Given the following XML fragment- what XPath expression would select a.pdf

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Given the following XML fragment, what XPath expression would select all the "book" elements? ibrary book t i tl e Harry Potter / t i tl e Pauthor ] . K. Rowling / author / book book t i tl e The Lord of the Rings / t i tl e Lauthor ] . R. R. Tolkien / author / book / l ib r a ry /library/[book] //book /book //library.

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Given the regular expression- 0(01)0 (a) Construct and -NFA and draw i.pdf

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Grouper Corporation is authorized to issue both preferred and commonstock. The par value of the preferred is $50 . During the first year of operations, the company had the following events and traruactions pectainung to its preferred stock. Feb. I Isoued 21.500 shares for cashat $60 pershare July: 1 Issued 10,500 shares for cishat $64 pershare Post to the stockholders' equity accounts. (Post entries in the order of joumat entrles prisented in the previous part).

Grouper Corporation is authorized to issue both preferred and commonst.pdf

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Guessing or knowing the initial TCP sequence number (ISN) that a server will choose enables an attacker to establish a TCP connection. Please discuss if the following solutions are secure (to prevent hijacking etc.) against off-path attackers and why. [x] denotes truncation of x to the 32 32 least significant bits. K is a (permanent) secret key stored locally and only known to the server. H represents a secure hash function (e.g., SHA256) and its algorithm is publicly known. Also note that || means concatenation and current timestamp is represented as UNIX timestamp. You can assume that 4 tuple information (source / destination IP and port) are known to the attacker. (1) Server selects ISN as ISN = [H(K)] . 32 (2) Server computes ISN as follows: ISN = [H(source IP address XOR destination IP address XOR current timestamp XOR K)] . 32 (3) Server computes ISN as ISN = [H(source IP address || destination IP address || source port number || destination port number || current timestamp)] . 32 (4) Server selects ISN using a standard (i.e., publicly-known) pseudo random generator with K as a seed. (5) Server selects ISN as ISN = [AES ECB(K, counter)] , where the counter is continuous from 32 the previous communication session..

Guessing or knowing the initial TCP sequence number (ISN) that a serve.pdf

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Greener Pastures Corporation borrowed $1 , 100 , 000 on November 1, 2021. The note carried a 9 percent interest rate with the principal and interest payable on June 1, 2022. (a) The note issued on November 1 . (b) The interest accrual on December 31 110.6 (Algo) Part 1 1. Indicate the effects of the amounts for the abovo transactions. (Enter any decreases to assets, liabilities, or stockholders equity with a minus sign. Do not round intermediate calculations.y.

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Given the following for the Titan Company- the company began operation.pdf

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Given the following class in Java : public class ThreeTenDynArray<T> { //default initial capacity / minimum capacity private static final int MIN_CAPACITY = 2; //underlying array for storage -- you MUST use this for credit! //Do NOT change the name or type private T[] data; private int size = 0; private int capacity = 0; // ADD MORE PRIVATE MEMBERS HERE IF NEEDED! /** * */ @SuppressWarnings("unchecked") public ThreeTenDynArray() { // Constructor // Initial capacity of the storage should be MIN_CAPACITY // Hint: Can't remember how to make an array of generic Ts? It's in the textbook... data = (T[])(new Object[MIN_CAPACITY]); size = 0; capacity = MIN_CAPACITY; } /** * @param initCapacity */ @SuppressWarnings("unchecked") public ThreeTenDynArray(int initCapacity) { // Constructor // Initial capacity of the storage should be initCapacity. // - Throw IllegalArgumentException if initCapacity is smaller than // MIN_CAPACITY 2 // - Use this _exact_ error message for the exception // (quotes are not part of the message): // "Capacity must be at least 2!" if (initCapacity < MIN_CAPACITY) { throw new IllegalArgumentException("Capacity must be at least 2!"); } } /** * @return */ public int size() { // Report the current number of elements // O(1) return size; //default return, remove/change as needed } /** * @return */ public int capacity() { // Report max number of elements of the current storage // (subject to change since this is a _dynamic_ ) // O(1) return capacity; //default return, remove/change as needed } /** * @param index index you're changing * @param value what you're adding * @return the old item at the index */ public T set(int index, T value) { // Replace the item at the given index to be the given value. // Return the old item at that index. // Note: You cannot add new items (i.e. cannot increase size) with this method. // O(1) //return firstIndexOf(value); // - Throw IndexOutOfBoundsException if index is not valid // - Use this code to produce the correct error message for // the exception (do not use a different message): // "Index: " + index + " out of bounds!" if (index < 0 && index >= size) { throw new IndexOutOfBoundsException("Index: " + index + " out of bounds!"); } // - Throw IllegalArgumentException if value is null. // - Use this _exact_ error message for the exception // (quotes are not part of the message): // "Cannot include null values!" if (value==null) { throw new IllegalArgumentException("Cannot include null values!"); } T oldValue = data[index]; data[index] = value; return oldValue; //default return, remove/change as needed } /** * @param index * @return */ public T get(int index) { // Return the item at the given index if (index < 0 && index >= size) { throw new IndexOutOfBoundsException("Index: " + index + " out of bounds!"); } // O(1) // Use the exception (and error message) described in set() // for invalid indicies. return data[index]; //default return, remove/change as needed } /** * @param value */ @SuppressWarn.

