for the
F2 generation if the inheritance of the mutant trait is: (Label clearly the phenotype).
REMEMBER: Example for Mendelian dominant recessive there are 4 possibles. DO ALL
FOUR a) both WILD alleles are DOMINANT b) both MUTANT alleles are DOMINANT c)
ONE MUTANT allele is DOMINANT and WILD allele for other gene are DOMINANT d)
Reverse of c For autosomal Punnett - dominant or recessive, For two sex linked Punnett -
dominant or recessive, incomplete dominant (for both sex linked and autosomal) (take a guess on
what phenotype might look like), lethal dominant as embryo (sex linked and autosomal) IS THIS
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(CVD) technology, an insulating material is deposited on the wafer surface, forming a thin layer
of solid material on the chip. - Patterning: Photolithography projects a microscopic circuit pattern
on the wafer surface, which has a light-sensitive chemical like the emulsion on photographic
film. It is repeated many times as each layer of the chip is built. - Etching: Etching removes
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What is the role of the index sequence in the version of Illumina sequencing by synthesis that we
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a. To allow amplification of DNA on the flow cell
b. To act as a termination region that releases the DNA polymerase so it can bind to another
DNA molecule
c. To allow binding of DNA molecules to the flow cell
d. To allow identification of which DNA molecules in the sequencing reaction belong to which
individuals
e. To act as an origin of replication that binds the DNA polymerase.
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fungi. All protists are microscopic. Complete the sentences about Stramenopila characteristics
with the correct terms. 1. Protists called algae are examples of Stramenopila. 2. The is an
example of a unicellular Stramenopila. 3. Stramenopila refers to fine hairs found on the 4. A
pathogenic member of the Stramenopila is the Complete the sentences about protist cell surfaces
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its surface. 3. A covering called a protects a cell from gastric acids. 4. A cell wall is an example
of the of algae. Which feature best distinguishes protists from other eukaryotes? Multiple Choice
They did not evolve organelles through endosymbiosis. They have cilia and flagella which are
absent in other eukaryotes. They live in many more environments than other eukaryotes. They
cannot be categorized into a single kingdom. They are the eukaryote most closely related to
prokaryotes. Which statement best explains one outcome of endosymbiosis? Multiple Choice It
is responsible for mitochondria. It led to the formation of the nucleus. It formed the endoplasmic
reticulum. It provided the ability to carry out glycolysis. It caused algae to produce cell walls..
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