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GEOMETRIC
SEQUENCE
WEEK 3
SEPTEMBER 18 – 22, 2023
OBJECTIVES
β€’ Illustrate a geometric sequence
β€’ Differentiate geometric sequence from arithmetic sequence
Think-pair-share
Materials: paper and scissors
Procedure:
a) Cut the paper in half
b) Stack the halves. Cut the stack in halves.
c) Continue stacking and cutting the paper strips about half an inch
wide.
Record the total number of pieces obtained in the given table.
Number of cuts 1 2 3 4 5 6 7 8
Number of pieces
New number of pieces
π‘π‘Ÿπ‘’π‘£π‘–π‘œπ‘’π‘  π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘œπ‘“ 𝑝𝑖𝑒𝑐𝑒𝑠
QUESTIONS TO PONDER:
1. WHAT DO YOU OBSERVE ABOUT THE CHANGE IN NUMBER OF PIECES
WITH EACH CUT AFTER THE FIRST?
2. LIST THE NUMBER IN ROW 2 FROM LEAST TPO GREATEST, SEPARATE
THE NUMBERS WITH COMMA.
3. WHAT IS THE COMMON RATIO BETWEEN ANY TWO CONSECUTIVE
TERMS IN THE SEQUENCE?
Complete the table
GEOMETRIC SEQUENCE
β€’ A SEQUENCE IN WHICH EACH TERM IS OBTAINED BY MULTIPLYING THE
PRECEDING TERM BY A FIXED NUMBER.
β€’ COMMON RATIO (r) IS THE FIXED NUMBER MULTIPLIED IN EACH TERM
OF A GEOMETRIC RATIO.
nth TERM OF A GEOMETRIC SEQUENCE
π‘Žπ‘› = π‘Žπ‘›βˆ’1 βˆ™ π‘Ÿ or π‘Žπ‘› = π‘Ž1 βˆ™ π‘Ÿπ‘›βˆ’1
Example1
β€’ Write a formula for the nth term of the given geometric sequence.
8, 2, Β½ , 1/8, 1/32, . . .
Solution: Find the common ratio: r =
π‘Ž2
π‘Ž1
=
2
8
=
1
4
π‘Žπ‘› = π‘Ž1 βˆ™ π‘Ÿπ‘›βˆ’1
𝒂𝒏 = πŸ– βˆ™ (
𝟏
πŸ’
)π’βˆ’πŸ
Check: π‘Ž1 = 8 βˆ™
1
4
1βˆ’1
= 8 π‘Ž2 = 8 βˆ™
1
4
2βˆ’1
= 2
π‘Ž3 = 8 βˆ™
1
4
3βˆ’1
=
1
2
π‘Ž5 = 8 βˆ™
1
4
5βˆ’1
=
1
32
Note: any number raise to 0 is
equal to 1.
Example 2
β€’ WRITE THE FIRST THREE TERMS OF A GEOMETRIC SEQUENCE WHOSE
nth TERM IS GIVEN BY π‘Žπ‘› = 3(βˆ’5)π‘›βˆ’1.
SOLUTION:
π‘Ž1 = 3(βˆ’5)1βˆ’1 π‘Ž2 = 3(βˆ’5)2βˆ’1 π‘Ž3 = 3(βˆ’5)3βˆ’1
π‘Ž1 = 3(βˆ’5)0
π‘Ž2 = 3(βˆ’5)1
π‘Ž3 = 3(βˆ’5)2
π‘Ž1 = 3 1 π‘Ž2 = 3(βˆ’5) π‘Ž3 = 3(25)
π‘Ž1 = 3 π‘Ž2 = βˆ’15 π‘Ž3 = 75
*AFTER GETTING THE FIRST TERM, THE OTHER TERMS MAY BE OBTAINED
BY MULTIPLYING THE PREVIOUS TERM BY -5.
EXAMPLE 3
β€’ FIND THE 8th TERM OF THE GEOMETRIC SEQUENCE 24, 12, 6, 3, . . .
GIVEN: π‘Ž1 = 24 r =
12
24
=
1
2
π‘Ž8 = ?
SOLUTION: π‘Žπ‘› = π‘Ž1π‘Ÿπ‘›βˆ’1
π‘Ž8 = 24(
1
2
)8βˆ’1
substitute the values in the formula
π‘Ž8 = 24(
1
2
)7
π‘Ž8 = 24(
1
128
)
π’‚πŸ– =
πŸπŸ’
πŸπŸπŸ–
or π’‚πŸ– =
πŸ‘
πŸπŸ”
EXAMPLE 4
FIND THE FIRST TERM OF A GEOMETRIC SEQUENCE, IF THE 6th TERM IS 96
and r = 2.
