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UNIT - 1
ALLIGATIONS or MIXTURES
Alligation:
It is the rule that enables us to find the ratio in which two
or more ingredients at the given price must be mixed to
produce a mixture of desired price.
Mean Price:
The cost of a unit quantity of the mixture is called the
mean price.
Rule of Alligation:
If two ingredients are mixed, then
(Quantity of cheaper / Quantity of dearer) = (C.P of dearer – mean price
/ mean price – C.P of cheaper)
The quantity of pure liquid= x[1-
(y/x)]^n
x--- Container’s initial volume
y--- Liters that taken out
n--- number of times we done this
operation
1. In what ratio must a grocer mix two varieties of pulses
costing Rs. 15 and Rs. 20 per kg respectively so as to get
a mixture worth Rs. 16.50 kg?
A. 3:7 B. 5:7 C. 7:3 D. 7:5
EXPLANATIONS:
Cheaper value is 15, Dearer value is 20 & Mean value is 16.50
Required rate = 3.50 : 1.50 = 7 :3
ANSWER : C
2.In what ratio must rice at Rs.9.30 kg be mixed with
rice at Rs.10.80 kg so that the mixture be worth Rs.10
kg?
A. 6:7 B. 8:7 C. 7:8 D. 7:5
EXPLANATIONS:
By rule of alligation,
Cheaper – 9.30
Dearer – 10.80
Mean – 10
8:7
ANSWER : B
3. In what ratio must tea at Rs.62 per kg be mixed with
tea at rs.72 per kg so that the mixture must be worth
Rs.64.50 per kg?
A. 3:1 B. 2:1 C. 1:3 D. 1:2
EXPLANATIONS:
C.P of a unit quantity of 1st kind = Rs. 62
C.P of a unit quantity of 2nd kind = Rs. 72
Mean price = Rs. 64.50
ANSWER: A
4.The cost of type 1 rice is Rs.15/ kg and type 2 rice is Rs.20/ kg. If both
the rice are mixed in the ratio of 2:3, then the price per kg of the mixed
variety of rice is:
A. 18 B. 20 C. 15 D. 12
EXPLANATIONS:
C.P of a unit quantity of 1st kind = Rs. 15
C.P of a unit quantity of 2nd kind = Rs. 20
Mean price = Rs . X
20 – X / X – 15 = 2/3
60 – 3X = 2X – 30
X = 18
ANSWER : A
5. In what ratio must water be mixed with milk to
gain 20% by selling the mixture at cost price?
A. 5:1 B. 2:1 C. 1:5 D. 1:2
EXPLANATIONS:
Water – Rs. 0
Milk – Rs. 1
Mean - Let Cost Price(C.P) of milk be Rs. 1 per litre. Then,
Selling Price(S.P) of 1 litre of mixture = Rs. 1 Gain obtained=
20% Then, C.P of 1 litre of mixture = Rs (100/120)*1 = Rs.
5/6.
ANSWER: C
6. In what ratio must a Grocer mix two varieties of Tea worth
Rs.60/Kg and Rs.65/kg so that by selling the mixture at
Rs.68.20/Kg he may gain 10%?
A. 5:2 B. 2:3 C. 2:5 D. 3:2
EXPLANATIONS:
C.P of a unit quantity of 1st kind = Rs. 60
C.P of a unit quantity of 2nd kind = Rs. 65
Mean price = Rs. 68.20 (10% GAIN)
ANSWER: D
7. Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with
a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs.
153 per kg, the price of the third variety per kg will be:
EXPLANATIONS:
Since 1st and 2nd varieties are mixed in equal proportions
So, their average price = Rs (126+135/2)= 130.50
C.P of a unit quantity of 1st kind = Rs. 130.50
C.P of a unit quantity of 2nd kind = Rs. X
Mean price = Rs. 153
ANSWER: 175.50
8. A container contains 40 liters of milk, from this
container 4 liters of milk was taken out and replaced
by water. This process was repeated further two times.
How many liters of milk is now in the container?
EXPLANATIONS:
In Intial stage,
Milk – 40 Water – 0
Step 1:
Milk – 36 Water – 4
Step 2:
Milk – 32.4 Water – 7.6
Step – 3
Milk – 29.16 Water – 10.84
9. In what ratio must water be mixed with milk to gain 16 2/3% on
selling the mixture at cost price?
A. 6:1 B. 2:1 C. 1:6 D. 1:2
EXPLANATIONS:
Water = Rs. 0
Milk = Rs. 1
Mean price = 6/7
ANSWER: 1:6
10. A container contains 80 liters of milk, from this container 8 liters of
milk was taken out and replaced by water. This process was repeated
further two times. How many liters of milk is now in the container?
EXPLANATIONS:
In Intial stage,
Milk – 80 Water – 0
Step 1:
Milk – 72 Water – 8
Step 2:
Milk – 64.8 Water – 15.2
Step – 3
Milk – 58.32 Water – 21.68
THANK YOU…

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Alligation OR mixture.pptx

  • 1.
