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Probability
• Denoted by P(Event)
outcomes
total
outcomes
favorable
)
( 
E
P
This method for calculating probabilities is only appropriate
when the outcomes of the sample space are equally likely.
Experimental Probability
• The relative frequency at which a
chance experiment occurs
–Flip a fair coin 30 times & get 17
heads
30
17
Law of Large Numbers
• As the number of repetitions of a
chance experiment increase, the
difference between the relative
frequency of occurrence for an
event and the true probability
approaches zero.
Basic Rules of Probability
Rule 1. Legitimate Values
For any event E,
0 < P(E) < 1
Rule 2. Sample space
If S is the sample space,
P(S) = 1
Rule 3. Complement
For any event E,
P(E) + P(not E) = 1
Rule 4. Addition
If two events E & F are disjoint,
P(E or F) = P(E) + P(F)
(General) If two events E & F are
not disjoint,
P(E or F) = P(E) + P(F) – P(E & F)
Ex 1) A large auto center sells cars made by
many different manufacturers. Three of these
are Honda, Nissan, and Toyota. (Note: these
are not simple events since there are many
types of each brand.) Suppose that P(H) =
.25, P(N) = .18, P(T) = .14.
Are these disjoint events?
P(H or N or T) =
P(not (H or N or T) =
yes
.25 + .18+ .14 = .57
1 - .57 = .43
Ex. 2) Musical styles other than rock
and pop are becoming more popular. A
survey of college students finds that the
probability they like country music is
.40. The probability that they liked jazz
is .30 and that they liked both is .10.
What is the probability that they like
country or jazz?
P(C or J) = .4 + .3 -.1 = .6
Independent
• Two events are independent if knowing that
one will occur (or has occurred) does not
change the probability that the other occurs
– A randomly selected student is female - What is
the probability she plays soccer for PWSH?
– A randomly selected student is female - What is
the probability she plays football for PWSH?
Independent
Not independent
Rule 5. Multiplication
If two events A & B are
independent,
General rule:
P(B)
P(A)
B)
&
P(A 

A)
|
P(B
P(A)
B)
&
P(A 

Ex. 3) A certain brand of light bulbs are
defective five percent of the time. You
randomly pick a package of two such
bulbs off the shelf of a store. What is the
probability that both bulbs are defective?
Can you assume they are independent?
0025
.
05
.
05
.
D)
&
P(D 


Ex 4)
If P(A) = 0.45, P(B) = 0.35, and A &
B are independent, find P(A or B).
Is A & B disjoint?
If A & B are disjoint, are they
independent?
Disjoint events do not happen at the same
time.
So, if A occurs, can B occur?
Disjoint events are
dependent!
NO, independent events cannot be disjoint
P(A or B) = P(A) + P(B) – P(A & B)
How can you
find the
probability of
A & B?
P(A or B) = .45 + .35 - .45(.35) = 0.6425
If
independent,
multiply
Ex 5) Suppose I will pick two cards from a standard
deck without replacement. What is the probability that
I select two spades?
Are the cards independent? NO
P(A & B) = P(A) · P(B|A)
Read “probability of B
given that A occurs”
P(Spade & Spade) = 1/4 · 12/51 = 1/17
The probability of getting a spade given
that a spade has already been drawn.
Rule 6. At least one
The probability that at least one
outcome happens is 1 minus the
probability that no outcomes
happen.
P(at least 1) = 1 – P(none)
Ex. 6) A certain brand of light bulbs are
defective five percent of the time. You
randomly pick a package of two such
bulbs off the shelf of a store.
What is the probability that at least one
bulb is defective?
P(at least one) = P(D & DC) or P(DC & D) or P(D & D)
or
1 - P(DC & DC)
.0975
Ex 7) For a sales promotion the
manufacturer places winning symbols
under the caps of 10% of all Dr. Pepper
bottles. You buy a six-pack. What is the
probability that you win something?
P(at least one winning symbol) =
1 – P(no winning symbols)
1 - .96 = .4686
Rule 7: Conditional Probability
• A probability that takes into
account a given condition
P(A)
B)
P(A
A)
|
P(B


given
and
A)
|
P(B 
Ex 6) In a recent study it was
found that the probability that a
randomly selected student is a
girl is .51 and is a girl and plays
sports is .10. If the student is
female, what is the probability
that she plays sports?
1961
.
51
.
1
.
P(F)
F)
P(S
F)
|
P(S 



Ex 7) The probability that a
randomly selected student plays
sports if they are male is .31. What
is the probability that the student is
male and plays sports if the
probability that they are male
is .49?
1519
.
49
.
31
.
P(M)
M)
P(S
M)
|
P(S




x
x
Conditional Probability
Example 1:
Only 5% of male high school basketball, baseball,
and football players go on to play at the college
level. Of these, only 1.7% enters major league
professional sports. Of the athletes that do not play
college sports, only 0.1% enters major league
professional sports. What is the probability that a
high school athlete will play professional sports?
What is the probability that a high school athlete
does not play college sports if he plays professional
sports?
Another approach:
Only 5% of male high school basketball, baseball,
and football players go on to play at the college level.
Of these, only 1.7% enters major league professional
sports. Of the athletes that do not play college
sports, only 0.1% enters major league professional
sports. What is the probability that a high school
athlete does not play college sports if he plays
professional sports?
Example 2:
Management has determined that customers return
12% of the items assembled by inexperienced
employees, whereas only 3% of the items assembled
by experienced employees are returned. Due to
turnover and absenteeism at an assembly plant,
inexperienced employees assemble 20% of the items.
Construct a tree diagram or a chart for this data.
What is the probability that an item is returned?
If an item is returned, what is the probability that an
inexperienced employee assembled it?