GIVEN: π‘Ž6 = 96 r = 2 π‘Ž1 = ?
SOLUTION: π‘Ž6 = π‘Ž1(2)6βˆ’1
96 = π‘Ž1(2)5
(2)5
= 2 βˆ— 2 βˆ— 2 βˆ— 2 βˆ— 2 = 32
96 = (32)π‘Ž1
96
32
=
(32)π‘Ž1
32
π’‚πŸ = πŸ‘
Sequence is
3, 6, 12, 24, 48, 96, . . .
EXAMPLE 5
β€’ FIND THE COMMON RATIO OF A GEOMETRIC SEQUENCE, IF THE FIRST
TERM IS 789 AND THE FIFTH TERM IS 12 624.
GIVEN: π‘Ž1 = 789 π‘Ž5 = 12 624 r = ?
SOLUTION: π‘Ž5 = π‘Ž1π‘Ÿ5βˆ’1
12 624 = 789(π‘Ÿ)4
12 624
789
=
789π‘Ÿ4
789
16 = π‘Ÿ4
4
16 =
4
π‘Ÿ4
𝟐 = 𝒓
EXAMPLE 6
β€’ IN A GEOMETRIC SEQUENCE THE FIRST TERM IS 1 AND THE COMMON
RATIO IS 4, WHAT TERM DOES 1024 REPRESENTS?
SOLUTION: π‘Žπ‘› = π‘Ž1π‘Ÿπ‘›βˆ’1
1 024 = 1(4)π‘›βˆ’1
1 024 = (4)π‘›βˆ’1
45 = 4π‘›βˆ’1
5 = 𝒏 βˆ’ 𝟏
πŸ“ + 𝟏 = 𝒏
6 = 𝒏
PRACTICE TASK
β€’ WRITE WHETHER THE GIVEN SEQUENCE IS ARITHMETIC, GEOMETRIC,
OR NEITHER. IF IT IS ARITHMETIC, GIVE THE COMMON DIFFERENCE. IF
IT IS GEOMETRIC, GIVE THE COMMON RATIO
1) 11, 14, 17, 20, . . .
2) 4, 8, 16, 32, . . .
3) 5, 8, 12, 17, 26, . . .
4) 100, -50, 25, -12.5, . . .
5) 1, 8, 27, 64, . . .
PRACTICE TASK
β€’WRITE THE nth TERM FORMULA OF THE FOLLOWING:
1) 4, 8, 16, 32, . . .
2) 100, -50, 25, -12.5, . . .
3) 1, 3, 9, 27, . . .
WRITE THE 6TH TO 10TH TERMS OF THE SEQUENCE
ABOVE.
PRACTICE TASK
β€’WRITE THE nth TERM FORMULA OF THE FOLLOWING:
1) 4, 8, 16, 32, . . .
2) 100, -50, 25, -12.5, . . .
3) 1, 3, 9, 27, . . .
WRITE THE 6TH TO 8TH TERMS OF THE SEQUENCE ABOVE.
ASSIGNMENT
β€’ Write whether the sequence is arithmetic or geometric. Write the nth
term of each sequence.
1)2, 8, 32, 128, 512, . . .
2)3, 12, 48, 192, 768, . . .
3)-35, -32, -29, -26, -23, . . .
4)-24, -14, -5, 6, 16, . . .
5)3, -9, 27, -81, 243, . . .
β€’WHAT IS GEOMETRIC SERIES?
β€’WHAT IS THE FORMULA FOR THE
GEOMETRIC SERIES?
β€’GIVE 3 OF YOUR OWN EXAMPLES OF
GEOMETRIC SEQUENCE,WRITE THE nth
TERM FORMULA.
JOURNAL ENTRY
β€’ HOW DID YOU FIND THE LESSON ABOUT GEOMETRIC SEQUENCE?
β€’ HOW WILL YOU FIND THE VALUE OF n IF THE GIVEN ARE
π‘Ž1 = 5, π‘Ÿ = 3, π‘Žπ‘› = 10935
EXPLAIN YOUR SOLUTION.
REFERENCES
β€’ E-MATH BOOK 10 BY ORENCE ET.AL.