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Given Information #1: Period 1 is when Devah is working and earning money, and Period 2 is when she is retired and not working. In the beginning of her life, she is provided with utility over consumption by During period 1, Devah will have total income of $1000 that she can either devote to c or to 1 savings, s . Any money that she saves can be used for consumption in period 2 (during which time she will not have any other source of income). Assume that interest on savings is zero. GIVEN INFORMATION #2 GIVEN INFORMATION #3 PLEASE SOLVE:.

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Give concise and substantial answers by relating your answers to your own experience. Practice intellectual integrity 1. Discuss the significance of the use of technology in teaching and learning language and literature. give particular technology applications that us use in the classroom to improve learning outcomes - 2. Discuss the use of social networking, research and technology to address global communication trends and issues - 25% 3. Narrate and explain how the various technology tools/ instruments may facilitate effective development of the ff. language skills 2.1 Writing 2.2. Listening and Speaking 3. Reading and 4. Viewing - Give particular examples -.

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Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list: IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list starting at firstNode. void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values. int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode. Note: The code for IntNode_Create() provided here differs from the code shown in the book. The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and IntNode_SumList(). main() reads 5 integers from a user: The number of nodes to be added to a new list The value of the first node of the list An increment between the values of two consecutive nodes. A value of a new node The position of a node after which the new node will be added, with 1 indicating the first node Ex: If the input is: the output is: Here's the code #include <stdio.h> #include <stdlib.h> typedef struct IntNode_struct { int dataVal; struct IntNode_struct* nextNodePtr; } IntNode; // Allocate a node for initData IntNode* IntNode_Create (int initData) { IntNode* newNode = (IntNode*)malloc(sizeof(IntNode)); newNode->dataVal = initData; newNode->nextNodePtr = NULL; return newNode; } /* Insert newNode after node. Before: thisNode -- next After: thisNode -- newNode -- next */ void IntNode_InsertAfter (IntNode* thisNode, IntNode* newNode) { IntNode* tmpNext = NULL; tmpNext = thisNode->nextNodePtr; // Remember next thisNode->nextNodePtr = newNode; // this -- new -- ? newNode->nextNodePtr = tmpNext; // this -- new -- next } // Print dataVal void IntNode_PrintNodeData(IntNode* thisNode) { printf("%d ", thisNode->dataVal); } // Grab location pointed by nextNodePtr IntNode* IntNode_GetNext(IntNode* thisNode) { return thisNode->nextNodePtr; } /* ******** New functions ********/ // Return the length of the list int IntNode_Length(IntNode* firstNode) { int length = 0; IntNode* currentNode = firstNode; while(currentNode != NULL) { ++length; currentNode = currentNode->nextNodePtr; } return length; } // Return the Nth element of the list. First node is 1. IntNode* IntNode_GetNth(IntNode* firstNode, int pos) { /* Type your code here. */ } // Print the entire list starting at firstNode void IntNode_PrintList(IntNode* firstNode) { /* Type your code here. */ } // Sum the numbers in the list int IntNode_SumList(IntNode* firstNode) { /* Type your code here. */ } int main(void) { IntNode* firstNode = NULL; IntNode* lastNode = NULL; IntNode* newNode = NULL; IntNode* curNode = NULL; int listSize; // how many integers to read int increment; // increment between consecutive node values int firstNum; // first node value // New node for newNum will be inserted after position newPos (first node = 1) int newPos; int newNum; int i; .

