N O dNaM d5SICs S SolutionAnswerThe artificial base pairs (d.pdf

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N O dNaM d5SICs S Solution Answer: The artificial base pairs (dNaM and d5SiCS)were first introduced by Floyd Romesberg into Escherichia coli (Bacteria). Both unnatural base pairs, dNaM and d5SiCS undergo Hydrophobic interactions. These are stable,during replication the retention was 99% in bacteria, they are not remove by error correction mechanisms but they couldn\'t be included into new copy of DNA after replication. As these unnatural bases are retained during replication, so we can tell that helicase can act on DNA containing unnatural bases and unwind strand..

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Consider the following probability distribution The Normal distribut.pdf

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1. Please explain: 1. What is cosolidation of a soi? 2. What are the assumptions for 1-D consoildation theory proposed by Kar Terzaghi? 3. Compared to compaction, what are the difference? 4. How do you define the process of a soil consolidation? 2. For settlements, what are the major components of a soil settlment? What is the difference between between settlment in sands and clays, please describe the details. Solution 1) Consolidation is the reduciton of soil volume by expulsion of pore water. 2) assumptions: 3) Compaction is expulsion of air and consolidation is expulsion of water. 4) Process of soil consolidation is not instataneous. It ia time taking process..

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What type of gametes did Sutton predict? Mendel? (parental, recombinant, both) Solution 1. According to Mendel’s law of segregation : 2 . The Chromosomal Theory of Inheritance (Theodor Boveri and Walter Sutton --1903) was consistent with Mendel\'s laws and the basic postulates were: -----------------------These lead to the conclusion that both Sutton and Mendel predicted parental types of gametes because in case of parental type , gametes are produced in equal proportion but recombinant type produces gametes in unequal proportions. Besides this , In 1911, after observing that linked traits could on occasion be inherited separately, Thomas Hunt Morgan suggested that \"crossovers\" can occur between linked genes and crossover is the prime reason for recombination.

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With reference to Barth (2014), discuss how the author assessed the extent to which unmodified historical cost, modified historical cost, and fair value measurement possess the qualitative characteristics specified in the IFRS Conceptual Framework. Solution The conceptual framework in IFRS states the qualitative characteristics of the financial statements to be useful which are as follows: 1. Fundamental : Fundamental qualitative characteristics are relevance and faithful representation. 2. Enhancing: Enhancing qualitative characteristics are comparability, completeness, verifiablity and understandability. According to Barth(2014), Historical cost does not possess the qualitative characteristics of the IFRS conceptual framework as it does not facilitates comparability and relevance but yes it is sometimes relevant. The historical cost should be modified to use in financial statements, it should be indexed for Inflation. Modified historical cost possess the qualitative characteristics of the IFRS. It is understandable, complete, accurate, but not considered as faithful representation. This is widely used but both modified historical cost and unmodified historical cost lack meaning. Whereas the Fair value presentation is more consistent with the new framework and hence it should be widely used. This paper concludes that assets and liabilities at large should be measured at fair value to provide the financial statements with the qualitative characteristics..

With reference to Barth (2014), discuss how the author assessed the .pdf

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1. Peter Grant - the evolutionary biologist who has studied finches on Daphne Major (an island in the Galapagos) for several decades - collected data on birds\' beak sizes, weight, diet and mating behavior to test his hypotheses. This kind of data is an example of: 2. In the video \"How Does Evolution Really Work?\", biologists described an example where the length of individual hummingbird beaks grew longer in response to changes in their food source (flowers). True False 3 The observation that the individuals possessing favorable traits are more likely to survive and reproduce than those possessing less favorable traits is the basis for: 4. Which one of the following descriptions, pertaining to a scientific hypothesis or theory, is NOT true? 5. Which of the following is involved in the scientific method (MARK ALL THAT APPLY)? making observations 6. Due to ___________________, \"bad science” (e.g. fake data or fake results) is eventually discovered and revealed. powerful police forces 7. Darwin\'s Hypothesis of Evolution by Natural Selection included the observation that populations often grow faster than the food supply and therefore individuals need to compete for resources. Darwin borrowed this idea from the work of: 8. Lamarck\'s \"Inheritance of Acquired Characteristics\" can best be described as: disease and starvation are required to keep population size in check 9. Aristotle and other early philosophers believed that species were \"immutable\" or \"fixed\", which means: species are always changing species don\'t change over timeA.taxonomy B.artificial selectionC.empirical evidenceD.non-factual informationE.a belief Solution 1)B)Artificial Selection as it tells about the way birds survive and their mating. 2)True yes it is rightly stated. 3)D)Natural selection which says traits move from one generation to other. and the ones with more traits survive more than other here. 4)E)it must deal with evidence that is empirical (i.e. the kind that can be observed).