β€’ MAKATI LMS
β€’ PREPARED BY: CHRISTINE ORQUIA, LPT 1

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QUARTER 1.2 GEOMETRIC SEQUENCE.pptx

  • 2. OBJECTIVES β€’ Illustrate a geometric sequence β€’ Differentiate geometric sequence from arithmetic sequence
  • 3. Think-pair-share Materials: paper and scissors Procedure: a) Cut the paper in half b) Stack the halves. Cut the stack in halves. c) Continue stacking and cutting the paper strips about half an inch wide. Record the total number of pieces obtained in the given table.
  • 4. Number of cuts 1 2 3 4 5 6 7 8 Number of pieces New number of pieces π‘π‘Ÿπ‘’π‘£π‘–π‘œπ‘’π‘  π‘›π‘’π‘šπ‘π‘’π‘Ÿπ‘œπ‘“ 𝑝𝑖𝑒𝑐𝑒𝑠 QUESTIONS TO PONDER: 1. WHAT DO YOU OBSERVE ABOUT THE CHANGE IN NUMBER OF PIECES WITH EACH CUT AFTER THE FIRST? 2. LIST THE NUMBER IN ROW 2 FROM LEAST TPO GREATEST, SEPARATE THE NUMBERS WITH COMMA. 3. WHAT IS THE COMMON RATIO BETWEEN ANY TWO CONSECUTIVE TERMS IN THE SEQUENCE?
  • 6. GEOMETRIC SEQUENCE β€’ A SEQUENCE IN WHICH EACH TERM IS OBTAINED BY MULTIPLYING THE PRECEDING TERM BY A FIXED NUMBER. β€’ COMMON RATIO (r) IS THE FIXED NUMBER MULTIPLIED IN EACH TERM OF A GEOMETRIC RATIO. nth TERM OF A GEOMETRIC SEQUENCE π‘Žπ‘› = π‘Žπ‘›βˆ’1 βˆ™ π‘Ÿ or π‘Žπ‘› = π‘Ž1 βˆ™ π‘Ÿπ‘›βˆ’1
  • 7. Example1 β€’ Write a formula for the nth term of the given geometric sequence. 8, 2, Β½ , 1/8, 1/32, . . . Solution: Find the common ratio: r = π‘Ž2 π‘Ž1 = 2 8 = 1 4 π‘Žπ‘› = π‘Ž1 βˆ™ π‘Ÿπ‘›βˆ’1 𝒂𝒏 = πŸ– βˆ™ ( 𝟏 πŸ’ )π’βˆ’πŸ Check: π‘Ž1 = 8 βˆ™ 1 4 1βˆ’1 = 8 π‘Ž2 = 8 βˆ™ 1 4 2βˆ’1 = 2 π‘Ž3 = 8 βˆ™ 1 4 3βˆ’1 = 1 2 π‘Ž5 = 8 βˆ™ 1 4 5βˆ’1 = 1 32 Note: any number raise to 0 is equal to 1.
  • 8. Example 2 β€’ WRITE THE FIRST THREE TERMS OF A GEOMETRIC SEQUENCE WHOSE nth TERM IS GIVEN BY π‘Žπ‘› = 3(βˆ’5)π‘›βˆ’1. SOLUTION: π‘Ž1 = 3(βˆ’5)1βˆ’1 π‘Ž2 = 3(βˆ’5)2βˆ’1 π‘Ž3 = 3(βˆ’5)3βˆ’1 π‘Ž1 = 3(βˆ’5)0 π‘Ž2 = 3(βˆ’5)1 π‘Ž3 = 3(βˆ’5)2 π‘Ž1 = 3 1 π‘Ž2 = 3(βˆ’5) π‘Ž3 = 3(25) π‘Ž1 = 3 π‘Ž2 = βˆ’15 π‘Ž3 = 75 *AFTER GETTING THE FIRST TERM, THE OTHER TERMS MAY BE OBTAINED BY MULTIPLYING THE PREVIOUS TERM BY -5.
  • 9. EXAMPLE 3 β€’ FIND THE 8th TERM OF THE GEOMETRIC SEQUENCE 24, 12, 6, 3, . . . GIVEN: π‘Ž1 = 24 r = 12 24 = 1 2 π‘Ž8 = ? SOLUTION: π‘Žπ‘› = π‘Ž1π‘Ÿπ‘›βˆ’1 π‘Ž8 = 24( 1 2 )8βˆ’1 substitute the values in the formula π‘Ž8 = 24( 1 2 )7 π‘Ž8 = 24( 1 128 ) π’‚πŸ– = πŸπŸ’ πŸπŸπŸ– or π’‚πŸ– = πŸ‘ πŸπŸ”
  • 10. EXAMPLE 4 FIND THE FIRST TERM OF A GEOMETRIC SEQUENCE, IF THE 6th TERM IS 96 and r = 2. GIVEN: π‘Ž6 = 96 r = 2 π‘Ž1 = ? SOLUTION: π‘Ž6 = π‘Ž1(2)6βˆ’1 96 = π‘Ž1(2)5 (2)5 = 2 βˆ— 2 βˆ— 2 βˆ— 2 βˆ— 2 = 32 96 = (32)π‘Ž1 96 32 = (32)π‘Ž1 32 π’‚πŸ = πŸ‘ Sequence is 3, 6, 12, 24, 48, 96, . . .
