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UNIVERSIDAD
ALEJANDRO DE
HUMBOLDT
República Bolivariana de Venezuela
Ministerio del poder Popular para la Educación Superior
Universidad Alejandro de Humboldt
Cátedra: Programación Numérica y No Numérica
Seudocódigo.
ALUMNO:
Danny Camacaro.
C.I.: 19.672.111
Caracas, 17 de Marzo de 2014
Los Vectores son;
A=(2,1,4,7,6,2) B=(1,6,7,2,8,3) Donde n=3
For i=1 to n do
K=i*(i-1)/2
For j=1 to i do
C(k+j)=0
For m=j to I do
C(k+j)=C(k+j)+A(k+m)*B(m*/(m-1)/2+j)
End for
End for
End for.
a: (2,1,4,7,6,2)
b: (1,6,7,2,8,3)
n=3
For i=1 to 3 do
K=1*(1-1)/2
k=0
For j=1 to 1 do
C(1)=0
For m=1 to 1 do
C(1)=C(1)+a(1)*b(1*(1-1)/2+1)
C(1)=C(1)+a1*b1
C(1)=0+2*1
C(1)=2
End for
End for
i=2 to 3 do
K=2*(2-1)/2
K=1
For j=1 to 2 do
C(2)=0
For m=1 to 2 do
C(2)=c(2)+a(2)*b(1*(1-1)/2+1)
C(2)=C(2)+a2*b1
C(2)=0+1*1
C(2)=1
m=2 to 2 do
C(2)=c(2)+a(3)*b(2*(2-1)/2+1)
C(2)=C(2)+a3+b2
C(2)=1+4*6
C(2)=25
end for
For j=2 to 2 do
C(3)=0
For m=2 to 2 do
C(3)=C(3)+a(3)*b(2*(2-1)/2+2)
C(3)=0+a3*b3
C(3)=0+4*7
C(3)=28
end for
end for
i=3 to 3 do
K=3*(3-1)/2
k=3
For j=1 to 3 do
C(4)=0
For m=1 to 3 do
C(4)=C(4)+a(4)*b(1*(1-1)/2+1)
C(4)=C(4)+A(4)*b1
C(4)=0+7*1
C(4)=7
m=2 to 3 do
C(4)=C(4)+a(5)*b(2*(2-1)/2+1)
C(4)=C(4)+a5*b2
C(4)=7+6*6
C(4)=43
m=3 to 3 do
C(4)=C(4)+a(6)*b(3*(3-1)/2+1)
C(4)=C(4)+a6*b4
C(4)=43+2*2
C(4)=47
end for
For j=2 to 3 do
C(5)=0
m=2 to 3 do
C(5)=C(5)+a(5)*b(2*(2-1)/2+2)
C(5)=C(5)+a5*b3
C(5)=0+6*7
C(5)=42
m=3 to 3 do
C(5)=C(5)+a(6)*b(3*(3-1)/2+2)
C(5)=C(5)+a6*b5
C(5)=42+2*8
C(5)=58
end for
For j=3 to 3 do
C(6)=0
m=3 to 3 do
C(6)=C(6)+a(6)*b(3*(3-1)/2+3)
C(6)=C(6)+a6*b6
C(6)=0+2*3
C(6)=6
end for
end for
end for

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Seudocodigo terminado.docx

  • 1. UNIVERSIDAD ALEJANDRO DE HUMBOLDT República Bolivariana de Venezuela Ministerio del poder Popular para la Educación Superior Universidad Alejandro de Humboldt Cátedra: Programación Numérica y No Numérica Seudocódigo. ALUMNO: Danny Camacaro. C.I.: 19.672.111
  • 2. Caracas, 17 de Marzo de 2014 Los Vectores son; A=(2,1,4,7,6,2) B=(1,6,7,2,8,3) Donde n=3 For i=1 to n do K=i*(i-1)/2 For j=1 to i do C(k+j)=0 For m=j to I do C(k+j)=C(k+j)+A(k+m)*B(m*/(m-1)/2+j) End for End for End for. a: (2,1,4,7,6,2) b: (1,6,7,2,8,3) n=3 For i=1 to 3 do K=1*(1-1)/2 k=0 For j=1 to 1 do C(1)=0 For m=1 to 1 do C(1)=C(1)+a(1)*b(1*(1-1)/2+1) C(1)=C(1)+a1*b1 C(1)=0+2*1 C(1)=2 End for End for i=2 to 3 do K=2*(2-1)/2 K=1 For j=1 to 2 do
  • 3. C(2)=0 For m=1 to 2 do C(2)=c(2)+a(2)*b(1*(1-1)/2+1) C(2)=C(2)+a2*b1 C(2)=0+1*1 C(2)=1 m=2 to 2 do C(2)=c(2)+a(3)*b(2*(2-1)/2+1) C(2)=C(2)+a3+b2 C(2)=1+4*6 C(2)=25 end for For j=2 to 2 do C(3)=0 For m=2 to 2 do C(3)=C(3)+a(3)*b(2*(2-1)/2+2) C(3)=0+a3*b3 C(3)=0+4*7 C(3)=28 end for end for i=3 to 3 do K=3*(3-1)/2 k=3 For j=1 to 3 do C(4)=0 For m=1 to 3 do C(4)=C(4)+a(4)*b(1*(1-1)/2+1) C(4)=C(4)+A(4)*b1 C(4)=0+7*1 C(4)=7 m=2 to 3 do C(4)=C(4)+a(5)*b(2*(2-1)/2+1) C(4)=C(4)+a5*b2 C(4)=7+6*6 C(4)=43 m=3 to 3 do C(4)=C(4)+a(6)*b(3*(3-1)/2+1) C(4)=C(4)+a6*b4 C(4)=43+2*2
  • 4. C(4)=47 end for For j=2 to 3 do C(5)=0 m=2 to 3 do C(5)=C(5)+a(5)*b(2*(2-1)/2+2) C(5)=C(5)+a5*b3 C(5)=0+6*7 C(5)=42 m=3 to 3 do C(5)=C(5)+a(6)*b(3*(3-1)/2+2) C(5)=C(5)+a6*b5 C(5)=42+2*8 C(5)=58 end for For j=3 to 3 do C(6)=0 m=3 to 3 do C(6)=C(6)+a(6)*b(3*(3-1)/2+3) C(6)=C(6)+a6*b6 C(6)=0+2*3 C(6)=6 end for end for end for