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If a researcher rejects a null hypothesis when that hypothesis is actually true, he has committed: a type I error a type II error a type III error no error a type I error a type II error a type III error no error Solution If a researcher rejects a null hypothesis when that hypothesis is actually true, he has committed: a type I error a type II error a type III error no error A type I error is the incorrectly rejecting a true null hypothesis. a type I error a type II error a type III error no error.

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Write an algorithm that reads a list of integers from the keyboard, creates a list of them using linked list implementation, and prints the result Solution /* Algorithm: Implementation of linked list. Create a node type class which will hold an integer and next pointer to point to another node. Create a constructor which will construct an object of type node with the integer type data as the only parameter and initializing next pointer to NULL. Create LinkedList class which will only have head pointer. Create a constructor which will initialize this head pointer to NULL. Create a append method which will recieve an input of type integer from the user and append it to LinkedList using below steps: 1.Create a Node type object. 1.IF head is NULL assign a Node type object created in 1st step. 2.IF head is not NULL then traverse to the end of the linked list till you found a Node which has next pointer set to NULL. 3.Add Node type object created in first step to the next pointer of last node. Create a print method which will traverse the list from the head of the linked list to the last node(Node with next pointer NULL) and while traversing it will keep printing the node data. Get the userinput: Ask user for integer continously till user input -1 and append all the integers to the linked list. */ PROGRAM: #include using namespace std; class Node { public: int data; Node *next; Node(int data) { this->data = data; this->next = NULL; } }; class LinkedList { private: Node *head; public: LinkedList() { head = NULL; } void addToFront(int data) { Node *temp = new Node(data); if(head == NULL) head = temp; else { temp->next = head; head = temp; } } void append(int data) { Node *temp = new Node(data); Node *current = head; if(current == NULL) { head = temp; return; } while(current->next != NULL) { current = current->next; } current->next = temp; } void print() { Node *current = head; if(current == NULL) cout << \"No element in list. \ \"; while(current != NULL) { cout << current->data << \" \"; current = current->next; } cout << endl; } void deleteLinkedList() { Node *prev; Node *current = head; while(current!=NULL) { prev = current; current = current->next; delete prev; } } void deleteLastNode() { Node *current = head; Node *prev = NULL; if(current == NULL) return; while(current->next != NULL) { prev = current; current = current->next; } if(prev == NULL) { delete current; head = NULL; } else { prev->next = NULL; delete current; } } ~LinkedList() { deleteLinkedList(); } }; int main() { LinkedList list; int data; while(1) { cout << \"Enter the integer(-1 to Quit) : \"; cin >> data; if(data==-1) break; list.append(data); } cout << \"Content of LinkedList is : \"; list.print(); return 0; } OUTPUT: Enter the integer(-1 to Quit) : 1 Enter the integer(-1 to Quit) : 2 Enter the integer(-1 to Quit) : 3 Enter the integer(-1 to Quit) : 4 Enter the integer(-1 to Quit) : -1 Content of LinkedList is : 1 2 3 4.

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The zygomycota produce... septate hyphae with solid septate coenocytic hyphae asexual spores that are the most desiccation-resistant stage of the life cycle multi-nuleate zygosporangia zygosporangia that are produced asexually two different types of spores: one through asexual processes and one through sexual processes septate hyphae with a central pore Solution Zygomycotina contain about 1050 species of fungi. These fungi live in soil as saprophytes or parasites on plants, insects and samll animals. The hyphae are coenocytic or multinucleate. The hyphae are not septate but sepat are formed at the site of formation of gametangia. The zygophores are produced during sexual reproduction and form zygosporangia by fusion of (+) and (-) hyphae. Asexual spores formed include mitospores and chlamydospores. These spores are dormant and desiccation resistant. Options 2, 3 and 6 are correct..

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