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Give examples of species interactions that might be recognizable in the fossil record. Why is competition considered to be a "negative - negative" type of interaction? What is the competitive exclusion hypothesis? Provide the various indices used to define population abundance patterns. How are population spatial patterns defined? Explain the equation relating the effects of competition on population growth rates. How would opportunistic vs. equilibrium species be recognized in the fossil record?.

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Getting error : (Return type of out-of-line definition of 'Product::GetProductCondition' differs from that in the declaration) Please help to show correct code in product file that will compile and build successfully. all code below and files Main.cpp #include <iostream> #include <time.h> #include "InventorySystem.hpp" #include <iostream> #include "Product.hpp" #include <time.h> #include <stdlib.h> using namespace std; int main() { srand(time( NULL )); Inventory_System *h1 = nullptr ; h1 = new Inventory_System("Radioshack", 117); h1->BuildInventory(); h1->ShowInventory(); h1->ShowDefectInventory(); h1->Terminate(); delete h1; return 0; }; InventorySystem.cpp #include "InventorySystem.hpp" #include "InventoryItem.hpp" #include "Product.hpp" #include <iostream> #include <fstream> #include <sstream> Inventory_System::Inventory_System() { } Inventory_System::Inventory_System(std::string name, int id) : store_name(name), store_id(id) { } Inventory_System::~Inventory_System() { for ( int i = 0; i < item_count; i++) { delete ptr_inv_item[i]; } } int Inventory_System::GetStoreId(){ return store_id; } int Inventory_System::GetItemCount(){ return item_count; } std::string Inventory_System::GetStoreName(){ return store_name; } void Inventory_System::BuildInventory() { std::ifstream file("products_test.txt", std::ios::in); std::string name, quantity, price, condition; Inventory_Item *item; if (!file) { std::cerr << "Error: Failed to open file\n"; exit(-1); } else { while (!file.eof()) { item = new Product(); Product *product = static_cast <Product*> (item); std::getline(file, name, ';'); product->SetItemName(name); std::getline(file, quantity, ';'); product->SetItemQuantity(stoi(quantity)); std::getline(file, price, ';'); product->SetProductPrice(stold(price)); std::getline(file, condition, '\n'); switch (condition[0]) { case 'D': product->SetProductCondition(PC_DEFECTIVE); break ; case 'N': product->SetProductCondition(PC_NEW); break ; case 'R': product->SetProductCondition(PC_REFURBISHED); break ; case 'U': product->SetProductCondition(PC_USED); break ; default : product->SetProductCondition(PC_NEW); break ; } product->SetProductId(rand() % 10000); ptr_inv_item[item_count] = product; item_count++; } } } void Inventory_System::ShowInventory() { for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); temp->Display(); } } void Inventory_System::ShowDefectInventory() { for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); if (temp->GetProductCondition() == PC_DEFECTIVE) { temp->Display(); } } } void Inventory_System::Terminate() { std::ofstream file; std::stringstream ss; file.open("example.txt"); for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); file << temp->GetItemName() << ";" << temp->GetItemQuantity() << ";" << temp->GetProductPrice() << ";"; switch (temp->GetProductCondition()) { case PC_DEFECTIVE: file << "D\n"; brea.