  • 11. EXAMPLE 5 β€’ FIND THE COMMON RATIO OF A GEOMETRIC SEQUENCE, IF THE FIRST TERM IS 789 AND THE FIFTH TERM IS 12 624. GIVEN: π‘Ž1 = 789 π‘Ž5 = 12 624 r = ? SOLUTION: π‘Ž5 = π‘Ž1π‘Ÿ5βˆ’1 12 624 = 789(π‘Ÿ)4 12 624 789 = 789π‘Ÿ4 789 16 = π‘Ÿ4 4 16 = 4 π‘Ÿ4 𝟐 = 𝒓
  • 12. EXAMPLE 6 β€’ IN A GEOMETRIC SEQUENCE THE FIRST TERM IS 1 AND THE COMMON RATIO IS 4, WHAT TERM DOES 1024 REPRESENTS? SOLUTION: π‘Žπ‘› = π‘Ž1π‘Ÿπ‘›βˆ’1 1 024 = 1(4)π‘›βˆ’1 1 024 = (4)π‘›βˆ’1 45 = 4π‘›βˆ’1 5 = 𝒏 βˆ’ 𝟏 πŸ“ + 𝟏 = 𝒏 6 = 𝒏
  • 13. PRACTICE TASK β€’ WRITE WHETHER THE GIVEN SEQUENCE IS ARITHMETIC, GEOMETRIC, OR NEITHER. IF IT IS ARITHMETIC, GIVE THE COMMON DIFFERENCE. IF IT IS GEOMETRIC, GIVE THE COMMON RATIO 1) 11, 14, 17, 20, . . . 2) 4, 8, 16, 32, . . . 3) 5, 8, 12, 17, 26, . . . 4) 100, -50, 25, -12.5, . . . 5) 1, 8, 27, 64, . . .
  • 14. PRACTICE TASK β€’WRITE THE nth TERM FORMULA OF THE FOLLOWING: 1) 4, 8, 16, 32, . . . 2) 100, -50, 25, -12.5, . . . 3) 1, 3, 9, 27, . . . WRITE THE 6TH TO 10TH TERMS OF THE SEQUENCE ABOVE.
  • 15. PRACTICE TASK β€’WRITE THE nth TERM FORMULA OF THE FOLLOWING: 1) 4, 8, 16, 32, . . . 2) 100, -50, 25, -12.5, . . . 3) 1, 3, 9, 27, . . . WRITE THE 6TH TO 8TH TERMS OF THE SEQUENCE ABOVE.
  • 16. ASSIGNMENT β€’ Write whether the sequence is arithmetic or geometric. Write the nth term of each sequence. 1)2, 8, 32, 128, 512, . . . 2)3, 12, 48, 192, 768, . . . 3)-35, -32, -29, -26, -23, . . . 4)-24, -14, -5, 6, 16, . . . 5)3, -9, 27, -81, 243, . . .
  • 17. β€’WHAT IS GEOMETRIC SERIES? β€’WHAT IS THE FORMULA FOR THE GEOMETRIC SERIES? β€’GIVE 3 OF YOUR OWN EXAMPLES OF GEOMETRIC SEQUENCE,WRITE THE nth TERM FORMULA.
  • 18.
  • 19. JOURNAL ENTRY β€’ HOW DID YOU FIND THE LESSON ABOUT GEOMETRIC SEQUENCE? β€’ HOW WILL YOU FIND THE VALUE OF n IF THE GIVEN ARE π‘Ž1 = 5, π‘Ÿ = 3, π‘Žπ‘› = 10935 EXPLAIN YOUR SOLUTION.
  • 20. REFERENCES β€’ E-MATH BOOK 10 BY ORENCE ET.AL. β€’ MAKATI LMS β€’ PREPARED BY: CHRISTINE ORQUIA, LPT 1

Editor's Notes

  1. BONIFACIO, MAGBANUA, JAENA
  2. Pio and Rizal
  3. Pio and Rizal