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8.1 Exploring Ratio and
Proportion
Ratio – a comparison of 2 numbers measured in the
same units
 The ratio of x to y can be written:
 x to y
 x:y
 Because a ratio is a quotient, its denominator cannot be zero.
 Ratios are expressed in simplified form.
 6:8 is simplified to 3:4.
y
x
Ex. 1: Simplifying Ratios
 Simplify the ratios:
a. 12 cm b. 6 ft
4 m 18 in
Ex. 1: Simplifying Ratios
 Simplify the ratios:
a. 12 cm
4 m
12 cm 12 cm 12 3
4 m 4∙100cm 400 100
Ex. 1: Simplifying Ratios
 Simplify the ratios:
b. 6 ft
18 in
6 ft 6∙12 in 72 in. 4
18 in 18 in. 18 in. 1
Ex. 2: Using Ratios
 The perimeter of
rectangle ABCD is 60
centimeters. The ratio
of AB: BC is 3:2. Find
the length and the
width of the rectangle
w
l
A
B
C
D
Ex. 2: Using Ratios
 SOLUTION: Because
the ratio of AB:BC is
3:2, you can represent
the length of AB as 3x
and the width of BC as
2x.
w
l
A
B
C
D
Solution:
Statement
2l + 2w = P
2(3x) + 2(2x) = 60
6x + 4x = 60
10x = 60
x = 6
Reason
Formula for perimeter of a rectangle
Substitute l, w and P
Multiply
Combine like terms
Divide each side by 10
So, ABCD has a length of 18 centimeters and a width of 12 cm.
Ex. 3: Using Ratios
 The measures of the angles in ∆JKL are in the
ratio 1:2:3. Find the measures of the angles.
Solution:
Statement
x°+ 2x°+ 3x° =
180°
6x = 180
x = 30
Reason
Triangle Sum Theorem
Combine like terms
Divide each side by 6
So, the angle measures are 30°, 2(30°) = 60°, and 3(30°) = 90°.
Ex. 4: Using Ratios
 The ratios of the side
lengths of ∆DEF to the
corresponding side
lengths of ∆ABC are
2:1. Find the unknown
lengths.
8 in.
3 in.
F
D E
C
A B
Ex. 4: Using Ratios
 SOLUTION:
 DE is twice AB and DE = 8,
so AB = ½(8) = 4
 Use the Pythagorean
Theorem to determine what
side BC is.
 DF is twice AC and AC = 3,
so DF = 2(3) = 6
 EF is twice BC and BC = 5,
so EF = 2(5) or 10
8 in.
3 in.
F
D E
C
A B
4 in
a2 + b2 = c2
32 + 42 = c2
9 + 16 = c2
25 = c2
5 = c
Using Proportions
 Proportion - An
equation that sets two
ratios equal to one
another
 = 
Means Extremes
The numbers a and d are the
extremes of the proportions.
The numbers b and c are the
means of the proportion.
 If using an extended
proportion –
 a:b:c = d:e:f
Properties of proportions
1. CROSS PRODUCT PROPERTY. The
product of the extremes equals the product of
the means.
If  = , then ad = bc
Properties of proportions
2. RECIPROCAL PROPERTY. If two ratios
are equal, then their reciprocals are also
equal.
If  = , then = 
b
a
Ex. 5: Solving Proportions
4
x
5
7
=
x =
28
5
Ex. 5: Solving Proportions
3
y + 2
2
y
=
y = 4
8.2 – Problem Solving
With Proportions
Ex:
Determine values of x and y:

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8 1 and 8 2 second version.ppt

  • 1. 8.1 Exploring Ratio and Proportion
  • 2. Ratio – a comparison of 2 numbers measured in the same units  The ratio of x to y can be written:  x to y  x:y  Because a ratio is a quotient, its denominator cannot be zero.  Ratios are expressed in simplified form.  6:8 is simplified to 3:4. y x
  • 3. Ex. 1: Simplifying Ratios  Simplify the ratios: a. 12 cm b. 6 ft 4 m 18 in
  • 4. Ex. 1: Simplifying Ratios  Simplify the ratios: a. 12 cm 4 m 12 cm 12 cm 12 3 4 m 4∙100cm 400 100
  • 5. Ex. 1: Simplifying Ratios  Simplify the ratios: b. 6 ft 18 in 6 ft 6∙12 in 72 in. 4 18 in 18 in. 18 in. 1
  • 6. Ex. 2: Using Ratios  The perimeter of rectangle ABCD is 60 centimeters. The ratio of AB: BC is 3:2. Find the length and the width of the rectangle w l A B C D
  • 7. Ex. 2: Using Ratios  SOLUTION: Because the ratio of AB:BC is 3:2, you can represent the length of AB as 3x and the width of BC as 2x. w l A B C D
  • 8. Solution: Statement 2l + 2w = P 2(3x) + 2(2x) = 60 6x + 4x = 60 10x = 60 x = 6 Reason Formula for perimeter of a rectangle Substitute l, w and P Multiply Combine like terms Divide each side by 10 So, ABCD has a length of 18 centimeters and a width of 12 cm.
  • 9. Ex. 3: Using Ratios  The measures of the angles in ∆JKL are in the ratio 1:2:3. Find the measures of the angles.
  • 10. Solution: Statement x°+ 2x°+ 3x° = 180° 6x = 180 x = 30 Reason Triangle Sum Theorem Combine like terms Divide each side by 6 So, the angle measures are 30°, 2(30°) = 60°, and 3(30°) = 90°.
  • 11. Ex. 4: Using Ratios  The ratios of the side lengths of ∆DEF to the corresponding side lengths of ∆ABC are 2:1. Find the unknown lengths. 8 in. 3 in. F D E C A B
  • 12. Ex. 4: Using Ratios  SOLUTION:  DE is twice AB and DE = 8, so AB = ½(8) = 4  Use the Pythagorean Theorem to determine what side BC is.  DF is twice AC and AC = 3, so DF = 2(3) = 6  EF is twice BC and BC = 5, so EF = 2(5) or 10 8 in. 3 in. F D E C A B 4 in a2 + b2 = c2 32 + 42 = c2 9 + 16 = c2 25 = c2 5 = c
  • 13.
  • 14.
  • 15. Using Proportions  Proportion - An equation that sets two ratios equal to one another  =  Means Extremes The numbers a and d are the extremes of the proportions. The numbers b and c are the means of the proportion.  If using an extended proportion –  a:b:c = d:e:f
  • 16. Properties of proportions 1. CROSS PRODUCT PROPERTY. The product of the extremes equals the product of the means. If  = , then ad = bc
  • 17. Properties of proportions 2. RECIPROCAL PROPERTY. If two ratios are equal, then their reciprocals are also equal. If  = , then =  b a
  • 18. Ex. 5: Solving Proportions 4 x 5 7 = x = 28 5
  • 19. Ex. 5: Solving Proportions 3 y + 2 2 y = y = 4
  • 20.
  • 21.
  • 22. 8.2 – Problem Solving With Proportions
  • 23.
  • 24.
  • 25. Ex: