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1 of 16
Equations
Transformable into
Quadratic Equations
PREPARED BY:
MRS. LIEZEL A. SERRANO
SST - II
Can you tell if these are quadratic
equations or not?
x ( x – 5 ) - 36
(x+5)2 + (x-2)2 = 37
𝟔
𝒙
+
𝒙−𝟑
𝟒
= 𝟐
x +
𝟖
𝒙−𝟐
= 𝟏 +
𝟒𝒙
𝒙 −𝟐
Equations Transformable into Quadratic
Equations
◦There are equations that are transformable
into quadratic equation form. These
equations may be given in different forms.
Hence, the procedures in transforming
these equations into quadratic equations
may be also different.
Two Categories
◦Quadratic Equations that are NOT
WRITTEN IN STANDARD FORM
◦RATIONAL ALGEBRAIC EQUATIONS
that are transformable into
quadratic equations
Quadratic Equations
that are not written in
Standard Form
Example 1: x (x-5) = 36
x (x-5) = 36
x2 – 5x – 36 = 0
Example 2: 3x (x-8) = 2
3x (x-8) = 2
3x2 – 24x – 2 = 0
Example 3: (s – 6)2 = 15
(s – 6)2 = 15
s2 – 12s + 36 – 15 = 0
s2 – 12s + 21 = 0
Example 4: (a – 2)2 + (a – 3)2 = 9
(a – 2)2 + (a – 3)2 = 9
(a2 – 4a + 4) + (a2 – 6a + 9) – 9 = 0
2a2 – 10a + 13 – 9 = 0
2a2 – 10a + 4 = 0
Example 5: (2r + 3)2 + (r + 4)2 = 10
(2r + 3)2 + (r + 4)2 = 10
(4r2 +12r + 9) + (r2 + 8r + 16) – 10 = 0
5r2 + 20r + 25 – 10 = 0
5r2 + 20r + 15 = 0
RATIONAL ALGEBRAIC
EQUATIONS that are
transformable into
quadratic equations
Example 6:
1
𝑥
+
2𝑥
5
= 0
1
𝑥
+
2𝑥
5
= 0
(
1
𝑥
+
2𝑥
5
= 0) (x)(5)
1(𝑥)(5)
𝑥
+
2𝑥(𝑥)(5)
5
= 0
5 + 2x2 = 0
2x2 + 5 = 0
Example 7:
6
𝑥
+
𝑥−3
4
= 2
24 + (x2 – 3x) = 8x
24 + x2 – 3x – 8x = 0
x2 – 11x + 24 = 0
6
𝑥
+
𝑥−3
4
= 2
(
6
𝑥
+
𝑥−3
4
= 2) (x)(4)
6 (𝑥)(4)
𝑥
+
(𝑥−3)(𝑥)(4)
4
= 2(x)(4)
Example 8: x +
𝟖
𝒙−𝟐
= 𝟏 +
𝟒𝒙
𝒙 −𝟐
x +
𝟖
𝒙−𝟐
= 𝟏 +
𝟒𝒙
𝒙 −𝟐
(x +
𝟖
𝒙−𝟐
= 𝟏 +
𝟒𝒙
𝒙 −𝟐
) (x-2)
x (x−2) +
𝟖(𝒙−𝟐)
𝒙−𝟐
= 𝟏(𝒙 − 𝟐) +
𝟒𝒙(𝒙−𝟐)
𝒙 −𝟐
)
x2 – 2x + 8 = x – 2 + 4x
x2 – 2x + 8 - x + 2 - 4x = 0
x2 – 7x + 10 = 0
Example 9:
𝟔
𝒔−𝟓
+
𝒔 −𝟓
𝟐
= 𝟑
𝟔
𝒔−𝟓
+
𝒔 −𝟓
𝟐
= 𝟑
(
𝟔
𝒔−𝟓
+
𝒔 −𝟓
𝟐
= 𝟑) (s-5)(2)
𝟔 (𝒔−𝟓)(𝟐)
𝒔−𝟓
+
(𝒔 −𝟓)(𝒔−𝟓)(𝟐)
𝟐
= 𝟑(s-5)(2)
12 + (s2 – 10s + 25) = 6(s-5)
12 + s2 – 10s + 25 = 6s – 30
12 + s2 – 10s + 25 – 6s + 30 = 0
s2 – 16s + 67 = 0
Change the following to quadratic
equations in standard form.
1.(m – 4)2 + (m – 7)2 = 15
2.
𝟐𝒙𝟐
𝟓
+
𝟓𝒙
𝟒
= 𝟏𝟎
3.
𝟐
𝒃
−
𝟑𝒃
𝟐
= 𝟕
4.
𝟑
𝒙
−
𝟒
𝟐𝒙
= −𝟏
5.