  • 2. UNIT - 1 ALLIGATIONS or MIXTURES
  • 3. Alligation: It is the rule that enables us to find the ratio in which two or more ingredients at the given price must be mixed to produce a mixture of desired price. Mean Price: The cost of a unit quantity of the mixture is called the mean price.
  • 4. Rule of Alligation: If two ingredients are mixed, then (Quantity of cheaper / Quantity of dearer) = (C.P of dearer – mean price / mean price – C.P of cheaper)
  • 5. The quantity of pure liquid= x[1- (y/x)]^n x--- Container’s initial volume y--- Liters that taken out n--- number of times we done this operation
  • 6. 1. In what ratio must a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 kg? A. 3:7 B. 5:7 C. 7:3 D. 7:5
  • 7. EXPLANATIONS: Cheaper value is 15, Dearer value is 20 & Mean value is 16.50 Required rate = 3.50 : 1.50 = 7 :3 ANSWER : C
  • 8. 2.In what ratio must rice at Rs.9.30 kg be mixed with rice at Rs.10.80 kg so that the mixture be worth Rs.10 kg? A. 6:7 B. 8:7 C. 7:8 D. 7:5
  • 9. EXPLANATIONS: By rule of alligation, Cheaper – 9.30 Dearer – 10.80 Mean – 10 8:7 ANSWER : B
  • 10. 3. In what ratio must tea at Rs.62 per kg be mixed with tea at rs.72 per kg so that the mixture must be worth Rs.64.50 per kg? A. 3:1 B. 2:1 C. 1:3 D. 1:2
  • 11. EXPLANATIONS: C.P of a unit quantity of 1st kind = Rs. 62 C.P of a unit quantity of 2nd kind = Rs. 72 Mean price = Rs. 64.50 ANSWER: A
  • 12. 4.The cost of type 1 rice is Rs.15/ kg and type 2 rice is Rs.20/ kg. If both the rice are mixed in the ratio of 2:3, then the price per kg of the mixed variety of rice is: A. 18 B. 20 C. 15 D. 12
  • 13. EXPLANATIONS: C.P of a unit quantity of 1st kind = Rs. 15 C.P of a unit quantity of 2nd kind = Rs. 20 Mean price = Rs . X 20 – X / X – 15 = 2/3 60 – 3X = 2X – 30 X = 18 ANSWER : A
  • 14. 5. In what ratio must water be mixed with milk to gain 20% by selling the mixture at cost price? A. 5:1 B. 2:1 C. 1:5 D. 1:2
  • 15.
  • 16. EXPLANATIONS: Water – Rs. 0 Milk – Rs. 1 Mean - Let Cost Price(C.P) of milk be Rs. 1 per litre. Then, Selling Price(S.P) of 1 litre of mixture = Rs. 1 Gain obtained= 20% Then, C.P of 1 litre of mixture = Rs (100/120)*1 = Rs. 5/6. ANSWER: C
  • 17. 6. In what ratio must a Grocer mix two varieties of Tea worth Rs.60/Kg and Rs.65/kg so that by selling the mixture at Rs.68.20/Kg he may gain 10%? A. 5:2 B. 2:3 C. 2:5 D. 3:2
  • 18.
  • 19. EXPLANATIONS: C.P of a unit quantity of 1st kind = Rs. 60 C.P of a unit quantity of 2nd kind = Rs. 65 Mean price = Rs. 68.20 (10% GAIN) ANSWER: D
  • 20. 7. Tea worth Rs. 126 per kg and Rs. 135 per kg are mixed with a third variety in the ratio 1 : 1 : 2. If the mixture is worth Rs. 153 per kg, the price of the third variety per kg will be:
  • 21. EXPLANATIONS: Since 1st and 2nd varieties are mixed in equal proportions So, their average price = Rs (126+135/2)= 130.50 C.P of a unit quantity of 1st kind = Rs. 130.50 C.P of a unit quantity of 2nd kind = Rs. X Mean price = Rs. 153 ANSWER: 175.50
  • 22. 8. A container contains 40 liters of milk, from this container 4 liters of milk was taken out and replaced by water. This process was repeated further two times. How many liters of milk is now in the container?
  • 23. EXPLANATIONS: In Intial stage, Milk – 40 Water – 0 Step 1: Milk – 36 Water – 4 Step 2: Milk – 32.4 Water – 7.6 Step – 3 Milk – 29.16 Water – 10.84
  • 24. 9. In what ratio must water be mixed with milk to gain 16 2/3% on selling the mixture at cost price? A. 6:1 B. 2:1 C. 1:6 D. 1:2
  • 25. EXPLANATIONS: Water = Rs. 0 Milk = Rs. 1 Mean price = 6/7 ANSWER: 1:6
  • 26. 10. A container contains 80 liters of milk, from this container 8 liters of milk was taken out and replaced by water. This process was repeated further two times. How many liters of milk is now in the container?
  • 27. EXPLANATIONS: In Intial stage, Milk – 80 Water – 0 Step 1: Milk – 72 Water – 8 Step 2: Milk – 64.8 Water – 15.2 Step – 3 Milk – 58.32 Water – 21.68