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getting errors in the Product.cpp file error: (Expected function body after function declarator) Please help to show correct code in product file that will compile and build successfully. all code below and files Main.cpp #include <iostream> #include <time.h> #include "InventorySystem.hpp" #include <iostream> #include "Product.hpp" #include <time.h> #include <stdlib.h> using namespace std; int main() { srand(time( NULL )); Inventory_System *h1 = nullptr ; h1 = new Inventory_System("Radioshack", 117); h1->BuildInventory(); h1->ShowInventory(); h1->ShowDefectInventory(); h1->Terminate(); delete h1; return 0; }; InventorySystem.cpp #include "InventorySystem.hpp" #include "InventoryItem.hpp" #include "Product.hpp" #include <iostream> #include <fstream> #include <sstream> Inventory_System::Inventory_System() { } Inventory_System::Inventory_System(std::string name, int id) : store_name(name), store_id(id) { } Inventory_System::~Inventory_System() { for ( int i = 0; i < item_count; i++) { delete ptr_inv_item[i]; } } int Inventory_System::GetStoreId(){ return store_id; } int Inventory_System::GetItemCount(){ return item_count; } std::string Inventory_System::GetStoreName(){ return store_name; } void Inventory_System::BuildInventory() { std::ifstream file("products_test.txt", std::ios::in); std::string name, quantity, price, condition; Inventory_Item *item; if (!file) { std::cerr << "Error: Failed to open file\n"; exit(-1); } else { while (!file.eof()) { item = new Product(); Product *product = static_cast <Product*> (item); std::getline(file, name, ';'); product->SetItemName(name); std::getline(file, quantity, ';'); product->SetItemQuantity(stoi(quantity)); std::getline(file, price, ';'); product->SetProductPrice(stold(price)); std::getline(file, condition, '\n'); switch (condition[0]) { case 'D': product->SetProductCondition(PC_DEFECTIVE); break ; case 'N': product->SetProductCondition(PC_NEW); break ; case 'R': product->SetProductCondition(PC_REFURBISHED); break ; case 'U': product->SetProductCondition(PC_USED); break ; default : product->SetProductCondition(PC_NEW); break ; } product->SetProductId(rand() % 10000); ptr_inv_item[item_count] = product; item_count++; } } } void Inventory_System::ShowInventory() { for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); temp->Display(); } } void Inventory_System::ShowDefectInventory() { for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); if (temp->GetProductCondition() == PC_DEFECTIVE) { temp->Display(); } } } void Inventory_System::Terminate() { std::ofstream file; std::stringstream ss; file.open("example.txt"); for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); file << temp->GetItemName() << ";" << temp->GetItemQuantity() << ";" << temp->GetProductPrice() << ";"; switch (temp->GetProductCondition()) { case PC_DEFECTIVE: file << "D\n"; break ; case PC_NEW: file << "N\n".

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Functionality You are to create an enhanced chat system. In particular, you will create a chat client and a chat server that are capable of transmitting messages as well as transferring files. In particular, the system will perform as follows: 1. The server will listen for connections from clients. 2. Once a client is connected, it can send messages, at will, to the server. It will also receive from the server all messages sent by the other connected clients. 3. The user will provide messages to the client using standard input. 4. NOTE: The first message sent by the client must be the name of the user, in order for the server to forward the name of the user who has sent a message. Additionally, the user name will be used to identify the user who owns a file that may be requested by another user. 5. Immediately after receiving a message, the server must forward the message and the name of the user who sent the message to all connected clients, except for the client that sent the message. DO NOT SEND THE MESSAGE BACK TO THE ORIGINATING CLIENT! 6. The format of the combined name and message includes a colon, followed by a single space, immediately after the name of the sender; the message follows. Hence, the format can be represented as follows: 7. Once it receives a message, which now includes the name of the sender, the client will write the message to standard output. 8. The client must write each message on its own line of output. 9. In addition to transmitting and receiving messages, the client and server will also transfer files using a binary transfer method, meaning that all of the bytes of a file will be transmitted exactly as is. 10. Because the client must also transfer files, it will monitor file transfer requests. Although the client could use the same socket connection for transferring files, the user of the client that is sending a file might interfere with the transfer process by sending a text message during the transfer. Therefore, you are strongly encouraged to create a separate socket connection for transferring files. 11. In order to initiate a file transfer request, the client must send the name of the file and the name of the user who owns a copy of the file to the server. A user may request a file at any time, and the name of the file and the owning user must be supplied by the requesting user through standard input. 12. When the server receives a file transfer request, it must immediately initiate a file transfer process. The server may set up a relay between the clients involved, i.e., the requesting client and the supplying client, or it may set up a peer-to-peer connection between the requesting client and the supplying client. In either case, all of the bytes in the file must be transmitted as is. If the file cannot be found or read, the client that is supposed to supply the file may simply ignore the request but it may not terminate. Whether requesting or supplying a file, the client must continue to send and receiv.

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