𝟐
𝒓−𝟏
−
𝟒
𝒓+𝟓
= 𝟏

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441990944-12-Equations-Transformable-into-Quadratic-Equations-pptx.pptx

  • 1. Equations Transformable into Quadratic Equations PREPARED BY: MRS. LIEZEL A. SERRANO SST - II
  • 2. Can you tell if these are quadratic equations or not? x ( x – 5 ) - 36 (x+5)2 + (x-2)2 = 37 𝟔 𝒙 + 𝒙−𝟑 𝟒 = 𝟐 x + 𝟖 𝒙−𝟐 = 𝟏 + 𝟒𝒙 𝒙 −𝟐
  • 3. Equations Transformable into Quadratic Equations ◦There are equations that are transformable into quadratic equation form. These equations may be given in different forms. Hence, the procedures in transforming these equations into quadratic equations may be also different.
  • 4. Two Categories ◦Quadratic Equations that are NOT WRITTEN IN STANDARD FORM ◦RATIONAL ALGEBRAIC EQUATIONS that are transformable into quadratic equations
  • 5. Quadratic Equations that are not written in Standard Form
  • 6. Example 1: x (x-5) = 36 x (x-5) = 36 x2 – 5x – 36 = 0
  • 7. Example 2: 3x (x-8) = 2 3x (x-8) = 2 3x2 – 24x – 2 = 0
  • 8. Example 3: (s – 6)2 = 15 (s – 6)2 = 15 s2 – 12s + 36 – 15 = 0 s2 – 12s + 21 = 0
  • 9. Example 4: (a – 2)2 + (a – 3)2 = 9 (a – 2)2 + (a – 3)2 = 9 (a2 – 4a + 4) + (a2 – 6a + 9) – 9 = 0 2a2 – 10a + 13 – 9 = 0 2a2 – 10a + 4 = 0
  • 10. Example 5: (2r + 3)2 + (r + 4)2 = 10 (2r + 3)2 + (r + 4)2 = 10 (4r2 +12r + 9) + (r2 + 8r + 16) – 10 = 0 5r2 + 20r + 25 – 10 = 0 5r2 + 20r + 15 = 0
  • 11. RATIONAL ALGEBRAIC EQUATIONS that are transformable into quadratic equations
  • 12. Example 6: 1 𝑥 + 2𝑥 5 = 0 1 𝑥 + 2𝑥 5 = 0 ( 1 𝑥 + 2𝑥 5 = 0) (x)(5) 1(𝑥)(5) 𝑥 + 2𝑥(𝑥)(5) 5 = 0 5 + 2x2 = 0 2x2 + 5 = 0
  • 13. Example 7: 6 𝑥 + 𝑥−3 4 = 2 24 + (x2 – 3x) = 8x 24 + x2 – 3x – 8x = 0 x2 – 11x + 24 = 0 6 𝑥 + 𝑥−3 4 = 2 ( 6 𝑥 + 𝑥−3 4 = 2) (x)(4) 6 (𝑥)(4) 𝑥 + (𝑥−3)(𝑥)(4) 4 = 2(x)(4)
  • 14. Example 8: x + 𝟖 𝒙−𝟐 = 𝟏 + 𝟒𝒙 𝒙 −𝟐 x + 𝟖 𝒙−𝟐 = 𝟏 + 𝟒𝒙 𝒙 −𝟐 (x + 𝟖 𝒙−𝟐 = 𝟏 + 𝟒𝒙 𝒙 −𝟐 ) (x-2) x (x−2) + 𝟖(𝒙−𝟐) 𝒙−𝟐 = 𝟏(𝒙 − 𝟐) + 𝟒𝒙(𝒙−𝟐) 𝒙 −𝟐 ) x2 – 2x + 8 = x – 2 + 4x x2 – 2x + 8 - x + 2 - 4x = 0 x2 – 7x + 10 = 0
  • 15. Example 9: 𝟔 𝒔−𝟓 + 𝒔 −𝟓 𝟐 = 𝟑 𝟔 𝒔−𝟓 + 𝒔 −𝟓 𝟐 = 𝟑 ( 𝟔 𝒔−𝟓 + 𝒔 −𝟓 𝟐 = 𝟑) (s-5)(2) 𝟔 (𝒔−𝟓)(𝟐) 𝒔−𝟓 + (𝒔 −𝟓)(𝒔−𝟓)(𝟐) 𝟐 = 𝟑(s-5)(2) 12 + (s2 – 10s + 25) = 6(s-5) 12 + s2 – 10s + 25 = 6s – 30 12 + s2 – 10s + 25 – 6s + 30 = 0 s2 – 16s + 67 = 0
  • 16. Change the following to quadratic equations in standard form. 1.(m – 4)2 + (m – 7)2 = 15 2. 𝟐𝒙𝟐 𝟓 + 𝟓𝒙 𝟒 = 𝟏𝟎 3. 𝟐 𝒃 − 𝟑𝒃 𝟐 = 𝟕 4. 𝟑 𝒙 − 𝟒 𝟐𝒙 = −𝟏 5. 𝟐 𝒓−𝟏 − 𝟒 𝒓+𝟓 = 𝟏