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Probability Part 2.ppt

  • 1.
  • 2. Probability • Denoted by P(Event) outcomes total outcomes favorable ) (  E P This method for calculating probabilities is only appropriate when the outcomes of the sample space are equally likely.
  • 3. Experimental Probability • The relative frequency at which a chance experiment occurs –Flip a fair coin 30 times & get 17 heads 30 17
  • 4. Law of Large Numbers • As the number of repetitions of a chance experiment increase, the difference between the relative frequency of occurrence for an event and the true probability approaches zero.
  • 5. Basic Rules of Probability Rule 1. Legitimate Values For any event E, 0 < P(E) < 1 Rule 2. Sample space If S is the sample space, P(S) = 1
  • 6. Rule 3. Complement For any event E, P(E) + P(not E) = 1
  • 7. Rule 4. Addition If two events E & F are disjoint, P(E or F) = P(E) + P(F) (General) If two events E & F are not disjoint, P(E or F) = P(E) + P(F) – P(E & F)
  • 8. Ex 1) A large auto center sells cars made by many different manufacturers. Three of these are Honda, Nissan, and Toyota. (Note: these are not simple events since there are many types of each brand.) Suppose that P(H) = .25, P(N) = .18, P(T) = .14. Are these disjoint events? P(H or N or T) = P(not (H or N or T) = yes .25 + .18+ .14 = .57 1 - .57 = .43
  • 9. Ex. 2) Musical styles other than rock and pop are becoming more popular. A survey of college students finds that the probability they like country music is .40. The probability that they liked jazz is .30 and that they liked both is .10. What is the probability that they like country or jazz? P(C or J) = .4 + .3 -.1 = .6
  • 10. Independent • Two events are independent if knowing that one will occur (or has occurred) does not change the probability that the other occurs – A randomly selected student is female - What is the probability she plays soccer for PWSH? – A randomly selected student is female - What is the probability she plays football for PWSH? Independent Not independent
  • 11. Rule 5. Multiplication If two events A & B are independent, General rule: P(B) P(A) B) & P(A   A) | P(B P(A) B) & P(A  
  • 12. Ex. 3) A certain brand of light bulbs are defective five percent of the time. You randomly pick a package of two such bulbs off the shelf of a store. What is the probability that both bulbs are defective? Can you assume they are independent? 0025 . 05 . 05 . D) & P(D   
  • 13. Ex 4) If P(A) = 0.45, P(B) = 0.35, and A & B are independent, find P(A or B). Is A & B disjoint? If A & B are disjoint, are they independent? Disjoint events do not happen at the same time. So, if A occurs, can B occur? Disjoint events are dependent! NO, independent events cannot be disjoint P(A or B) = P(A) + P(B) – P(A & B) How can you find the probability of A & B? P(A or B) = .45 + .35 - .45(.35) = 0.6425 If independent, multiply
  • 14. Ex 5) Suppose I will pick two cards from a standard deck without replacement. What is the probability that I select two spades? Are the cards independent? NO P(A & B) = P(A) · P(B|A) Read “probability of B given that A occurs” P(Spade & Spade) = 1/4 · 12/51 = 1/17 The probability of getting a spade given that a spade has already been drawn.
  • 15. Rule 6. At least one The probability that at least one outcome happens is 1 minus the probability that no outcomes happen. P(at least 1) = 1 – P(none)
  • 16. Ex. 6) A certain brand of light bulbs are defective five percent of the time. You randomly pick a package of two such bulbs off the shelf of a store. What is the probability that at least one bulb is defective? P(at least one) = P(D & DC) or P(DC & D) or P(D & D) or 1 - P(DC & DC) .0975
  • 17. Ex 7) For a sales promotion the manufacturer places winning symbols under the caps of 10% of all Dr. Pepper bottles. You buy a six-pack. What is the probability that you win something? P(at least one winning symbol) = 1 – P(no winning symbols) 1 - .96 = .4686
  • 18. Rule 7: Conditional Probability • A probability that takes into account a given condition P(A) B) P(A A) | P(B   given and A) | P(B 
  • 19. Ex 6) In a recent study it was found that the probability that a randomly selected student is a girl is .51 and is a girl and plays sports is .10. If the student is female, what is the probability that she plays sports? 1961 . 51 . 1 . P(F) F) P(S F) | P(S    
  • 20. Ex 7) The probability that a randomly selected student plays sports if they are male is .31. What is the probability that the student is male and plays sports if the probability that they are male is .49? 1519 . 49 . 31 . P(M) M) P(S M) | P(S     x x
  • 21. Conditional Probability Example 1: Only 5% of male high school basketball, baseball, and football players go on to play at the college level. Of these, only 1.7% enters major league professional sports. Of the athletes that do not play college sports, only 0.1% enters major league professional sports. What is the probability that a high school athlete will play professional sports? What is the probability that a high school athlete does not play college sports if he plays professional sports?
  • 22. Another approach: Only 5% of male high school basketball, baseball, and football players go on to play at the college level. Of these, only 1.7% enters major league professional sports. Of the athletes that do not play college sports, only 0.1% enters major league professional sports. What is the probability that a high school athlete does not play college sports if he plays professional sports?
  • 23. Example 2: Management has determined that customers return 12% of the items assembled by inexperienced employees, whereas only 3% of the items assembled by experienced employees are returned. Due to turnover and absenteeism at an assembly plant, inexperienced employees assemble 20% of the items. Construct a tree diagram or a chart for this data. What is the probability that an item is returned? If an item is returned, what is the probability that an inexperienced employee assembled it?